\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
{\em Electronic Journal of Differential Equations},
Vol. 2006(2006), No. 01, pp. 1--11.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu  (login: ftp)}
\thanks{\copyright 2006 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2006/01\hfil Continuous selections of solution sets]
{Continuous selections of solution sets to Volterra integral
inclusions in Banach spaces}
\author[S. Aizicovici, V. Staicu\hfil EJDE-2006/01\hfilneg]
{Sergiu Aizicovici, Vasile Staicu}  % in alphabetical order

\address{Sergiu Aizicovici\hfill\break
Department of Mathematics, Ohio University,
Athens, OH 45701, USA}
\email{aizicovi@math.ohiou.edu}

\address{Vasile Staicu \hfill\break
Department of Mathematics, Aveiro University,
3810-193 Aveiro, Portugal}
\email{vasile@ua.pt}

\date{}
\thanks{Submitted July 26, 2005. Published January 6, 2006.}
\subjclass[2000]{34G25, 45D05, 45N05, 47H06}
\keywords{Volterra integral equation;  m-accretive operator;
\hfill\break\indent integral solution; multivalued map}

\begin{abstract}
 We consider a  nonlinear Volterra integral equation governed by
 an m-accretive operator and a multivalued perturbation
 in a separable Banach. The existence of a continuous selection
 for the corresponding solution map is proved. The case when
 the m-accretive operator in the integral inclusion depends on
 time is also discussed.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{definition}[theorem]{Definition}
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{remark}[theorem]{Remark}

\section{Introduction}

In this paper we establish the existence of a continuous selection of the
solution set to the nonlinear Volterra integral inclusion
\begin{equation}
u(t)+\int_{0}^{t}a(t-s)[Au(s)
+F(s,u(s))]ds\ni\xi+g(t),\quad t\in I:=[0,T]\label{1.1}
\end{equation}
in a Banach space $X$. Here $A$ denotes an $m$-accretive operator in $X$,
$F:I\times X\to2^{X}\backslash\{\emptyset\}$ is a
multivalued perturbation, $a:I\to\mathbb{R}$, $\xi\in X$,
$g:I\to X$, and the integral is taken in the sense of Bochner. The
case when $A$ depends on time is also considered.

Existence and continuous dependence results for Volterra equations
of type \eqref{1.1} in infinite dimensional spaces were earlier
proved in \cite{Aiz-Pa1,Aiz-Pa2,Aiz-Di-Pa}. Continuous selection
theorems for semilinear abstract integrodifferential inclusions
have recently been obtained in \cite{An-Mu}. As compared to
\cite{Aiz-Pa1}, \cite{Aiz-Pa2}, we do not impose any compactness
restriction on the semigroup generated by $-A$ (respectively, on
the corresponding evolution operator, when $A$ is time-dependent),
and allow $X$ to be a general (non-reflexive) Banach space.

We note that in the special case when $a=1$ and $g=0$, equation
\eqref{1.1} reduces to
\begin{equation}
u'(t)+Au(t)+F(t,u(
t))\ni 0,\quad t\in I;u(0)=\xi. \label{1.2}
\end{equation}
The existence of continuous selections for the multivalued
solution map associated with $(\ref{1.2})$ was proved by Staicu
\cite{St} in a Hilbert space setting. The present work may be
viewed as a direct  attempt to extend the theory of \cite{St} to a
broader class of nonlinear inclusions in a general Banach space.

The plan of the paper is as follows. Section $2$ contains background material
on multifunctions, $m$-accretive operators and evolution equations. The main
results for equation \eqref{1.1} and its time dependent
counterpart are stated in Section $3$. The proofs are carried out in Section
$4$. Finally, in Section $5$ we present an example to which our abstract
theory applies.

\section{Preliminaries}

For further background and details pertaining to this section we
refer the reader to \cite{Au-Ce,Ba1,Cr-Paz,Hu-Pa1,Ka-Sh,Pav,Vr}.

Throughout this paper, $X$ stands for a real separable Banach
space with norm $\|\cdot \| $ and dual
$(X^{\ast},\|\cdot\|_{\ast})$. If $\Omega$ is a subset of $X$,
then the closure of $\Omega$ will be denoted by
$\overline{\Omega}$, or alternatively by $cl(\Omega)$.

Let $I=[0,T]$ and let $\mathcal{L}$ be the $\sigma-$algebra of all
Lebesgue measurable subsets of $I$. By $C(I,X)$ (resp.
$L^{1}(I,X)$) we denote the Banach space of all continuous (resp.
Bochner integrable) functions $u:I\to X$ equipped with the
standard norm $\|u\| _{\infty}=\sup_{t\in I}\| u(t)\| $ (resp.
$\|u\| _{1}=\int _{0}^{T}\|u(t)\| dt$). $W^{1,1}( I,X)$
designates the space of all absolutely continuous functions
$u:I\to X$ which can be written as
\[
u(t)=u(0)+\int_{0}^{t}v(s) ds,\quad t\in I,
\]
for some $v\in$ $L^{1}(I,X)$. We will also use $L^{1}(I)$, $AC(I)$
and $BV(I)$ to indicate the space of all Lebesgue integrable
functions, absolutely continuous functions, and respectively
functions with bounded variation from $I$ to $\mathbb{R}$. A
subset $K\subset$ $L^{1}(I,X)$ is called decomposable if for all
$u$, $v\in K$ and $A\in\mathcal{L}$ , one has that $u\chi_{A}
+v\chi_{I\backslash A}\in K$, where $\chi_{A}$ stands for the
characteristic function of $A$. The family of all nonempty, closed
and decomposable subsets of $L^{1}(I,X)$ is denoted by
$\mathcal{D}$.

The notation $2^{X}$ (resp. $\mathcal{P}(X))$ will designate
the collection of all (resp. all nonempty closed) subsets of $X$. The
Hausdorff distance on $\mathcal{P}(X)$ is defined by
\[
h(A,B)=\max\big\{\sup_{a\in A}d(a,B)
,\sup_{b\in B}d(b,A)\big\},\quad \forall A,B\in\mathcal{P}(
X),
\]
where $d(a,B)=\inf\{\|a-b\| :b\in B\}$. $\mathcal{B}(X)$ will
denote the $\sigma-$algebra of Borel subsets of $X$ and
$\mathcal{L\otimes B}(X)$ will stand for the $\sigma-$algebra on
$I\times X$ generated by all sets of the form $A\times B$ with
$A\in\mathcal{L}$ and $B\in\mathcal{B}(X) $.

Let $S$ be a separable metric space and let $\mathcal{A}$ denote a $\sigma
-$algebra of subsets of $S$. A multivalued map $G:S\to2^{X}
\backslash\{\emptyset\}$ is said to be $\mathcal{A}
$-\textit{measurable} if for each closed subset $C$ of $X$, the set $\{
s\in S:G(s)\cap C\neq\emptyset\}$ belongs to
$\mathcal{A}$.

A function $g:S\to X$ satisfying $g(s)\in G(s)$, for all $s\in S$,
is called a selection of $G$. The multivalued
map $G$ is said to be \textit{lower semicontinuous} (l. s. c.) if for every
closed set $C$ of $X$, the set
$\{s\in S:G(s)\subset C\}$ is closed in $S$.

The following two results of \cite{Ce-Fr-Rz-St} will play a key role
in the sequel.

\begin{proposition} \label{prop1}
Assume that $F^{\ast}:I\times S\to\mathcal{P}(X)$ is
$\mathcal{L\otimes B}(S)$ measurable and that
$F^{\ast}(t,.)$ is l.s.c. for each $t\in I$. Then the map
$\xi\to G_{F}(\xi)$ given by
\begin{equation}
G_{F}(\xi)=\{v\in L^{1}(I,X):v(
t)\in F^{\ast}(t,\xi),\text{ a.e. on }I\}
\label{2.1}
\end{equation}
is l.s.c. from $S$ into $\mathcal{D}$ if and only if there exists
a continuous map $\beta:S\to L^{1}(I)$, such that for every
$\xi\in S$
\begin{equation}
d(0,F^{\ast}(t,\xi))\leq\beta(\xi)
(t),\quad \text{a.e. on }I. \label{2.2}
\end{equation}
\end{proposition}

\begin{proposition} \label{prop2}
Let $G:S\to\mathcal{D}$ be a l.s.c. multifunction, and let
$\varphi:S\to L^{1}(I,X)$ and $\psi:S\to L^{1}(I)$ be
 continuous maps. Assume that for each $\xi\in S$,
the set
\begin{equation}
H(\xi)=cl\{v\in G(\xi):\| v(t)-\varphi(\xi)(t)\|
<\psi(\xi)(t),\text{ a.e. on }I\} \label{2.3}
\end{equation}
is nonempty. Then the map $\xi\to H(\xi)$ (with
$H(\xi)$ given by \eqref{2.3}, from $S$ into
$\mathcal{D}$, admits a continuous selection.
\end{proposition}

The remaining of this section is devoted to a brief discussion of accretive
operators and related evolution equations.

Let $A:X\to2^{X}$ be a set-valued operator in $X$ and let
\[
D(A):=\{x\in X:Ax\neq\mathbb{\emptyset}\},\quad
 \mathcal{R}(A):=\bigcup_{x\in D(A)}Ax
\]
be the \textit{domain} and \textit{range} of $A$, respectively. We say that
$A$ is an \textit{accretive operator} if
\[
\|x_{1}-x_{2}\| \leq\|x_{1}-x_{2}+\lambda( y_{1}-y_{2})\| ,\quad
\forall\lambda>0, \;\forall x_{i}\in D(A),
\;\forall y_{i}\in Ax_{i}\;(i=1,2).
\]
If in addition $R(Id+\lambda A)=X$ for all (equivalently, some)
$\lambda>0$, where $Id$ is the identity in $X$, then $A$ is said to be
\textit{$m$-accretive.}

The accretivity of $A$ is equivalent to the condition
\[
\langle y_{1}-y_{2},x_{1}-x_{2}\rangle _{s}\geq 0,\quad
\;\forall x_{i}\in D(A),
\forall y_{i}\in Ax_{i}(i=1,2),
\]
with $\langle .,.\rangle _{s}$ given by $\langle
y,x\rangle _{s}=\sup\{x^{\ast}(y):x^{\ast}\in J(x)\}$,
where $J:X\to2^{X^{\ast}}$ is the duality map defined by
\[
J(x)=\{x^{\ast}\in X^{\ast}:x^{\ast}(x)=\|x\| ^{2}=\|x^{\ast}\|
_{\ast}^{2}\}.
\]

Consider now the initial value problem
\begin{equation}
u'(t)+Au(t)\ni f(t),\quad t\in I;u(0)=\xi,
\label{2.4}
\end{equation}
where $A$ is m-accretive in $X$, $\xi\in\overline{D(A)}$ and
$f\in L^{1}(I,X)$, whose solutions are meant in the sense of
the following definition due to B\'{e}nilan \cite{Ben}.

\begin{definition} \label{def3} \rm
A function $u\in C(I,\overline{D(A)})$ is called
an \textit{integral solution} of the problem \eqref{2.4} if
$u(0)=\xi$ and the inequality
\[
\|u(t)-x\| ^{2}\leq\|u(s)-x\| ^{2} +2\int_{s}^{t}\langle
f(\tau)-y,u(\tau)-x\rangle _{s}d\tau
\]
holds for all $x$, $y\in X$, with $y\in Ax$, and all $0\leq s\leq t\leq T$.
\end{definition}

It is well-known that the problem \eqref{2.4} has a unique
integral solution for each $f\in L^{1}(I,X)$ and each $\xi
\in\overline{D(A)}$. The following property of integral
solutions will be used in Section 4.

\begin{proposition} \label{prop4}
Let $u$ and $v$ be integral solutions of \eqref{2.4} that
correspond to $(\xi,f)$ and $(\eta,g)$,
respectively (where $\xi$, $\eta\in\overline{D(A)}$ and $f$,
$g\in L^{1}(I,X))$. Then
\begin{equation}
\|u(t)-v(t)\| \leq\|\xi-\eta\| +\int_{0}^{t}\|f(\tau)-g( \tau)\|
d\tau\label{2.5}
\end{equation}
for all $t\in I$.
\end{proposition}

We note that Benilan's original definition of an integral solution
\cite{Ben}
required the operator $A$ to be merely accretive. The accretivity alone
doesn't generally guarantee the well-posedness of the problem
\eqref{2.4} and the validity of the inequality \eqref{2.5}.
If, however, $A$ is m-accretive, then problem
\eqref{2.4} has a unique integral solution, and
\eqref{2.5} holds.

Now let $\{A(t):t\in I\}$ be a family of
(possibly multivalued) operators on $X$, of domains $D(A(t)), $ with
$\overline{D(A(t))}=\overline{D}$ (independent of $t)$ which satisfy
the assumption

\begin{enumerate}
\item[(H1)]
\begin{enumerate}
\item[(i)] $R(Id+\lambda A(t))=X$, for all $\lambda>0$ and $t\in I$,

\item[(ii)] There exists a continuous function $m_{1}:I\to X$ and a
continuous nondecreasing function $m_{2}:\mathbb{R}_{+}\to\mathbb{R}_{+}$
($\mathbb{R}_{+}:=[0,\infty)$)
such that
\begin{align*}
&  \langle y_{1}-y_{2},x_{1}-x_{2}\rangle _{s}\\
&\geq -\|m_{1}(t)-m_{1}(s)\| \| x_{1}-x_{2}\| m_{2}(\max\{\|x_{1}\|
,\|x\| _{2}\}),
\end{align*}
for all $x_{1}\in D(A(t))$, $y_{1}\in A(t)x_{1}$,
$x_{2}\in D(A(s))$, $y_{2}\in A(s)x_{2}$, $0\leq s\leq t\leq T$.
\end{enumerate}
\end{enumerate}

We remark that (H1) implies that $A(t)$ is m-accretive for each $t\in I$.
 We consider the nonautonomous Cauchy problem
\begin{equation}
u'(t)+A(t)u(t)\ni
f(t),\quad t\in I;u(0)=\xi, \label{2.6}
\end{equation}
where $A(t)$ satisfy (H1),
$\xi\in\overline{D}$ and $f\in L^{1}(I,X)$.

\begin{definition} \label{def5} \rm
An integral solution of \eqref{2.6} is a function
$u\in C(I,\overline{D})$ such that $u(0)=\xi$ and the
inequality
\begin{align*}
\|u(t)-x\| ^{2} &  \leq\|u(s)-x\|
^{2}+2\int_{s}^{t}[\langle f(\tau)-y,u(\tau)-x\rangle _{s}\\
& \quad  +C\|u(\tau)-x\| \|m_{1}(\tau) -m_{1}(\theta)\| ]d\tau
\end{align*}
holds for all $0\leq s\leq t\leq T$, $\theta\in I$,
$x\in D(A(\theta))$, $y\in A(\theta)x$, and
$C=m_{2}(\max\{\|x\| ,\|u\|_{\infty}\})$, with $m_{1}$ and $m_{2}$
 as in (H1)(ii).
\end{definition}

Recall (cf., e.g., \cite{Pav}) that \eqref{2.6} has a unique
integral solution for each $\xi\in\overline{D}$ and
$f\in L^{1}(I,X)$, provided that (H1) is
satisfied. Moreover, the following analog of Proposition \ref{prop4} is true.

\begin{proposition} \label{prop6}
Let (H1) be satisfied and let $u$ and
$v$ be integral solutions of \eqref{2.6} corresponding to
$(\xi,f)$ and $(\eta,g)$, respectively (with
$\xi$, $\eta\in\overline{D}$ and $f$, $g\in L^{1}(I,X))$. Then
the inequality \eqref{2.5} holds for all $t\in I$.
\end{proposition}

\section{Main results}

We consider the Volterra integral inclusion \eqref{1.1} under
the following conditions:

\begin{enumerate}
\item[(H2)] $A$ is an m-accretive operator in $X$, with
domain $D(A)$, and there exists an open subset $U$ of $X$ such
that $U_{A}:=U\cap\overline{D(A)}$ is nonempty;

\item[(H3)] $a\in AC(I)$ with $a'\in BV(I)$ and $a(0)=1;$

\item[(H4)]

\begin{enumerate}
\item[(i)] $F:I\times X\to\mathcal{P}(X)$ is $\mathcal{L\otimes B}(X)$
 measurable,

\item[(ii)] There exists $k\in L^{1}(I,(0,\infty))$ such that
\[
h(F(t,x),F(t,y))\leq k( t)\|x-y\| ,\quad \forall x,\; y\in
X,\quad\mbox{a.e. on } I\,,
\]

\item[(iii)] There exists $\beta\in L^{1}(I,\mathbb{R}_{\mathbb{+}})$
such that
\[
d(0,F(t,0))\leq\beta(t),\quad \mbox{a.e.  on } I\,;
\]
\end{enumerate}

\item[(H5)] $g\in W^{1,1}(I,X)$ and $g(0)=0$.
\end{enumerate}

\begin{remark} \label{rmk7} \rm
The restriction $a(0)=1$ in (H3) is only
made for convenience. The essential condition is $a(0)>0$; see
\cite[p. 317]{Cr-No}.
\end{remark}

For each $\xi\in U_{A}$, we reduce the study of \eqref{1.1}
to that of the equivalent functional differential inclusion (cf.
\cite{Aiz-Pa1,Cr-No})
\begin{equation}
u'(t)+Au(t)+F(t,u(t))\ni\Gamma(u)(t),\quad t\in
I;\quad u(0)=\xi, \label{3.1}
\end{equation}
where $\Gamma:C\big(I,\overline{D(A)}\big)\to L^{1}(I,X)$ is defined by
\begin{gather}
\Gamma(u)(t)  =g'(t)
+\int_{0}^{t}r(t-s)g'(s)ds-r(0)u(t)+r(t)\xi
 -\int_{0}^{t}u(t-s)dr(s), \label{3.2}
\\
r(t)+\int_{0}^{t}a'(t-s)r(
s)ds=-a'(t). \label{3.3}
\end{gather}


Note that by  (H3), the function $r$ (as defined
in \eqref{3.3}) is a function with bounded variation.

\begin{definition} \label{def8} \rm
A function $u\in C(I,\overline{D(A)})$ is said
to be an integral solution of the equation \eqref{1.1}
(equivalently, \eqref{3.1}) if there exists
$\widehat{f}\in L^{1}(I,X)$ with
$\widehat{f}(t)\in F(t,u(t))$, $a$. $e$. on $I$, such that $u$ is an
integral solution, in the sense of Definition \ref{def3}, of the problem
\eqref{2.4} with $\Gamma(u)(t) -\widehat{f}(t)$ in place of $f(t)$.
\end{definition}

In the following, $\mathcal{S}(\xi)$ denotes the set of all
integral solutions of the equation \eqref{1.1}, which is
viewed as a subset of $C(I,\overline{D(A)})$,
for each $\xi\in U_{A}$.

\begin{theorem} \label{thm9}
Let assumptions (H2), (H3), (H4), (H5) be satisfied. Then there exists
$u:I\times U_{A}\to\overline{D(A)}$ such that:
\begin{gather}
u(.,\xi)\in\mathcal{S}(\xi),\quad \forall
\xi\in U_{A}, \label{3.4}
\\
\xi\to u(.,\xi)\text{ is continuous from }U_{A}\text{
into }C(I,\overline{D(A)}). \label{3.5}
\end{gather}
\end{theorem}

\begin{remark} \label{rmk10} \rm
(i) In the case when $a=1$, $g=0$ and $X$ is a Hilbert space
we recover \cite[Theorem 2.4]{St}.

\noindent (ii) A similar result can be derived for the Volterra
integral equation
\[
u(t)+\int_{0}^{t}a(t-s)[Au(
s)+F(s,u(s))]ds\ni g(
\xi)+\int_{0}^{t}p(s)ds,\quad t\in I,
\]
where $g:U_{A}\to X$ is continuous, $p\in L^{1}(I,X)$,
and conditions (H2), (H3) and (H4) are satisfied. For simplicity,
we have restricted our attention to equations of the form
\eqref{1.1}.
\end{remark}

Next, we are concerned with the time-dependent analog of $(
\ref{1.1})$, namely
\begin{equation}
u(t)+\int_{0}^{t}a(t-s)[A(
s)u(s)+F(s,u(s))]
ds\ni\xi+g(t),\quad t\in I, \label{3.6}
\end{equation}
where $\{A(t):t\in I\}$ is a family of
m-accretive operators in $X$ that satisfy assumption (H1), 
while $a$, $F$ and $g$ are subject to conditions
(H3), (H4) and (H5), respectively, and $\xi\in\overline{D}$. As in
\cite{Aiz-Di-Pa,Cr-No} we can replace \eqref{3.6} by an equivalent
functional differential equation of the form $(\ref{3.1})$
(with $A(t)$ in place of $A$), where
$\Gamma:C(I,\overline{D})\to L^{1}(I,X)$ is given by
\eqref{3.2}.

\begin{definition} \label{def11} \rm
A function $u\in C(I,\overline{D})$ is called an integral
solution of equation \eqref{3.6} if there exists
$\widehat{f}\in L^{1}(I,X)$ with
$\widehat{f}(t)\in F(t,u(t))$, $a$. $e$. on $I$, such that $u$ is
an integral solution, in the sense of Definition \ref{def5}, of the problem
\eqref{2.6} where $f(t)$ is replaced by
 $\Gamma(u)(t)-\widehat{f}(t)$.
\end{definition}

For each $\xi\in\overline{D}$, let $\mathcal{T}(\xi)$ denote
the set of all integral solutions of the equation \eqref{3.6}),
which is regarded as a subset of $C(I,\overline{D})$. The
following counterpart of Theorem \ref{thm9} is valid.

\begin{theorem} \label{thm12}
Let conditions (H1), (H3), (H4), (H5) be
satisfied. In addition assume that there exists an open subset $V$
 of $X$ such that $V_{A}:=V\cap\overline{D}$ is nonempty.
Then there exists $u:I\times V_{A}\to\overline{D}$ such that
\begin{gather}
u(.,\xi)\in\mathcal{T}(\xi),\quad \forall
\xi\in V_{A}, \label{3.7}
\\
\xi\to u(.,\xi)\text{ is continuous from }V_{A}\text{
into }C(I,\overline{D}). \label{3.8}
\end{gather}
\end{theorem}

\section{Proofs}

\begin{proof}[Proof of Theorem \ref{thm9}]
We adapt the technique used in \cite{Ce-Fr-Rz-St,St} to handle
\eqref{3.1}, which is the functional
differential inclusion equivalent of the integral equation
\eqref{1.1}.

Fix $\varepsilon>0$ and set $\varepsilon_{n}:=\varepsilon/2^{n+1}$,
$n\in\mathbb{N}$, where $\mathbb{N}$ denotes the set of all nonnegative
integers. For $\xi\in U_{A}$, let $u_{0}(.,\xi):I\to\overline{D(A)}$
be the unique integral solution of
\[
u'(t)+Au(t)\ni\Gamma(u)
(t),\quad t\in I;\quad u(0)=\xi.
\]
The existence and uniqueness of $u_{0}(.,\xi)$ follows from
\cite[Prop. 1 and Theorem 1]{Cr-No}, on account of
(H2), (H4) and (H5). Set
\begin{equation}
\alpha(\xi)(t):=\beta(t)+k( t)\|u_{0}(t,\xi)\| ,\quad m(
t):=\int_{0}^{t}k(s)ds,t\in I, \label{4.1}
\end{equation}
where $k(.)$ and $\beta(.)$ are as in (H4) (ii) and (iii),
respectively. Also define
\begin{equation}
\gamma(t):=\left\vert r(0)\right\vert
+var\{r:[0,t]\},\quad t\in I;\quad M:=e^{\int_{0}^{t}\gamma(s)ds}, \label{4.2}
\end{equation}
where the function $r(.)$ satisfies \eqref{3.3} and
$var\{r:[0,t]\}$ indicates the total
variation of $r$ over $[0,t]$. Let $f_{-1}(\xi)(t)\equiv0$.

We will construct two sequences of functions
$(u_{n}(.,\xi))_{n\in\mathbb{N}}\subset C(I,\overline{D(A)})$
and $(f_{n}(\xi))_{n\in\mathbb{N}}\subset L^{1}(I,X)$
satisfying the following conditions:

\begin{enumerate}
\item[(C1)] $u_{n}(.,\xi):I\to
\overline{D(A)}$ is the unique integral solution of the problem
\begin{equation}
u'(t)+Au(t)\ni\Gamma(u) (t)-f_{n-1}(\xi)(t),\quad
u(0)=\xi; \label{En}
\end{equation}

\item[(C2)] $\xi\to f_{n}(\xi)$ is
continuous from $U_{A}$ into $L^{1}(I,X);$

\item[(C3)] $f_{n}(\xi)(t)\in F(t,u_{n}(t,\xi))$, for all $\xi\in U_{A}$,
a.e. on $I$;

\item[(C4)] $\|f_{n}(\xi)(t)-f_{n-1}(\xi)(t)\| \leq k(t)\beta_{n}(\xi)(t)$,
for all $\xi\in U_{A}$, a.e. on $I$,
\end{enumerate}
where
\[
\beta_{0}(\xi)(t):=(\alpha(\xi)(t)+\varepsilon_{0})(k(t))^{-1},
\]
and, for $n\geq1$,
\begin{equation}
\beta_{n}(\xi)(t)=M^{n}\int_{0}^{t}\alpha(
\xi)(s)\frac{[m(t)-m(
s)]^{n-1}}{(n-1)!}ds+M^{n}T\frac{[
m(t)]^{n-1}}{(n-1)!}\sum_{i=0}
^{n}\varepsilon_{i}, \label{4.3}
\end{equation}
with $\alpha(\xi)(.)$, $m(.)$ and
$M$ defined in \eqref{4.1} and \eqref{4.2}.

We remark that $u_{0}(.,\xi)$ is the integral solution of
\eqref{En} with $n=0$. We claim that the map
$\xi\to u_{0}(.,\xi)$ is continuous from $U_{A}$ into
$C(I,\overline{D(A)})$. Indeed, for $\xi_{1},\xi_{2}\in U_{A}$, we can
invoke \eqref{2.5} to deduce, for $t\in I$,
\begin{equation}
\|u_{0}(t,\xi_{1})-u_{0}(t,\xi_{2})\|
 \leq\|\xi_{1}-\xi_{2}\| + \int_{0}^{t}\|\Gamma(u_{0}(.,\xi_{1})
)(s)-\Gamma(u_{0}(.,\xi_{2}) )(s)\| ds.
 \label{4.4}
\end{equation}
It is easily seen that the definition of $\Gamma$ (cf. \eqref{3.2}) implies
\begin{equation}
\begin{aligned}
&  \int_{0}^{t}\|\Gamma(u_{0}(.,\xi_{1})
)(s)-\Gamma(u_{0}(.,\xi_{2}) )(s)\| ds\\
&  \leq r(t)\|\xi_{1}-\xi_{2}\| +\int_{0}
^{t}\gamma(s)\|u_{0}(.,\xi_{1}) -u_{0}(.,\xi_{2})\|
_{\infty}(s)ds,
\end{aligned} \label{4.5}
\end{equation}
where $\|u\| _{\infty}(s):=\sup_{\tau \in[0,s]}\| u(\tau)\| $ is
the norm in $C([0,s],X)$ and $\gamma( .)$ is given by
\eqref{4.2}. Since $r( .)\in BV(I)$, one has that
$\|r\|_{\infty}:=\sup_{t\in I}\vert r(t)\vert <\infty$. Using
\eqref{4.5} in \eqref{4.4} and applying Gronwall's lemma, we
conclude that
\[
\|u_{0}(.,\xi_{1})-u_{0}(.,\xi_{2}) \| _{\infty}\leq M(1+\|r\|
_{\infty}) \| \xi_{1}-\xi_{2}\| .
\]
This yields the continuity of $\xi\to u_{0}(.,\xi)$
from $U_{A}$ into $C(I,\overline{D(A)})$, as claimed.

Next, by (H4) (ii), (iii) and \eqref{4.1}, we have
\begin{equation}
d(0,F(t,u_{0}(t,\xi)))\leq
\alpha(\xi)(t),\quad \mbox{a.e.  on } I,
\label{4.6}
\end{equation}
where it is to be noted that $\alpha(.)$ is continuous as a
function from $U_{A}$ into $L^{1}(I)$. Define the
multifunctions $G_{0}$, $H_{0}:U_{A}\to2^{L^{1}(I,X)}$
by
\begin{gather}
G_{0}(\xi):=\{v\in L^{1}(I,X):v(
t)\in F(t,u_{0}(t,\xi)),\mbox{ a.e. on }I\}, \label{4.7}
\\
H_{0}(\xi):=cl\{v\in G_{0}(\xi) :\|v(t)\| <\alpha(\xi)(
t)+\varepsilon_{0},\mbox{ a.e. on }I\}. \label{4.8}
\end{gather}


Setting $F^{\ast}(t,\xi):=F(t,u_{0}(t,\xi))$ and invoking
assumptions (H4) (i), (ii), \cite[Proposition 2.66, p.61]{Hu-Pa1},
the continuity of
$\alpha(.)$ on $U_{A}$ and \eqref{4.6}, we
conclude by applying Proposition \ref{prop1} that $G_{0}(.)$ is lower
semicontinuous from $U_{A}$ into $\mathcal{D}$ and the set
$H_{0}(\xi)$ is nonempty. Therefore, by Proposition \ref{prop2}, there
exists $h_{0}\in C(U_{A},L^{1}(I,X))$ such that
$h_{0}(\xi)\in H_{0}(\xi)$, $\forall\xi\in U_{A}$. Set
\begin{equation}
f_{0}(\xi)(t):=h_{0}(\xi)(t),\quad \forall\xi\in U_{A},t\in I, \label{4.9}
\end{equation}
and remark that, by virtue of \eqref{4.7},  \eqref{4.8},
\eqref{4.9} and the fact that $F$ is closed valued, $f_{0}(.)$
is continuous from $U_{A}$ into $L^{1}(I,X)$,
$f_{0}(\xi)(t)\in F(t,u_{0}(t,\xi))$ and
$\|f_{0}( \xi)(t)\| \leq k(t)\beta_{0}(\xi)(t)$, $a.e$. $on$ $I$.
Recalling that $u_{0}(.,\xi)$ is
the integral solution of \eqref{En} with $n=0$, we conclude that conditions
$(C_{1})-( C_{4})$ hold for $n=0$.

We now proceed inductively. Assume that the functions
 $\{u_{0},\quad u_{1},\dots ,u_{n}\}$ and
$\{f_{0},\quad f_{1},\dots ,f_{n}\}$ have been constructed such
that conditions $(C_{1})-(C_{4})$ are satisfied.
For $\xi\in U_{A}$, let $u_{n+1}(.,\xi):I\to\overline{D(A)}$ be the
unique integral solution of \eqref{En} with $n+1$ in place of $n$. 
(Taking into account
that $f_{n}(\xi)\in L^{1}(I,X)$, we can again
invoke  \cite[Prop. 1 and Theorem 1]{Cr-No} to establish
the existence and uniqueness of $u_{n+1}(.,\xi)$).
Inasmuch as $u_{n}(.,\xi)$ and $u_{n+1}(.,\xi)$ satisfy
\eqref{En}, and \eqref{En} with $n+1$ instead of $n$, respectively,
 we can apply Proposition \ref{prop4} to obtain, for $t\in I$,
\begin{equation}
\begin{aligned}
\|u_{n+1}(t,\xi)-u_{n}(t,\xi) \|
&\leq\int_{0}^{t}\|\Gamma(u_{n+1}( .,\xi))(s)-\Gamma(u_{n}(
.,\xi))(s)\| ds\\
& \quad  +\int_{0}^{t}\|f_{n}(\xi)(s) -f_{n-1}(\xi)(s)\| ds.
\end{aligned}\label{4.10}
\end{equation}

 From \eqref{3.2} it follows that
\begin{equation}
\begin{aligned}
&  \int_{0}^{t}\|\Gamma(u_{n+1}(.,\xi)) (s)-\Gamma(u_{n}(.,\xi))(
s)\| ds\\
&  \leq\int_{0}^{t}\gamma(s)\|u_{n+1}( .,\xi)-u_{n}(.,\xi)(s)\|
_{\infty}(s)ds.
\end{aligned} \label{4.11}
\end{equation}
Combining \eqref{4.10} with \eqref{4.11} and
using Gronwall's lemma, we arrive at
\begin{equation}
\|u_{n+1}(t,\xi)-u_{n}(t,\xi) \| \leq M\int_{0}^{t}\|f_{n}(\xi)(
s)-f_{n-1}(\xi)(s)\| ds,t\in I.\label{4.12}
\end{equation}
Employing property (C4) in $(\ref{4.12})$,
we have
\begin{equation}
\|u_{n+1}(t,\xi)-u_{n}(t,\xi) \| \leq
M\int_{0}^{t}k(s)\beta_{n}(\xi) (s)ds,t\in I.\label{4.13}
\end{equation}
If $n=0$, this implies, by virtue of \eqref{4.3},
\begin{equation}
\|u_{1}(t,\xi)-u_{0}(t,\xi)\|
  \leq M\int_{0}^{t}\alpha(\xi)(s)ds
  <\beta_{1}(\xi)(t),\quad \mbox{a.e.  on } I.\label{4.14}
\end{equation}
If $n>0$, then \eqref{4.13} and \eqref{4.3}
lead to
\begin{equation}
\begin{aligned}
  \|u_{n+1}(t,\xi)-u_{n}(t,\xi)\|
&  \leq M^{n+1}\int_{0}^{t}k(s)\int_{0}^{s}\alpha(
\xi)(\tau)\frac{[m(s)-m(\tau)]^{n-1}}{(n-1)!}d\tau ds\\
&\quad  +M^{n+1}T[\sum_{i=0}^{n}\varepsilon_{i}]\int_{0}^{t}k(
s)\frac{[m(s)]^{n-1}}{(n-1)!}ds,
\end{aligned} \label{4.15}
\end{equation}
for $t\in I$. Recalling the definition of $m$ (cf. \eqref{4.1}),
and interchanging the order of integration in the first term on the
right-hand side of \eqref{4.15}, we get
\begin{equation}
\begin{aligned}
&  \|u_{n+1}(t,\xi)-u_{n}(t,\xi)\|\\
&  \leq M^{n+1}\int_{0}^{t}\alpha(\xi)(\tau)
\frac{[m(t)-m(\tau)]^{n}}
{n!}d\tau+M^{n+1}T[\sum_{i=0}^{n}\varepsilon_{i}]\frac{[
m(t)]^{n}}{n!}\\
&  <\beta_{n+1}(\xi)(t),\quad \mbox{a.e. on } I.
\end{aligned} \label{4.16}
\end{equation}
By \eqref{4.14}, \eqref{4.16}, (C3) and (H4) (ii), it follows
that
\begin{equation}
d(f_{n}(\xi)(t),F(t,u_{n+1}(
t,\xi)))<k(t)\beta_{n+1}(
\xi)(t),\quad\mbox{a.e.  on } I,\label{4.17}
\end{equation}
and subsequently
\begin{equation}
d(0,F(t,u_{n+1}(t,\xi))) \leq\|f_{n}(\xi)(t)\|
+k(t)\beta_{n+1}(\xi)(t) ,\quad\mbox{a.e.  on } I,\label{4.18}
\end{equation}
where the expression on the right-hand side of \eqref{4.18}
is continuous from $U_{A}$ into $L^{1}(I)$ (cf. (C2), \eqref{4.1}
 and \eqref{4.3}).

For $\xi\in U_{A}$, we define
\[
G_{n+1}(\xi)=\{v\in L^{1}(I,X):v(
t)\in F(t,u_{n+1}(t,\xi)),\mbox{ a.e. on } I\},
\]
\begin{equation}
H_{n+1}(\xi)=cl\{v\in G_{n+1}(\xi) :\|v(t)-f_{n}(\xi)(t) \|
<k(t)\beta_{n+1}(\xi)( t),\mbox{ a.e. on } I\}. \label{4.19}
\end{equation}
Clearly, $G_{n+1}(.)$ is lower semicontinuous from $U_{A}$ into
$\mathcal{D}$ and $H_{n+1}(\xi)$ is nonempty, because of
\eqref{4.17} and \eqref{4.18}. Therefore,
one can apply Proposition \ref{prop2} to derive the existence of
$h_{n+1}\in C(U_{A},L^{1}(I,X))$ such that
$h_{n+1}(\xi)\in H_{n+1}(\xi)$, for all $\xi\in U_{A}$.

Setting $f_{n+1}(\xi)(t)=h_{n+1}(
\xi)(t)$, for all $\xi\in U_{A}$ and almost all
$t\in I$, we conclude that $f_{n+1}(.)$ is continuous
from $U_{A}$ into $L^{1}(I,X)$ and
$f_{n+1}(\xi)(t)\in F(t,u_{n+1}(t,\xi))$, a.e. on $I$;
hence $f_{n+1}(\xi)$ and $u_{n+1}(.,\xi)$
satisfy conditions $(C_{1})-(C_{3})$. Condition
(C4) is also satisfied on account of  \eqref{4.19},
and the induction argument has been completed.

By (C4), \eqref{4.1} and \eqref{4.3} we now successively obtain
\begin{equation}
\begin{aligned}
  \|f_{n}(\xi)-f_{n-1}(\xi)\|_{1}
&  \leq \int_{0}^{T} k(s)\beta_{n}(\xi)(s) ds\\
&  =M^{n}\int_{0}^{T}\alpha(\xi)(s)\frac{[
m(T)-m(s)]^{n}}{n!}ds+M^{n}T[
\sum_{i=0}^{n}\varepsilon_{i}]\frac{[m(T)]^{n}}{n!}\\
& \leq\frac{M^{n}(\|k\| _{1})^{n}} {n!}(\| \alpha(\xi)\| _{1}
+T\varepsilon).
\end{aligned}\label{4.20}
\end{equation}
 From the above inequality, it follows that $(f_{n}(\xi))_{n\in\mathbb{N}}$ is
a Cauchy sequence in $L^{1}(I,X)$, hence it converges in $L^{1}(I,X)$
to some function $f(\xi)\in L^{1}(I,X)$. Then, for a
subsequence (again denoted by $(f_{n}(\xi))_{n\in\mathbb{N}}$ ),
we have
\begin{equation}
f_{n}(\xi)(t)\to f(\xi)
(t),\quad \text{as $n\to\infty$,  a.e.  on } I. \label{4.21}
\end{equation}

Next, from \eqref{4.12} and \eqref{4.20} it
follows that
\[
\|u_{n+1}(.,\xi)-u_{n}(.,\xi) \| _{\infty}\leq\frac{M^{n+1}(\|k\|
_{1})^{n}}{n!}(\|\alpha(\xi)\| _{1}+T\varepsilon)
\]
and, since the map $\xi\to\|\alpha(\xi) \| _{1}$ is continuous,
this implies that $(u_{n}( .,\xi))_{n\in\mathbb{N}}$ is a Cauchy
sequence in $C( I,X)$, locally uniformly in $\xi$. Therefore, if
we denote by $u(.,\xi)$ its limit, then $\xi\to u( .,\xi)$ is
continuous from $U_{A}$ into $C(I,X)$.

Since the multifunction $F$ is closed valued and since, by
(C3) and (H4) (ii),
\[
d(f_{n}(\xi)(t),F(t,u( t,\xi)))\leq k(t)\| u_{n}(t,\xi)-u(t,\xi)\|,
\]
passing to the limit as $n\to\infty$, we have by
\eqref{4.21} that
\[
f(\xi)(t)\in F(t,u(t,\xi)),\quad\mbox{a.e  on } I.
\]
Finally, let $u^{\ast}(.,\xi)$ be the unique integral solution
of
\[
u'(t)+Au(t)\ni\Gamma(u) (t)-f(\xi)(t),\quad
t\in I;u(0)=\xi.
\]
Since $u_{n+1}(.,\xi)$ satisfies \eqref{En} with $n+1$ instead of $n$, we
obtain, with the help of Proposition \ref{prop4} (compare to \eqref{4.12}),
\begin{equation}
\|u_{n+1}(.,\xi)-u^{\ast}(.,\xi) \| _{\infty}\leq M\|f_{n}(\xi)-f(
\xi)\| _{1},\quad \xi\in U_{A}. \label{4.22}
\end{equation}


Hence, letting $n\to\infty$ in \eqref{4.22} we obtain
that $u(t,\xi)=u^{\ast}(t,\xi)$ for each $t\in I$.
Then, we conclude that $(\ref{3.4})$ holds and since
$\xi\to u(.,\xi)$ is continuous from $U_{A}$ into
$C(I,X)$, it follows that \eqref{3.5} is
satisfied, as well, and the proof is complete.
\end{proof}


\begin{proof}[Proof of Theorem \ref{thm12}]
As specified in Section 3, we consider the functional
differential equivalent of \eqref{3.6}, namely
\begin{equation}
u'(t)+A(t)u(t)+F(
t,u(t))\ni\Gamma(u)(t),\quad t\in I;u(0)=\xi. \label{4.23}
\end{equation}
The theory of \cite[p. 323-24]{Cr-No}, can be adapted to justify the
equivalence between \eqref{3.6} and \eqref{4.23} under assumption
(H1); see also \cite{Aiz-Di-Pa}. The proof then follows that of
Theorem \ref{thm9}, with the mention that $\overline{D}$, $V_{A}$
and Proposition \ref{prop6} are now used
in place of $\overline{D(A)}$, $U_{A}$ and Proposition \ref{prop4}, respectively.
The details are left to the reader.
\end{proof}

\section{An example}

Let $\Omega$ be a bounded domain in $\mathbb{R}^{n}$ ($n\geq1)$ with
 a smooth boundary $\Gamma$, and let $\rho:\mathbb{R\to R}$ satisfy

\begin{enumerate}
\item[(H6)] $\rho\in C(\mathbb{R})$,
$\rho(0)=0$, $\rho$ is nondecreasing.
\end{enumerate}
Let $X=L^{1}(\Omega)$, and define the operator $A:D(
A)\subset X\to X$ by
\begin{equation}
Au=-\Delta\rho(u),\quad D(A)=\{u\in
L^{1}(\Omega):\rho(u)\in W_{0}^{1,1}(
\Omega),\Delta\rho(u)\in L^{1}(\Omega)
\}. \label{5.1}
\end{equation}
It is well-known (see, e.g., \cite[Example 1.5.5]{Vr}) that $A$
is m-accretive in $X$, with $\overline{D(A)}=X$.

Next, let $f_{i}:I\times\Omega\times\mathbb{R\to R}$ ($I=[
0,T]$, $i=1,2$) be given functions satisfying $f_{1}\leq f_{2}$ on
$I\times\Omega\times\mathbb{R}$ and the following conditions

\begin{enumerate}
\item[(H7)]
\begin{enumerate}
\item[(i)] $(t,x)\to f_{i}(t,x,r)$ is measurable for all $r\in\mathbb{R}$,

\item[(ii)] There exists $k:I\times\Omega\mathbb{\to}(0,\infty)$,
$k\in L^{1}(I,L^{\infty}(\Omega))$ such that
\[
\vert f_{i}(t,x,r)-f_{i}(t,x,\overline{r})
\vert \leq k(t,x)\vert r-\overline{r}\vert
\quad \text{a.e. on $I\times\Omega$, for all $r, \overline{r}$
in $\mathbb{R}$},
\]

\item[(iii)] $f_{i}(.,.,0)\in L^{1}(I\times\Omega)$.
\end{enumerate}
\end{enumerate}
Introduce the multifunction $\widehat{f}:I\times\Omega\times
\mathbb{R\to}2^{\mathbb{R}}$ by
\begin{equation}
\widehat{f}(t,x,r)=[f_{1}(t,x,r),f_{2}(t,x,r)]\label{5.2}
\end{equation}
and define $F:I\times X\to2^{X}$ by
\begin{equation}
F(t,u)(x)=\{v\in X:v(x)\in\widehat{f}(t,x,u(x)),\text{ a.e. on }
\Omega\}. \label{5.3}
\end{equation}

By (H7) (i)-(iii), \eqref{5.2} and \eqref{5.3}, it is an easy exercise
to show that $F$ satisfies (H4). (One uses the definition
of the Hausdorff distance, \cite[Theorem 7.26, p. 237]{Hu-Pa1} and
measurability arguments similar to those in \cite[p. 97]{Hu-Pa2}).

Finally, let $\xi:\Omega\to\mathbb{R}$ and $\overline{g}:I\times
\Omega$ $\mathbb{\to R}$ satisfy

\begin{enumerate}
\item[(H8)] $\xi\in L^{1}(\Omega)$,

\item[(H9)] $\overline{g}\in W^{1,1}(I,L^{1}(\Omega))$;
 $\overline{g}(0,x)=0$, a.e. on $\Omega$
\end{enumerate}
and set
\begin{equation}
g(t)(x)=\overline{g}(t,x)\quad
\text{for all }t\in I\text{ and a.a. }x\in\Omega. \label{5.4}
\end{equation}
Obviously, by (H9), condition (H5) is verified.

Consider the problem
\begin{equation}
\begin{gathered}
u(t,x)+\int_{0}^{t}a(t-s)[-\Delta \rho(u(s,x))+\widehat{f}(s,x,u(
s,x))]ds \\
\ni\xi(x) +\overline{g}(t,x)\text{ on }I\times\Omega \,,\\
u(t,x)=0,\quad \text{on }I\times\Gamma\,,
\end{gathered}  \label{5.5}
\end{equation}
where $a$ satisfies (H3). In view of the above discussion,
it is clear that \eqref{5.5} can be rewritten in the abstract
form \eqref{1.1} in the Banach space $X=L^{1}(\Omega)$, with $A$, $F$
 and $g$ defined by \eqref{5.1}, \eqref{5.3} and \eqref{5.4},
respectively. Consequently, an application of Theorem \ref{thm9} (with $U_{A}=X)$
yields following result.

\begin{theorem} \label{thm13}
Under assumptions (H3), (H6)--(H9),
Problem \eqref{5.5} has an integral solution
$u(.,\xi)\in C(I,L^{1}(\Omega))$ such that
$\xi\to u(.,\xi)$ is continuous from $L^{1}(\Omega)$ into
$C(I,L^{1}(\Omega))$.
\end{theorem}

\subsection*{Acknowledgements}
This paper was completed while the first author was
visiting the University of Aveiro as an Invited Scientist.
The hospitality and financial support of the host institution are
gratefully acknowledged. The second author acknowledges partial
financial support from FCT under project
FEDER POCTI/MAT/55524/2004.


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\end{document}
