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\markboth{Lavrentiev Phenomenon in Microstructure Theory\hfil EJDE--1996/06}%
{EJDE--1996/06\hfil Matthias Winter\hfil}

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\begin{document}
\title{\vspace{-1in}\parbox{\linewidth}{\footnotesize\noindent
{\sc  Electronic Journal of Differential Equations},
Vol.\ {\bf 1996}(1996), No.\ 06, pp. 1--12. \newline
ISSN: 1072-6691. URL: http://ejde.math.swt.edu or http://ejde.math.unt.edu
\newline ftp (login: ftp) 147.26.103.110 or 129.120.3.113}
 \vspace{\bigskipamount} \\
Lavrentiev Phenomenon in Microstructure Theory
\thanks{ {\em 1991 Mathematics Subject Classifications:}
49K40, 73S10.\newline\indent
{\em Key words and phrases:} Singular perturbation, Lavrentiev phenomenon,
\newline\indent martensitic phase transformation.
\newline\indent
\copyright 1996 Southwest Texas State University  and University of
North Texas.\newline\indent
Submitted April 30, 1996. Published August 22, 1996.} }
\date{}
\author{Matthias Winter}
\maketitle
\begin{abstract}
A variational problem arising as a model in martensitic phase transformation
including surface energy is studied. It explains the complex, 
multi-dimensional pattern of twin branching which is often observed in a
martensitic phase near the austenite interface. 

We prove that a Lavrentiev phenomenon can occur
if the domain is a rectangle.  We show that this phenomenon
disappears under arbitrarily small shears
of the domain. We also prove that other perturbations of the problem lead to
an extinction of the Lavrentiev phenomenon.
\end{abstract}

\section{Introduction}
\setcounter{equation}{0}

Phase transitions in solids often involve structure on a microscale.
In martensitic phase transformation for example this is quite well 
understood. A common approach is by elastic energy minimization (see Ball and
James \cite{BJ87,BJ92} for a geometrically nonlinear theory or 
 Khachaturyan,
Shatalov and Roitburd 
\cite{Kh83,KS69,Ro78}
for a geometrically linear theory). 
The stored energies are typically nonconvex (and not quasiconvex) and  so the
variational integrals involved are typically not lower semicontinuous.
Therefore the minimum is not attained. However, there exist minimizing
sequences, which involve finer and finer oscillations describing the
microstructure in the solid.

Considering elastic energy alone one is capable of predicting
many properties of the 
microstructure, for
example the layering directions in twinned patterns or the
lattice orientation of the different phases. However, other features such as lengthscales are still arbitrary. If also interfacial energy is incorporated into
the model these can be  determined, too.
 We consider two ways to represent interfacial
energy. The first is by adding a singular perturbation involving higher order gradients, the second is by essentially adding the surface area of the interfaces.

In this paper we revisit a model which was introduced and analyzed by
 Kohn and M\"uller
\cite{KM92,KM94,KM95}. 
The model is as follows. 
Minimize 
\begin{equation}
E^{\epsilon}(u)=\int_{R_L}u_x^2+(u_y^2-1)^2+\epsilon^2 u_{yy}^2\,dx\,dy
\label{prob}
\end{equation}
subject to
\[
u=0 \mbox{ for } x=0
\]
where $R_L=(0,L)\times(0,1)$.
\onefigure{\Ipe{fig1.ps}}{A rectangular domain ($\Omega=R_L$)}{rect}

The double-well potential $u_x^2+(u_y^2-1)^2$ represents elastic energy
of the martensite, the preferred values $\nabla u=(0,\pm1)$ being the
stress-free states of two different variants of martensite. The higher-order
term $\epsilon^2 u_{yy}^2$ describes interfacial energy
by singular perturbation. The boundary $x=0$
represents the austenite--twinned-martensite interface. The boundary
condition $u=0$ for $x=0$ refers to elastic compatibility with the austenite phase
in the extreme case of complete rigidity of the austenite.

The variational problem (\ref{prob}) is closely related to the following one.
Minimize
\begin{equation}
I^{\epsilon}(u)=\int_{R_L} u_x^2+\epsilon|u_{yy}|\,dx\,dy
\label{probb} 
\end{equation}
subject to
\[
|u_y|=1 \mbox{ a.e.,}
\hspace{1cm}
u=0 \mbox{ for }x=0.
\]
(The precise class of admissible functions will be introduced in section 2.)
Note that in both formulations (\ref{prob}) and (\ref{probb}) of the variational problem the surface terms consider only changes of $u$ in $y$-direction.
To simplify the presentation
other components are neglected since the transition zones or interfaces, respectively, between the two variants of martensite are expected to be
essentially horizontal.
Our results, in particular Theorem \ref{lav}, remain valid also
without this approximation.

There is no rigorous proof of a relationship between the two formulations of the problem. 
For a heuristic connection note that, following Modica 
\cite{Mo87}, 
\begin{eqnarray*}
\int_{x=x_0} (u_y^2-1)^2+\epsilon^2u_{yy}^2\,dy
&\geq&
\int_{x=x_0} 2\epsilon |u_y^2-1|\,|u_{yy}|\,dy
\\
&=&\int_{x=x_0} 2\epsilon |H(u_y)_y|\,dy
\end{eqnarray*}
where $H(t)$ is a primitive of $|t^2-1|$. The inequality becomes sharp if
$\epsilon u_{yy}=\pm(u_y^2-1)$, i.e.~if in the layer where $u_y$ changes
between $\pm1$ one has got the appropriate profile. Note  that the unknowns of
$I^{\epsilon}$ are the (sharp) interfaces where $u_y$ changes its
value between $\pm1$, and $1/2 \int_0^1|u_{yy}|\,dy$ counts the number of
these changes
along the segment $x=\mbox{const}$, $0\leq y\leq1$.
We will present a striking difference between the two formulations of the 
problem, namely that a Lavrentiev phenomenon holds for the 
 ``sharp'' formulation (\ref{probb}) but not for the
 ``diffusional''  one
(\ref{prob}).


It was shown in 
\cite{KM92,KM94,KM95} that
 for energy minimization 
of elastic and interfacial energy  
it is not enough to consider only a one-dimensional twinned pattern. On the
contrary, 
  in this situation it is necessary to study complex, two-dimensional patterns
which are asymptotically self-similar. A rigorous analysis is 
performed in the context of formulation (\ref{probb}) of the
 variational problem. See also Schreiber \cite{Sch94}
 who extended
many of the results to the situation of (\ref{prob}).

In this paper we show that for the variational problem  (\ref{probb})
a ``{\it Lavrentiev phenomenon}'' occurs.
Our main result is as follows.
In the class $W^{1,\infty}(R_L)$ there is not even a function
possessing finite energy in contrary to the class
 $H^1(R_L)$. 


On the other hand, this Lavrentiev phenomenon does not occur if $\Omega$ is
a parallelogram. We prove this explicitly giving an example of a function in
 $W^{1,\infty}(\Omega)$ 
having finite energy.

Note that a rectangle is mapped onto a parallelogram by an arbitrarily 
small
shear. Thus the behavior observed here depends
on changes of the domain  in a highly singular way.
 To our knowledge this example is the first where
such a highly singular behavior of the Lavrentiev phenomenon on changes of the 
domain
has been observed. 


We show that this Lavrentiev phenomenon also vanishes if we consider
the ``diffusional''  variational problem 
(\ref{prob}) instead of the ``sharp'' one (\ref{probb}).. Furthermore, we prove
that
if we omit the surface area term in (\ref{probb}) and study the
energy functional
\[ I^{\e}(u)=\int_{R_L}u_x^2 \,dx \,dy \]
subject to
\[
|u_y|=1 \mbox{ a.e.,}
\hspace{1cm}
u=0\mbox{ for }x=0
\]
the Lavrentiev phenomenon also disappears. This shows that the introduction
of surface energy into the model not only captures new physical features but also 
changes the problem in a fundamental way thus highlighting the importance
of considering surface energy effects. 

A refinement of our results would be question: Is the minimal value the same for
functions chosen in $H^1$ or in $W^{1,\infty}$? Our results clearly show that
this not the case for a rectangular domain and the ``sharp'' formulation 
since the first is finite, the latter is infinite. We expect that in case the
domain is a parallelogram and/or for the ``diffusional'' formulation the minimal
values are the same.  But to our knowledge these are open questions.


 In a general context the term Lavrentiev phenomenon is used to describe 
that the value of the minimum of a variational problem increases strictly if
the admissibility class
 $W^{1,p}(\Omega)$ 
is replaced by
 $W^{1,q}(\Omega)$ where $\Omega$ is a bounded domain  and $1\leq p<q$.
 Such effects were first observed by Lavrentiev \cite{La26}. There were 
refinements due to
 Mania \cite{Ma34}
and Ball and Mizel \cite{BM85}. 
 See also Cesari \cite{Ce83} and Dacorogna \cite{Da89}. 
In these works examples were presented where the energy of the absolute 
minimizer is
different for the
admissibility classes
 $W^{1,q}(\Omega)$ 
and
 $W^{1,p}(\Omega)$ for some or all $p$ with $1\leq p<q$.
All of the treatments quoted above assume
$q=\infty$ except for the work of Ball and Mizel where an
example was presented with $q=3$. All these studies consider one-dimensional
problems. 
Connections between the Lavrentiev phenomenon in higher dimensions
and cavitation were studied by Ball
\cite{Ba82}.
Numerical computations of the Lavrentiev phenomenon by truncation methods
were 
recently performed by Li \cite{Li95}. 
 
The Lavrentiev phenomenon is of great physical importance. Very often in the 
materials sciences it is important to know the maximum value of the gradients.
If they are too big the approximation of the continuum model to the lattice
model might no longer be valid. Furthermore, big gradients even on a very
small set very often lead
to fracture of the body or other effects. So in this case the model would have
to be extended to account for these. 

The structure of the paper is as follows. In section 2 we show that 
for the ``sharp'' variational problem (1.2) on a rectangular domain
there is
no Lipschitz function with finite energy and that this statement is not true
if the domain is a parallelogram. In section 3 we consider two other changes to
the variational problem, namely studying the ``diffusional formulation'' and
omitting surface energy. We show that then there exist Lipschitz functions
with finite energy.

We use $C$ to denote generic constants which can vary from line to line.

\paragraph{Acknowledgements.} 
It is a great pleasure to thank Professors J.M. Ball, R.V. Kohn and S. M\"uller for many
interesting discussions on microstructure and energy minimization. 
I thank Mrs. Tanya Smekal for the careful preparation of the figures.
The
hospitality of Courant Institute and the Institute for Advanced Study
is gratefully acknowledged. This work 
is supported by an Individual Fellowship of 
the European Union (HCM Programme, contract no ERBCHBICT930744)
which enabled the author to spend almost two years at Heriot-Watt University,
Edinburgh.



\section{The ``sharp'' formulation of the variational problem}
\setcounter{equation}{0}
In this section we study the minimization of the model energy
\[
I^{\epsilon}(u)=\int_{R_L} u_x^2+\epsilon|u_{yy}|\,dx\,dy 
\]
amongst all functions in the admissibility class
\begin{eqnarray*} 
{\cal A}_0&=&\{u\in H^1(R_L):\,|u_y|=1 \mbox{ a.e., }u_{yy}
\mbox{ is a Radon measure on }R_L \\
&&\mbox{ with finite mass, } u=0 \mbox { for } x=0\}
\end{eqnarray*}
where
$R_L=(0,L)\times(0,1)$.

To get an intuition for the condition that $u_{yy}$ is a Radon measure
the reader may think that $u_y$ is $=1$ or $-1$, respectively, on subsets of $R_L$
which are separated by smooth curves. Then
for each Borel set $A\subset R_L$  
its distributional derivative satisfies
\[\int_A |u_{yy}|(x,y)\,dx\,dy=2 \times\mbox{ (length of the interfaces lying in }A
\mbox{)}.\]
This is the prototype of the Radon measure in our variational problem. 

The theoretical reason for choosing Radon measures is that they have good
compactness properties and guarantee existence of minimizers. 
For more background information on Radon measures see for example the
monography \cite{EG92}. 

 Kohn and M\"uller proved in \cite{KM94} that this problem has a minimizer using the direct method in the calculus of
variations. 
They also showed the following result which plays the role of the Euler-Lagrange
equation.
\begin{lemma}
({\sc Equipartition of Energy}) Let $u$ be a minimizer of $I^{\e}$ on
${\cal A}_0$. Then there exists a constant $\lambda$ (depending on $\e,\,L$, and $u$) such that
\begin{equation}
\int_0^1 \e |u_{yy}|(x,y)dy -  \int_0^1 u_x^2(x,y)dy=\lambda
\label{el}
\end{equation}
for a.e. $x\in (0,L).$
\end{lemma}
Furthermore, they derived the following scaling law:
\begin{theorem}
There are constants $c,C>0$ such that for $\e$ sufficiently small 
\begin{equation} 
c\e^{2/3}L^{1/3}\leq \min I^{\e} \leq C\e^{2/3}L^{1/3}.
\end{equation}
\label{scal}
\end{theorem}
We show that if we restrict the admissibility class to the set of Lipschitz
functions
\begin{eqnarray*} 
{\cal B}_0&=&{\cal A}_0 \cap W^{1,\infty}(R_L)\\
&=&\{u\in W^{1,\infty}(R_L):\,|u_y|=1 \mbox{ a.e., }u_{yy}
\mbox{ is a Radon measure on }R_L \\
&&\mbox{ with finite mass, } u=0 \mbox { for } x=0\}
\end{eqnarray*}
this statement is no longer true. In fact, we prove the following 
\begin{theorem} 
If $\Omega=R_L$ then
for all functions $u\in{\cal B}_0$ $I^{\e}(u)=\infty$.
\label{lav}
\end{theorem}
\begin{remark}
It is easy to see that for all $p\in [1,\infty)$ the class
\begin{eqnarray*}
&\{u\in W^{1,p}(R_L):\,|u_y|=1 \mbox{ a.e., }u_{yy}
\mbox{ is a Radon measure on }R_L& \\ 
&\mbox{ with finite mass, } u=0 \mbox { for } x=0\}&
\end{eqnarray*}
contains a function $u$ such that $I^{\e}(u)<\infty.$
An example for this is obtained by modifying {\bf Example 3.1} below such that
\[\begin{array}{ll}
\theta\in \left(\frac{1}{4},\frac{1}{2}\right) & \mbox{if }1\leq p\leq 2, 
\\ \\
\theta\in \left(2^{p/(1-p)},\frac{1}{2}\right) & \mbox{if }2<p<\infty. \\
\end{array}
\]
%\[\theta\in (2^{p/(1-p)}, \frac{1}{2})\cap (\frac{1}{4},\frac{1}{2}).\]
Note that
\begin{eqnarray*}
\int_{R_L} u_x^p \,dy\,dx&=&\sum_{i=0}^{\infty}\int_{x_1}^L\int_0^{2^i}
(2\theta)^{-pi}u_x^p 2^{-i}\theta^i\,dy\,dx\\
&=&\sum_{i=0}^{\infty} 2^{-pi}\theta^{(1-p)i}\int_{x_1}^L\int_0^1u_x^p\,
dy\,dx\end{eqnarray*}
and 
the series is convergent if and only if
\[\theta>2^{p/(1-p)}.\] 
Furthermore, note that
\begin{eqnarray*}\int_{R_L}\e |u_{yy}|\,dy\,dx
&=&\e\sum_{i=0}^{\infty}\int_{x_1}^L\int_0^{2^i}
2^{i}|u_{yy}|2^{-i}\theta^i\,dy\,dx\\
&=&\e\sum_{i=0}^{\infty}
 (2\theta)^{i}\int_{x_1}^L\int_0^1|u_{yy}|\,dy\,dx\end{eqnarray*}
and 
the series is convergent if and only if
\[\theta<\frac{1}{2}.\] 
\end{remark}
\paragraph{Proof of Theorem  \ref{lav}.}
Assume that there is a constant $K>0$ such that
\[ |\nabla u|\leq K
\hspace{1cm}\mbox{ for a.e. }x\in R_{L}.
\]
 Then we have by the Cauchy-Schwarz inequality
\[u^2(l,y)=\left(\int_0^l 1\cdot u_x(x,y)\,dx\right)^2
\leq \int_0^l 1^2 \,dx \cdot\int_0^l u_x^2(x,y)\,dx.
\]
 This implies 
 the following Poincar\'e inequality
\begin{equation}
\int_0^1 u^2(l,y)dy\leq l \int_0^l\int_0^1 |\nabla u(x,y)|^2 \,dx \,dy\leq CK^2l^2.
\hspace{1cm} 
\label{poin}
\end{equation}
 for all $l\in (0,L]$. 

  Next we use a ``zig-zag'' inequality which was proved
by Kohn and M\"uller \cite{KM94}.
\begin{lemma}
Let $f\in W^{1,\infty}(0,1).$ Assume that $|f'|=1$ a.e. and that $f'$ changes
sign $N$ times. Then
\[
\int_0^1 f^2 \,dx \geq
\frac{1}{12}(N+1)^{-2}=
\frac{1}{12}\left(\frac{1}{2}\int_0^1|f''|dx+1\right)^{-2}.
\]
\label{zigzag}
\end{lemma}
Lemma \ref{zigzag} implies
\begin{equation}
\frac{1}{12}\left(\frac{1}{2}\int_0^1|u_{yy}(l,y)|dy +1\right)^{-2}\leq 
\int_0^1 u^2(l,y)dy.
\label{zagzig}
\end{equation}
Combining (\ref{poin}) and (\ref{zagzig}) we get
\[
\int_0^1 |u_{yy}(l,y)|dy\geq C K^{-1}l^{-1}-2
\]
where $C$ is independent of $K$ and $l$. 
After integration we have
\[
\int_0^L\int_0^1 \e |u_{yy}(l,y)|\, dy\, dl\geq C \int_0^L l^{-1}\, dl-2\e L=\infty.
\]
This implies Theorem \ref{lav}. \epr 


We now assume that the domain is a parallelogram. 
To simplify the presentation assume that the parallelogram
has interior angles of $\pi/4$ and $3\pi/4$. But note that our method also
 works for other
angles (except for $\pi/2$, of course). Set $\Omega=\{(x,y):\,y<x<y+L,y\in(0,1)\}=:P_L.$
\onefigure{\Ipe{fig2.ps}}{The domain is a  parallelogram 
($\Omega=P_L$)}{para}
We consider the variational problem
\[
I^{\epsilon}(u)=\int_{P_L} u_x^2+\epsilon|u_{yy}|\,dx\,dy 
\]
amongst all functions in the admissibility class
\begin{eqnarray*} 
{\cal A}_0&=&\{u\in H^1(R_L):\,|u_y|=1 \mbox{ a.e., }u_{yy}
\mbox{ is a Radon measure on }R_L \\ 
&&\mbox{ with finite mass, } u=0 \mbox { for } x=y,\,0\leq x\leq 1\}.
\end{eqnarray*}
Furthermore, define
\[{\cal B}_0={\cal A}_0\cap W^{1,\infty}(P_L).\]
The existence theorem of Kohn and M\"uller \cite{KM94} applies to this case, too. Now Theorem \ref{lav} is no longer true, but we have the following
result.
\begin{theorem}
If $\Omega=P_L$ then
there is a function $u\in {\cal B}_0$ such that $I^{\e}(u)<\infty$.
\label{paral}
\end{theorem}
\paragraph{ Proof of Theorem \ref{paral}.} 
Choose
the function $u(x,y)=x-y.$ Then  we have $u\in H^1(P_L),$ $u_y=-1$ on $P_L,$ 
$u_{yy}=0$
on $P_L,$ and $u=0$ if $x=y,\,0\leq x\leq1.$ This implies $u\in {\cal B}_0.$
Finally,  we calculate
\[I^{\e}(u)=\int_{P_L} u_x^2+\e|u_{yy}| \,dx \,dy=\int_{P_L} 1^2
\,dx\,dy=|P_L|<\infty.\mbox{\epr}\]

\section{Other perturbations of the  ``sharp'' formulation of the variational problem}
\setcounter{equation}{0}

In this 
section we consider other perturbations of the ``sharp'' formulation (\ref{probb}) of the
variational problem and show that for them the Lavrentiev phenomenon 
observed in Section 2
disappears, i.e. there are Lipschitz functions with finite energy.

We first study the ``diffusional''
formulation (\ref{prob}) of the problem, i.e. we consider the model energy
\[
E^{\epsilon}(u)=\int_{\Omega}u_x^2+(u_y^2-1)^2+\epsilon^2 u_{yy}^2\,dx\,dy.
\]
The class of admissible functions  for $\Omega=R_L$
is
\[{\cal A}_1=\{u\in H^2(R_L) \,: \, u=0 \mbox{ for } x=0\}\]
and for $\Omega=P_L$
\[{\cal A}_1=\{u\in H^2(R_L) \,: \, u=0 \mbox{ for } x=y,\,0\leq x\leq 1\}.\]
In analogy to section 2 we consider how the behavior of the problem changes by restricting the admissibility class to
\[{\cal B}_1={\cal A}_1\cap
W^{1,\infty}(\Omega).\]
We show that the Lavrentiev phenomenon observed in section 2 does not occur 
here.
To this end for $\Omega=R_L$ consider the function $u=0$.
Note that $0\in {\cal B}_1$ and calculate 
\[E^{\e}(0)= \int_{R_L} 1^2 \,dx\, dy=|R_L|<\infty.\]

For $\Omega=P_L$ the same function and the same calculation as in section 2
provide an example of a function in ${\cal B}_1$ which has finite energy. 
We conclude that the Lavrentiev phenomenon does not occur for the
``diffusional'' formulation of the variational problem.

We finally consider the 
``sharp'' formulation of the variational problem without surface energy terms
on a rectangle ($\Omega=R_L$).
Our goal is to show that Theorem \ref{lav} does not hold. To this end we
have to show that there exists a function $u\in{\cal B}_0$ such that
\[
I^{0}(u)<\infty. 
\]
Recall that  
\begin{eqnarray*}
{\cal B}_0&=&\{u\in W^{1,\infty}(R_L):\,|u_y|=1 \mbox{ a.e., }u_{yy}
\mbox{ is a Radon measure on }R_L  \\
&&\mbox{ with finite mass, } u=0 \mbox { for } x=0\}\,.
\end{eqnarray*}
To give such an example we revisit the microstructure given in the work of
Kohn and M\"uller
\cite{KM92,KM94,KM95}.
 It turns out that this will give the desired example. However,
we will have to choose the scaling parameter $\theta$ 
in the range $91/2,1)$ for which the surface
energy would be infinite. But because we ignore surface energy we are allowed
to do so. 

{\bf Example 3.1.} 
The microstructure is constructed as follows.
First introduce a
function $\nu: [0,1]\times [0,1/2]\to R$ defined as
\[
\nu(x,y)=
\left\{
\begin{array}{ll}
y & \mbox{if }0\leq y\leq (x+1)/8,\\ \\
(x+1)/4-y & \mbox{if }(x+1)/8\leq y\leq (x+3)/8, \\ \\
y- 1/2    & \mbox{if }(x+3)/8\leq y\leq 1/2.
\end{array}\right.
\]
Then $\nu$ is extended antiperiodically in $y$ to $[0,1]\times[0,1]$
\onefigure{\Ipe{fig3.ps}}{The function $\nu$}{nu}
The function $\nu$ satisfies
$|\nu_y|=1$ a.e., $\nu(x,y+1)=\nu(x,y)$, 
$\nu(0,y)=\frac{1}{2}\nu(1,2y)$, and 
\[ \int_0^1 \int_0^1 \nu_x^2 +\e|\nu_{yy}| \,dx \,dy= \frac{1}{2} 
\left( \frac{1}{4} \right)^2 +8\e\,. \]
Now choose $\theta\in (0,1)$ and set
\[ x_i=\theta^i L,\hspace{1cm}i=0,1,\ldots.\]
For $x\in [x_1,L]$ define
\[u(x,y)=\nu\left(\frac{x-x_1}{L-x_1}, y\right).\]
Extend $u$ periodically from $[x_1,L]\times[0,1]$ to $[x_1,L]\times R$. 
Note that  on $[x_1,L]\times R$ $u$ satisfies 
\[ |u|=1 \hspace{1cm}\mbox{a.e.,} \quad
 u(x,y+1)=u(x,y), \quad
 u(x_1,y)=\frac{1}{2}u(L,2y), \mbox{ and } \]
\[ \int_{x_1}^L \int_0^1 u_x^2 +\e|u_{yy}| \,dy \,dx= \frac{1}{32}\frac{1}{L-x_1} 
 +8\e(L-x_1)\,. \]
Then continue $u$ to $(0,L]\times [0,1]$ by
\[u(x,y)=2^{-i} u(\theta^{-i}x,2^i y) \hspace{1cm}\mbox{if } x\in [x_{i+1},x_i].\]
Note that the resulting function is continuous.
Obviously $u$ can be extended continuously to $[0,L]\times [0,1]$ by setting
\[u(0,y)=0 \hspace{1cm} \mbox{ for } 0\leq y\leq 1.\]
Note that $u\in W^{1,\infty}(R_L)$ if and only if $\theta\in [1/2,1)$.
We calculate  the energy of $u$ as follows
\[I^0(u)=
\sum_{i=0}^{\infty}
\int_{x_{i+1}}^{x_i}\int_0^1 u_x^2 \,dy\,dx \]
\[=\sum_{i=0}^{\infty}
\int_{x_1}^{L}\int_0^{2^i}
 (2\theta)^{-2i}u_x^2 2^{-i}\theta^i \,dy \,dx
=
\sum_{i=0}^{\infty} (4\theta)^{-i}
\int_{x_1}^{L}\int_0^{1}
u_x^2 \, dy \,dx.\]
The last expression is finite if and only if $\theta\in (1/4,1)$. Therefore we have
$u\in {\cal B}_0$ and $I^0(u)<\infty$ if and only if
$\theta\in [1/2,1)$. 
This is the desired counterexample and we conclude that the problem without
surface energy does not exhibit the Lavrentiev phenomenon. 



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\end{thebibliography}
\bigskip

{\sc Matthias Winter\newline
Mathematisches Institut A \newline
 Universit\"at Stuttgart \newline
Stuttgart, Germany \newline}
E-mail: winter@mathematik.uni-stuttgart.de


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