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\markboth{\hfil Rotationally Symmetric Deformations of a Spherical Cap \hfil}%
{\hfil John V. Baxley \& Stephen B. Robinson \hfil}
\begin{document}
\title{\vspace{-1in}\parbox{\linewidth}{\footnotesize\noindent
{\sc  Differential Equations and Computational Simulations III}\newline
J. Graef, R. Shivaji, B. Soni, \& J. Zhu (Editors)\newline
Electronic Journal of Differential Equations, Conference~01, 1997, pp. 11-21. \newline
ISSN: 1072-6691. URL: http://ejde.math.swt.edu or http://ejde.math.unt.edu
\newline ftp  147.26.103.110 or 129.120.3.113 (login: ftp)}
 \vspace{\bigskipamount} \\
 Rotationally Symmetric Deformations of a Spherical Cap 
\thanks{ {\em 1991 Mathematics Subject Classifications:} 34B15, 65L10.
\hfil\break\indent
{\em Key words and phrases:} singular nonlinear boundary value problems,
\hfil\break\indent  existence and uniqueness, upper and lower solutions.
\hfil\break\indent
\copyright 1998 Southwest Texas State University  and University of
North Texas. \hfil\break\indent
Published November 12, 1998.} }

\date{}
\author{John V. Baxley \& Stephen B. Robinson}
\maketitle

\begin{abstract} 
We prove the existence and uniqueness of rotationally symmetric
solutions to a nonlinear boundary value problem representing the
elastic deformation of a spherical cap. 
\end{abstract}

\newtheorem{lemma}{Lemma}
\newtheorem{theorem}{Theorem}

\section{Introduction}

Suppose that a rotationally symmetric membrane is subjected to a vertical
pressure as well as a prescribed displacement at its boundary. 
In \cite{D1}, Wayne Dickey derived a
model to describe the deformation of this membrane.
 Under the assumption of small strains, i.e. Hooke's laws, Dickey derived the following problem.
\begin{eqnarray}
&  \left (\frac{r}{m}(rT)'\right )'=\frac{mT}{\sqrt{G^2+T^2}}-1+mT+
 \frac{\nu(r^2G^2)'}{2r\sqrt{G^2+T^2}}\, 
 \mbox{ in } (0,1),& \nonumber \\
 & |T(0)|<\infty, \mbox{ and }& \label{bvp1} \\
 & \left (\frac{(rT)'}{m}-\nu\sqrt{G^2+T^2}\right )_{r=1}=\mu\,,&\nonumber
\label{ap}
\end{eqnarray}
where $(r,z(r))$ represents the profile of the undeformed membrane in
 cylindrical coordinates, 
$m=\sqrt{1+(z')^2}$, $ G=\frac{1}{Ehr}\int_0^r\rho m P\, d\rho$, $E$ is
Young's modulus, $h$ is the thickness, $P(r)$ is the
pressure, $\nu$ is the Poisson ratio, and $\mu$ is the displacement at
 the boundary. $T$ is an auxiliary function that can be used to derive
 the exact shape of the deformed membrane, as well as the internal stresses
  and strains.
For the case of small pressure and shallow caps $T$ can be thought of as a rescaled radial stress, and the substitution $T=\sigma_r$ is often used in the literature. (See \cite{D1}.)

This problem is usually studied with additional simplifying
assumptions. Specifically, assuming a shallow membrane with 
undeformed shape $z(r)=c(1-r^{\gamma})$, where $\gamma >1$ and 
$0\leq c \ll 1$,
 and assuming that the membrane is subjected to a small constant pressure 
 with the property that
$\lim_{G\rightarrow 0}\frac{G}{T}=-z'$, then Dickey derived
an approximate theory where $T$ must satisfy
\begin{eqnarray}
&  r^2T''+3rT'=\frac{\lambda^2r^{2\gamma-2}}{2}+\frac{\beta\nu r^2}{T}
 -\frac{r^2}{8T^2} 
 \mbox{ in } (0,1),&\nonumber \\
 & |T(0)|<\infty , \mbox{ and}&\label{bvp2} \\
 & T'(1)+(1-\nu)T(1)=\mu\,, &\nonumber
\end{eqnarray}
where $\lambda$ and $\beta$ are positive constants depending on 
$P,h,$ and $E$. In the case that $\gamma=2$ the model serves as a good
approximation of the spherical cap. The assumption on $\frac{G}{T}$ is motivated by a search for deformations that are small when pressure is small.
This problem has been studied extensively
in recent literature. A relatively complete treatment of the problem
 is contained in \cite{J1,J2,B2,B3}, although
 there are still some open questions, such as the existence of 
 multiple solutions under certain conditions, and the stability of radial solutions. Earlier fundamental work is
 contained in papers such as \cite{R,G,BS,D2,D3,B1}.

In this paper we examine a special case of the more general model
(\ref{bvp1}), with the assumptions that
 $\nu=0$ and that $z(r)\in C^2[0,1]$ is a positive decreasing concave function with 
 $z'(0)=0$ and $z''(0)<0$. Observe that this includes spherical caps as a special case. The
 model reduces to
\begin{eqnarray}
& \left (\frac{r}{m}(rT)'\right )'=\frac{mT}{\sqrt{G^2+T^2}}-1+mT\, 
 \mbox{ in } (0,1),&\nonumber \\
 & |T(0)| <\infty, \mbox{ and}& \label{bvp3} \\
 & T'(1)+T(1)=m(1)\mu\,. \nonumber
\end{eqnarray}
It should be noted that the derivation of this model assumes small strains
 and stresses. As a consequence the physical relevance of the model is lost
  for large values of $|\mu|$. Also, the assumption that $\nu =0$ indicates that we are modeling a material that is easily compressed.

We will show that problem (\ref{bvp3}) has a unique solution for all 
$\mu\in{\mathbb R}$. 
This conclusion agrees well with recent investigations of the approximate problem (\ref{bvp2}). Our primary tool is the technique of upper and lower solutions, and in some ways our methods simplify the shooting arguments used in the references mentioned above. 

We would like to thank the referee for several helpful suggestions and
 corrections.

\section{ Preliminaries}

In this section we rewrite (\ref{bvp3}) in a convenient form, 
and we establish the necessary framework for an upper and lower solutions
 argument. Specifically, we must understand some of the geometry associated
  with the nonlinear term, and then we must establish some regularity
 estimates and a comparison theorem for the differential operator.

Problem (\ref{bvp3}) can be rewritten as
\begin{eqnarray}
& \left (\frac{r^3}{m}T'\right )'=
 r\left [\frac{mT}{\sqrt{G^2+T^2}}-1+kT \right ]\, 
 \mbox{ in } (0,1),&\nonumber \\
& |T(0)|<\infty , \mbox{ and} & \label{bvp4} \\
&  T'(1)+T(1)=m(1)\mu\,, \nonumber 
\end{eqnarray}
where $ k=\left (m-(\frac{r}{m})'\right )$.
For notational convenience in what follows we let
\[
LT:= \left (\frac{r^3}{m}T'\right )',\,\mbox{ and } f(r,T):=\frac{mT}{\sqrt{G^2+T^2}}-1+kT.
\]

We begin our analysis of (\ref{bvp4}) by a careful examination of 
$f(r,T)$.  It is particularly important to
describe the level set $f^{-1}(0)$, and to determine how $f(r,T)$
 behaves near $r=0$.

First, observe that
\[
 m'=\frac{z'z''}{m}\,.
\]
Thus $m$ is strictly increasing with $ \lim_{r\rightarrow 0}\frac{m'}{r}=(z''(0))^2$ and 
$ \lim_{r\rightarrow 0} m(r) =1$.
Next we see that
\[
k=\frac{(z')^2+(z')^4+rz'z''}{m^3}\,.
\]
Therefore $k(r)>0$ for $r>0$ and $\lim_{r\rightarrow 0} \frac{k}{r^2}= 2(z''(0))^2$.
Since $P$ is assumed to be constant, $G$ can be simplified as follows.
\[
G=\frac{P}{Ehr}\int_0^rm\rho d\rho\,.
\]
And so $G\in C^1[0,1]$ with
\begin{eqnarray*}
&\frac{Pr}{2Eh}\leq G\leq \frac{Prm(r)}{2Eh}, \mbox{ and}& \\
& G'(0)=\frac{P}{2Eh}.&
\end{eqnarray*}
It is certainly possible to obtain more detailed information about the
properties of $m,k$, and $G$, but the given information will suffice.

The following lemmas describe the level set $f^{-1}(0)$.

\begin{lemma}
$f^{-1}(0)\bigcap \left ((0,1]\times {\mathbb R}\right )$ is the graph of a strictly 
positive smooth function $\tau (r)$.
\label{lemma1}
\end{lemma}

\noindent{\bf Proof:}
A straight forward computation gives
\[
 f_T=\frac{mG^2}{(G^2+T^2)^{3/2}}+k\,.
\]
Since $f_T\geq k(r)>0$ for all $r>0$, it follows
that there is a function $\tau \in C^1(0,1]$ such that $\tau (r)$ is the unique solution
of $f(r,\tau (r))=0$ and $ \tau'=-f_r/f_T$. It is clear that $f(r,T)\leq -1$ for
$T\leq 0$, so $\tau (r)>0$. 
\hfill$\diamondsuit$\medskip

It should be clear that $f(r,T)<0$ for $T<\tau (r)$ and $f(r,T)>0$ for $T>\tau (r)$.

\begin{lemma}
$ \lim_{r\rightarrow 0} \tau (r)$ exists and is strictly positive. 
\end{lemma}

\noindent{\bf Proof:}
We begin by claiming that $ \lim_{r\rightarrow 0}k(r)\tau (r)=0$. If not, there must be a sequence $\{r_n\}$ such that $r_n\rightarrow 0$ and $\liminf_{n\rightarrow\infty}k(r_n)\tau (r_n)>0$. Since $k(r_n)\rightarrow 0$, we know that $\tau (r_n)\rightarrow \infty$.
Since $m(r_n)\rightarrow 1$ and $G(r_n)\rightarrow 0$, it follows that
$$ \frac{m(r_n)\tau (r_n)}{\sqrt{G(r_n)^2+\tau(r_n)^2}}\rightarrow 1
$$, and,
since $f(r_n,\tau (r_n))=0$, we get $k(r_n)\tau (r_n)\rightarrow 0$, a
 contradiction.

Now rewrite the equation $f(\tau,r)=0$  as
\[m^2\tau^2=(1-k\tau)^2(G^2+\tau^2).\]
After a rearrangement of terms we get
\[
((z')^2+2k\tau-k^2\tau^2)\tau^2=G^2(1-k\tau)^2\,.
\]
If we divide through by $r^2z''(0)^2$ we get a polynomial in $\tau$ whose
coefficients converge as $r\rightarrow 0$ yielding the limiting polynomial
\[ 4\tau^3+\tau^2=\left (\frac{P}{2Ehz''(0)}\right )^2.\]
It is not hard to see that $\tau (r)$ must converge to the unique positive
 root, $\tau_0$, of the limiting polynomial as $r\rightarrow 0$.
\hfill$\diamondsuit$\medskip

The next lemmas describe $f(r,T)$ near $r=0$.

\begin{lemma}
Let $D_\epsilon:=\{(r,T):T\geq \sqrt{\epsilon^2-r^2}\mbox{ for }r< \epsilon\}$. There is a continuous function $h:D_\epsilon\rightarrow{\mathbb R}$, which is continuously differentiable in $T$,
such that $f(r,T)=r^2h(r,T)$ in $D_\epsilon$.
\end{lemma}

\noindent{\bf Proof:}
This assertion is clear for $r\neq 0$. For points where $r=0$ and
$T\geq\epsilon$ the result is a consequence of the following limits. 
\begin{eqnarray*}
 \lim_{r\rightarrow 0} \frac{f(r,T)}{r^2} & =&
 \lim_{r\rightarrow 0} \frac{1}{r^2}\left (\frac{mT}{\sqrt{G^2+T^2}}-1
+kT \right )  \\
 &=& \lim_{r\rightarrow 0}  \frac{1}{r^2}\left (
 \frac{m-\sqrt{1+\frac{G^2}{T^2}}}
{\sqrt{1+\frac{G^2}{T^2}}} \right )+2(z''(0))^2T  \\
& =&\lim_{r\rightarrow 0} \frac{1}{r^2}\left (
\frac{1+\frac{1}{2}(z')^2+o((z')^2)-1-\frac{1}{2}\frac{G^2}{T^2}-
o(\frac{G^2}{T^2})}
{\sqrt{1+\frac{G^2}{T^2}}}\right )\\
&&+2(z''(0))^2T \\
& =&\frac{1}{2}(z''(0))^2-\frac{1}{2}\left (
\frac{P}{2Eh}\right )^2T^{-2}+2(z''(0))^2T,
\end{eqnarray*}
and similarly
\[
\lim_{r\rightarrow 0} \frac{f_T(r,T)}{r^2}=
 \lim_{r\rightarrow 0} \frac{1}{r^2}\left (\frac{mG^2}{(G^2+T^2)^{\frac{3}{2}}}+k\right )=
\left (\frac{P}{2Eh}\right )^2T^{-3}+2(z''(0))^2.
\]
\hfill$\diamondsuit$\medskip


The properties established so far are elementary but have important
consequences. Knowledge of $f^{-1}(0)$ allows us to choose constant
upper and lower solutions when $\mu>0$. 
The monotonicity of $f(r,\cdot)$ will imply the uniqueness of solutions. The 
previous  lemma  allows
us to think of the differential equation as $LT=r^3h(r,T)$, which has
useful consequences in terms of regularity, as we shall see below. Moreover, 
it will allow us to show that, on any compact subset of $D_{\epsilon}$, there is a $\delta>0$ such that
$rf(r,T)-\delta r^3 T=r^3(h(r,T)-\delta T)$ is 
decreasing as a function of $T$. 
This last detail will be crucial to the
success of our iteration scheme.

This is a good point for a remark on the derivation of the approximate problem (\ref{ap}), and its relation to problem (\ref{bvp4}). In the previous proof we wrote
\[
f(r,T)=\frac{\frac{1}{2}(z')^2-\frac{1}{2}\frac{G^2}{T^2} +o((z')^2)+o(\frac{G^2}{T^2})}{\sqrt{1+\frac{G^2}{T^2}}}+kT.
\]
Under the assumptions of small pressure and shallow caps, as in (\ref{ap}), it is quite
reasonable to drop the $o((z')^2)$ and $o(\frac{G^2}{T^2})$ terms, and to substitute $1$ for 
$\sqrt{1+\frac{G^2}{T^2}}$. Also, if we are looking for solutions such that $T\rightarrow 0$ as $P\rightarrow 0$, then it is reasonable to drop the $kT$ term. What remains is in agreement with Dickey's derivation for the case $\nu=0$.

Next we study the differential operator  $L$.
Consider  the  problem
\begin{eqnarray}
 & Lv-r^3g(r)=0\, \mbox{ in } (0,1),& \nonumber \\
 & |v(0)|<\infty, \mbox{ and}&\label{linbvp} \\
 & T'(1)+T(1)=m(1)\mu \,,& \nonumber
\end{eqnarray}
where $g\in C[0,1]$.
We will show that this problem is uniquely solvable and establish
estimates for the solutions. 

\begin{lemma}
If $v$ is a solution of (\ref{linbvp}), then
$\lim_{r\rightarrow 0} r^3v'(r)=0$.
\label{lemma3}
\end{lemma}
\noindent{\bf Proof:}
Observe that for $a,r\in (0,1)$ $v$ must satisfy
\[
\frac{a^3}{m(a)}v'(a)-\frac{r^3}{m(r)}v'(r)=\int_r^a t^3g(t)\,dt\,.
\]
Since the limit of the integral clearly exists as $r\rightarrow 0$, 
and $m(r)\rightarrow 1$, then $\lim_{r\rightarrow 0} r^3v'(r)$ must
also exist. However, if this limit is not zero, then in some neighborhood
of $0$ there will be an $\epsilon>0$ such that
$ v'\geq \frac{\epsilon}{r^3}$, or 
$ v'\leq -\frac{\epsilon}{r^3}$. 
This implies that $\lim_{r\rightarrow 0} |v|=\infty$, contradicting the given boundary condition. 
\hfill$\diamondsuit$\medskip


By integrating the differential equation and using Lemma \ref{lemma3}
 we derive the equivalent problem 
\[
v'(r)=\frac{m}{r^3}\int_0^rt^3g(t)dt,\,\mbox{and } 
v'(1)+v(1)=m(1)\mu\,.
\]
This implies
\[
|v'(r)|\leq m\frac{r}{4}|g|_{0},
\]
where $|\cdot |_{0}$ represents the usual sup-norm on $C[0,1]$. Notice that this
estimate provides a more precise description of the behavior of $v'$ near
$0$ than the given boundary condition indicates.  It also helps determine
the smoothness of the solution. In particular, 
this indicates that $ |v'|_0\leq\frac{m(1)}{4}|g|_0.$ Observe that this bound
is independent of the boundary data.

Differentiating the formula for $v'(r)$ leads to 
\[
v''(r)= \left (\frac{m}{r^3}\right )'\int_0^r t^3g(t)\,dt+m(r)g(r)\,.
\]
It follows that $v\in C^2[0,1]$ with 
$ |v''|_0\leq ( \max_{[0,1]}|z'z''|+\frac{7}{4}m(1))|g|_0$, 
and $ v''(0)=g(0)/4$.
Now integrate $v'(r)$  to get
\[
v(r)=v(0)+\int_0^r\frac{m}{t^3}\int_0^ts^3g(s)\,ds\,dt.
\]
We can solve for $v(0)$ as follows.
\begin{eqnarray*}
 v(0)& =&v(1)-\int_0^1\frac{m}{t^3}\int_0^ts^3g(s)\,ds\,dt\\
& =& m(1)\mu -v'(1) -\int_0^1\frac{m}{t^3}\int_0^ts^3g(s)\,ds\,dt \\
& =& m(1)\mu-m(1)\int_0^1 t^3g(t)dt-\int_0^1\frac{m}{t^3}\int_0^ts^3g(s)
\,ds\,dt.
\end{eqnarray*}
Thus we have an explicit formula for $v(r)$ and it is clear that
 $|v|_0\leq c_1 +c_2|g|_0$ for some constants $c_1,c_2$.

For convenience we use the notation $v=L^{-1}g$. Our estimates
indicate that 
\[
L^{-1}:C[0,1]\rightarrow C^2[0,1],
\]
is a continuous affine map sending bounded sets to bounded sets.
Moreover, an application of the Arzela-Ascoli theorem implies that
\[
L^{-1}:C[0,1]\rightarrow C^1[0,1]
\]
is compact. 

In order to apply an upper/lower solution technique we need a comparison
result. 

\begin{lemma}
Suppose $\delta\geq0$ and let $v_1,v_2 \in C^2[0,1]$ such that 
$Lv_1-\delta r^3v_1\leq Lv_2-\delta r^3v_2$ in $(0,1)$,and 
$v'_1(1)+v_1(1)\geq v'_2(1)+v_2(1)$. Then $v_1\geq v_2$ on all of $[0,1]$.
\end{lemma}

\noindent{\bf Proof:}
Suppose $v_1<v_2$ at some point in $[0,1]$, and let $[a,b]\subset [0,1]$
be the maximal subinterval, containing this point, where the inequality
$v_1\leq v_2$ is satisfied. Observe that
$L(v_1-v_2)\leq \delta r^3 (v_1-v_2)\leq 0$. It follows that $v_1-v_2$
cannot achieve its negative minimum in $(a,b)$. Suppose that minimum is
achieved at $r=b$. It must be that $b=1$.
Further, $v_1(1)<v_2(1)$ and $v'_1(1)\leq v'_2(1)$. Thus
$v'_2(1)+v_2(1))> v'_1(1)+v_1(1)$, a contradiction. The only remaining
possibility is that
the negative minimum is achieved at $a$ with $a=0$. If this is the case
then $L(v_1-v_2)<0$ in a neighborhood of $r=0$. Integrating gives
$\frac{r^3}{m}(v'_1-v'_2)<0$ and so $(v_1-v_2)$ must be decreasing in
a neighborhood of $r=0$, which contradicts the fact that a minimum is
achieved at $0$.\hfill$\diamondsuit$\medskip

An immediate consequence of Lemma 5 is that $I-\delta L^{-1}$ is injective
 for any $\delta\geq 0$. Since $L^{-1}$ is compact it follows from the
 Fredholm Alternative that $I-\delta L^{-1}$ is invertible. Hence the
 problem
\begin{eqnarray}
& Lv-r^3\delta v=r^3g\, \mbox{ in } (0,1),&\nonumber \\
& |v(0)|<\infty, \mbox{ and}&\label{bvp6} \\
& v'(1)+v(1)=m(1)\mu &\nonumber
\end{eqnarray}
has a solution operator $(L-r^3\delta)^{-1}$ such that
\[
(L-r^3\delta)^{-1}:C[0,1]\rightarrow C^2[0,1]
\]
is continuous, and is thus compact as a map from $C[0,1]$ into $C^1[0,1]$.
(We are indebted to the referee for the preceding application of the
Fredholm Alternative, which simplified and clarified this portion of the
argument.)

We finish this section with a lemma that provides qualitative
information about the desired solutions.

\begin{lemma}
Suppose that $T$ is a solution of (\ref{bvp4}). Then $T(0)>0$ and
$T'(0)=0$.
\end{lemma}

\noindent{\bf Proof:} Suppose
that $T(0)\leq 0$. Choose a maximal $\epsilon\in (0,1]$ such that $T(r)\leq \tau (r)$ for $r\in [0,\epsilon]$, where $\tau (r)$ is the curve describing $f^{-1}(0)$ . Since $f(r,T)\leq 0$ on this interval, integrating the DE
yields
\[
\frac{r^3}{m}T'(r)\leq 0\,.
\]
Thus $T$ is nonincreasing and $T\leq 0<\tau (r)$ in $[0,\epsilon]$, and thus in $[0,\epsilon]$. It must
 be the case that 
$\epsilon =1$. Since $T\leq 0$ we know that $f(r,T)\leq -1$ and integrating the DE yields
\[
\frac{r^3}{m}T'(r)<-\frac{r^2}{2}\,.
\]
Hence, 
\[
T'(r)<-\frac{m}{2r}\,,
\]
which implies $ \lim_{r\rightarrow 0} T(r)=-\infty$, a contradiction.

Since $T(0)>0$ we know that the graph of $T$ lies in $D_\epsilon$ for some
$\epsilon$. Thus $T=L^{-1}(rf(r,T))=L^{-1}(r^3h(r,T))$, where
$h(r,T(r))\in C[0,1]$ so our estimates imply that $T'(0)=0$.
\hfill$\diamondsuit$\medskip

Similar arguments show that if $T(0)\leq \min \{T:f(r,T)=0\}$, then
$T$ is decreasing on $[0,1]$, and if $T(0)\geq \max \{T:f(r,T)=0\}$, then $T$ is
increasing on $[0,1]$.

Finally, we remark that the previous arguments are valid for much more
general boundary data. Given any smooth boundary operator
$B(\alpha,\beta)$ such that $B_\alpha\geq 0$ and $B_\beta\geq c>0$ for
some constant $c$, then the results above can all be proved with analogous
arguments using the boundary condition $B(v'(1),v(1))=0$. In our case we
are using $B=\alpha +\beta -m(1)\mu$.

\section{ Existence and Uniqueness }

In this section we prove the main theorems using the method of upper and
lower solutions. Recall that an upper solution of (\ref{bvp4}) is defined
as a function $u$ satisfying
\begin{eqnarray}
&  \left (\frac{r^3}{m}u'\right )'\leq
 r\left [\frac{mu}{\sqrt{G^2+u^2}}-1+ku \right ]\, 
 \mbox{ in } (0,1),&\nonumber \\
 & |u(0)|<\infty , \mbox{ and}&  \\
 & u'(1)+u(1)\geq m(1)\mu\,,& \nonumber
\end{eqnarray}
and a lower solution is defined similarly with the inequalities reversed.
In our proofs we will identify upper and lower solutions $u$ and $l$,
respectively, such that $l\leq u$, and then we will show that a sequence of
 approximate solutions, starting with $l$, increases monotonically to a
 solution $T$ such that $l\leq T\leq u$. In many cases we can choose
 constant functions for $u$ and $l$. In general it will be important that
 we can choose $u$ and $l$ lying in $D_\epsilon$ for some $\epsilon>0$.

\begin{theorem}
The boundary value problem (\ref{bvp4}) has at most one solution.
\end{theorem}

\noindent{\bf Proof:}
Suppose that $T_1$ and $T_2$ are distinct solutions. Without loss of
generality, $T_1>T_2$ on some interval $(a,b)$, and we can assume that
this interval is maximal. By the monotonicity of
$f(r,\cdot)$ we have that $L(T_2)=rf(r,T_2)<rf(r,T_1)=L(T_1)$ in $(a,b)$.
We also know that $T_1'(1)+T_1(1)=T_2'(1)+T_2(1)$. In each of the cases
$0<a<b<1$, $0<a<b=1$, or $0=a<b<1$, the comparison lemma, or a minor
 modification of it, is valid. Thus $T_1\leq T_2$, a contradiction.
 \hfill$\diamondsuit$\medskip

\begin{theorem}
(\ref{bvp4}) has a solution for all $\mu\in{\mathbb R}$.
\end{theorem}

First, we assume that $\mu>0$. Let $\tau (r)$ describe the level set
$f^{-1}(0)$ as in the previous section.
Let $a$ and $b$ be positive constants such that $0<a\leq \tau (r)\leq b$
 for all $r$, and such that $a<m(1)\mu<b$. Choose
$ \delta>\max_{[0,1]\times [a,b]}|h_T(r,T)|$ . It follows that
$f(r,a)\leq 0\leq f(r,b)$ for all $r$, and that 
$rf(r,T)-r^3\delta T$ is strictly decreasing as a function of $T$ for
$a\leq T \leq b$.

Consider the following iteration scheme. Let $T_0\equiv a$, and for
integers $n\geq 0$ let $T_{n+1}$ satisfy
\begin{eqnarray}
& LT_{n+1}-r^3\delta T_{n+1} =rf(r,T_n)-\delta r^3 T_n\, \mbox{ in } (0,1),
&\nonumber \\
& |T_{n+1}(0)|<\infty, \mbox{ and} & \\
&  T_{n+1}'(1)+T_{n+1}(1)=m(1)\mu\,.\nonumber
\end{eqnarray}

We will show that this sequence is well-defined, is bounded between $a$
and $b$, and increases monotonically to a solution of (\ref{bvp4}).

\begin{lemma}
$T_1$ exists and satisfies $a\leq T_1 \leq b$.
\end{lemma}

\noindent{\bf Proof:}
Since $T_0\equiv a>0$ we can write
$LT_1-\delta r^3T_1=r^3(h(r,a)-\delta a)$ and our comments in the previous
 section guarantee the existence of $T_1$.
Moreover,
\[
LT_1-r^3\delta T_1=rf(r,T_0)-\delta r^3 T_0< LT_0-\delta r^3 T_0\,,
\]
and
\[
T_1'(1)+T_1(1)=m(1)\mu>a=T_0'(1)+T_0(1)\, .
\]
Hence, $T_1\geq T_0\equiv a$ by the comparison lemma. A similar comparison
yields the upper bound.
\hfill$\diamondsuit$\medskip

Now we continue by induction

\begin{lemma}
$T_n$ exists for all $n$,and $a\leq T_{n-1}\leq T_n\leq b$.
\end{lemma}

\noindent{\bf Proof:}
Assume the statement is true for $T_1,\dots,T_n$.
Since $T_n\geq a$ we know that $T_{n+1}$ exists, just as in the previous
proof. Moreover,
\[
LT_{n+1}-\delta r^3T_{n+1}=rf(r,T_n)-\delta r^3 T_n \leq rf(r,T_{n-1})-\delta r^3T_{n-1}=
LT_n-\delta r^3T_n\,,
\]
where we have used the inductive hypothesis and the fact that
$rf(r,\cdot)-\delta r^3\cdot$ is decreasing.
We also have $T_{n+1}'(1)+T_{n+1}(1)=T_n'(1)+T_n(1)$, and thus
$T_{n+1}\geq T_n$. A similar comparison yields the upper bound
$T_{n+1}\leq b$.
\hfill$\diamondsuit$\medskip


Thus $\{T_n\}$ is a bounded and monotonically increasing sequence in
$C[0,1]$.
By regularity it follows that $\{T_n\}$ is bounded in $C^2[0,1]$. 
By compactness we know
that $T_n\rightarrow T$ in $C^1[0,1]$, and we can bootstrap to get
$T_n\rightarrow T$ in $C^2[0,1]$. $T$ is clearly a solution of (\ref{bvp4}).

We have established existence for $\mu>0$. Now we can extend this result
to $\mu\in{\mathbb R}$ by repeating the iteration scheme with new choices of
upper and lower solutions. It is a nice property of this method that we can
use previously established solutions as upper or lower solutions
that extend the results. 

Let $M=\{\mu\in{\mathbb R} :\mbox{ (\ref{bvp4}) has a solution }\}$. For $\mu\in M$
let $T_{\mu}$ represent the corresponding solution. Our work so far has
shown that $(0,\infty)\subset M$. The following lemmas establish that
$M={\mathbb R}$.

\begin{lemma}
If $\mu\in M$, then $[\mu,\infty)\subset M$.
\end{lemma}

\noindent{\bf Proof:}
If $\mu_1>\mu$ then $T_{\mu}$ can replace the constant $a$ as the
lower solution in the iteration scheme, and the constant $b$ can be
chosen as before to be an upper solution. The set 
$J:=\{(r,T):T_{\mu}(r)\leq T\leq b\}$ is a compact subset of $D_\epsilon$ for some $\epsilon>0$, so
we may choose $ \delta>\max_{J}|h_T(r,T)|$, and conclude that
$rf(r,T)-\delta r^3 T$ is decreasing as a function of $T$ in $J$. 
The iteration
scheme will work precisely as before to yield a solution for $\mu_1$.
\hfill$\diamondsuit$\medskip

\begin{lemma}
$M$ is open.
\end{lemma}

\noindent{\bf Proof:}
Suppose that $\mu\in M$. Consider 
$ l:=T_{\mu}-\frac{1}{2}T_{\mu}(0)$ and 
$ u:=T_{\mu}$. These will serve as lower and upper solutions,
respectively, and the
iteration scheme implies the existence of solutions for 
$ \mu_0\geq \mu-\frac{T_\mu(0)}{2}$
\hfill$\diamondsuit$\medskip


\begin{lemma}
$M={\mathbb R}$.
\end{lemma}

\noindent{\bf Proof:}
Suppose that $M=(\mu,\infty)$ with $\mu>-\infty$, and suppose that
$\mu_n$ is a decreasing sequence converging to $\mu$. 
By arguments similar to those above we can show that
the corresponding sequence of solutions
is monotonically decreasing. Each
member of this sequence is positive at $r=0$ and cannot attain a negative interior
minimum, so if $T_{\mu_n}(1)$ is bounded below, then the 
solution sequence is also bounded below. If $T_{\mu_n}(1)<0$, then
$T_{\mu_n}$ achieves its minimum at $r=1$, so $T'_{\mu_n}(1)\leq 0$ .
Thus
$ \mu\leq \frac{1}{m(1)}( T'_{\mu_n}(1)+T_{\mu_n}(1))\leq
T_{\mu_n}(1)$. Hence the solution sequence is bounded below,
and converges monotonically to a function $T_\mu$.
Standard arguments can now be applied
to show that $T_\mu\in C[0,1]$, $T_\mu$ satisfies
the differential equation in $(0,1]$, and $T_\mu$ satisfies
 the boundary data at $r=1$.
Thus $\mu\in M$, a contradiction.
\hfill$\diamondsuit$\medskip

Thus  Theorem 2 is proved. This theorem agrees in many respects with the
spherical cap results in the references. It remains to be seen how the 
problem will behave for more general
membranes and for $\nu>0$. We remark that an application of the Implicit
Function Theorem extends existence and uniqueness to small $\nu>0$, but
a thorough investigation of these matters is left for future work.

\begin{thebibliography}{99}
\bibitem{B1} J. V. Baxley, A singular nonlinear boundary value problem:
 membrane response of a spherical cap,  {Siam J. Appl. Math.}
 {\bf 48} (1988), 497-505.
\bibitem{B2} J. V. Baxley and Y. Gu, Nonlinear boundary value problems
 for shallow membrane caps, to appear in { Comm. Appl. Anal.} {\bf 3} (1999).

\bibitem{B3} J. V. Baxley and S. B. Robinson, Nonlinear boundary value
 problems for shallow membrane caps II, {Journal of Computational and Applied Mathematics} {\bf 88} (1998), 203-224

\bibitem{BG} A. Beck and H. Grabm\"{u}ller, Wrinkle-free solutions in
 the theory of curved circular membrane problems, 
 {J. Engineering Math.} {\bf 27} (1993), 389-409.
\bibitem{BS} E. Bromberg and J. J. Stoker, Non-linear theory of curved
 elastic sheets,  {Quart. of Appl. Math.} {\bf 3} (1945/46), 246-265.
\bibitem{D1} R. W. Dickey, Membrane caps,  {Quart. of Appl. Math.}
 {\bf 45} (1987), 697-712.
\bibitem{D2} \rule{0.7in}{0.01in}, Membrane caps under hydrostatic
 pressure,  {Quart. of Appl. Math.} {\bf 46} (1988), 95-104.
\bibitem{D3} \rule{0.7in}{0.01in}, Rotationally symmetric solutions for
 shallow membrane caps,  {Quart.}  {of Appl. Math.} {\bf 47} (1989),
 571-581.
\bibitem{FMM} G. E. Forsythe, M. A. Malcolm, and C. B. Moler,
 {Computer Methods for Mathematical Computations}, Prentice-Hall,
 Englewood Cliffs, New Jersey, 1977.
\bibitem{G} M. A. Goldberg, An iterative solution for rotationally
 symmetric non-linear membrane problems,  {Int. J. Non-linear Mechs.}
 {\bf 1} (1966), 169-178.
\bibitem{J2} K. N. Johnson, Circularly symmetric deformation of shallow
 elastic membrane caps. Doctoral Thesis, University of Wisconsin, Madison,
 Wisconsin, 1994.
\bibitem{J1} \rule{0.7in}{0.01in}, Circularly symmetric deformation of
 shallow elastic membrane caps, {Quart. of Appl. Math.} to appear.
\bibitem{R} E. Reissner, Rotationally symmetric problems in the theory of
 thin elastic shells,  {3rd U.S. Natl. Congress of Applied Mechanics}, 1958.
\end{thebibliography}
\bigskip

\noindent{\sc John V. Baxley} (e-mail baxley@mthcsc.wfu.edu)\newline
{\sc Stephen B. Robinson} (e-mail robinson@mthcsc.wfu.edu)\newline
Department of Mathematics and Computer Science \newline
Wake Forest University \newline
Winston-Salem, NC  27109. USA

\end{document}
