
\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
{\em Electronic Journal of Differential Equations},
Vol. 2005(2005), No. 75, pp. 1--9.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu  (login: ftp)}
\thanks{\copyright 2005 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}

\title[\hfilneg EJDE-2005/75\hfil 
Controllability of integrodifferential equations]
{Controllability of semilinear integrodifferential equations with nonlocal
conditions} 

\author[R. Atmania, S. Mazouzi\hfil EJDE-2005/75\hfilneg]
{Rahima Atmania, Said Mazouzi}  % in alphabetical order


\address{Rahima Atmania \hfill \break 
Department of Mathematics, University of Annaba\\
P. O. Box 12, Annaba 23000, Algeria}

\address{Said Mazouzi \hfill \break 
Department of Mathematics, University of Annaba\\
P. O. Box 12, Annaba 23000, Algeria}
\email{mazouzi.s@voila.fr}


\date{}
\thanks{Submitted April 06, 2005. Published July 8, 2005.}
\subjclass[2000]{34A10, 35A05}
\keywords{Controllability; nonlocal condition; fixed-point theorem; semigroup}

\begin{abstract}
 We establish sufficient conditions for the controllability of  
 some semilinear integrodifferential systems with nonlocal  
 condition in a Banach space. The results are obtained  
 using the Schaefer fixed-point theorem and semigroup theory.
\end{abstract}

\maketitle

\numberwithin{equation}{section} 
\newtheorem{theorem}{Theorem}[section]

\section{Introduction}

The first step in the study of the problem of controllability is to
determine if an objective can be reached by some suitable control function
The problem of controllability happens when a system described by a state 
$x( t) $ is controlled by a given law such as a differential equation 
$x'=G( t,x( t) ,u( t) )$. We discuss the possibility of driving a
solution of a given system from an initial state to a final state by an
adequate choice of the control function $u$.

Several authors have studied the problem of controllability of linear
semilinear and nonlinear systems of ordinary differential equations in
finite or infinite dimensional Banach spaces with bounded operators. For
instance, Naito \cite{n1} studied the controllability of semilinear systems,
Yamamoto and Park \cite{p1} discussed this problem for a parabolic equation
with uniformly bounded nonlinear terms, Chukwu and Lenhart \cite{c1} studied
the controllability of nonlinear systems in abstract spaces, Zhou \cite{z1}
discussed the approximate controllability for a class of semilinear abstract
equations, Naito \cite{n2} established the controllability for nonlinear
Volterra integrodifferential systems. Finally, Balachandran and Sakhtivel 
\cite{b1,b2} studied the controllability of functional semilinear
integrodifferential systems in Banach spaces.

In this paper, we study the controllability of some semilinear
integrodifferential system subject to nonlocal condition in Banach space
whose mild solution has been proved by Mazouzi and Tatar \cite{m1} by using
Schaefer fixed-point theorem \cite{d1}.

\section{Preliminaries}

Consider the following functional semilinear integrodifferential system
subject to a nonlocal condition: 
\begin{equation}  \label{e1}
\begin{gathered} \begin{aligned} x'( t)&=Ax( t) +Bu( t) \\ 
&\quad +F\Big(
t,x(\delta _{1}(t)),\int_0^{t}g\Big( t,s,x( \delta _{2}( s) ) ,\int_0^{s}k(
s,\tau ,x(\delta _{3}( \tau ) ) ) d\tau \Big) ds\Big) \end{aligned}\\ 
x( 0) +h( t_{1},\dots ,t_{p},x( .) ) =x_0, \\ 
0<t_{1}<t_{2}\dots <t_{p}\leq b,\quad t\in I=[ 0,b] . 
\end{gathered}
\end{equation}
The expression $h( t_{1},\dots ,t_{p},x( .) ) $ indicates that the function 
$x$ is valued only on the set $\{t_{1},t_{2}\dots ,t_{p}\} $. Actually, the
nonlocal condition has a better effect on the solution and is more precise
for physical measurements than the classical condition $x(0) =x_0$ alone.
The control function $u$ is given in the Banach space of admissible control
functions $\mathbb{L}^{2}( I,U) $, $U$ being a Banach space. $A$ is the
infinitesimal generator of a strongly continuous\ semigroup of bounded
linear operators $T(t)$, $t\geq 0$ in $X$, $B$ is a bounded linear operator
from $U$ into $X$. Furthermore, $F:I\times X\times X\to X$, $g:I\times
I\times X\times X\to X$, $k:I\times I\times X\to X$, $h:I^{p}\times X\to X$,
and $\delta _{i}\in C( I,I)$ are given functions such that $0\leq \delta
_{i}( t) \leq t$, $t\in I$ for $i=1,2,3$.

We need the following fixed-point theorem due to Schaefer \cite{d1}:

\begin{theorem}
\label{thm1} Let $E$ be a normed linear space. If $A:E\to E$ is a completely
continuous operator (that is, it is continuous and the image of any bounded
set is contained in a compact set), then either the subset $\{ x\in
E:x=\lambda Ax\text{ for some }\lambda \in ( 0,1)\} $ is unbounded or $A$
has a fixed point.
\end{theorem}

\noindent\textbf{Definition.}  The system \eqref{e1} is said to be
controllable on the interval $I$ if for every initial state $x( 0)$ and a
final state $x_{1}$ there exists a control $u\in \mathbb{L}^{2}( I,U) $ such
that the solution $x( t) $ of \eqref{e1} satisfies $x( b) =x_{1}$.

For this article, we set the following assumptions:

\begin{itemize}
\item[(H1)]  For each $t\in I$, $F( t,.,.) \in C( X\times X,X)$, and for
each $( x,y) \in X\times X$, $F( .,x,y)$ is strongly measurable

\item[(H2)]  There exist continuous functions $p$ and $q:I\to [ 0,+\infty [$, 
and $\alpha \geq 1 $ such that 
\[
\| F( t,x,y) \| \leq p( t) \| x\| ^{\alpha }+q( t) \| y\|, 
\]
for all $x,y\in X$ and $t\in I$.

\item[(H3)]  $g$ and $k$ are continuous functions such that 
\begin{gather*}
\| g( t,s,x,y) \| \leq m_{1}( t,s) \| x\| ^{\alpha -1}\varphi ( \| x\| )
+m_{2}( s) \| y\| ,\quad\mbox{for all } x,y\in X, \\
\| k( t,s,x) \| \leq m_{3}( t,s) \| x\| ^{\alpha -1}\varphi ( \| x\| ) ,
\quad \mbox{for all } t,s\in I,
\end{gather*}
where $\varphi :[ 0,+\infty [ \to ] 0,+\infty [ $ it is a continuous
nondecreasing function, $m_{1}:I\times I\to [0,+\infty [ $ is continuous and
differentiable almost everywhere with respect to the first variable, 
$m_{2}:I\to [ 0,+\infty [ $ is continuous, $m_{3}:I\times I\to [ 0,+\infty [ $
is continuous

\item[(H4)]  $T( t)$, $t\geq 0$ is a compact semigroup and there exist some
constants $M>1$ and $\omega \in \mathbb{R}^{+}$ such that $\| T( t) \| \leq
Me^{\omega t}$, $t\geq 0$.

\item[(H5)]  $h\in C( I,X)$, and there exists a constant $H>0$ such that $\|
h( t_{1},\dots t_{p},x) \| \leq H$, for $x\in B_{r}=\{ x\in X:\| x( t) \|
\leq r\}$. Moreover, there exists $H_{1}>0$ such that 
\[
\| h( t_{1},\dots t_{p},x_{1}( .) ) -h( t_{1},\dots t_{p},x_{2}( .) ) \|
\leq H_{1} \sup_{t\in I}\| x_{1}( t) -x_{2}( t) \| 
\]

\item[(H6)]  
\[
\int_0^{b}\widetilde{Q}( t) dt <\int_{a}^{+\infty} \frac{dz}{\varphi ( z)
+z^{\alpha }+z }, 
\]
where $\widetilde{Q}( t) =\max \{ \omega ,\omega MM_{1}M_{2},\omega Mp( t)
,\omega Mq( t) ,h( t)\}$ with 
\[
h( t) =\frac{1}{\alpha }m_{1}( t,t) +\frac{1}{ \alpha }\int_0^{t}\big| 
m_{2}( t) m_{3}( t,\tau ) +\frac{\partial m_{1}( t,\tau ) }{\partial t}\big| 
d\tau , 
\]
and $a^{\alpha }=M^{\alpha }( \| x_0\| +H) ^{\alpha }+N$, with 
\[
N=\Big( \| x_{1}\| +Me^{\omega b}( \| x_0\| +H) +M\int_0^{b}e^{\omega (
b-\tau ) }\| \phi (\tau ,x)\| d\tau \Big) . 
\]

\item[(H7)]  The linear operator $W:\mathbb{L}^{2}( I,U)\to X$ defined by 
\[
Wu=\int_0^{b}T( b-s) Bu( s) ds 
\]
has an invertible operator $W^{-1}$ which takes values in 
$\mathbb{L}^{2}(I,U) /\ker W$ and there exist positive constants 
$M_{1}$, $M_{2}>0$ such
that $\| B\| \leq M_{1}$ and $\| W^{-1}\| <M_{2}$.
\end{itemize}

\section{Main result}

Our main theorem is the following theorem:

\begin{theorem}
\label{thm2}  Under hypotheses (H1)--(H7) the system \eqref{e1} is
controllable on $I$.
\end{theorem}

\begin{proof}
Let us define the control function
\begin{equation}
u( t) =W^{-1}\Big( x_{1}-T( b) ( x_0-h( t_{1},\dots
t_{p},x( .) ) ) -\int_0^{b}T( b-s) \phi (s,x)ds\Big) ( t) . \label{e2}
\end{equation}
where
\[
\phi (t,x)=F\Big( t,x(\delta _{1}(t)),\int_0^{t}g( t,s,x( \delta _{2}(
s) ) ) ,\int_0^{s}k( s,\tau ,x( \delta _{3}( \tau ) ) ) d\tau ds\Big)
\]
We shall show that with this control the solution  $x( t)$ of system
\eqref{e1} satisfies $x( b) =x_{1}$.
Indeed, we apply Schaefer theorem to show that the operator
$\Phi :V\to V$, with $V=C( I,X) $, defined by
\[
( \Phi x) ( t) =T( t) ( x_0-h( t_{1},\dots t_{p},x) )
+\int_0^{t}T(t-s) Bu( s) ds \\
+\int_0^{t}T( t-s) \phi ( s,x) ds
\]
has a fixed point which is a solution of \eqref{e1}. We
observe that $( \Phi x) ( b) =x_{1}$ which means that $u$ steers
the integrodifferential system from $x_0$ to $x_{1}$ in time $b$.

We consider the parametrized problem with a parameter $\lambda \in
( 0,1) $ such that
\begin{equation}
\begin{gathered}
x'( t) =Ax( t) +\lambda Bu( t) +\lambda \phi ( t,x) ,\quad
0\leq t\leq b \\
x( 0) +\lambda h( t_{1},\dots t_{p},x( .) ) =\lambda x_0,
\end{gathered} \label{e3}
\end{equation}
and we show that the solution to this equation is bounded.
First, it is not hard to see that system \eqref{e3} has a mild solution
 satisfying the integral equation
\begin{equation} \label{e4}
\begin{aligned}
x( t) &=\lambda T( t) ( x_0-h( t_{1},\dots t_{p},x( .) ) )
+\lambda \int_0^{t}T( t-s) Bu( s) ds   \\
&\quad +\lambda \int_0^{t}T( t-s) \phi ( s,x) ds.
\end{aligned}
\end{equation}
It follows that
\begin{align*}
\| x( t) \|
&\leq M.e^{\omega t}( \| x_0\| +H) +Me^{\omega
t}\int_0^{t}e^{-\omega s}\Big[ p( s) \| x( \delta _{1}( s) ) \| ^{\alpha }\\
&\quad +q( s) \int_0^{s}m_{1}( s,\theta
) \| x( \delta _{2}( s) ) \| ^{\alpha -1}\varphi ( x( \delta _{2}(
\theta ) ) ) \\
&\quad + m_{2}( \theta )
\int_0^{\theta }m_{3}( \theta ,\tau ) \| x( \delta _{3}( \theta )
) \| ^{\alpha -1}\varphi ( \| x( \delta _{3}( \theta ) ) \| )
d\tau d\theta \Big] ds \\
&\quad +MM_{1}M_{2}N.e^{\omega t}\int_0^{t}e^{-\omega s}ds.
\end{align*}
Denote the right hand side of the above inequality by
$e^{\omega t}z( t) $, then
\[
{\rm \ \ }\| x( t) \| \leq e^{\omega t}z( t) ,\quad 0\leq t\leq b.
\]
In particular, we have $z( 0) =M( \| x_0\| +H) $.
Differentiating $z( t) $ we obtain
\begin{align*}
z'( t)&=Me^{-\omega t}
\Big[ p( t) \| x( \delta _{1}( t) ) \|
^{\alpha }+q( t) \int_0^{t}(m_{1}( t,\theta ) \| x( \delta _{2}(
\theta ) ) \| ^{\alpha -1} \varphi ( \| x( \delta _{2}(\theta ) ) \| ) \\
&\quad +m_{2}( \theta ) \int_0^{\theta
}m_{3}( \theta ,\tau ) \| x( \delta _{3}( \tau ) ) \| ^{\alpha
-1}\varphi ( \| x( \delta _{3}( \theta ) ) \| ) d\tau )d\theta
+M_{1}M_{2}N\Big].
\end{align*}
Since $0\leq \delta _{i}( t) \leq t$, for
$i=1,2,3$  and $z( t) $ is nondecreasing, it follows that
\begin{align*}
&z'( t) \\
&\leq Me^{-\omega t}\Big[ p( t) e^{\alpha \omega t}z^{\alpha
}( t) +q( t) \int_0^{t}(m_{1}( t,\theta ) e^{( \alpha -1) \omega
\theta }z^{\alpha -1}\varphi ( e^{\omega \theta }z( \theta ) )
\\
&\quad +m_{2}( \theta ) \int_0^{\theta }m_{3}( \theta ,\tau ) e^{(
\alpha -1) \omega \tau }z^{\alpha -1}( \tau ) \varphi ( e^{\alpha
\omega t}z( \tau ) ) d\tau )d\theta +M_{1}M_{2}N\Big] .
\end{align*}
Setting $Q( t) =\max ( p( t) ,q( t) ,M_{1}M_{2})$ and
\begin{align*}
v^{\alpha }( t) &= e^{\alpha \omega t}z^{\alpha }( t)
+\int_0^{t} (m_{1}( t,\theta ) e^{( \alpha -1) \omega \theta}
z^{\alpha -1}\varphi ( e^{\omega \theta}z( \theta ) ) \\
&\quad + m_{2}( \theta ) \int_0^{\theta } m_{3}( \theta ,\tau )
e^{(\alpha -1) \omega \tau } z^{\alpha -1}( \tau ) \varphi
( e^{\alpha \omega t}z( \tau ) ) d\tau )d\theta +N,
\end{align*}
we obtain
\[
z'( t) \leq Me^{-\omega t} Q( t) v^{\alpha }( t) ,\quad
v^{\alpha }( 0) =z^{\alpha }( 0) +N, \quad
v^{\alpha }( t) \geq e^{\alpha \omega t}z^{\alpha }( t) ,
\]
so that $v( t) \geq \ e^{\omega t}z( t) $.
Differentiating  $v^{\alpha }( t) $ we obtain, after a few
calculations,
\[
\ v'( t) \leq \omega v( t) +\omega M.Q( t) v^{\alpha }+h( t) \
\varphi ( v( t) ) .
\]
Therefore,
\[
v'( t) \leq \widetilde{\text{ }Q}( t) ( \varphi ( v) +v^{\alpha
}+v) .
\]
Integrating between $0$ and $t$, we obtain
\[
\int_{a}^{v( t) }\frac{dz}{\varphi ( z) +z^{\alpha }+z}
\leq \int_0^{b}\widetilde{Q} ( t) dt <
\int_{a}^{\infty }\frac{dz }{\varphi ( z) +z^{\alpha }+z}.
\]
 Hence there exists a constant $c>0$ such that $v( t) \leq c$, for
 every $t\in I$. Consequently, $\| x( t) \| \leq c$ for every $t\in I$.

In what follows we prove that the operator $\Phi $ is completely continuous.
If $y( t) \in V:\| y( t) \| \leq r$,  for $r>0$, then
\begin{align*}
&\big\| F\Big( t,y( t) ,\int_0^{t}g\Big( t,\theta ,y( \theta )
,\int_0^{\theta }k( \theta ,\tau
,y( \tau ) ) d\tau \Big) d\theta \Big) \big\| \\
&\leq p( t) \| y( t) \| ^{\alpha }+\ q( t)
\int_0^{t}m_{1}( t,\theta ) \| y( \theta ) \| ^{\alpha -1}\varphi
( \| y( \theta ) \| ) \\
&\quad +\ m_{2}( \theta )
\int_0^{\theta }m_{3}( \theta ,\tau ) \| y( \tau ) \| ^{\alpha
-1}\varphi ( \| y( \tau ) \| ) d\tau \,d\theta \\
&\leq p( t) r^{\alpha }+q( t) r^{\alpha
-1}\varphi ( r) \int_0^{t}( m_{1}( t,\theta ) +m_{2}( \theta )
\int_0^{\theta }m_{3}( \theta ,\tau ) d\tau )\, d\theta .
\end{align*}
We denote the last term of the latter inequality by $F_{r}( t) $.
It is obvious that for each $r>0$, $F_{r}$ is summable over $I$.

Consider a sequence  $( x_{n}) _{n\geq 1}\subset V$
converging to $\widehat{x}\in V$, then $( x_{n}) _{n\geq 1}( t) $
and $\widehat{x}( t) $ must be contained in some closed ball
$B(0,r) \subset X$, for all $t\in I$.
It follows from hypotheses (H1) and (H2) that
\[
\lim_{n\to \infty } \phi ( t,x_{n})
=\phi ( t,\widehat{x}) \quad\text{and}\quad
\| \phi ( t,x_{n}) -\phi (t,\widehat{x}) \| \leq 2F_{r}( t) .
\]
We conclude by\ the dominated convergence theorem that
\[
\int_0^{b}\| \phi ( s,x_{n}) -\phi ( s, \widehat{x}) \|
ds\to 0,\quad  \text{when }n\to \infty .
\]
Define  the sequence $\{ u_{n}\}_{n\geq 1}$ as follows
\[
u_{n}( t) =W^{-1}\Big( x_{1}-T( b) ( x_0-h( t_{1},t_{2},\dots
,t_{p},x_{n}) ) -\int_0^{b}T( b-s) \phi ( s,x_{n}) ds\Big) ( t).
\]
Then
\begin{align*}
&\| Bu_{n}( s) -Bu( s) \|\\
&\leq \| BW^{-1}\| \Big[ \| T( b) ( h(
t_{1},t_{2},\dots ,t_{p},x_{n}) -h( t_{1},t_{2},\dots
,t_{p},\widehat{x} ) ) \|  \\
&\quad + \| \int_0^{b}T( b-s) ( \phi ( s,x_{n}) -\phi (
s,\widehat{x}) ) ds\| \Big]\\
&\leq MM_{1}M_{2}e^{\omega b} \Big(H_{1}\sup_{t\in I}\|x_{n}
-\widehat{x}\| +\int_0^{b}e^{-\omega s}\| \phi ( s,x_{n})
-\phi ( s,\widehat{x}) \| ds\Big) \to 0,
\end{align*}
as $n\to \infty $. We infer that
\begin{align*}
\| \Phi x_{n}-\Phi \widehat{x}\|
& \leq \sup_{t\in I}\| T( t) ( h( t_{1},t_{2},\dots ,t_{p},x_{n})
-h(t_{1},t_{2},\dots ,t_{p},\widehat{x}) ) \|\\
&\quad +\sup_{t\in I} \| \int_0^{t}T( t-s) [ ( \phi (
s,x_{n}) -\phi ( s,\widehat{x}) ) +( Bu_{n}( s) -Bu( s) ) ]
ds\|  \\
&\leq MH_{1}e^{\omega t}\sup_{t\in I}\| x_{n}(t) -\widehat{x}( t) \| \\
&\quad + Me^{\omega b}\Big[ \int_0^{b}( \| \phi ( s,x_{n}) -\phi (
s,\widehat{x}) \| +\| Bu_{n}( s) -Bu( s) \| ) ds\Big] \to
0\,,
\end{align*}
as $n\to \infty $. This shows that $\Phi $ is continuous.

For every positive real number $r$ we set $B_{r,V}=\{ x\in
V:\| x( t) \| \leq r\} $.  To show that $\Phi (B_{r,V}) $  is precompact
 in $V$ we only have to check the
precompactness  of $\Phi ( B_{r,V}) ( t) $ in $V$, for
each $t\in I$, according to Arzela -Ascoli theorem. Let $t$ be
fixed in $] 0,b] $ and $n\in \mathbb{N}^{*}:\frac{1}{n}<t$.
For every $x\in B_{r,V}$ we have
\begin{equation} \label{e5}
\begin{aligned}
( \Phi x) ( t)
&=T( t) (x_0-h( t_{1},\dots t_{p},x) )+T( \frac{1}{n}) \int_0^{t-
 \frac{1}{n}}T( t-s-\frac{1}{n})  \\
&\times ( Bu( s) +\phi ( s,x) ) ds+\int_{t-\frac{1}{n}}^{t}T(
t-s) ( Bu( s) +\phi ( s,x) ) ds.
\end{aligned}
\end{equation}
We set
\[
( T_{n}x) ( t) =\int_{t-\frac{ 1}{n}}^{t}T( t-s)
( Bu( s) +\phi ( s,x) ) ds.
\]
 For every $\epsilon >0$,
there exists $n_0\in \mathbb{N}^{*}$ such that for every
$n\geq n_0$, and $x\in B_{r,V}$, we have
\[
\| ( T_{n}x) ( t) \| \leq \int_{t-\frac{1}{n}}^{t}\| T( t-s)
\| ( M_{1}M_{2}\tilde{N}+F_{r}( s) ) ds < \epsilon \,,
\]
where
\[
\tilde{N}=\Big( \| x_{1}\| +Me^{\omega b}( \| x_0\| +H)
+M\int_0^{b}e^{\omega ( b-\tau ) }F_{r}( \tau ) d\tau \Big) .
\]
Next, we define
\begin{align*}
&( S_{n}( x) ) ( t)\\
& =T( t) ( x_0-h( t_{1},\dots t_{p},x) ) +T( \frac{1}{n})
\int_0^{t-\frac{1}{n}}T( t-s-\frac{1}{n}) ( Bu( s) +\phi ( s,x)
) ds\,.
\end{align*}
Following the steps of the proof of the main theorem
in \cite{m1} we can show that $\Phi ( B_{r,V}) ( t) $ is compact and
consequently the operator $\Phi $ is completely
continuous. Therefore, $\Phi $ has a fixed point in
$V=C(I,X) $ which is the expected mild solution we are seeking and
accordingly the system is controllable on $I$.
\end{proof}

\section{Example}

Consider the problem 
\begin{equation}  \label{e6}
\begin{gathered} \begin{aligned} z_{t}( t,y) &=z_{yy}( t,y) +u( t,y) +
\frac{z^{2}( t,y) \sin ( z( t,y) ) }{ ( 1+t) ( 1+t^{2}) } \\ &\quad
+\int_0^{t}\Big[ \frac{z( s,y) }{( 1+t)( 1+t^{2}) ^{2}( 1+s) ^{2}}\\ &\quad
+\frac{1}{( 1+t) ( 1+t^{2}) } \int_0^{s}\frac{z( \tau,y) }{( 1+s) (1+\tau )
}\exp z( \tau ,y) d\tau \Big] ds \end{aligned} \\[3pt] z( t,0) = z( t,1) =0,
\quad t\in I=[0,1] \\ z( 0,y) -\sum_{i=1}^p t_{i}z( t_{i},y) =z_0( y) ,
\quad 0<y<1,\; 0< t_{1}<t_{2}<\dots <t_{p}\leq 1. \end{gathered}
\end{equation}

Let $X$ denote the Banach space $\mathbb{L}^{2}( I) $, $z(t,y)=x(t)(y)$ and 
$u\in \mathbb{L}^{2}( I,X) $ be the control function. Let 
\[
h( t_{1},t_{2},\dots ,t_{p},x( .) ) = \sum_{i=1}^p t_{i}x( t_{i}) . 
\]
We can easily check that there exists $H>0$ such that $|h( t_{1},t_{2},\dots
,t_{p},x( .) )| <H$; for instance, we may take $H=pt_{p}r$, if $\| x( t) \|
\leq r$. On the other hand, we have 
\[
\| h( t_{1},t_{2},\dots ,t_{p},x_{1}( .) ) -h( t_{1},t_{2},\dots
,t_{p},x_{2}( .) ) \| <pt_{p}\| x_{1}( t) -x_{2}( t) \| . 
\]
Moreover, since 
\begin{align*}
&F\big( t,x( t) ,\int_0^{t}g( t,s,x( s) ,\int_0^{s}k( s,\tau ,x(\tau ) ) d\tau )
ds\big) \\
&=\frac{x^{2}( t) \sin ( x( t) ) }{ ( 1+t) ( 1+t^{2})} \\
&\quad +\int_0^{t}\big[ \frac{ x( s) }{( 1+t) ( 1+t^{2}) ^{2}( 1+s)^{2}} +
\frac{1}{( 1+t) (1+t^{2}) }\int_0^{s}\frac{x( \tau ) }{( 1+s) ( 1+\tau ) }
\exp x(\tau ) d\tau \big] ds,
\end{align*}
we have 
\[
\| F( t,x,j) \| =\| \frac{ 1}{( 1+t) (1+t^{2}) }( x^{2}\sin x+j) \|  \leq 
\frac{1}{ ( 1+t^{2}) }\| x\| ^{2}+\frac{1}{( 1+t) } \| j\| , 
\]
where 
\[
j=\int_0^{t}g\Big( t,s,x( s) ,\int_0^{s}k( s,\tau ,x( \tau ) ) d\tau \Big) 
ds. 
\]
Next, if $h=\int_0^{s}k( s,\tau ,x( \tau ) ) d\tau $, then 
\begin{align*}
\| g( t,s,x,h) \|&=\| \frac{x}{ ( 1+t) ( 1+t^{2}) ^{2}( 1+s) ^{2}}+\frac{h }{
( 1+t) ( 1+t^{2}) }\| \\
& \leq \frac{1}{ ( 1+t^{2}) ( 1+s) }\| x\| +\frac{1}{( 1+t^{2}) ( 1+t) }\|
h\| .
\end{align*}
Finally, we have 
\[
\| k( s,\tau ,x) \| =\| \frac{xe^{x}}{(1+s) ( 1+\tau ) }\| \leq \frac{1}{(
1+s) ( 1+\tau ) }\| x\| \exp ( \| x\| ) . 
\]
Define the operator $A:D( A) \subset X\to X$ by $Av=v^{\prime\prime}$ with
domain 
\[
D( A) =\{ v\in X:v,v'\text{ absolutely continuous, }
v^{\prime\prime}\in X,\; v( 0) =v( 1) =0\} . 
\]
Note that $D( A) $ is dense in $X$ and $A$ is a closed operator. We conclude
by the Hille-Yosida theorem that $A$ is an infinitesimal generator of an
analytic semigroup $T( t)$, $t\geq 0$ which is also compact and satisfies
hypothesis (\textbf{H4}). Furthermore, 
\begin{gather*}
Av =\sum_{n=1}^{\infty }n^{2}( v,v_{n}) v_{n},\quad v\in D( A) \\
T( t) v=\sum_{n=1}^{\infty }\exp ( -n^{2}t) ( v,v_{n}) v_{n},\quad v\in X,
\end{gather*}
where $\lambda _{n}=n^{2}$, $n=1,2,\dots $ are the eigenvalues of $A,$ and 
$\{ v_{n}( s) =\sqrt{2}\sin ns\} _{n\geq 1}$ is the orthogonal set of
eigenfunctions of $A$.

Let $Bu:I\to X$ be defined by $Bu( t) ( y) =u( t,y)$, $y\in ( 0,1)$. Define
the linear operator $W$ by 
\[
Wu =\int_0^{1}T( 1-s) u( s) ds \newline
=\sum_{n=1}^{\infty }\int_0^{1}\exp [ -n^{2}( 1-s) ] ( u( s,y) ,v_{n})
v_{n}ds, 
\]
assuming that it has a bounded inverse operator $W^{-1}$ in $L^{2}( I,X)
/\ker W$ satisfying hypothesis (H7).

With this choice of $A$, $B$, $F$, and $h$, we observe that \eqref{e1} is an
abstract formulation of \eqref{e6}, and accordingly, system \eqref{e6} is
controllable on $I$ whose control function is 
\begin{align*}
u( t) &=W^{-1}\Big( x_{1}-T( 1) (x_0-\sum_{i=1}^p t_{i}x( t_{i}) ) \\
&\quad -\int_0^{1}T(1-s) \frac{1}{( 1+s) ( 1+s^{2}) } \Big[ z^{2}( s,y) \sin
(z( s,y) ) \\
&\quad +\int_0^{s}\Big( \frac{ z( \tau ,y) }{( 1+s^{2}) ( 1+\tau )^{2}}
+\int_0^{\tau }\frac{z( v,y) }{( 1+\tau ) ( 1+v) }e^{z( v,y) }dv\Big) d\tau 
\Big] ds\Big) ( t) .
\end{align*}

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\end{document}
