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 \markboth{ Transient effects of stochastic multi-population models }
 { Thomas C. Gard }
 \begin{document}
 \setcounter{page}{81}
 \title{\vspace{-1in}\parbox{\linewidth}{\footnotesize\noindent
 Nonlinear Differential Equations, \newline
 Electron. J. Diff. Eqns., Conf. 05, 2000, pp. 81--90\newline
 http://ejde.math.swt.edu or http://ejde.math.unt.edu
 \newline ftp  ejde.math.swt.edu or ejde.math.unt.edu (login: ftp)}
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 %
  Transient effects of stochastic \\ multi-population models
 %
 \thanks{ {\em Mathematics Subject Classifications:} 92D25, 60H10.
  \hfil\break\indent
 {\em Key words:} multi-population models,
  stochastic differential equations, transient behavior.
  \hfil\break\indent
 \copyright 2000 Southwest Texas State University.
 \hfil\break\indent Published October 25, 2000. } }

 \date{}
 \author{ Thomas C. Gard }
 \maketitle

 \begin{abstract}
 We give some estimates for exit probabilities through specific
 portions of the boundary of bounded subsets of the feasible region for
 solutions of stochastic population interaction models. These exit
 probability estimates can indicate initial tendencies for survival or
 extinction for the modeled populations. When the subset boundaries are
 given by level curves of multiple Liapunov type functions, the estimates
 are more tractable.
 \end{abstract}



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 \section{Introduction and main result}

 Transient effects are often
 overlooked in the mathematical analysis of population dynamics models.
 Generally the focus of qualitative investigations is on long term
properties
 such as asymptotic stability, while for the short term picture,
simulations
 are carried out. Even after fairly exhaustive efforts of the latter type,
 it may be still difficult to conclude anything of very general nature
 concerning short-to-intermediate time horizon events. Such information
 could have crucial practical significance. If the location of a stable
 equilibrium, periodic solution or strange attractor is close to the
boundary
 of the feasible region, or if trajectories typically sweep close to the
 boundary before settling down near some special trajectory, the transient
 behavior of the model may be more important than some of these other
 qualitative properties. The situation may be even more critical if random
 features ([1]) are incorporated in the model.

  We address this situation with a result for a generic such model - an Ito
 stochastic $n$-dimensional multi-population interaction model
 (in Kolmogorov form)
 \begin{equation}
 dX=D(X) [f(X)\,dt+G(X) \,dW].
 \end{equation}
 Here
 $$
 X=(X_1,X_2,...,X_n)
 $$
 with $X_i$ representing the ith-species population density, and
 $$
 D=D(X)=\mathop{\rm diag}\{X_1,X_2,...,X_n\};
 $$
 more precisely,
 $$
 X=X(t,\omega)=\{X_1(t,\omega),X_2(t,\omega),...,X_n(t,\omega)\}
 $$
 and
 $$
 W=W(t,\omega)=\{W_1(t,\omega),W_2(t,\omega),...,W_m(t,\omega)\}
 $$
 with the $W_j$ denoting independent Brownian motion processes, $t>0$, and
 $\omega\in\Omega$, a probability sample space.  Formally, (1.1) can arise
if
 one models the impact of environmental stochasticity by characterizing the
 net per capita growth rates of the populations  $F(x)$,
 \begin{equation}
 F_i(x) = \frac{1}{x_i}\frac{dx_i}{dt},
 \end{equation}
 as random noise fluctuations about some average values
 $f(x)$ with intensities $G(x)$ dependent on the population size $x$
 $$
 F(x)=f(x)+G(x)N
 $$
 where
 $$
 N=N(t,\omega)=\{N_1(t,\omega),N_2(t,\omega),...,N_m(t,\omega)\}
 $$
 with the $N_j$, $t>0$, and $\omega\in\Omega$, specifying independent white
 noises.

 Specifically, we are interested in the solutions
 $X=X(t,\omega;x)$ of $(1.1)$
 which satisfy the initial conditions
 $$
 X(0,\omega;x)=x\in B,
 $$
 for almost all $\omega$, where $B$ is a bounded subset of the the positive
 cone in $R^n$
 $$
 R^n_{+}=\{x=(x_1,...,x_n):x_i>0,i=1,...,n\},
 $$
 the interior of the feasible region for (1.1). The result in this paper
 gives estimates for exit probabilities of $X$ through certain portions of
 the boundary of $B$.  The result generalizes slightly an earlier result
 ([9],[10]) of the author, and indicates the use of
 multiple Liapunov functions in its application in the study of practical
 persistence for stochastic population interaction models([11]).

  The set-up thus far is nearly identical to the setting of the
 Wentzell-Freidlin exit problem ([6]).  Our goal here also is
 similar to that in the W-F problem - to obtain features of the exit
 probability of $X$ from $B$.  However, unlike the W-F problem, we do not
 consider the noise necessarily as a small perturbation, and the set $B$ is
 not required to be an attractor or a basin of attraction of an equilibrium
of
 a corresponding deterministic model.  Also, instead of trying to obtain
the
 complete exit distribution - which may not be needed to deduce important
 biological implications, we will be satisfied, for now,  with just
 determining some relevant characteristics of the exit probability.

  We will assume that (1.1) is non-degenerate in $B$, i. e., that
 there is a
 positive constant $m$ such that
 $$
 \xi^TD(x)G(x)G^T(x)D(x)\xi\geq m\|\xi\|^2\eqno(H)
 $$
 for all $\xi$ in $R^n $and $x$ in $B$ (superscript $T$ denoting
transpose).
   It is well-known (see [8], for example) that if the noise
 intensity matrix G satisfies {\it (H)} in $B$, then any such solution $X$
must
 exit $B$ in finite (random) time
 $$
 \tau=\tau_x=\inf\{t\geq 0:X(t)\notin B, X(0)=x\}
 $$
 almost surely (no matter what the form of the drift term $f(x)$). In fact,
 the expected exit time
 $$
 v(x)=E(\tau_x)
 $$
 is known ([8]) to solve the following boundary value problem:
 \begin{eqnarray}
 &\mathcal{L} v(x)=\dot{v}(x)+
 \frac{1}{2}\mathop{\rm trace}(D(x)G(x)G^T(x)D(x)v_{xx}(x))=-1, \;
 x\in \mathop{\rm int}B&\\
 &v(x)=0, \quad  x\in\partial B&
 \end{eqnarray}
 where above
 $$
 \dot{v}(x)=\sum_{i=1}^nx_if_i(x)\frac{\partial
 v(x)}{\partial x_i}  \quad \mbox{and} \quad
 v_{xx}(x)=\Bigl\{\frac{\partial^2v(x)}{\partial x_i\partial
 x_j}\Bigr\}^n_{i,j=1}.
 $$
 (Equation (1.3) is known as Dynkin's equation ([5]).) The
 expected exit time has been suggested as characterizing relative
persistence
 in the case of models of the form (1.1) and computation techniques have
 been proposed ([14],[15]). For simplicity and
 clarity here we will assume {\it (H)} and that at least an estimate of
 $E(\tau)$
 has been determined. The question then is where (through which portion of
 the boundary of $B$) does the exit take place. The answer may indicate if
 modeled populations are at risk in the near future.

  The main point in this paper is that it may be useful to consider
 sets $B$ defined by certain multiple Liapunov type functions $V_k$.
 In particular we assume the boundary of $B$ is given by pieces of
 certain level surfaces of the functions $V_k$
 $$
 S_{kj}=\{x:V_k(x)=\nu_j\},
 $$
 where the $\nu_j$ are positive constants.  Such functions, sometimes
 referred to as
 average Liapunov functions, have the property that, if $\nu_j$ is small,
 some component of $x$ is small for every $x$ in $S_{kj}$. Construction of
 Liapunov
 functions  has been a principal technique in the investigation of
permanence or
 uniform persistence ([13]), in particular, practical persistence, in
 deterministic
 dynamical system models of population interactions ([2],[3],[4],[7],[12]).
 The typical form for such functions is
 $$
 V_k(x)=\prod_{i = 1}^nx^{\alpha_{ki}}_i ,
 $$
 where the $\alpha_{ki}$ are constants, at least one of which being
positive
 for each $k$. We are ready to state the main result. For simplicity, we
state
 the result for a single Liapunov type function $V$.


 \begin{theorem} Suppose $V$ is $a$ non-negative $C^2$ function
 defined on the bounded set $B$ with
 $$
 \eta =\inf\{V(x):x\in B\} \quad\mbox{and}\quad
 \mu =\sup\{V(x):x\in B\},
 $$
 and assume that the level surface
 $$
 S =\{x:V(x)=\eta\}
 $$
 forms part of the boundary of $B$. Suppose also that condition (H) holds
 in $B$.
 For any $x\in B$, let $X(t)=X(t,\omega;x)$ be the solution of (1.1) with
 $X(0)=x$,
 and let
 $$
 \tau=\tau_x=\inf\{t\geq 0:X(t)\notin B\},
 $$
 the first exit time of $X$ starting from $x$ in $B$.  If there is a
  positive constant $c$, such that
 \begin{equation}
 \mathcal{L} V=\dot{V}+\frac{1}{2}\mathop{\rm tr}(DGG^TDV_{xx}) \geq c
 \end{equation}
 then
 \begin{equation}
 \mathop{\rm Prob}\{X(\tau)\in S\}\leq\frac{\mu-V(x)-cE(\tau)}{\mu-\eta}.
 \end{equation}
 If the level surface
 $$
 T =\{x:V(x)=\mu\}
 $$
 forms part of the boundary of $B$, if (H)
 holds in $B$, and if there is a positive constant $c$ such that
 \begin{equation}
 \mathcal{L} V=\dot{V}+\frac{1}{2}\mathop{\rm tr}(DGG^TDV_{xx}) \leq-c
 \end{equation}
 then
 \begin{equation}
 \mathop{\rm Prob}\{X(\tau)\in T\}\leq\frac{V(x)-\eta-cE(\tau)}{\mu-\eta}.
 \end{equation}
 \end{theorem}


 \paragraph{Proof:} For $x\in B$, $\eta\leq V(x)\leq\mu$.  Let
 $$
 S =\{x\in\partial B:V(x)=\eta\},\quad T =\{x\in\partial B:V(x)= \mu\},
 \quad R =\partial B-S-T,
 $$
 and further, let
 $$
 p=\mathop{\rm Prob}\{X(\tau)\in S\}, \quad
 q=\mathop{\rm Prob}\{X(\tau)\in T\}, \quad
 r=\mathop{\rm Prob}\{X(\tau)\in R\}.
 $$
 Since {\it (H)} holds in $B$, $p+q+r=1$. Therefore,
 \begin{eqnarray}
 E(V(X(\tau))) &=& p \eta +\int_RV(x)dP+q\mu \\
 &\leq& p \eta+r\mu+q\mu=p \eta+(1-p)\mu\nonumber
 \end{eqnarray}

 On the other hand, by Dynkin's Formula and (1.5), we get
 \begin{equation}
 E(V(X(\tau)))-V(x)=E\int_0^\tau {\cal L} V(X(s)))ds\geq cE(\tau)
 \end{equation}
 Now from (1.9) and (1.10), we have
 \begin{equation}
 p \eta+(1-p)\mu\geq V(x)+cE(\tau)
 \end{equation}
 Solving (1.11) for $p$, we obtain
 $$
 p\leq\frac{\mu-V(x)-cE(\tau)}{\mu-\eta}
 $$
 which is the first conclusion of the Theorem.

  Similarly
 \begin{eqnarray}
 E(V(X(\tau))) &=& p \eta + \int_RV(x)dP+q \mu \\
 &\geq& p \eta+r \eta+q \mu=(1-q) \eta+q\mu \nonumber
 \end{eqnarray}
 which, similarly to (1.10) and (1.11), together (1.7) leads to
 \begin{equation}
 (1-q)\eta+q\mu\leq V(x) - cE(\tau).
 \end{equation}
 Solving for $q$ in (1.13) gives
 $$
 q\leq\frac{V(x)-\eta-cE(\tau)}{\mu-\eta}
 $$
 which is the second conclusion, and the proof is
 complete.\hfill$\diamondsuit$\medskip

  Before giving a population example, we will consider the
 following simple
 example - the simplest of all SDEs - to get a feeling about what this
 result gives us.
  In this case we know both the expected exit time $E(\tau)$ and the
 probability of exit $q$ explicitly, and so we can compare with the
estimate
 (1.8)
 obtained in the result above.

 \paragraph{Example 1.} We consider $dX=dW,  X(0)= x\in (0,1]$.  For
 some $r$ in $(0, 1)$, take
 $$V(x)=x^r.
 $$
 In this example, $W$ is a scalar Brownian motion (with
 $W(0)=0$ a.s.), and thus $X$ is Brownian motion starting at $x$.  The set
 $B$ is the unit interval $[0,1]$.  The boundary of $B$ is made up of the
 level sets for $V$ corresponding to $\eta=0$ and $\mu=1$. That $V$ is not
 differentiable at $0$ causes no problems. Indeed, for $x\in(0,1],$
 \begin{equation}
 {\cal L}V(x)=\frac{1}{2}r(r-1)x^{r-2}\leq-\frac{1}{2}r(1-r).
 \end{equation}
 The probability of exit for $X$ through the top boundary
 $$
 u(x)=\mathop{\rm Prob}\{X(\tau)=1\}(=q)
 $$
 solves the boundary-value problem
 $$
 0={\cal L}u(x)=\frac{1}{2}u''(x),\quad  u(0)=0,u(1)=1.
 $$
 (See ([8]), for example.) The solution is
 \begin{equation}
 u(x)=x.
 \end{equation}
 The expected exit time $v(x)=E_x(\tau)$
 on the other hand solves the problem:
 $$
 -1={\cal L}v(x)=\frac{1}{2}v^{ \prime\prime}(x), v(0)=0,v(1)=0.
 $$
 Its solution is
 \begin{equation}
 v(x)=x-x^2.
 \end{equation}
 Now, the conclusion (1.8) of the theorem is equivalent to
 \begin{equation}
 u(x)\leq\frac{V(x)-0-cv(x)}{1-0}
 \end{equation}
 Using (1.15) and (1.16) and taking the value of $c$ from (1.14) in
 (1.17) results in the estimate of $x$ by a concave function:
 \begin{equation}
 x\leq x^r-\frac{1}{2}r(1-r)(x-x^2),\ \ 0\leq x\leq 1.
 \end{equation}
 Inequality (1.18) could be called a ``bow saw inequality''.

 \begin{figure}[ht]
 \begin{center}
 \epsfxsize=9cm
 \epsffile{fig1.eps}
 \end{center}
 \caption{}
 \end{figure}

 \section{A predator-prey example}

 We consider the following predator-prey example
 to illustrate that the key conditions (1.2) and (1.3) are obtainable in
 the population interaction situation.

 \paragraph{Example 2.}
 \begin{eqnarray}
 dX&=&X[ a-bX-Yh(X,Y)] dt+g_1X dW_1\\
 dY&=&Y [-k+mXh(X,Y)] dt+g_2Y dW_2\nonumber
 \end{eqnarray}
 In (2.1), $a, b, k, m,  g_1$ and $g_2$ are positive constants and the
 function $h$ satisfies
 $$
 h(x,y) >0 \quad \mbox{in } R^2_{+}=\{(x,y):x>0,y>0\}.
 $$
 We consider the multiple Liapunov functions
 $$
 V_0=mx+y, \quad  V_1=xy^{-\alpha},\quad    V_2=x^\beta y
 $$
 where $\alpha$ and $\beta$ are positive constants to be determined
possibly
 from the analysis of the corresponding deterministic predator-prey model
 \begin{eqnarray}
 \frac{dx}{dt}&=&x [a-bx-yh(x,y)]\\
  \frac{dy}{dt}&=&y [-k+mxh(x,y)] \nonumber
 \end{eqnarray}
 For (2.2) the derivative of $V_0$ along solution trajectories satifies
 \begin{equation}
 \dot{V}_0=mx(a-bx)-ky\leq c-kmx-ky=c-kV_0,
 \end{equation}
 for a sufficiently large constant $c$. If we take
 $$
 K=\frac{c}{k},
 $$
 from (2.3) it follows that all trajectories of (2.2) must eventually
 reside in the set
 $$
 C=\{(x,y)\in\overline{R}^2_{+}:V_0(x,y)=mx+y\leq K\}.
 $$
 It is of interest, therefore, to choose positive constants
 $\eta_1,\eta_2,\mu_1$,and $\mu_2$ so that
 $$
 B=\{(x,y)\in\overline{R}^2_{+}:\eta_1\leq V_1\leq\mu_1,\eta_2\leq
 V_2\leq\mu_2\}\subseteq \mathop{\rm int} C.
 $$
 The boundary $\partial B$ of $B$ is contained in the set $C$ and is
composed
 of the four segments $S_{\eta_1}, S_{\mu_1}, S_{\eta_2},$ and $S_{\mu_2},$
 where
 $$
 S_{\eta_1}=\{(x,y)\in\overline{R}^2_{+}:V_1=\eta_1, \eta_2\leq
 V_2\leq\mu_2\}
 $$
 with the other segments given analogously.


 \begin{figure}
 \begin{center}
 \epsfxsize=9cm
 \epsffile{fig2.eps}
 \end{center}
 \caption{}
 \end{figure}


  Now, for the choices of $V_1$ and $V_2$ above, we have
 \begin{eqnarray}
 \dot{V}_1&=&V_1 [a-bx+\alpha k-h(x,y)(y+\alpha mx)]\\
 \dot{V}_2&=&V_2 [\beta(a-bx)-k-h(x,y)(
 \beta y-mx)].\nonumber
 \end{eqnarray}
 The noise intensity matrix here is
 $DGG^TD$ = $\mathop{\rm diag}\{g_1^2x^2,g_2^2y^2\}$
 and thus we obtain
 \begin{eqnarray}
 \mathop{\rm tr}(DGG^TDV_{1xx})&=& V_1 [\alpha(\alpha+1)g_2^2] \\
 \mathop{\rm tr}(DGG^TDV_{2xx}) &=& V_2 [\beta(\beta-1)g_1^2]\nonumber
 \end{eqnarray}
 Putting together (2.4) and (2.5) we get
 \begin{eqnarray}
 {\cal L}V_1 &=& V_1 [a-bx+\alpha k-h(x,y)(y+\alpha
 mx)+\frac{1}{2}(\alpha(\alpha+1)g_2^2)] \\% (2.6)
 {\cal L}V_2 &=& V_2 [\beta(a-bx)-k-h(x,y)(\beta
 y-mx)+\frac{1}{2}(\beta(\beta-1)g_1^2)].
 \end{eqnarray}

 For the special case of Michaelis-Menten dynamics,
 $$
 h(x,y) = \frac{r}{s + x}
 $$
 where $r$ and $s$ are positive constants, we have
 \begin{eqnarray*}
 \lefteqn{ a-bx + \alpha k-h(x,y)(y+\alpha mx) }\\
  &=& a-bx+\alpha k-r(y+\alpha mx)/(s+x)\\
  &=&a + \alpha k - [b+r\alpha m/(s+x)]x -ry/(s+x)
 \end{eqnarray*}
 and
 \begin{eqnarray*}
 \lefteqn{ \beta(a - bx)-k-h(x,y)(\beta y-mx) }\\
  &=&\beta( a-bx)-k-r(\beta y-mx)/(s+x)\\
  &=&\beta a-k- [\beta b-rm/(s+x)]x - r\beta y/(s+x)
 \end{eqnarray*}
 both of which are bounded in  $B$.  Therefore, if
 $g_2^2$ sufficiently large, there is a $c_1>0$, such that in $B$
 $$
{\cal L}V_1\geq c_1.
$$
 Thus, from the theorem
 $$
 p_1=\mathop{\rm Prob}\{(X(\tau),Y(\tau))\in
 S_{\eta_1}\}\leq\frac{\mu_1-V_1(x)-c_1E(\tau)}{\mu_1-\eta_1}.\eqno{(2.7)}
 $$
 Similarly, if  $\beta<1 $ and $ g_1^2$ sufficiently large, there
 is a $c_2>0$, such that in $B$,
$$
{\cal L}V_2\leq-c_2,
$$
 and so
 $$
 q_2=\mathop{\rm Prob}\{(X(\tau),Y(\tau))\in
 S_{\mu_2}\}\leq\frac{V_2(x)-\eta_2-c_2E(\tau)}{\mu_2-\eta_2}.\eqno{(2.8)}
 $$
 Inequalities (2.7) and (2.8) give estimates for first tendencies of
 predator extinction and prey explosion respectively.

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 }\end{thebibliography}\medskip

 \noindent{\sc Thomas C. Gard}\\
 Department of Mathematics\\
 The University of Georgia \\
 Athens GA 30602 USA \\
 e-mail: tgard@uga.edu

 \end{document}