\documentclass[reqno]{amsart}

\AtBeginDocument{{\noindent\small
{\em Electronic Journal of Differential Equations},
Vol. 2004(2004), No. 40, pp. 1--22.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu  (login: ftp)}
\thanks{\copyright 2004 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}

\title[\hfilneg EJDE-2004/40\hfil Homogenization in chemical reactive flows]
{Homogenization in chemical reactive flows}

\author[C. Conca, J. I. D\'{\i}az, A. Li\~{n}\'{a}n, C. Timofte
\hfil EJDE-2004/40\hfilneg]
{Carlos Conca, Jesus Ildefonso D\'{\i}az,\\
 Amable Li\~{n}\'{a}n, Claudia Timofte} % in alphabetical order

\address{Carlos Conca \hfill\break
Departamento de Ingenier\'{\i}a Matem\'{a}tica \\
and Centro de Modelamiento Matem\'{a}tico, UMR 2071 CNRS-U Chile \\
Facultad de Ciencias F\'{\i}sicas y Matem\'{a}ticas \\
Universidad de Chile\\
Casilla 170/3, Santiago, Chile}
\email{cconca@dim.uchile.cl}

\address{Jesus Ildefonso D\'{\i}az \hfill\break
Departamento de Matem\'{a}tica Aplicada \\
Facultad de Matem\'{a}ticas \\
Universidad Complutense \\
28040 Madrid, Spain}
\email{ildefonso\_diaz@mat.ucm.es}

\address{Amable Li\~{n}\'{a}n \hfill\break
Escuela T. S. de Ingenieros Aeron\'{a}uticos \\
Universidad Polit\'{e}cnica de Madrid \\
Madrid, Spain}
\email{linan@tupi.dmt.upm.es}

\address{Claudia Timofte \hfill\break
Department of Mathematics\\
Faculty of Physics \\
University of Bucharest\\
P.O. Box MG-11, Bucharest-Magurele, Romania}
\email{claudiatimofte@hotmail.com}

\date{}
\thanks{Submitted April 3, 2003. Published March 22, 2004.}
\subjclass[2000]{47A15, 46A32, 47D20}
\keywords{Homogenization, reactive flows, variational inequality, \hfil\break\indent
monotone graph}

\begin{abstract}
  This paper concerns the homogenization of two nonlinear models for
  chemical reactive flows through the exterior of a domain containing
  periodically distributed reactive solid grains (or reactive obstacles).
  In the first model, the chemical reactions take place on the walls of
  the grains, while in the second one the fluid penetrates the grains
  and the reactions take place therein. The effective behavior of these
  reactive flows is described by a new elliptic boundary-value problem
  containing an extra zero-order term which captures the effect of the
  chemical reactions.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{corollary}[theorem]{Corollary}
\newtheorem{remark}[theorem]{Remark}

\section{Introduction}

The general question which will be subject of this paper is the
homogenization of chemical reactive flows through the exterior of
a domain containing periodically distributed reactive solid grains
(or reactive obstacles). We will focus our attention on two
nonlinear problems which describe the motion of a reactive fluid
having different chemical features. For a nice presentation of the
chemical aspects involved in our first model (and also for some
mathematical and historical backgrounds) we refer to Antontsev et
al.~\cite{Antontsev}, Bear \cite{Bear}, D\'{\i}az \cite{Diaz1,Diaz2,Diaz3}
and Norman \cite{Norman}. For the
second model, the interested reader can consult the books by
Hornung \cite{Hornung} and Norman \cite{Norman} and the references
therein.

Let $\Omega $ be an open bounded set in $\mathbb{R}^n$ and let us introduce
a set of periodically distributed reactive obstacles. As a result, we obtain
an open set $\Omega ^{\varepsilon }$ which will be referred to as being the
\textit{exterior domain}; $\varepsilon $ represents a small parameter
related to the characteristic size of the reactive obstacles.

The first nonlinear problem studied in this paper concerns the stationary
reactive flow of a fluid confined in $\Omega ^{\varepsilon }$, of
concentration $u^{\varepsilon}$, reacting on the boundary of the obstacles.
A simplified version of this problem can be written as follows:
\begin{equation}
\begin{gathered}
-D_{f}\Delta u^{\varepsilon }=f\quad \text{in }\Omega ^{\varepsilon }, \\
-D_{f} {\frac{\partial u^{\varepsilon }}{\partial \nu }}
=a\varepsilon g(u^{\varepsilon })\quad \text{on }S^{\varepsilon }, \\
u^{\varepsilon }=0\quad \text{on }\partial \Omega .
\end{gathered}
\end{equation}
Here, $\nu $ is the exterior unit normal to $\Omega ^{\varepsilon }$, $a>0$,
$f\in L^{2}(\Omega )$ and $S^{\varepsilon}$ is the boundary of our exterior
medium $\Omega \setminus \overline{\Omega^{\varepsilon}}$. Moreover, the
fluid is assumed to be homogeneous and isotropic, with a constant diffusion
coefficient $D_{f}>0$.

The semilinear boundary condition on $S^{\varepsilon}$ in problem (1.1)
describes the chemical reactions which take place locally at the interface
between the reactive fluid and the grains. From strictly chemical point of
view, this situation represents, equivalently, the effective reaction on the
walls of the chemical reactor between the fluid filling $\Omega^{\varepsilon}
$ and a chemical reactant located in the rigid solid grains.

The function $g$ in (1.1) is assumed to be given. Two model
situations will be considered; the case in which $g$ is a monotone
smooth function satisfying the condition $g(0)=0$ and the case of
a maximal monotone graph with $g(0)=0$, i.e. the case in which $g$
is the subdifferential of a convex lower semicontinuous function
$G$. These two general situations are well illustrated by the
following important practical examples
\begin{itemize}
\item[(a)] $g(v)=\frac{\alpha v}{1+\beta v}$, $\alpha, \beta>0$ (Langmuir kinetics)
\item[(b)] $g(v)=|v|^{p-1}v$, $0<p<1$ (Freundlich kinetics).
\end{itemize}
The exponent $p$ is called \emph{the order of the reaction}. In some
applications the limit case $(p=0)$ is of great relevance (see Remark \ref{rmk2.8}).
It is worth remarking that if we assume $f\geq 0$, one can prove (see, e.g.
\cite{Diaz3}) that $u^{\varepsilon}\geq 0$ in $\Omega \setminus \overline{%
\Omega^{\varepsilon}}$ and $u^{\varepsilon}>0$ in
$\Omega^{\varepsilon}$, although $u^{\varepsilon}$ is not
uniformly positive, except in the case in which $g$ is a monotone
smooth function satisfying the condition $g(0)=0$, as, for
instance, in example (a).

The existence and uniqueness of a weak solution of (1.1) can be settled by
using the classical theory of semilinear monotone problems (see, for
instance, \cite{Brezis}, \cite{Diaz1} and \cite{Lions}). As a result, we
know that there exists a unique weak solution $u^{\varepsilon}\in
V^{\varepsilon}\bigcap H^{2}(\Omega ^{\varepsilon})$, where
\[
V^{\varepsilon}=\{v\in H^{1}(\Omega^{\varepsilon}) : v=0\text{ on }
\partial \Omega\}.
\]
Moreover, if in the second model situation, which is in fact the most
general case we treat here, with $\Omega ^{\varepsilon}$ we associate the
following nonempty convex subset of $V^{\varepsilon}$:
\begin{equation}
K^{\varepsilon }=\{ v\in V^{\varepsilon }:
G(v)\big|_{S^{\varepsilon }} \in L^{1}(S^{\varepsilon })\},
\end{equation}
then $u^{\varepsilon}$ is also known to be characterized as being the unique
solution of the following variational problem:
\begin{quote}
Find $u^{\varepsilon }\in K^{\varepsilon }$ such that
\begin{equation}
D_{f} \int_{\Omega ^{\varepsilon }}Du^{\varepsilon
}D(v^{\varepsilon }-u^{\varepsilon })dx- \int_{\Omega
^{\varepsilon }}f(v^{\varepsilon }-u^{\varepsilon
})dx+a\langle \mu ^{\varepsilon },G(v^{\varepsilon
})-G(u^{\varepsilon })\rangle \geq 0
\end{equation}
for all $v^{\varepsilon }\in K^{\varepsilon }$, where
$\mu^{\varepsilon }$ is the linear form on $W_{0}^{1,1}(\Omega )$
defined by
\[
\langle \mu ^{\varepsilon },\varphi \rangle
=\varepsilon \int_{S^{\varepsilon }}\varphi d\sigma \quad \forall
\varphi \in W_{0}^{1,1}(\Omega ).
\]
\end{quote}

 From a geometrical point of view, we shall just consider periodic
structures obtained by removing periodically from $\Omega$, with
period $\varepsilon Y$ (where $Y$ is a given hyper-rectangle in
$\mathbb{R^n}$), an elementary reactive obstacle $T$ which has
been appropriated rescaled and which is strictly included in $Y$,
i.e. $\overline{T}\subset Y$.

As usual in homogenization, we shall be interested in obtaining a suitable
description of the asymptotic behavior, as $\varepsilon$ tends to zero, of
the solution $u^{\varepsilon }$ in such domains. We will wonder, for
example, whether the solution $u^{\varepsilon }$ converges to a limit $u$ as
$\varepsilon \rightarrow 0$. And if this limit exists, can it be
characterized?

In the second model situation (in absence of any additional regularity on $g$),
the solution $u^{\varepsilon}$, properly extended to the whole of $\Omega$,
converges to the unique solution of the variational inequality:
$u\in H^{1}_{0}(\Omega)$,
\begin{equation}
\int_{\Omega }QDuD(v-u)dx\geq
\int_{\Omega }f(v-u)dx-a\frac{| \partial T|}{| Y\setminus T | }
\int_{\Omega}(G(v)-G(u))dx,
\end{equation}
for all $v \in H^{1}_{0}(\Omega)$.

 Here, $Q=((q_{ij}))$ is the classical homogenized matrix, whose
entries are
\begin{equation}
q_{ij}=D_{f}\Big( \delta _{ij}+\frac{1}{|Y\setminus T|}
 \int_{Y\setminus T}\frac{\partial \chi
_{j}}{\partial y_{i}}dy\Big)
\end{equation}
in terms of the functions $\chi _{i}$, $i=1,\dots ,n$,
solutions of the so-called cell problems
\begin{equation}
\begin{gathered}
-\Delta \chi _{i}=0 \quad \text{in } Y\setminus T, \\
 \frac{\partial (\chi _{i}+y_{i})}{\partial \nu }=0 \quad
\text{on }\partial T, \\
\chi _{i}\quad\text{is $Y$-periodic.}
\end{gathered}
\end{equation}
We remark that if $g$ is smooth, then $g$ is the classical derivative
of $G$.

The chemical situation behind the second nonlinear problem that we will treat in
this paper is slightly different from the previous one; it also involves a
chemical reactor containing reactive grains, but we assume that now there is
an internal reaction inside the grains, instead just on their boundaries. In
fact, it is therefore a transmission problem with an unknown flux on the
boundary of each grain.

To simplify matters, we shall just focus on the case of a function $g$ which
is continuous, monotone increasing and such that $g(0)=0$; examples (a) and
(b) are both covered by this class of functions $g's$ and, of
course, both are still our main practical examples.

A simplified setting of this kind of models is as follows:
\begin{equation}
\begin{gathered}
-D_{f}\Delta u^{\varepsilon }=f\quad \text{in }\Omega ^{\varepsilon }, \\
-D_{p}\Delta v^{\varepsilon }+ag(v^{\varepsilon })=0,\quad
\text{in }\Omega
\setminus \overline{\Omega ^{\varepsilon }} \\
-D_{f}{\frac{\partial u^{\varepsilon }}{\partial \nu }}=D_{p}
 {\frac{\partial v^{\varepsilon }}{\partial \nu }}\quad \text{on }S^{\varepsilon }, \\
u^{\varepsilon }=v^{\varepsilon }\quad \text{on }S^{\varepsilon }, \\
u^{\varepsilon }=0\quad \text{on }\partial \Omega,
\end{gathered}
\end{equation}
where $D_p$ is a second diffusion coefficient characterizing the granular
material filling the reactive obstacles. As in the previous case, the
classical semilinear theory guarantees the well-posedness of this problem.

When we define $\theta^{\varepsilon}$ as
\[
\theta ^{\varepsilon }(x)=\begin{cases}
u^{\varepsilon }(x)& x\in \Omega ^{\varepsilon }, \\
v^{\varepsilon }(x)& x\in \Omega \setminus \overline{\Omega^{\varepsilon }},
\end{cases}
\]
and we introduce
\[
A=\begin{cases}
D_{f}Id & \text{in }Y\setminus T \\
D_{p}Id & \text{in }T,%
\end{cases}
\]
then our main result of convergence for this model shows that
$\theta^{\varepsilon}$ converges weakly in $H^{1}_{0}(\Omega)$ to the unique
solution of the homogenized problem
\begin{equation}
\begin{gathered}
-{\sum_{i,j=1}^{n}a_{ij}^{0}}{\frac{\partial ^{2}u}{\partial x_{i}
\partial x_{j}}}+a{\frac{|T|}{|Y\setminus T |}}g(u)=f\quad \text{in }\Omega, \\
u=0\quad \text{on }\partial \Omega.
\end{gathered}
\end{equation}
Here, $A^{0}=((a_{ij}^{0}))$ is the homogenized matrix, whose
entries are
\begin{equation}
a_{ij}^{0}=\frac{1}{|Y|}\int_{Y}\big( a_{ij}+a_{ik}
\frac{\partial \chi_{j}}{\partial y_{k}}\big)dy,
\end{equation}
in terms of the functions $\chi _{j}$, $j=1,\dots ,n$,
solutions of the so-called cell problems
\begin{equation}
\begin{gathered}
-\mathop{\rm div}(AD(y_{j}+\chi _{j}))=0\quad \text{in }Y, \\
\chi_{j} \quad\mbox{is $Y$-periodic}.
\end{gathered}
\end{equation}

Note that the two reactive flows studied in this paper, namely (1.1) and
(1.7), lead to completely different effective behavior. The macroscopic
problem (1.4) arises from the homogenization of a boundary-value problem in
the exterior of some periodically distributed obstacles and the zero-order
term occurring in (1.4) has its origin in this particular structure of the
model. The influence of the chemical reactions taking place on the
boundaries of the reactive obstacles is reflected in the appearance of this
zero-order extra-term. On the other hand, the second model is again a
boundary-value problem, but this time in the whole domain $\Omega$, with
discontinuous coefficients. Its macroscopic behavior (see (1.8)) also
involves a zero-order term, but of a completely different nature; it is
originated in the chemical reactions occurring inside the grains.

The approach we used is the so-called energy method introduced by
Tartar \cite{Tartar1}, \cite{Tartar2} for studying homogenization
problems. It consists of constructing suitable test functions that are used
in our variational problems. However, it is worth mentioning that the
$\Gamma $-convergence of integral functionals involving oscillating obstacles
could be a successful alternative. Extensive references on this topic can be
found in the monographs of Dal Maso \cite{DalMaso} and of
Braides and Defranceschi \cite{Braides-Defranceschi}. For
example, our main result in Chapter 2 (cf. Theorem \ref{thm2.6}) can also be
interpreted as a $\Gamma$-convergence-type result for the functionals
\[
v\mapsto \frac {1}{2} D_{f}\int_{\Omega ^{\varepsilon
}}DvDvdx+a\langle \mu ^{\varepsilon
},G(v)\rangle-\int_{\Omega ^{\varepsilon }}fvdx
+I_{K^{\varepsilon }}(v)
\]
(where $I_{K^{\varepsilon }}$ is the indicator function of the set $%
K^{\varepsilon }$, i.e. $I_{K^{\varepsilon }}$ is equal to zero if v belongs
to $K^{\varepsilon }$ and $+\infty $ otherwise) to the limit functional
\[
v\mapsto \frac{1}{2}\int_{\Omega}QDvDvdx+a
\frac{|\partial T|}{|Y\setminus T |}%
\int_{\Omega }G(v)dx-\int_{\Omega}fvdx,
\]
which is the energy functional associated to (1.3).

Also, let us mention that another possible way to get the limit problem
(1.8) could be to use the two-scale convergence technique, coupled with
periodic modulation, as in \cite{Bourgeat-Luckhaus-Mikelic}.

Regarding our second problem, i.e. chemical reactive flows through periodic
array of cells, a related work was completed by
{Hornung et al.} \cite{Hornung-Jager-Mikelic} using nonlinearities which are
essentially different
from the ones we consider in the present paper. The proof of these authors
is also different, since it is mainly based on the technique of two-scale
convergence, which, as already mentioned, proves to be a successful
alternative for this kind of problems. However, we have decided to use the
energy method, coupled with monotonicity methods and results from the theory
of semilinear problems, because it offered us the possibility to cover the
nonlinear cases of practical importance mentioned above.

The structure of our paper is as follows: first, let us mention that we
shall just focus on the case $n\geq 3$, which will be treated explicitly.
The case $n=2$ is much more simpler and we shall omit to treat it. In
Section 2 we start by analyzing the first nonlinear problem, namely (1.1).
We begin with the case of a monotone smooth function $g$ and we prove the
convergence result using the energy method. Next, we treat the case of a
maximal monotone graph, by writing our microscopic problem in the form of a
variational inequality. The case of a reactive flow penetrating a periodical
structure of grains is addressed in Section 3.

Finally, notice that throughout the paper, by $C$ we shall denote a generic
fixed strictly positive constant, whose value can change from line to line.

\section{Chemical reactions on the walls of a chemical reactor}

In this section, we will be concerned with the stationary reactive flow of a
fluid confined in the exterior of some periodically distributed obstacles,
reacting on the boundaries of the obstacles. We will treat separately the
situation in which the nonlinear function $g$ in (1.1) is a monotone smooth
function satisfying the condition $g(0)=0$ and the situation in which $g$ is
a maximal monotone graph with $g(0)=0$.

Let $\Omega $ be a smooth bounded connected open subset of $\mathbb{R}^{n}$ $%
(n\geq 3)$ and let $Y$ $=[0,l_{1}[\times \dots [0,l_{n}[$ be the
representative cell in $\mathbb{R}^{n}$. Denote by $T$ an open
subset of $Y$ with smooth
boundary $\partial T$ such that $\overline{T}\subset Y$. We shall refer to $%
T $ as being \textit{the elementary obstacle}.

Let $\varepsilon $ be a real parameter taking values in a sequence of
positive numbers converging to zero. For each $\varepsilon $ and for any
integer vector $k\in \mathbb{Z}^{n}$, set $T_{k}^{\varepsilon }$ the
translated image of$\ \varepsilon T$ by the vector $%
kl=(k_{1}l_{1},\dots ,k_{n}l_{n}):$%
\[
T_{k}^{\varepsilon }=\varepsilon (kl+T).
\]
The set $T_{k}^{\varepsilon }$ represents the obstacles in $\mathbb{R}^{n}$.
Also, let us denote by $T^{\varepsilon }$ the set of all the obstacles
contained in $\Omega $, i.e.
\[
T^{\varepsilon }=\bigcup \left\{ T_{k}^{\varepsilon } :
\overline{T_{k}^{\varepsilon }}\mathbf{\subset }\Omega , k\in \mathbb{%
Z}^{n}\right\} .
\]
Set
\[
\Omega ^{\varepsilon }=\Omega \setminus {\overline{T^{\varepsilon }}}.
\]
Hence, $\Omega ^{\varepsilon }$ is a periodical domain with periodically
distributed obstacles of size of the same order as the period. Remark that
the obstacles do not intersect the boundary $\partial \Omega $.
Let
\[
S^{\varepsilon }=\cup \{\partial T_{k}^{\varepsilon }\mid \overline{%
T_{k}^{\varepsilon }}\mathbf{\subset }\Omega , k\in
\mathbb{Z}^{n}\}.
\]
So
\[
\partial \Omega ^{\varepsilon }=\partial \Omega \cup S^{\varepsilon }.
\]
We shall also use the following notation:
$|\omega |$ is the Lebesgue measure of any measurable subset
$\omega$ of $\mathbb{R}^{n}$,
$\chi _{\omega }$ is the characteristic function of the
set $\omega$, $Y^{*}=Y\setminus \overline{T}$, and
\begin{equation}
\rho =\frac{|Y^{*}|}{|Y|}.
\end{equation}
Moreover, for an arbitrary function $\psi \in L^{2}(\Omega ^{\varepsilon })$,
we shall denote by $\widetilde{\psi }$ its extension by zero inside the
obstacles:
\[
\widetilde{\psi }=\begin{cases}
\psi & \text{in } \Omega ^{\varepsilon }, \\
0 & \text{in } \Omega \setminus \overline{\Omega ^{\varepsilon }}.
\end{cases}
\]
Also, for any open subset $D\subset \mathbb{R}^{n}$ and any
function $g\in L^{1}(D)$, we set
\begin{equation}
\mathcal{M}_{D}(g)=\frac{1}{|D|}\int_{D}gdx.
\end{equation}
In the sequel we reserve the symbol $\#$ to denote periodicity
properties.

\subsection{Setting of the problem}

As already mentioned, we are interested in studying the behavior of the
solution, in such a periodical domain, of the problem
\begin{equation}
\begin{gathered}
-D_{f}\Delta u^{\varepsilon }=f\quad \text{in }\Omega ^{\varepsilon }, \\
-D_{f} {\frac{\partial u^{\varepsilon }}{\partial \nu }}
=a\varepsilon g(u^{\varepsilon })\quad \text{on }S^{\varepsilon }, \\
u^{\varepsilon }=0\quad \text{on }\partial \Omega .
\end{gathered}
\end{equation}
Here, $\nu $ is the exterior unit normal to $\Omega ^{\varepsilon }$, $a>0$,
$f\in L^{2}(\Omega )$ and $g$ is assumed to be given. Two model situations
will be considered; the case in which $g$ is a monotone smooth function
satisfying the condition $g(0)=0$ and the case of a maximal monotone graph
with $g(0)=0$, i.e. the case in which $g$ is the subdifferential of a convex
lower semicontinuous function $G$. These two general situations are well
illustrated by the following important practical examples:
\begin{itemize}
\item[(a)] $g(v)=\dfrac{\alpha v}{1+\beta v}$, $\alpha, \beta>0$
(Langmuir kinetics)
\item[(b)] $g(v)=|v|^{p-1}v$, $0<p<1$ (Freundlich kinetics).
\end{itemize}
The exponent $p$ is called \emph{the order of the reaction}. It is worth
remarking that if we assume $f\geq 0$, one can prove (see, e.g. \cite{Diaz3}%
) that $u^{\varepsilon}\geq 0$ in $\Omega \setminus \overline{%
\Omega^{\varepsilon}}$ and $u^{\varepsilon}>0$ in $\Omega^{\varepsilon}$,
although $u^{\varepsilon}$ is not uniformly positive except in the case in
which $g$ is a monotone smooth function satisfying the condition $g(0)=0$,
as, for instance, in example $a)$. Moreover, since $u$ represents a
concentration, it could be natural to assume that $f\leq 1$, and again one
can prove that, in this case, $u \leq 1$. Without loss of generality, in
what follows we shall assume that $D_{f}=1$.

\subsection{First model situation: $g$ smooth}

Let $g$ be a continuously differentiable function, monotonously
non-decreasing and such that $g(v)=0$ if and only if $v=0$. We shall suppose that there
exist a positive constant $C$ and an exponent $q$, with $0\leq q< n/(n-2)$,
such that
\begin{equation}
|\frac{\partial g}{\partial v}|\leq C(1+|v|^{q}).
\end{equation}
Let us introduce the functional space
\[
V^{\varepsilon }=\left\{ v\in H^{1}(\Omega ^{\varepsilon
}) : v=0\text{on }\partial \Omega \right\} ,
\]
with
$\| v\| _{V^{\varepsilon }}=\| \nabla v\|_{L^{2}(\Omega ^{\varepsilon })}$.
The weak formulation of problem (2.3) (written for $D_{f}=1$) is:\\
Find $u^{\varepsilon }\in V^{\varepsilon }$ such that
\begin{equation}
{\int_{\Omega ^{\varepsilon }}\nabla u^{\varepsilon
}\cdot \nabla \varphi dx+a\varepsilon \int_{S^{\varepsilon
}}g(u^{\varepsilon })\varphi d\sigma =\int_{\Omega ^{\varepsilon
}}f\varphi dx}\quad \forall \varphi \in V^{\varepsilon }.
\end{equation}
By classical existence results (see \cite{Brezis}), there exists a unique
weak solution $u^{\varepsilon }\in V^{\varepsilon }\cap H^{2}(\Omega
^{\varepsilon })$ of problem (2.3).

The solution $u^{\varepsilon }$ of problem (2.3) being defined only on $%
\Omega ^{\varepsilon }$, we need to extend it to the whole of $\Omega $ to
be able to state the convergence result. In order to do that, let us recall
the following well-known extension result (see \cite{Cioranescu-Paulin}).

\begin{lemma} \label{lm2.1}
There exists a linear continuous extension operator
$$
P^{\varepsilon }\in \mathcal{L}(L^{2}(\Omega ^{\varepsilon });L^{2}(\Omega ))
\cap \mathcal{L} (V^{\varepsilon}; H_{0}^{1}(\Omega ))
$$
and a positive constant $C$, independent of $\varepsilon $, such that
for any $v\in V^{\varepsilon }$,
\begin{gather*}
\| P^{\varepsilon }v\| _{L^{2}(\Omega )}\leq C\| v\|_{L^{2}
(\Omega ^{\varepsilon })},\\
\| \nabla P^{\varepsilon }v\|_{L^{2}(\Omega )}\leq C\|
\nabla v\|_{L^{2}(\Omega ^{\varepsilon })}\,.
\end{gather*}
\end{lemma}

An immediate consequence of the previous lemma is the following
Poincar\'{e}'s inequality in $V^{\varepsilon }$.

\begin{lemma} \label{lm2.2}
There exists a positive constant $C$, independent of $\varepsilon $, such
that for any $v\in V^{\varepsilon }$,
\[
\| v\|_{L^{2}(\Omega ^{\varepsilon })}\leq C\| \nabla
v\|_{L^{2}(\Omega ^{\varepsilon })}\,.
\]
\end{lemma}

The main result of this section is as follows.

\begin{theorem} \label{thm2.3}
One can construct an extension $P^{\varepsilon }u^{\varepsilon }$ of the
solution $u^{\varepsilon }$ of the variational problem (2.5) such that
$P^{\varepsilon }u^{\varepsilon }\rightharpoonup u$
weakly in $H_{0}^{1}(\Omega )$,
where $u$ is the unique solution of
\begin{equation}
\begin{gathered}
-{\sum_{i,j=1}^{n}q_{ij}}{\frac{\partial ^{2}u}{\partial x_{i}\partial
x_{j}}}+a{\frac{|\partial T|}{|Y^{*}|} }g(u)=f\quad \text{in }\Omega, \\
u=0\quad \text{on }\partial \Omega \,.
\end{gathered}
\end{equation}
Here, $Q=((q_{ij}))$ is the classical homogenized matrix, whose
entries are
\begin{equation}
q_{ij}=\delta _{ij}+\frac{1}{|Y^{*}|}
\int_{Y^{*}}\frac{\partial \chi _{j}}{\partial y_{i}}dy
\end{equation}
in terms of the functions $\chi _{i}$, $i=1,\dots ,n$,
solutions of the so-called cell problems
\begin{equation}
\begin{gathered}
-\Delta \chi _{i}=0 \quad \text{in } Y^{*}, \\
 \frac{\partial (\chi _{i}+y_{i})}{\partial \nu }=0 \quad\text{on } \partial T, \\
\chi _{i}\quad\text{is $Y$-periodic.}
\end{gathered}
\end{equation}
The constant matrix $Q$ is symmetric and positive-definite.
\end{theorem}


\begin{proof} We divide the proof into four steps.

\noindent\textit{First step.} Let $u^{\varepsilon }\in V^{\varepsilon }$ be the
solution of the variational problem (2.5) and let $P^{\varepsilon
}u^{\varepsilon }$ be the extension of $u^{\varepsilon }$ inside the
obstacles given by Lemma \ref{lm2.1}. Taking $\varphi =u^{\varepsilon }$ as a test
function in (2.5), using Schwartz and Poincar\'{e}'s inequalities, we easily
get
\[
\| P^{\varepsilon }u^{\varepsilon }\|_{H_{0}^{1}(\Omega )}\leq C.
\]
Consequently, by passing to a subsequence, still denoted by $P^{\varepsilon
}u^{\varepsilon }$, we can assume that there exists $u\in H_{0}^{1}(\Omega )$
such that
\begin{equation}
P^{\varepsilon }u^{\varepsilon }\rightharpoonup u\quad \text{weakly in }%
H_{0}^{1}(\Omega ).
\end{equation}
It remains to identify the limit equation satisfied by $u$.

\noindent\textit{Second step}. In order to get the limit equation satisfied by $u$ we
have to pass to the limit in (2.5). For getting the limit of the second term
in the left hand side of (2.5), let us introduce, for any
$h\in L^{s'}(\partial T)$, $1\leq s'\leq \infty $, the linear form
$\mu_{h}^{\varepsilon }$ on $W_{0}^{1,s}(\Omega )$ defined by
\[
\langle \mu _{h}^{\varepsilon },\varphi \rangle
=\varepsilon \int_{S^{\varepsilon }}h(\frac{x}{\varepsilon
})\varphi d\sigma \quad \forall \varphi \in W_{0}^{1,s}(\Omega ),
\]
with $1/s+1/s'=1$. It is proved in \cite{Cioranescu-Donato} that
\begin{equation}
\mu _{h}^{\varepsilon }\rightarrow \mu _{h}\quad \text{strongly in }%
(W_{0}^{1,s}(\Omega ))',
\end{equation}
where $\langle \mu _{h},\varphi \rangle =\mu _{h}\int_{\Omega}\varphi dx$,
with
\[
\mu _{h}=\frac{1}{|Y|}\int_{\partial T}h(y)d\sigma .
\]
In the particular case in which $h\in L^{\infty }(\partial T)$ or even when $h$
is constant, we have
\[
\mu _{h}^{\varepsilon }\rightarrow \mu _{h}\quad \text{strongly in }%
W^{-1,\infty }(\Omega ).
\]
In what follows, we shall denote by $\mu ^{\varepsilon }$ the above
introduced measure in the particular case in which $h=1$. Notice that in
this case $\mu _{h}$ becomes $\mu _{1}=|\partial T|/|Y|$.
Let us prove now that for any $\varphi \in \mathcal{\ D}(\Omega )$ and for
any $v^{\varepsilon }\rightharpoonup v$ weakly in $H_{0}^{1}(\Omega )$, we
get
\begin{equation}
\varphi g(v^{\varepsilon })\rightharpoonup \varphi g(v)\quad
\text{weakly in }W_{0}^{1,\overline{q}}(\Omega ),
\end{equation}
where
\[
\overline{q}=\frac{2n}{q(n-2)+n}.
\]
To prove (2.11), let us first note that
\begin{equation}
\sup \| \nabla g(v^{\varepsilon })\|_{L^{\overline{q}}(\Omega
)}<\infty .
\end{equation}
Indeed, from the growth condition (2.4) imposed to $g$, we get
\begin{align*}
\int_{\Omega }\big|\frac{\partial g}{\partial
x_{i}}(v^{\varepsilon })\big|^{\overline{q}}dx
&\leq C\int_{\Omega }\big( 1+|v^{\varepsilon }|
^{q\overline{q}}\big) |\frac{\partial v^{\varepsilon
}}{\partial x_{i}}|^{\overline{q}}dx\\
&\leq C( 1+( \int_{\Omega }|v^{\varepsilon }|^{q\overline{q}\gamma }dx)
^{1/\gamma }) ( \int_{\Omega }|\nabla
v^{\varepsilon }|^{\overline{q}\delta }dx) ^{1/\delta },
\end{align*}
where we took $\gamma $ and $\delta $ such that $\overline{q}\delta =2$, $%
1/\gamma +1/\delta =1$ and $q\overline{q}\gamma =2n/(n-2)$. Note that from
here we get $\overline{q}={\frac{2n}{q(n-2)+n}}$. Also, since
$0\leq q< n/(n-2)$, we have $\overline{q}> 1$. Now, since
\[
\sup \| v^{\varepsilon }\|_{L^{\frac{2n}{n-2}}(\Omega )}<\infty,
\]
we get immediately (2.12). Hence, to get (2.11), it remains only to prove
that
\begin{equation}
g(v^{\varepsilon })\rightarrow g(v)\quad \text{strongly in }L^{\overline{q}%
}(\Omega ).
\end{equation}
But this is just a consequence of the following well-known result
(see \cite{DalMaso} and \cite{Lions}).

\begin{theorem} \label{thm2.4}
Let $G:\Omega \times \mathbb{R}\rightarrow \mathbb{R}$ be a Carath\'{e}odory
function, i.e.
\begin{itemize}
\item[(a)] For every $v$ the function $G(\cdot ,v)$ is measurable with respect to
$x\in \Omega $.

\item[(b)] For every (a.e.) $x\in \Omega $, the function $G(x,\cdot )$ is continuous
with respect to $v$.
\end{itemize}
Moreover, if we assume that there exists a positive constant $C$
such that
\[
|G(x,v)|\leq C\big( 1+|v|^{r/t}\big) ,
\]
with $r\geq 1$ and $t<\infty $, then the map $v\in L^{r}(\Omega )\mapsto
G(x,v(x))\in L^{t}(\Omega )$ is continuous in the strong topologies.
\end{theorem}

Indeed, since
\[
|g(v)|\leq C(1+|v|^{q+1}),
\]
applying the above theorem for $G(x,v)=g(v)$, $t=\overline{q}$ and $%
r=(2n/(n-2))-r'$, with $r'>0$ such that $q+1<r/t$ and
using the compact injection $H^{1}(\Omega )\hookrightarrow L^{r}(\Omega )$
we easily get (2.13).

Finally, from (2.10) (with $h=1$) and (2.11) written for $v^{\varepsilon
}=P^{\varepsilon }u^{\varepsilon }$, we conclude
\begin{equation}
\langle \mu ^{\varepsilon },\varphi g(P^{\varepsilon }u^{\varepsilon
})\rangle \rightarrow \frac{|\partial T|}{|Y|
}\int_{\Omega }\varphi g(u)dx\quad \forall \varphi \in \mathcal{D}%
(\Omega )
\end{equation}
and this ends this step of the proof.

\noindent \textit{Third step}. Let $\xi ^{\varepsilon }$ be the gradient of $%
u^{\varepsilon }$ in $\Omega ^{\varepsilon }$ and let us denote by $%
\widetilde{\xi ^{\varepsilon }}$ its extension with zero to the whole of $%
\Omega $, i.e.
\[
\widetilde{\xi ^{\varepsilon }}=
\begin{cases}
\xi ^{\varepsilon }& \text{in } \Omega ^{\varepsilon }, \\
0 & \text{in }\Omega \setminus \overline{\Omega ^{\varepsilon }}.
\end{cases}
\]
Obviously, $\widetilde{\xi ^{\varepsilon }}$ is bounded in
$(L^{2}(\Omega))^{n}$ and hence there exists $\xi \in (L^{2}(\Omega ))^{n}$ such
that
\begin{equation}
\widetilde{\xi ^{\varepsilon }}\rightharpoonup \xi \quad \text{weakly in }
(L^{2}(\Omega ))^{n}.
\end{equation}
Let us see now which is the equation satisfied by $\xi $. Take
$\varphi \in \mathcal{D}(\Omega )$. From (2.5) we get
\begin{equation}
\int_{\Omega }\widetilde{\xi ^{\varepsilon }}\cdot \nabla \varphi
dx+a\varepsilon \int_{S^{\varepsilon }}g(u^{\varepsilon })\varphi
d\sigma =\int_{\Omega }\chi _{\Omega ^{\varepsilon } } f\varphi dx.
\end{equation}
Now, we can pass to the limit, with $\varepsilon \rightarrow 0$, in all the
terms of (2.16). For the first one, we have
\begin{equation}
\lim_{\varepsilon\rightarrow 0}\int_{\Omega }\widetilde{\xi
^{\varepsilon }}\cdot \nabla \varphi dx=\int_{\Omega }\xi \cdot
\nabla \varphi dx.
\end{equation}
For the second term, using (2.14), we get
\begin{equation}
\lim _{\varepsilon\rightarrow 0} a\varepsilon \int_{S^{\varepsilon
}}g(u^{\varepsilon })\varphi d\sigma =a\frac{|\partial T|}{%
|Y|}\int_{\Omega }g(u)\varphi dx.
\end{equation}
It is not difficult to pass to the limit in the right-hand side of (2.16).
Since
\[
\chi_{\Omega ^{\varepsilon }} f\rightharpoonup \frac{|
Y^{*}|}{|Y|}f\quad \text{weakly in
}L^{2}(\Omega ),
\]
we obtain
\begin{equation}
\lim _{\varepsilon\rightarrow 0}\int_{\Omega }\chi_{\Omega
^{\varepsilon }} f\varphi dx=\frac{|Y^{*}|}{|Y|}%
\int_{\Omega }f\varphi dx.
\end{equation}
Putting together (2.17)-(2.19), we have
\[
\int_{\Omega }\xi \cdot \nabla \varphi dx+a\frac{|\partial
T|}{|Y|}\int_{\Omega }g(u)\varphi
dx=\frac{|Y^{*}|}{|Y|}\int_{\Omega
}f\varphi dx \quad \forall \varphi \in \mathcal{D}(\Omega ).
\]
Hence $\xi $ verifies
\begin{equation}
-\mathop{\rm div}\xi +a\frac{|\partial T|}{|Y|}g(u)=%
\frac{|Y^{*}|}{|Y|}f\quad \text{in
}\Omega .
\end{equation}
It remains now to identify $\xi $.

\noindent\textit{Fourth step.} In order to identify $\xi $, we shall make
use of the solutions of the cell-problems (2.8). For any fixed
$i=1,\dots ,n$, let us define
\begin{equation}
\Phi _{i\varepsilon }(x)=\varepsilon \big( \chi _{i}(\frac{x}{\varepsilon }%
)+y_{i}\big) \quad \forall x\in \Omega ^{\varepsilon },
\end{equation}%
where $y=x/\varepsilon$.
By periodicity
\begin{equation}
P^{\varepsilon }\Phi _{i\varepsilon }\rightharpoonup x_{i}\quad \text{
weakly in }H^{1}(\Omega ).
\end{equation}
Let $\eta _{i}^{\varepsilon }$ be the gradient of $\Phi _{i\varepsilon }$ in
$\Omega ^{\varepsilon }$. Denote by $\widetilde{\eta _{i}^{\varepsilon }}$
the extension by zero of $\eta _{i}^{\varepsilon }$ inside the obstacles.
 From (2.21), for the $j$-component of $\widetilde{\eta _{i}^{\varepsilon }}$
we get
\[
\big( \widetilde{\eta _{i}^{\varepsilon }}\big) _{j}
=\Big( \widetilde{\frac{\partial \Phi _{i\varepsilon }}{\partial x_{j}}}\Big)
=\Big(\widetilde{\frac{\partial \chi _{i}}{\partial y_{j}}(y)}\Big)
+\delta_{ij}\chi _{Y^{\ast }}
\]
and hence
\begin{equation}
\big( \widetilde{\eta _{i}^{\varepsilon }}\big) _{j}\rightharpoonup
\frac{1}{|Y|}\Big( \int_{Y^{\ast }}\frac{\partial
\chi _{i}}{\partial y_{j}}dy+|Y^{\ast }|\delta _{ij}\Big)
=\frac{|Y^{\ast }|}{|Y|}q_{ij}\quad \text{weakly in }L^{2}(\Omega ).
\end{equation}
On the other hand, it is not difficult to see that $\eta _{i}^{\varepsilon }$
satisfies
\begin{equation}
\begin{gathered}
-\mathop{\rm div}\eta _{i}^{\varepsilon }=0\quad \text{in }\Omega
^{\varepsilon}, \\
\eta _{i}^{\varepsilon }\cdot \nu =0\quad \text{on }S^{\varepsilon }.
\end{gathered}
\end{equation}
Now, let $\varphi \in \mathcal{D}(\Omega )$. Multiplying the first equation
in (2.24) by $\varphi u^{\varepsilon }$ and integrating by parts over $%
\Omega ^{\varepsilon }$ we get
\[
\int_{\Omega ^{\varepsilon }}\eta _{i}^{\varepsilon }\cdot \nabla
\varphi u^{\varepsilon }dx+\int_{\Omega ^{\varepsilon }}\eta
_{i}^{\varepsilon }\cdot \nabla u^{\varepsilon }\varphi dx=0.
\]%
So
\begin{equation}
\int_{\Omega }\widetilde{\eta _{i}^{\varepsilon }}\cdot \nabla
\varphi P^{\varepsilon }u^{\varepsilon }dx+\int_{\Omega
^{\varepsilon }}\eta _{i}^{\varepsilon }\cdot \nabla
u^{\varepsilon }\varphi dx=0.
\end{equation}%
On the other hand, taking $\varphi \Phi _{i\varepsilon }$ as a test function
in (2.5) we obtain
\[
\int_{\Omega ^{\varepsilon }}(\nabla u^{\varepsilon }\cdot \nabla
\varphi )\Phi _{i\varepsilon }dx+\int_{\Omega ^{\varepsilon
}}(\nabla u^{\varepsilon }\cdot \nabla \Phi _{i\varepsilon
})\varphi dx+a\varepsilon \int_{S^{\varepsilon }}g(u^{\varepsilon
})\varphi \Phi _{i\varepsilon }d\sigma =\int_{\Omega ^{\varepsilon
}}f\varphi \Phi _{i\varepsilon }dx
\]
which, using the definitions of $\widetilde{\xi ^{\varepsilon }}$ and $%
\widetilde{\eta _{i}^{\varepsilon }}$, gives
\[
\int_{\Omega }\widetilde{\xi ^{\varepsilon }}\cdot \nabla \varphi
P^{\varepsilon }\Phi _{i\varepsilon }dx+\int_{\Omega ^{\varepsilon
}}\nabla u^{\varepsilon }\cdot \eta _{i}^{\varepsilon }\varphi
dx+a\varepsilon \int_{S^{\varepsilon }}g(u^{\varepsilon })\varphi
\Phi _{i\varepsilon }d\sigma =\int_{\Omega }f\chi _{\Omega
^{\varepsilon }}\varphi P^{\varepsilon }\Phi _{i\varepsilon }dx.
\]
Now, using (2.25), we get
\begin{equation}
\int_{\Omega }\widetilde{\xi ^{\varepsilon }}\cdot \nabla \varphi
P^{\varepsilon }\Phi _{i\varepsilon }dx-\int_{\Omega
}\widetilde{\eta _{i}^{\varepsilon }}\cdot \nabla \varphi
P^{\varepsilon }\Phi _{i\varepsilon }dx+a\varepsilon
\int_{S^{\varepsilon }}g(u^{\varepsilon })\varphi \Phi
_{i\varepsilon }d\sigma =\int_{\Omega }f\chi _{\Omega
^{\varepsilon }}\varphi P^{\varepsilon }\Phi _{i\varepsilon }dx.
\end{equation}
Let us pass to the limit in (2.26). Firstly, using (2.15) and (2.22), we
have
\begin{equation}
\lim _{\varepsilon\rightarrow 0}\int_{\Omega }\widetilde{\xi
^{\varepsilon }}\cdot \nabla \varphi P^{\varepsilon }\Phi
_{i\varepsilon }dx=\int_{\Omega }\xi \cdot \nabla \varphi x_{i}dx.
\end{equation}
On the other hand, (2.9) and (2.23) imply that
\begin{equation}
\lim _{\varepsilon\rightarrow 0}\int_{\Omega }\widetilde{\eta
_{i}^{\varepsilon }}\cdot \nabla \varphi P^{\varepsilon }u^{\varepsilon }dx=%
\frac{|Y^{*}|}{|Y|}\int_{\Omega
}q_{i}\cdot \nabla \varphi udx,
\end{equation}
where $q_{i}$ is the vector having the $j$-component equal to $q_{ij}$.

Because the boundary of $T$ is smooth, of class $C^{2}$,
$P^{\varepsilon}\Phi _{i\varepsilon }\in W^{1,\infty }(\Omega )$ and
$P^{\varepsilon }\Phi_{i\varepsilon }\rightarrow x_{i}$ strongly in
$L^{\infty }(\Omega )$. Then,
since $g(P^{\varepsilon }u^{\varepsilon })P^{\varepsilon }\Phi
_{i\varepsilon }\rightarrow g(u)x_{i}$ strongly in $L^{\overline{q}}(\Omega
) $ and $g(P^{\varepsilon }u^{\varepsilon })P^{\varepsilon }\Phi
_{i\varepsilon }$ is bounded in $W^{1,\overline{q}}(\Omega )$, we have
$g(P^{\varepsilon }u^{\varepsilon })P^{\varepsilon }\Phi _{i\varepsilon
}\rightharpoonup g(u)x_{i}$ weakly in $W^{1,\overline{q}}(\Omega )$. So
\begin{equation}
\lim _{\varepsilon\rightarrow 0}a\varepsilon \int_{S^{\varepsilon
}}g(u^{\varepsilon })\varphi \Phi _{i\varepsilon }d\sigma
=a\frac{|
\partial T|}{|Y|}\int_{\Omega }g(u)\varphi
x_{i}dx.
\end{equation}
Finally, for the limit of the right-hand side of (2.26), since $\chi_{\Omega
^{\varepsilon }} f\rightharpoonup {\frac{|Y^{*}|}{|Y|}}f$ weakly in
$L^{2}(\Omega )$, using again (2.22) we have
\begin{equation}
\lim _{\varepsilon\rightarrow 0}\int_{\Omega }f\chi _{\Omega^{\varepsilon }}
\varphi P^{\varepsilon }\Phi _{i\varepsilon }dx
=\frac{|Y^{*}|}{|Y|}\int_{\Omega }f\varphi x_{i}dx.
\end{equation}
Hence we get
\begin{equation}
\int_{\Omega }\xi \cdot \nabla \varphi x_{i}dx-\frac{|
Y^{*}|}{|Y|}\int_{\Omega }q_{i}\cdot \nabla
\varphi udx+a\frac{|\partial T|}{|Y|}%
\int_{\Omega }g(u)\varphi x_{i}dx=\frac{|Y^{*}|
}{|Y|}\int_{\Omega }f\varphi x_{i}dx.
\end{equation}
Using Green's formula and equation (2.20), we have
\[
-\int_{\Omega }\xi \cdot \nabla x_{i}\varphi dx+\frac{|
Y^{*}|}{|Y|}\int_{\Omega }q_{i}\cdot \nabla
u\varphi dx=0\quad \text{in }\Omega .
\]
The above equality holds true for any $\varphi \in \mathcal{D}(\Omega )$.
This implies that
\begin{equation}
-\xi \cdot \nabla x_{i}+\frac{|Y^{*}|}{|Y|}q_{i}\cdot \nabla u=0
\quad \text{in }\Omega .
\end{equation}
Writing (2.30) by components, differentiating with respect to $x_{i}$, summing
after $i$ and using (2.19), we conclude that
\[
\frac{|Y^{*}|}{|Y|}\sum_{i,j=1}^{n}q_{ij}%
\frac{\partial ^{2}u}{\partial x_{i}\partial x_{j}}=\text{div}\,\xi =-\frac{%
|Y^{*}|}{|Y|}f+a\frac{|\partial T|}{%
|Y|}g(u),
\]
which implies that $u$ satisfies
\[
-\sum_{i,j=1}^{n}q_{ij}\frac{\partial ^{2}u}{\partial
x_{i}\partial x_{j}}+a\frac{|\partial T|}{|
Y^{*}|}g(u)=f\quad \text{in }\Omega .
\]
Since $u\in H_{0}^{1}(\Omega )$ (i.e. $u=0$ on $\partial \Omega $) and $u$
is uniquely determined, the whole sequence $P^{\varepsilon }u^{\varepsilon }$
converges to $u$ and Theorem \ref{thm2.3} is proved.
\end{proof}

\begin{remark} \label{rmk2.5} \rm
As already mentioned, it is worth remarking that if we assume $f\geq 0$, the
function $g$ in example $a)$ is indeed a particular example of our first
model situation. Moreover, the growth condition (2.4) for $g$ holds with $q=0
$, hence we get $\overline{q}=2$ and convergence (2.11) holds in $%
H_{0}^{1}(\Omega)$. Since $g$ is Lipschitz continuous, one can prove (see
{J.I.~D\'{\i}az}~\cite{Diaz3}) that the solution of the homogenized
problem is also strictly positive on $\Omega$. This will not be the case
when $g$ is not necessarily regular.
\end{remark}

\subsection{Second model situation: The case of a monotone graph}

In this subsection we shall treat the case in which the function $g$
appearing in (1.1) is a single-valued maximal monotone graph in $\mathbb{%
R\times R}$, satisfying the condition $g(0)=0$. Also, if we denote
by $D(g)$ the domain of $g$, i.e. $D(g)=\{\xi \in \mathbb{R}:
 g(\xi )\neq \emptyset \}$, then we suppose that
$D(g)=\mathbb{R}$. Moreover, we assume that $g$ is continuous and
there exist $C\geq 0$ and an exponent $q$, with $0\leq q<
n/(n-2)$, such that
\begin{equation}
|g(v) |\leq C(1+|v|^{q}).
\end{equation}

Note that the second important practical example (b) mentioned in the
Introduction is a particular example of such a single-valued maximal
monotone graph.

We know that in this case there exists a lower semicontinuous convex
function $G$ from $\mathbb{R}$ to $]-\infty ,+\infty ]$, $G$ proper, i.e. $%
G\not\equiv +\infty $ such that $g$ is the subdifferential of $G$, $%
g=\partial G$ ($G$ is an indefinite ''integral`` of $g$). Let $%
G(v)=\int_{0}^{v}g(s)ds$.

Define the convex set
\begin{equation}
K^{\varepsilon }=\left\{ v\in V^{\varepsilon } :
G(v)| _{S^{\varepsilon }} \in L^{1}(S^{\varepsilon }) \right\}.
\end{equation}
For a given function $f\in L^{2}(\Omega )$ the weak solution of the problem
(2.3) is also the unique solution of the  variational inequality:
\begin{quote}
Find $u^{\varepsilon }\in K^{\varepsilon }$ such that
\begin{equation}
 \int_{\Omega ^{\varepsilon }}Du^{\varepsilon}D(v^{\varepsilon }
-u^{\varepsilon })dx- \int_{\Omega^{\varepsilon }}f(v^{\varepsilon }
-u^{\varepsilon})dx+a\langle \mu ^{\varepsilon },G(v^{\varepsilon
})-G(u^{\varepsilon })\rangle \geq 0
\end{equation}
for all $v^{\varepsilon }\in K^{\varepsilon }$.
\end{quote}
First, let us notice that there exists a unique weak solution
$u^{\varepsilon }\in V^{\varepsilon }\cap H^{2}(\Omega ^{\varepsilon })$ of
the above variational inequality (see \cite{Brezis}). Also, notice that it
is well-known that the solution $u^{\varepsilon }$ of the variational
inequality (2.35) is also the unique solution of the minimization problem:
\[
\begin{gathered}
u^{\varepsilon }\in K^{\varepsilon }, \\
J^{\varepsilon }(u^{\varepsilon })=\inf_{v\in K^{\varepsilon }}
J^{\varepsilon }(v),
\end{gathered}
\]
where
\[
J^{\varepsilon }(v)=\frac{1}{2}\int_{\Omega ^{\varepsilon }}|
Dv|^{2}dx+a\langle \mu ^{\varepsilon
},G(v)\rangle -\int_{\Omega ^{\varepsilon }}fvdx.
\]
Introduce the following functional defined on $H_{0}^{1}(\Omega )$:
\[
J^{0}(v)=\frac{1}{2}\int_{\Omega }QDvDvdx+a
\frac{|\partial T|}{|Y^{*}|}\int_{\Omega
}G(v)dx-\int_{\Omega }fvdx.
\]


The main result of this subsection is as follows.

\begin{theorem} \label{thm2.6}
One can construct an extension $P^{\varepsilon }u^{\varepsilon }$ of the
solution $u^{\varepsilon }$ of the variational inequality (2.35) such that
$P^{\varepsilon }u^{\varepsilon }\rightharpoonup u$ weakly in
$\ H_{0}^{1}(\Omega )$, where $u$ is the unique solution of the minimization
problem: Find $u\in H_{0}^{1}(\Omega )$ such that
\begin{equation}
J^{0}(u)=\inf_{v\in H_{0}^{1}(\Omega )} J^{0}(v).
\end{equation}
Moreover, $G(u)\in L^{1}(\Omega )$. Here,\ $Q=((q_{ij}))$\ is the classical
homogenized matrix, whose entries were defined by (2.7)-(2.8).
\end{theorem}

Note that $u$ also satisfies
\[
\begin{gathered}
-{\sum_{i,j=1}^{n}q_{ij} \frac{\partial^{2}u}{\partial x_{i}\partial x_{j}}
+a \frac{|\partial T|}{|Y^{*}|}g(u)=f}\quad \text{in } \Omega, \\
u=0 \quad \text{on }\partial \Omega.
\end{gathered}
\]

\begin{proof}[Proof of Theorem \ref{thm2.6}]
Let $u^{\varepsilon }$ be the solution of the variational inequality (2.35).
We shall use the same extension $P^{\varepsilon }u^{\varepsilon }$ as in the
previous case (given by Lemma \ref{lm2.1}). It is not difficult to see that
$P^{\varepsilon}u^{\varepsilon }$ is bounded in $H_{0}^{1}(\Omega )$.
So by extracting a subsequence, one has
\begin{equation}
P^{\varepsilon }u^{\varepsilon }\rightharpoonup u\quad
\text{weakly in }\ H_{0}^{1}(\Omega ).
\end{equation}
Let $\varphi \in \mathcal{D}(\Omega )$. By classical regularity results $%
\chi _{i}\in L^{\infty }$. Using the boundedness of $\chi _{i}$ and $\varphi
$, there exists $M\geq 0$ such that
\[
\| \frac{\partial \varphi }{\partial x_{i}}\|_{L^{\infty
}}\| \chi _{i}\|_{L^{\infty }}<M.
\]
Let
\begin{equation}
v^{\varepsilon }=\varphi +\sum_{i}\varepsilon \frac{\partial \varphi }{%
\partial x_{i}}(x)\chi _{i}(\frac{x}{\varepsilon }).
\end{equation}
Then $v^{\varepsilon }\in K^{\varepsilon }$ which will allow us to take it
as a test function in (2.35). Moreover, $v^{\varepsilon }\rightarrow \varphi
$ strongly in $L^{2}(\Omega )$.
Let us compute $Dv^{\varepsilon }$:
\[
Dv^{\varepsilon }=D\varphi +\sum_{i}\frac{\partial \varphi }{\partial x_{i}}%
(x)D\chi _{i}(\frac{x}{\varepsilon })+\varepsilon \sum_{i}D\frac{%
\partial \varphi }{\partial x_{i}}(x)\chi _{i}(\frac{x}{\varepsilon }).
\]
So
\[
Dv^{\varepsilon }=\sum_{i}\frac{\partial \varphi }{\partial x_{i}}(x)(%
\mathbf{e}_{i}+D\chi _{i}(\frac{x}{\varepsilon }))+\varepsilon
\sum_{i}D\frac{\partial \varphi }{\partial x_{i}}(x)\chi _{i}(\frac{x%
}{\varepsilon }),
\]
where $\mathbf{e}_{i}$, $1\leq i\leq n$, are the elements of the canonical
basis in $\mathbb{R}^{n}$.

Using $v^{\varepsilon }$ as a test function in (2.35), we can write
\[
\int_{\Omega ^{\varepsilon }}Du^{\varepsilon }Dv^{\varepsilon
}dx\geq \int_{\Omega ^{\varepsilon }}f(v^{\varepsilon
}-u^{\varepsilon })dx+\int_{\Omega ^{\varepsilon }}Du^{\varepsilon
}Du^{\varepsilon }dx-a\langle \mu ^{\varepsilon
},G(v^{\varepsilon })-G(u^{\varepsilon })\rangle .
\]
In fact, we have
\begin{equation}
\int_{\Omega }DP^{\varepsilon }u^{\varepsilon }\widetilde{%
(Dv^{\varepsilon })}dx\geq \int_{\Omega ^{\varepsilon
}}f(v^{\varepsilon }-u^{\varepsilon })dx+\int_{\Omega
^{\varepsilon }}Du^{\varepsilon }Du^{\varepsilon }dx-a\langle
\mu ^{\varepsilon },G(v^{\varepsilon })-G(u^{\varepsilon
})\rangle .
\end{equation}
Denote
\begin{equation}
\rho Q\mathbf{e}_{j}=\frac{1}{|Y^{*}|
}\int_{Y^{*}}(D\chi _{j}+\mathbf{e}_{j})dy,
\end{equation}
where $\rho =|Y^{*}|/|Y|$. Neglecting the term $%
\varepsilon \sum_{i}D\frac{\partial \varphi }{\partial
x_{i}}(x)\chi _{i}(\frac{x}{\varepsilon })$ which actually
tends strongly to zero, we can pass immediately to the limit in
the left-hand side of (2.39). Hence
\begin{equation}
\int_{\Omega }DP^{\varepsilon }u^{\varepsilon }\widetilde{%
Dv^{\varepsilon }}dx\rightarrow \int_{\Omega }\rho QDuD\varphi dx.
\end{equation}
It is not difficult to pass to the limit in the first term of the right-hand
side of (2.39). Indeed, since $v^{\varepsilon }\rightarrow \varphi $
strongly in $L^{2}(\Omega )$, we get
\begin{equation}
\int_{\Omega ^{\varepsilon }}f(v^{\varepsilon }-u^{\varepsilon
})dx=\int_{\Omega }f\chi _{_{\Omega ^{\varepsilon
}}}(v^{\varepsilon }-P^{\varepsilon}u^{\varepsilon })dx\rightarrow
\int_{\Omega }f\rho (\varphi -u)dx.
\end{equation}
For the third term of the right-hand side of (2.39), assuming the growth
condition (2.33) for the single-valued maximal monotone graph $g$ and
reasoning exactly like in the previous subsection, we get
\[
G(P^{\varepsilon }u^{\varepsilon })\rightharpoonup G(u)\quad
\text{weakly in }W_{0}^{1,\overline{q}}(\Omega )
\]
and then
\[
\langle \mu ^{\varepsilon },G(P^{\varepsilon }u^{\varepsilon
})\rangle \rightarrow \frac{|\partial T|
}{|Y|}\int_{\Omega }G(u)dx.
\]
In a similar manner, we obtain
\[
\langle \mu ^{\varepsilon },G(v^{\varepsilon })\rangle
\rightarrow \frac{|\partial T|}{|Y|}%
\int_{\Omega }G(\varphi )dx
\]
and hence we get
\begin{equation}
a\langle \mu ^{\varepsilon },G(v^{\varepsilon
})-G(P^{\varepsilon }u^{\varepsilon })\rangle \rightarrow
a\frac{|\partial T|}{|Y|}\int_{\Omega
}(G(\varphi )-G(u))dx.
\end{equation}
So, it remains to pass to the limit only in the second term of the
right-hand side of (2.39). For doing this, we can write down the
subdifferential inequality
\begin{equation}
\int_{\Omega ^{\varepsilon }}Du^{\varepsilon }Du^{\varepsilon
}dx\geq \int_{\Omega ^{\varepsilon }}Dw^{\varepsilon
}Dw^{\varepsilon }dx+2\int_{\Omega ^{\varepsilon }}Dw^{\varepsilon
}(Du^{\varepsilon }-Dw^{\varepsilon })dx,
\end{equation}
for any $w^{\varepsilon }\in H_{0}^{1}(\Omega )$. Reasoning as before and
choosing
\[
w^{\varepsilon }=\overline{\varphi }+{\sum_{i}}\varepsilon \frac{\partial
\overline{\varphi }}{\partial x_{i}}(x)\chi _{i}(\frac{x}{\varepsilon
}),
\]
where $\overline{\varphi }$ enjoys similar properties as the corresponding $%
\varphi $, the right-hand side of the inequality (2.44) passes to the limit
and one has
\[
\liminf_{\varepsilon \rightarrow 0}\int_{\Omega ^{\varepsilon
}}Du^{\varepsilon }Du^{\varepsilon }dx\geq \int_{\Omega }\rho QD%
\overline{\varphi }D\overline{\varphi }dx+2\int_{\Omega }\rho QD%
\overline{\varphi }(Du-D\overline{\varphi })dx,
\]
for any $\overline{\varphi }\in \mathcal{D}(\Omega )$. But since $u\in
H_{0}^{1}(\Omega )$, taking $\overline{\varphi } \rightarrow u$ strongly in $%
H_{0}^{1}(\Omega )$, we conclude
\begin{equation}
\liminf_{\varepsilon \rightarrow 0}\int_{\Omega ^{\varepsilon
}}Du^{\varepsilon }Du^{\varepsilon }dx\geq \int_{\Omega }\rho
QDuDudx.
\end{equation}
Putting together (2.41)-(2.43) and (2.45), we get
\[
\int_{\Omega }\rho QDuD\varphi dx\geq \int_{\Omega }f\rho (\varphi
-u)dx+\int_{\Omega }\rho QDuDudx-a\frac{|
\partial T|}{|Y|}\int_{\Omega
}(G(\varphi )-G(u))dx,
\]
for any $\varphi \in \mathcal{D}(\Omega )$ and hence by density for any $%
v\in H_{0}^{1}(\Omega )$.

So, finally, we obtain
\[
\int_{\Omega }QDuD(v-u)dx\geq \int_{\Omega }f(v-u)dx
-a\frac{|\partial T|}{|Y^{*}|}\int_{\Omega}(G(\varphi )-G(u))dx,
\]
which gives exactly the limit problem (2.36). This completes the proof of
Theorem \ref{thm2.6}.
\end{proof}


\begin{remark} \label{rmk2.7} \rm
The choice of the test function (2.38) gives, in fact, a first-corrector
term for the weak convergence of $P^{\varepsilon }u^{\varepsilon }$ to $u$.
\end{remark}

\begin{remark} \label{rmk2.8} \rm
We can treat in a similar manner the case of a multi-valued maximal monotone
graph, which includes various semilinear classical boundary-value problems,
such as Dirichlet or Neumann problems, Robin boundary conditions,
Signorini's unilateral conditions, climatization problems (see, for
instance, \cite{Brezis}, \cite{Cioranescu-Donato}, \cite{Conca-Donato} and
\cite{Conca-Murat-Timofte}). We could also include here the case of the
so-called zeroth-order reactions, in which, formally, $g$ is given by the
discontinuous function $g(v)=0$, if $v\leq 0$ and $g(v)=1$ if $v>0$ (see,
for instance, \cite{Aris}). The correct mathematical treatment needs the
problem to be reformulated by using the maximal monotone graph of $\mathbb{%
R^2}$ associated to the Heaviside function $\beta(v)=\{0\}$ if $v<0$, $%
\beta(0)=[0,1]$ and $\beta(v)={1}$ if $v>0$. The existence and uniqueness of
a solution can be found, for instance, in Br\'{e}zis \cite{Brezis} and
D\'{\i}az \cite{Diaz1}. The solution is obtained
by passing to the limit in a sequence of problems associated to a monotone
sequence of Lipschitz functions approximating $\beta$ and the results of
this section remain true. Notice that now the homogenized problem becomes
\begin{gather*}
-{\sum_{i,j=1}^{n}q_{ij} \frac{\partial^{2}u}{\partial x_{i}\partial x_{j}}
+a \frac{|\partial T|}{|Y^{*}|}\beta(u)\ni f}\quad \text{in } \Omega, \\
u=0 \quad \text{on }\partial \Omega.
\end{gather*}
A curious fact is that this type of problems arises in very different
contexts (see, for instance, \cite{Ughi}).
\end{remark}

\begin{remark} \label{rmk2.9}\rm
Under the assumptions of this section, $g$ does not need to be Lipschitz
continuous (as, for instance, in the second example or in the multivalued
example of the previous remark) and so the solution of the homogenized
problem may give rise to a ``dead zone" (where $u(x)=0$) when a suitable
balance between the ``size" of some norm of $f$ and the ``size" of the
greatest ball included in $\Omega$ holds (see D\'{\i}az \cite{Diaz3}).
\end{remark}

\begin{remark} \rm
The case of a spherically symmetric isolated particle under singular
reaction kinetics was considered by Vega and Li\~n\'{a}n \cite{Vega-Liņan}.
\end{remark}

\section{Chemical reactive flow through grains}

As already mentioned in Introduction, the chemical situation behind the
second nonlinear problem we will treat here involves a chemical reactor with
the grains constituted by solid catalyst particles. We assume that now the
chemical reactions take place inside the grains, instead just on their
boundaries. In fact, the problem corresponds to a transmission problem
between the solutions of two separated equations. A simplified version of
this kind of models can be formulated as follows:
\begin{equation}
\begin{gathered}
-D_{f}\Delta u^{\varepsilon }=f\quad \text{in }\Omega ^{\varepsilon }, \\
-D_{p}\Delta v^{\varepsilon }+ag(v^{\varepsilon })=0,\quad
\text{in }\Pi^{\varepsilon }, \\
-D_{f}{\frac{\partial u^{\varepsilon }}{\partial \nu }}=D_{p}%
 {\frac{\partial v^{\varepsilon }}{\partial \nu }}\quad \text{on }S^{\varepsilon }, \\
u^{\varepsilon }=v^{\varepsilon }\quad \text{on }S^{\varepsilon }, \\
u^{\varepsilon }=0\quad \text{on }\partial \Omega .
\end{gathered}
\end{equation}
Here, $\Pi ^{\varepsilon }=\Omega \setminus \overline{\Omega ^{\varepsilon }}$,
$\nu $ is the exterior unit normal to $\Omega ^{\varepsilon }$, $a$,
$D_{f}$, $D_{p}>0$,
$f\in L^{2}(\Omega )$ and $g$ is a
continuous function, monotonously non-decreasing and such that
$g(v)=0$ if and only if  $v=0$. Moreover, we shall suppose that there exist a
positive constant $C$ and an exponent $q$, with $0\leq q<n/(n-2)$,
such that
\[
|g(v)|\leq C(1+|v|^{q+1}).
\]
Note that examples $a)$ and $b)$ are both covered by this class
of functions $g's$ and, of course, both are still our main practical
examples.

Let us consider again the functional space
\[
V^{\varepsilon }=\left\{ v\in H^{1}(\Omega ^{\varepsilon}) : v=0\text{on }
\partial \Omega \right\}
\]
and introduce the space
\[
H^{\varepsilon }=\left\{ w^{\varepsilon }=(u^{\varepsilon },v^{\varepsilon })
 : u^{\varepsilon }\in V^{\varepsilon },
v^{\varepsilon }\in H^{1}(\Pi ^{\varepsilon }),
u^{\varepsilon }=v^{\varepsilon } \text{on }S^{\varepsilon} \right\} ,
\]
with the norm
\[
\| w^{\varepsilon }\|_{H^{\varepsilon }}^{2}=\| \nabla
u^{\varepsilon }\|_{L^{2}(\Omega ^{\varepsilon })}^{2}+\| \nabla
v^{\varepsilon }\|_{L^{2}(\Pi ^{\varepsilon })}^{2}.
\]
The variational formulation of problem (3.1) is as follows:
\begin{quote}
Find $w^{\varepsilon }\in H^{\varepsilon }$ such that
\begin{equation}
{D_{f}\int_{\Omega ^{\varepsilon }}\nabla
u^{\varepsilon }\cdot \nabla \varphi dx+D_{p}\int_{\Pi
^{\varepsilon }}\nabla v^{\varepsilon }\cdot \nabla \psi
dx+a\int_{\Pi ^{\varepsilon }}g(v^{\varepsilon })\psi dx
=\int_{\Omega ^{\varepsilon }}f\varphi dx}
\end{equation}
for all $(\varphi ,\psi )\in K^{\varepsilon }$
\end{quote}
Under the above structural hypotheses and the conditions fulfilled by
$H^{\varepsilon }$, it is well-known by classical existence and uniqueness
results (see \cite{Brezis} and \cite{Lions}) that (3.2) is a well-posed
problem.

Let us note that we can write the above microscopic model in the
equivalent weak form:
\begin{equation}
\begin{gathered}
{D_{f}\int_{\Omega ^{\varepsilon }}\nabla
u^{\varepsilon }\cdot \nabla \varphi dx+D_{p}\int_{\Pi
^{\varepsilon }}\nabla v^{\varepsilon }\cdot \nabla \varphi
dx+a\int_{\Pi ^{\varepsilon }}g(v^{\varepsilon })\varphi dx} \\
={\int_{\Omega ^{\varepsilon }}f\varphi dx}\quad
\forall \varphi \in H^{1}(\Omega ),  \varphi =0\quad
\text{on }\partial \Omega, \\
{D_{p}\int_{\Pi ^{\varepsilon }}\nabla v^{\varepsilon
}\cdot \nabla \psi dx+a\int_{\Pi ^{\varepsilon }}g(v^{\varepsilon
})\psi dx=0}\quad \forall \psi \in H_{0}^{1}(\Pi ^{\varepsilon }), \\
u^{\varepsilon }=v^{\varepsilon }\quad \text{on }S^{\varepsilon }.
\end{gathered}
\end{equation}
Also, note that if we let
\[
\theta ^{\varepsilon }(x)=
\begin{cases}
u^{\varepsilon }(x)& x\in \Omega ^{\varepsilon }, \\
v^{\varepsilon }(x) & x\in \Pi ^{\varepsilon },
\end{cases}
\]
then (3.3) is a weak form of
\begin{gather*}
-D\Delta \theta ^{\varepsilon }=F\quad \text{in }\Omega, \\
\theta ^{\varepsilon }=0\quad \text{on }\partial \Omega ,
\end{gather*}
where
\begin{gather*}
D=\chi_{\Omega ^{\varepsilon }} D_{f}+(1-\chi _{\Omega
^{\varepsilon }} )D_{p},\\
F=\chi_{ \strut \Omega ^{\varepsilon }} f-(1-\chi_{ \strut \Omega
^{\varepsilon }})ag.
\end{gather*}
By classical existence results there is a unique solution $\theta
^{\varepsilon }\in H_{0}^{1}(\Omega )$ and, by restriction, we obtain $%
u^{\varepsilon }$ and $v^{\varepsilon }$ as required.

Let us introduce the matrix
\[
A=\begin{cases}
D_{f}Id & \text{in }Y\backslash T \\
D_{p}Id & \text{in }T.
\end{cases}
\]
The main result of this section is as follows:

\begin{theorem} \label{thm3.1}
One can construct an extension $P^{\varepsilon }u^{\varepsilon }$ of the
solution $u^{\varepsilon }$ of the variational problem (3.2) such that
$P^{\varepsilon }u^{\varepsilon }\rightharpoonup u$ weakly in
$H_{0}^{1}(\Omega )$, where $u$ is the unique solution of
\begin{equation}
\begin{gathered}
-{\sum_{i,j=1}^{n}a_{ij}^{0}}{\frac{
\partial ^{2}u}{\partial x_{i}\partial x_{j}}}+a{\frac{|
T|}{|Y^{*}|}}g(u)=f\quad \text{in }\Omega, \\
u=0\quad \text{on }\partial \Omega .
\end{gathered}
\end{equation}
Here, $A^{0}=((a_{ij}^{0}))$ is the homogenized matrix, whose
entries are
\begin{equation}
a_{ij}^{0}=\frac{1}{|Y|}\int_{Y}\big( a_{ij}+a_{ik}
\frac{\partial \chi_{j}}{\partial y_{k}}\big)dy,
\end{equation}
in terms of the functions $\chi _{i}$, $i=1,\dots ,n$,
solutions of the so-called cell problems
\begin{equation}
\begin{gathered}
-\mathop{\rm div}(AD(y_{j}+\chi _{j}))=0\quad \text{in }Y, \\
\chi_{j}\quad\mbox{is $Y$-periodic.}
\end{gathered}
\end{equation}
The constant matrix $A^{0}$ is symmetric and
positive-definite.
\end{theorem}

\subsection{A priori estimates}

Apart from the results given by Lemma \ref{lm2.1} and Lemma \ref{lm2.2}, we recall the
following well-known result (see, for instance, \cite{Hornung-Jager} and
\cite{Monsurro}).

\begin{lemma} \label{lm3.2}
There exists a positive constant $C$, independent of $\varepsilon $, such
that for all $v\in V^{\varepsilon }$,
\begin{equation}
\| v\|_{L^{2}(S^{\varepsilon })}^{2}\leq C(\varepsilon
^{-1}\| v\|_{L^{2}(\Omega ^{\varepsilon })}^{2}+\varepsilon
\| \nabla v\|_{L^{2}(\Omega ^{\varepsilon })}^{2})\,.
\end{equation}
\end{lemma}

Also, in the same spirit of \cite[lemma 6.1]{Conca}, we can
prove immediately the following result.

\begin{lemma} \label{lm3.3}
There exists a positive constant $C$, independent of $\varepsilon $, such
that for every $v\in H^{1}(\Pi ^{\varepsilon })$,
\begin{equation}
\| v\|_{L^{2}(\Pi ^{\varepsilon })}^{2}\leq C(\varepsilon
\| v\|_{L^{2}(S^{\varepsilon })}^{2}+\varepsilon ^{2}\|
\nabla v\|_{L^{2}(\Pi ^{\varepsilon })}^{2})\,.
\end{equation}
\end{lemma}

To describe the effective behavior of $u^{\varepsilon}$ and
$v^{\varepsilon}$, as $\varepsilon \rightarrow 0$, we need to prove some a
priori estimates for them.

\begin{proposition}
Let $u^{\varepsilon }$ and $v^{\varepsilon }$ be the solutions of the
problem (3.1). There exists a positive constant $C$, independent of
$\varepsilon $, such that
\begin{gather}
\| P^{\varepsilon }u^{\varepsilon }\|_{H_{0}^{1}(\Omega )}\leq C, \\
\| \widetilde{v^{\varepsilon }}\|_{L^{2}(\Omega )}\leq C, \\
\| \nabla w^{\varepsilon }\|_{L^{2}(\Omega ^{\varepsilon
})\times L^{2}(\Pi ^{\varepsilon })}\leq C, \\
\| P^{\varepsilon }u^{\varepsilon }-v^{\varepsilon }\|
_{L^{2}(\Pi ^{\varepsilon })}\leq C\varepsilon .
\end{gather}
\end{proposition}

\begin{proof} Let us take $(u^{\varepsilon },v^{\varepsilon })$ as a test
function in (3.2). Using the properties of $f$ and $g$, H\"{o}lder and
Poincar\'{e}'s inequalities, the first three estimates come immediately. In
order to get the fourth one, we shall make use of Lemma \ref{lm3.3}:
\begin{align*}
\| P^{\varepsilon }u^{\varepsilon }-v^{\varepsilon }\|_{L^{2}(\Pi ^{\varepsilon })}^{2}
&\leq C\big( \varepsilon \|
u^{\varepsilon }-v^{\varepsilon }\|_{L^{2}(S^{\varepsilon
})}^{2}+\varepsilon ^{2}\| \nabla (P^{\varepsilon }u^{\varepsilon
}-v^{\varepsilon })\|_{L^{2}(\Pi ^{\varepsilon })}^{2}\big) \\
&\leq C\varepsilon ^{2}\big( \| \nabla P^{\varepsilon }u^{\varepsilon
}\|_{L^{2}(\Omega )}+\| \nabla v^{\varepsilon }\|
_{L^{2}(\Pi ^{\varepsilon })}\big) ^{2}\\
&\leq C\varepsilon ^{2}\big( \| \nabla u^{\varepsilon }\|_{L^{2}
(\Omega ^{\varepsilon })}+\| \nabla v^{\varepsilon }\|_{L^{2}(\Pi ^{\varepsilon
})}\big) ^{2}\leq C\varepsilon ^{2},
\end{align*}
which completes the proof.
\end{proof}

\begin{corollary} \label{coro3.5}
If $u^{\varepsilon }$ and $v^{\varepsilon }$ are the solutions of (3.1), then,
passing to a subsequence, still denoted by $\varepsilon$, there exist
$u\in H_{0}^{1}(\Omega )$ and $v\in L^{2}(\Omega )$ such that
\begin{gather}
P^{\varepsilon }u^{\varepsilon }\rightharpoonup u\quad \text{weakly in }
H_{0}^{1}(\Omega ), \\
\widetilde{v^{\varepsilon }}\rightharpoonup v\quad \text{weakly in }
L^{2}(\Omega )
\end{gather}
and
\begin{equation}
v=\frac{|T|}{|Y|}u.
\end{equation}
\end{corollary}

\begin{proof} The convergence results (3.13)-(3.14) are direct
consequences of the estimates (3.9)-(3.10). To prove (3.15), let $\varphi
\in L^{2}(\Omega )$. We have
\[
\int_{\Omega }\widetilde{v^{\varepsilon }}\varphi dx=\int_{\Pi
^{\varepsilon }}v^{\varepsilon }\varphi dx=\int_{\Pi ^{\varepsilon
}}(v^{\varepsilon }-P^{\varepsilon }u^{\varepsilon })\varphi
dx+\int_{\Pi ^{\varepsilon }}P^{\varepsilon }u^{\varepsilon
}\varphi dx\quad \forall \varphi \in L^{2}(\Omega ).
\]
 From Proposition 3.4 we get
\[
| \int_{\Pi ^{\varepsilon }}(v^{\varepsilon }-P^{\varepsilon
}u^{\varepsilon })\varphi dx| \leq \| v^{\varepsilon
}-P^{\varepsilon }u^{\varepsilon }\|
_{L^{2}(\Pi^{\varepsilon} )}\| \varphi \|
_{L^{2}(\Omega )}\rightarrow 0.
\]
Hence, using (3.13) and the fact that $\chi _{\Pi ^{\varepsilon}}
\rightharpoonup |T|/|Y|$ weakly in $L^{2}(\Omega )$, we have
\[
\lim_{\varepsilon \rightarrow 0}\int_{\Omega }
\widetilde{v^{\varepsilon }}\varphi dx
=\lim_{\varepsilon \rightarrow 0}\int_{\Omega }\chi_{\Pi ^{\varepsilon }}
P^{\varepsilon}u^{\varepsilon }\varphi dx=\frac{|T|}{|Y|}
\int_{\Omega }u\varphi dx,
\]
which gives exactly (3.15).
\end{proof}

Finally, let us note that there exists a positive constant $C$, independent
of $\varepsilon $, such that
\[
\int_{\Omega }|\theta ^{\varepsilon }|^{2}dx\leq C
\quad\mbox{and}\quad
\int_{\Omega }|\nabla \theta ^{\varepsilon }|
^{2}dx\leq C\,.
\]
Hence, there exists $\theta \in H_{0}^{1}(\Omega )$ such that
$\theta ^{\varepsilon }\rightharpoonup \theta$ weakly in
$H_{0}^{1}(\Omega )$
and it is not difficult to see that $\theta =u$. This proves, in fact, the
following statement.

\begin{corollary}
Let $\theta^{\varepsilon}$ be defined by
\[
\theta ^{\varepsilon }(x)=
\begin{cases}
u^{\varepsilon }(x) & x\in \Omega ^{\varepsilon }, \\
v^{\varepsilon }(x) & x\in \Pi ^{\varepsilon }.
\end{cases}
\]
Then there exists $\theta \in H_{0}^{1}(\Omega)$ such that
$\theta^{\varepsilon}\rightharpoonup\theta$ weakly in $H_{0}^{1}(\Omega)$,
where $\theta$ is the unique solution of
\begin{gather*}
-{\sum_{i,j=1}^{n}a_{ij}^{0}}{\frac{\partial ^{2}\theta}{\partial x_{i}
\partial x_{j}}}+a{\frac{|T|}{|Y^{*}|}}g(\theta)=f\quad \text{in }\Omega,\\
\theta=0\quad \text{on }\partial \Omega,
\end{gather*}
and $A^{0}$ is given by (3.5)-(3.6), i.e. $\theta=u$, due to the
well-posedness of problem (3.4).
\end{corollary}

\subsection{Proof of Theorem \ref{thm3.1}}

Set
\[
\xi ^{\varepsilon }=(\xi _{1}^{\varepsilon },\xi _{2}^{\varepsilon
})=(D_{f}\nabla u^{\varepsilon },D_{p}\nabla v^{\varepsilon }).
\]
 From (3.11) it follows that there exists a positive constant $C$ such that
\[
\| \xi _{1}^{\varepsilon }\|_{L^{2}(\Omega ^{\varepsilon })}\leq C
\quad\mbox{and}\quad
\| \xi _{2}^{\varepsilon }\|_{L^{2}(\Pi ^{\varepsilon })}\leq C\,.
\]
If we denote by $\sim$ the zero extension to the whole of $\Omega $ of
functions defined on $\Omega ^{\varepsilon }$ or $\Pi ^{\varepsilon }$, we
see that $\widetilde{\xi _{1}^{\varepsilon }}$ and
$\widetilde{\xi_{2}^{\varepsilon }}$ are bounded in $(L^{2}(\Omega ))^{n}$
and hence there
exist $\xi _{1},\xi _{2}\in (L^{2}(\Omega ))^{n}$ such that
\begin{equation}
\widetilde{\xi _{i}^{\varepsilon }}\rightharpoonup \xi _{i}\quad \text{
weakly in }(L^{2}(\Omega ))^{n},\quad i=1,2.
\end{equation}
Let us see now which equation is satisfied by $\xi _{1}$ and $\xi _{2}$.
Let $\phi \in \mathcal{D}(\Omega )$. Taking $(\phi _{\mid \Omega
^{\varepsilon }},\phi _{\mid \Pi ^{\varepsilon }})$ as a test function in
(3.2) we get
\begin{equation}
\int_{\Omega }\widetilde{\xi _{1}^{\varepsilon }}\cdot \nabla \phi
dx+\int_{\Omega }\widetilde{\xi _{2}^{\varepsilon }}\cdot \nabla
\phi dx+a\int_{S^{\varepsilon }}g(v^{\varepsilon })\phi d\sigma
=\int_{\Omega }\chi _{\Omega ^{\varepsilon }} f\phi dx.
\end{equation}
Now, we can pass to the limit, with $\varepsilon \rightarrow 0$, in all the
terms of (3.17). For the first two, we have
\begin{equation}
\lim_{\varepsilon \rightarrow 0}\int_{\Omega }\widetilde{\xi
_{1}^{\varepsilon }}\cdot \nabla \phi dx=\int_{\Omega }\xi
_{1}\cdot \nabla \phi dx
\end{equation}
and
\begin{equation}
\lim_{\varepsilon \rightarrow 0}\int_{\Omega }\widetilde{\xi
_{2}^{\varepsilon }}\cdot \nabla \phi dx=\int_{\Omega }\xi
_{2}\cdot \nabla \phi dx.
\end{equation}

In order to pass to the limit in the third term, let us notice that, exactly
like in Section 2.2, using Theorem \ref{thm2.4}, we can easily prove that for any $%
\phi \in \mathcal{D}(\Omega )$ and for any $z^{\varepsilon }\rightharpoonup z
$ weakly in $H_{0}^{1}(\Omega )$, we get
\[
\phi g(z^{\varepsilon })\rightharpoonup \phi g(z)\quad \text{strongly in }%
L^{\overline{q}}(\Omega ).
\]
In particular, we have
\begin{equation}
\phi g(\theta ^{\varepsilon })\rightharpoonup \phi g(\theta )\quad
\text{strongly in }L^{\overline{q}}(\Omega ).
\end{equation}
Now, let us write $a\int_{\Pi ^{\varepsilon }}g(v^{\varepsilon
})\phi d\sigma $ in the following form
\begin{equation}
a\int_{\Pi ^{\varepsilon }}g(v^{\varepsilon })\phi d\sigma
=a\int_{\Pi ^{\varepsilon }}g(\theta ^{\varepsilon })\phi d\sigma
=a\int_{\Omega }g(\theta ^{\varepsilon })\phi d\sigma
-a\int_{\Omega ^{\varepsilon }}g(\theta ^{\varepsilon })\phi
d\sigma.
\end{equation}
Obviously
\begin{equation}
\lim_{\varepsilon \rightarrow 0}a\int_{\Omega }g(\theta
^{\varepsilon })\phi d\sigma =a\int_{\Omega }g(\theta )\phi
dx=a\int_{\Omega }g(u)\phi dx.
\end{equation}
On the other hand, we know that $\chi_{\Omega ^{\varepsilon
}}\rightharpoonup |Y^{*}|/|Y|$ weakly in any $L^{\sigma }(\Omega )$ with
$\sigma \geq 1$. In particular, defining $q^{*}$ such that
\[
\frac{1}{\overline{q}}+\frac{1}{q^{*}}=1,
\]
we see that $q^{*}\geq 1$ and, consequently,
\begin{equation}
\chi_{\Omega ^{\varepsilon }}\rightharpoonup \frac{|
Y^{*}|}{|Y|}\quad \text{weakly in
}L^{q^{*}}(\Omega ).
\end{equation}
Hence, from (3.20)-(3.23), we obtain
\begin{equation}
\lim_{\varepsilon \rightarrow 0}a\int_{\Pi ^{\varepsilon
}}g(v^{\varepsilon })\phi d\sigma =a\frac{|T|}{|Y|}%
\int_{\Omega }g(u)\phi dx.
\end{equation}
It is not difficult to pass to the limit in the right-hand side of (3.17).
Since
\[
\chi_{\Omega ^{\varepsilon }} f\rightharpoonup \frac{|
Y^{*}|}{|Y|}f\quad \text{weakly in }L^{2}(\Omega ),
\]
we obtain
\begin{equation}
\lim_{\varepsilon \rightarrow 0}\int_{\Omega }\chi_{\Omega
^{\varepsilon } } f\phi dx=\frac{|Y^{*}|}{|Y|}%
\int_{\Omega }f\phi dx.
\end{equation}
Putting together (3.18), (3.19), (3.24) and (3.25), we have
\[
\int_{\Omega }\xi _{1}\cdot \nabla \phi dx+\int_{\Omega }\xi
_{2}\cdot \nabla \phi dx+a\frac{|T|}{|Y|}%
\int_{\Omega }g(u)\phi dx=\frac{|Y^{*}|}{|
Y|}\int_{\Omega }f\phi dx\quad \forall \phi \in
\mathcal{D}(\Omega ).
\]
Hence
\begin{equation}
-\mathop{\rm div}(\xi _{1}+\xi _{2})+a\frac{|T|}{|Y|}%
g(u)=\frac{|Y^{*}|}{|Y|}f\quad \text{in }\Omega .
\end{equation}
It remains now to identify $\xi _{1}+\xi _{2}$. Introducing the auxiliary
periodic problem (3.6) and following the same classical procedure like in
the last step of the proof of Theorem \ref{thm2.3}, one easily gets
\begin{equation}
\xi _{1}+\xi _{2}=A^{0}\nabla u.
\end{equation}
Since $u\in H_{0}^{1}(\Omega )$ (i.e. $u=0$ on $\partial \Omega $) and $u$
is uniquely determined, the whole sequence $P^{\varepsilon }u^{\varepsilon }$
converges to $u$ and Theorem \ref{thm3.1} is proved.
%\end{proof}

\begin{remark} \label{rmk3.7} \rm
In (3.1) we took the ratio of our diffusion coefficients to be of order one
just for a better comparison between the two situations we intended to deal
with: the case in which the chemical reactions take place on the boundary of
the grains and the case in which the chemical reactions occur inside them.
However, a much more interesting problem would arise if we consider
different orders for the diffusion in the "obstacles" and in the ``pores".
More precisely, if one takes the ratio of the diffusion coefficients to be
of order $\varepsilon^{2}$, then the limit model will be the so-called
\emph{double-porosity model}. This scaling preserves the physics of the
flow inside the grains, as $\varepsilon \rightarrow 0$. The less permeable
part of our medium (the grains) contributes in the limit as a nonlinear
memory term. In fact, the effective limit model includes two equations, one
in $T$ and another one in $\Omega$, the last one containing an extra-term
which reflects the remaining influence of the grains (see, for instance,
\cite{Arbogast-Douglas-Hornung}, \cite{Bourgeat2}, \cite%
{Bourgeat-Luckhaus-Mikelic}, \cite{Conca-Diaz-Timofte}, \cite{Hornung-Jager}).
\end{remark}

\begin{remark} \label{rmk3.8} \rm
As in Section 2, $g$ does not need to be Lipschitz continuous (as it is the
case, for instance, of the second example or the multivalued example of
Remark \ref{rmk2.8}) and so, again, the solution of the homogenized problem may give
rise to a ``dead zone''  (where $u(x)=0$)
(see D\'{\i}az \cite{Diaz3}). As a matter of fact, some
``dead zone'' may be formed, this time, at
the level of the microscopic problems, since the equation satisfied by
function $v^{\varepsilon }$ leads to such type of behaviors when $g$ is not
Lipschitz continuous and a suitable balance between the data and the spatial
domain is satisfied (see D\'{\i}az \cite{Diaz3}). It is quite
surprising that the macroscopic balance on the data and domain necessary for
the formation of ``macroscopic dead zone''
may take place by passing to the limit in the microscopic system
independently if the microscopic condition for the formation of the
``microscopic dead zone''  holds or not.
\end{remark}


\subsection*{Acknowledgments.} This work has been partially supported
by Fondap through its Programme on Mathematical Mechanics. The first author
gratefully acknowledges the Chilean and French Governments through the
Scientific Committee Ecos-Conicyt. The research of J.I. D\'{\i}az was
partially supported by project REN2003-0223-C03 of the DGISGPI (Spain). J.I.
D\'{\i}az and A. Li\~{n}\'{a}n are members of the RTN HPRN-CT-2002-00274 of
the EC. The work of the fourth author is part of the European Research
Training Network HMS 2000, under contract HPRN-2000-00109. Also, the fourth
author wishes to thank Centro de Modelamiento Matem\'{a}tico de la
Universidad de Chile for the warm hospitality and support.

The authors are grateful to the anonymous referee for his/her valuable
comments and suggestions and for bringing to their attention the reference
\cite{Hornung-Jager-Mikelic}.


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\end{thebibliography}



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