\documentclass[reqno]{amsart}
\usepackage{graphicx}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
{\em Electronic Journal of Differential Equations},
Vol. 2006(2006), No. 112, pp. 1--11.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu  (login: ftp)}
\thanks{\copyright 2006 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2006/112\hfil Analysis of a single species]
{Analysis of a single species with diffusion in a polluted
environment}

\author[J. Wang, K. Wang\hfil EJDE-2006/112\hfilneg]
{Jing Wang, Ke Wang}  % in alphabetical order

\address{Jing Wang\newline
Department of Mathematics Harbin Institute of Technology,
Harbin 150001,  China\newline
School of Mathematics and statistics Northeast Normal University,
Changchun 130024,  China}
\email{wangj487@nenu.edu.cn }

\address{Ke Wang \newline
Department of Mathematics, Harbin Institute of Technology,
Weihai 264209,   Shandong, China}
\email{w\_k@hotmail.com}


\date{}
\thanks{Submitted March 20, 2006. Published September 19, 2006.}
\thanks{Supported by  grants 10201005 from  NNS of
   China, and 20050103 from the Science Foundation  \hfill\break\indent
   for Young Teachers of Northeast Normal University.}
\subjclass[2000]{93C15}
\keywords{Protective patch; equilibrium; permanence; extinction}


\begin{abstract}
 In this paper, the effect of diffusion on the permanence
 and extinction in the polluted environment is studied
 by a single population diffusive system in two patches.
 Assume that the two patches are a protective patch and a
 non-protective patch. We examine the effects of protective
 patch and conclude that it is effective for the conservation
 of a population facing polluted environment.  The conditions
 for the permanence and extinction of the population are obtained.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{definition}[theorem]{Defintion}


\section{Introduction}

Biological resources are renewable resources.  In recent years, many
countries have already realized that the pollution of the
environment is a very urgent problem.  Specialists coming from all
kinds of fields have studied and solved it.  One of the most
meaningful question in mathematical biology is the permanence and
extinction of a population in a polluted environment. Organisms are
often exposed to a polluted environment and take up toxicant.
Therefore,  it is important to study the effects of a toxicant and
diffusion on populations and to find a theoretical threshold value,
which determines permanence or  extinction  of a population or
community.

In order to prevent the biological resources from destruction and
protect the environment,  all kinds of measures have been proposed.
Establishing protective patch as for a resource population is
applied widely. The practical effects of the protective patch on the
polluted population is worth examination.

Since Hallam and his colleagues proposed a toxicant-population model
in the early 1980s \cite{1}-\cite{3},  many authors have studied the
mathematical models with toxicant effect \cite{4,5}.  In this
paper, pollution together with diffusional migration is taken into
account comprehensively.  It is particularly interested in the
managers who need to deal with the size and control of barriers in
protective patch \cite{6,7}. The organization of this paper is
as follows. In the next section, we formulate our model as a system
of non-autonomous ordinary differential equations,  and describe
our hypotheses.  In section 3,  we determine the equilibria of two
autonomous systems. In section 4,  sufficient conditions are
obtained for permanence and extinction of population.

\section{The Model}

Let $N(t)$ be the density of population in region
$\Omega$ at time $t$; $C_0(t)$ be the toxicant density in a
body; $C_e(t)$ be the toxicant density of environment;
$u(t)$ be the exogenous toxicant input rate,  which is nonnegative, continuous
and bounded function in the internal $[0,\infty)$.

 The basic assumption is that
compared with the number of the individuals, the content of the
environment is large enough, the uptake and egestion by the
organisms can be neglected.  Equation of the polluted population
reads
\begin{equation} \label{e2.1}
\begin{gathered}
\dot{N}(t)=N(t)[r(t)-d(t)C_0(t)-a(t)N(t)],\\
\dot{C_0}(t)=k(t)C_e(t)-g(t)C_0(t)-m(t)C_0(t),\\
\dot{C_e}(t)=-h(t)C_e(t)+u(t),
\end{gathered}
\end{equation}
where $r(t), d(t)C_0(t), a(t)$ are the intrinsic growth rate,
death rate,  density restriction respectively,
$k(t)C_e(t)$ represents the uptake of the toxicant from the
environment by the population, $g(t)C_0(t)$ represents the
toxicant quantity input to the environment from the population due
to egestion, $m(t)C_0(t)$ represents the metabolic processes and
other losses, $h(t)C_e(t)$ represents the losses of the toxicant
from the environment due to egestion.

To protect the
population resources, $\Omega$ is divided into two patches
$\Omega_1$ and $\Omega_2$. Pollution is permitted in $\Omega_1$ and
is inhibited in $\Omega_2$. We call $\Omega_2$ the protective patch.
The densities of population in $\Omega_1$ and $\Omega_2$ are denoted
by $x(t),y(t)$ respectively,  $b(t)$ is the density restriction of
the population. The mathematical model of the polluted population
with protective patch can be described as
\begin{equation} \label{e2.2}
\begin{gathered}
\dot{x}(t)=x(t)[r(t)-d(t)C_0(t)-a(t)x(t)]+D(t)(y(t)-x(t)),\\
\dot{y}(t)=y(t)[r(t)-b(t)y(t)]+D(t)(x(t)-y(t)),\\
\dot{C_0}(t)=k(t)C_e(t)-g(t)C_0(t)-m(t)C_0(t),\\
\dot{C_e}(t)=-h(t)C_e(t)+u(t).
\end{gathered}
\end{equation}
The initial conditions are $x_0=x(0)>0$, $y_0=y(0)>0$,
$0\leq C_0(0)\leq 1$, $0\leq C_e(0)\leq 1$. Since the difference of
densities between patch $\Omega_1$ and $\Omega_2$ exists, the
diffusive migration can occur between the two patches, which is
assumed to be $D(t)$.    The coefficients in the models are all
nonnegative, continuous and bounded functions in the internal
$[0,\infty)$.

To simplify our representations,  we introduce the following
notations in this paper: if $f(t)$ is a nonnegative, continuous and
bounded functions in the internal $(-\infty,\infty)$,
$$
f^u=\max_{t\in R}f(t),\quad f^l=\min_{t\in R}f(t).
$$
Considering the realistic situation,  the toxicant density of single
body or the environment can't be greater than 1,  or any population
wiil not survive.  So we should give some conditions,  such that
$$
0\leq C_0(t)\leq 1,\quad 0\leq C_e(t)\leq 1,\quad
\text{for all }t\geq 0.
$$

\begin{lemma} \label{lem2.1}
The set 
$$
\{(x(t),y(t),C_0(t),C_e(t)):  x(t)>0,y(t)>0,C_0(t)>0,C_e(t)>0\}
$$ 
is an invariant region of system  \eqref{e2.2}
\end{lemma}

\begin{lemma} \label{lem2.2}
 For \eqref{e2.2}, if $k^u\leq g^l+m^l$, $u^u\leq h^l$,  then
$0\leq C_0(t)\leq 1$, $0\leq C_e(t)\leq 1$, for all $t\geq 0$.
\end{lemma}

\begin{proof}
According to Lemma \ref{lem2.1},  we have $0\leq C_0(t)$, $0\leq C_e(t)$,
for all $t\geq 0$.  Now we are going to prove that
$C_0(t)\leq 1$, $C_e(t)\leq 1$, for all $t\geq 0$.

If the conclusion is false,  then the maximum interval is $[0,T]$.
 At least one of the following cases will happen:
 \begin{enumerate}
\item  $C_0(t)=1$, $C_e(t)<1$;
\item  $C_0(t)<1$, $C_e(t)=1$;
\item  $C_0(t)=1$, $C_e(t)=1$.
\end{enumerate}
  We will prove that none of  this cases will happen.
 (1)  $C_0(t)=1$, $C_e(t)<1$: Using the condition
$k^u\leq g^l+m^l$,  we get
$$
\frac{dC_0(t)}{dt}|_{t=T}=k(t)C_e(t)-g(t)C_0(t)-m(t)C_0(t)\leq 0,
$$
thus $\exists t_1>0$,  such that $C_0(t)\leq 1$, $C_e(t)<1$,
for all $t \in [T,T+t_1]$.
This is the contradiction with the
definition of the interval $[0,T]$.  So there is no $T$  such that
$C_e(t)<1$,  $t\in [0,T]$;  $C_0(t)<1$,  $t\in [0,T) $ and $C_0(T)=1$.

With the same reasoning as in case (1), for cases (2) and (3),  as far
as $t$  which keeps $C_0(t)\leq 1$  and $C_e(t)\leq 1$ is concerned,
the interval $[0,T]$  can be extended rightwards.  This contradicts the
property of $T$.  Therefore,  there is no such $T$,  furthermore
$0\leq C_0(t)\leq 1$, $0\leq C_e(t)\leq 1$, for  all $t\geq 0$.
\end{proof}


It is clear $C_0(t)$ and $C_e(t)$ can be easily solved formally from
the last two equations of the system \eqref{e2.2},
\begin{gather*}
C_0(t)=e^{-\int(m(s)+g(s))ds}[\int k(s)
e^{\int (m(s)+g(s))ds}C_e(s)ds+C_0(0)],
\\
C_e(t)=e^{-\int(h(s))ds}[\int u(s)
e^{\int(h(s))ds}ds+C_e(0)],
\end{gather*}
Substituting $C_e(t)$ in $C_0(t)$,
we can express $C_0(t)$   in term of some bounded continuous
functions;  therefore, the system \eqref{e2.1} may be simplified as
follows:
\begin{equation} \label{e2.3}
\begin{gathered}
\dot{x}(t) = x(t)[r(t)-d(t)C_0(t)-a(t)x(t)]+D(t)(y(t)-x(t)),\\
\dot{y}(t) = y(t)[r(t)-b(t)y(t)]+D(t)(x(t)-y(t)).
\end{gathered}
\end{equation}
The initial conditions are $x_0=x(0)>0$,  $y_0=y(0)>0$.
For the simplified model \eqref{e2.3}, because the $C_0(t)$ may be regarded as a
known function of $t$, we need only to impose the conditions of the
diffusive coefficient $D(t)$ and the toxicant density in a body
$C_0(t)$ in order to investigate the threshold between permanence
and extinction of the populations. There is toxicant in patch
$\Omega_1$, but not in patch $\Omega_2$ of systems \eqref{e2.2},
\eqref{e2.3}.
Assume patch $\Omega_2$ is the protective patch in order to the
conservation of population resources in the polluted environment,
though in some case the extinction can not be eliminated.

Considering the biological significance, we study system \eqref{e2.3} in
the region
$$
R_+^2=\{(x,y)\in \mathbb{R}^{2}:x\geq 0,y\geq 0\}.
$$

\begin{definition}\cite{6}]  \label{def2.1} \rm
A solution $x(t)$ of the system \eqref{e2.3} is said to be permanent if for
 any $x(0)>0$, there exist
positive constants $0<\delta<\varepsilon$ (independent of $x(0)$)
such that $\delta<x(t)<\varepsilon$,  then $x(t )$ is said to be
uniformly permanent for large enough $t$. $x(t)$  is said to go to
extinction if $\lim_{t\to+\infty} x(t)=0$.
\end{definition}

\begin{definition}[\cite{8}] \label{def2.2} \rm
 The differential equation
$$
\dot x(t)=F(t,x),\quad x\in \mathbb{R}^n,
$$
is said to be cooperative if
the off-diagonal elements of $D_xF(t,x)$  are nonnegative,  where
$D_xF(t,x)$ is the $n\times n$ matrix derivative of $F$ with
respect to $x$.
\end{definition}

\begin{theorem}[Kamke] \label{kamekethm}
 Let $x(t)$  and $y(t)$be the solutions of
\begin{gather*}
\dot x(t)=F(t,x) \\
\dot y(t)=G(t,x)
\end{gather*}
respectively,  where both systems are assumed to have
the uniqueness property for initial value problems.  Assume both
$x(t)$  and $y(t)$ belong to a domain  $D\subseteq  \mathbb{R}^n$ for
$[t_0,t_1]$  in which one of the two systems is cooperative and
$$
F(t,z)\leq G(t,z)\quad (t,z)\in [t_0,t_1]\times D.
$$
if  $x(t_0)\leq y(t_0)$  then $x(t_1)\leq y(t_1)$.  If $F=G$  and
$x(t_0)< y(t_0)$  then $x(t_1)< y(t_1)$.
\end{theorem}

\begin{lemma} \label{lem2.3}
 The set $R_+^2$  is an invariant region of system  \eqref{e2.3}.
\end{lemma}

\begin{lemma} \label{lem2.4}
Solutions of system \eqref{e2.3} with the positive initial conditions
are uniformly bounded and ultimately uniformly  bounded.
\end{lemma}

\begin{proof}  Let
\begin{gather*}
\Delta>\max\{\frac{r^u-d^lC_0^l}{a^l},\frac{r^u}{b^l}\},\\
\dot x(t)|_{x=\Delta,y<\Delta}\leq
x(r^l-d^uC_0^u-a^ux)+D(t)(y-x)<0, \\
\dot y(t)|_{y=\Delta,x<\Delta}\leq y(r^l-b^uy)+D(t)(x-y)<0,
\end{gather*}
\begin{itemize}
\item[(i)]  If $\max\{x(0),y(0)\}\leq \Delta$,  then
$\max\{x(t),y(t)\}\leq \Delta$ for $t\geq 0$.

\item[(ii)]  If $\max\{x(0),y(0)\}> \Delta$,    then there exists
$\mu>0$, $\max\{x(t),y(t)\}> \Delta$,  for $t\in [0,\mu)$.
\end{itemize}
When $\max\{x(t),y(t)\}=x(t)$,  letting
$\alpha=a^l(\frac{r^u-d^lC_0^l}{a^l}-\Delta)<0$, we have
\begin{align*}
\dot x(t)&=  x(t)[r(t)-d(t)C_0(t)-a(t)x(t)]+D(t)(y(t)-x(t))\\
&\leq a^lx(\frac{r^u-d^lC_0^l}{a^l}-x)\\
&< \alpha x\,.
\end{align*}
Then $x(t)$ is monotone decreasing with
speed $\alpha$,  so there exists
$T_1=\frac{-1}{\alpha}\ln\frac{\Delta}{x(0)}$, such that $x(t)<
\Delta $ for $t\geq T_1$.

When $\max\{x(t),y(t)\}=y(t)$,   letting
$\alpha=b^l(\frac{r^u}{b^l}-\Delta)<0$, we have
\begin{align*}
\dot y(t)&=  y(t)[r(t)-b(t)y(t)]+D(t)(x(t)-y(t))\\
&\leq b^lx(\frac{r^u}{b^l}-\Delta)\\
&< \alpha y\,.
\end{align*}
Then $y(t)$ is monotone decreasing with
speed $\alpha$,  so there exists
$T_2=\frac{-1}{\alpha}\ln\frac{\Delta}{y(0)}$, such that $y(t)<
\delta $ for $t\geq T_2$.

So that $\max\{x(t),y(t)\}$ is monotonically decreasing with speed $\alpha$
in the interval $[0,\mu)$.  For all $t^*\in [0,+\infty)$,  if
$\max\{x(t^*),y(t^*)\}>\Delta$,  there exists $\mu$,  such that
$\max\{x(t),y(t)\}$ is monotonically decreasing with speed $\alpha$ in
the interval $[t^*,t^*+\mu)$. Then there is $T^*>t^*$, with
$\max\{x(t),y(t)\}<\Delta$,  for $t>T^*$.

Solutions of system \eqref{e2.3} with positive initial conditions are
uniformly bounded and ultimately uniformly  bounded.
\end{proof}



\section{Two Cooperative Systems}

In this section we consider two autonomous systems generated by the
system  \eqref{e2.3}:
\begin{equation} \label{e3.1}
\begin{gathered}
\dot{x}= x[r^u-D^l-d^lC_0^l-a^l x]+D^u y:=P_1(x,y),\\
\dot{y}= y[r^u-D^l-b^ly]+D^u x:=Q_1(x,y),
\end{gathered}
\end{equation}
and
\begin{equation} \label{e3.2}
\begin{gathered}
\dot{x}= x[r^l-D^u-d^uC_0^u-a^u x]+D^l y:=P_2(x,y),\\
\dot{y}= y[r^l-D^u-b^uy]+D^l x:=Q_2(x,y).
\end{gathered}
\end{equation}
Obviously,  systems \eqref{e3.1}  and  \eqref{e3.2} are cooperative.  Now we
study the existence and the stability of  equilibria of \eqref{e3.1},
which are solutions of
\begin{equation} \label{e3.3}
\begin{aligned}
l_1:&\quad  x[r^u-D^l-d^lC_0^l-a^l x]+D^u y=0,\\
l_2:&\quad  y[r^u-D^l-b^ly]+D^u x=0.
\end{aligned}
\end{equation}
We are only interested in the non-negative equilibria, they are the
intersection of the isoclines  $l_1,l_2$.  The graph of $l_{1}$ and
$l_{2}$ are parabolas. $l_{1}$ is symmetric to line
$x=-\frac{r^u-D^l-d^lC_0^l}{2a^l}$ and $l_{2}$ is symmetric to line
$y=-\frac{r^u-D^l}{2b^l}$. We denote the intersection in the first
quadrant by $(x^*, y^*)$.

Let $k_{i}$ ($i=1,2$) denote the slope of the tangent line
of $l_{i}$   at $(0,0)$. Clearly
$k_{1}=\frac{d^lC_0^l+D^l-r^u}{D^u}$,
$k_{2}=\frac{D^u}{D^l-r^u}$.

\noindent Condition 1:   If $r^u<D^l$ and
$(D^u)^2<(D^l-r^u)(d^lC_0^l+D^l-r^u)$,  then $0<k_{1},0<k_{2}$ and
$k_{1}>k_{2}$,  the curves $l_{1}, l_{2}$ do not intersect in the
positive quadrant.  That is to say,  the unique non-negative
equilibrium is $(0,0)$ (see Fig. 1(a)).

\noindent Condition 2:   If $r^u<D^l$ and
$(D^u)^2>(D^l-r^u)(d^lC_0^l+D^l-r^u)~$,  then $0<k_{1},0<k_{2}$ and
$k_{1}<k_{2}$,  the curves $l_{1}, l_{2}$  intersect in the positive
quadrant.  That is to say, the unique positive equilibrium is
$(x^*,y^*)$ in the positive quadrant.  At the same time,  the unique
nonnegative equilibrium $(0,0)$ exists(see Fig. 1(b)).

\noindent Condition 3: If $r^u\geq D^l$,  the existence of the
unique positive equilibrium  $(x^*,y^*)$ and the nonnegative
equilibrium $(0,0)$ can be proved  (see Fig.1(c)(d)(e)).
\begin{figure}[ht]
\begin{center}
\includegraphics[width=0.8\textwidth]{fig1ab} %{(ab)}
\end{center}
\end{figure}
\begin{figure}[ht]
\begin{center}
\includegraphics[width=0.8\textwidth]{fig1cd} %{cd}
\end{center}
\end{figure}
\begin{figure}[ht]
\begin{center}
\includegraphics[width=0.3\textwidth]{fig1e} %{e}
\end{center}
\caption{} \label{fig:figure3.1}
\end{figure}


\begin{theorem} \label{thm3.1}
The point $(0,0)$ is always an equilibrium of system \eqref{e3.1}.
If $r^u<D^l$ and $(D^u)^2<(D^l-r^u)(d^lC_0^l+D^l-r^u)$,
then $(0,0)$ is the unique nonnegative equilibrium,  it is a stable node.
\end{theorem}

\begin{proof}
Obviously,  $(0,0)$ is an equilibrium system of
\eqref{e3.1}.  The Jacobian matrix corresponding to the linearized system
of \eqref{e3.1},  at $(0,0)$, is
$$
J(0,0)=\begin{pmatrix}
r^u-D^l-d^lC_0^l & D^u \\
D^u & r^u-D^l
\end{pmatrix}.
$$
Hence,  the stability of $(0,0)$ is determined by the characteristic
equation's eigenvalues $\lambda_1,\lambda_2$  that satisfy
$$
\lambda^2-[2r^u-2D^l-d^lC_0^l]\lambda+(r^u-D^l)(r^u-D^l-d^lC_0^l)-(D^u)^2=0.
$$
Solving it produces
\begin{align*}
\Delta &= [2r^u-2D^l-d^lC_0^l]^2-4(r^u-D^l)(r^u-D^l-d^lC_0^l)+4(D^u)^2\\
&= (d^lC_0^l)^2+4(D^u)^2>0.
\end{align*}
Assuming without loss of generality that $\lambda_1<\lambda_2$,  we
have
\begin{gather*}
\lambda_{1}+\lambda_{2}=2r^u-2D^l-d^lC_0^l<0,\\
\lambda_{1}\lambda_{2}=(r^u-D^l)(r^u-D^l-d^lC_0^l)-(D^u)^2>0.
\end{gather*}
Hence, when the condition of the theorem is satisfied,  which
implies  $\lambda_1<\lambda_2<0$,  therefore $(0,0)$ is a stable
node. This completes the proof.
\end{proof}

\begin{theorem} \label{thm3.2}
 If $r^u<D^l$, and $(D^u)^2> (D^l-r^u)(d^lC_0^l+D^l-r^u)$,
 or $r^u\geq D^l$, then there exists a unique positive equilibrium
 $(x^{*},y^{*})$ of \eqref{e3.1}
which is a stable node.
\end{theorem}

\begin{proof} our previous discussion establishes the
existence of a positive equilibrium. Now, we analyze the local
geometric properties of $(x^{*},y^{*})$. The Jacobian matrix of
$(x^{*},y^{*})$ is
\begin{align*}
J(x^{*},y^{*})&=\begin{pmatrix}
r^u-D^l-d^lC_0^l-2a^lx^* & D^u \\
D^u & r^u-D^l-2b^ly^*
\end{pmatrix} \\
&=\begin{pmatrix}
-\frac{D^u y^{*}}{x^{*}}-a^l x^{*} & D^u\\
D^u & -\frac{D^u x^{*}}{y^{*}}-b^l y^{*}
\end{pmatrix}.
\end{align*}
Hence, the stability of $(x^{*},y^{*})$ determined by the
characteristic equation's eigenvalues
$$
\lambda^{2}+ [\frac{D^u y^{*}}{x^{*}}+a^l x^{*}
+\frac{D^u x^{*}}{y^{*}}+b^l y^{*}]\lambda +(\frac{D^u
y^{*}}{x^{*}}+a^l x^{*})(\frac{D^u x^{*}}{y^{*}}+b^l
y^{*})-(D^u)^2=0.
$$
\begin{align*}
\Delta &= [\frac{D^u y^{*}}{x^{*}}+a^l x^{*} +\frac{D^u
x^{*}}{y^{*}}+b^l y^{*}]^{2} -4(\frac{D^u y^{*}}{x^{*}}+a^l
x^{*})(\frac{D^u x^{*}}{y^{*}}+b^l
y^{*})+4(D^u)^2\\
&= [(\frac{D^u y^{*}}{x^{*}}+a^l x^{*})-(\frac{D^u x^{*}}{y^{*}}+b^l
y^{*})]^{2} +4(D^u)^2>0.
\end{align*}
Under the condition of the theorem,  it produces
$\lambda_{1}+\lambda_{2}<0$, $\lambda_{1}\lambda_{2}>0$. We have
$\lambda_{1}<\lambda_{2}<0$.  $(x^{*},y^{*})$ is a stable node. The
proof is completed.
\end{proof}

\begin{theorem} \label{thm3.3}
Each trajectory of \eqref{e3.1} starting in $R^2_+$ is positive-going bounded.
\end{theorem}

\begin{proof}
We want to construct an outer boundary of
a positive invariant region which contains $(x^{*},  y^{*})$. Let
$AB$ and $BC$ be the line segments of $L_{1}:x=p$,  $L_{2}:y=q$, and
$(p, q)$ is an arbitrary fixed point in $R^2_+$ satisfying $p>x^{*}$
and
$$
\frac{r^u-D^l+\sqrt{(r^u-D^l)^2+4b^lD^up}}
{2b^l}<q<\frac{(a^lp+d^lC_0^l+D^l-r^u)p}{D^u}
$$
where the intersections of the straight line $L_1$ and $l_1,l_2$ are
$F(p,y_2)$ and $E(p,y_1)$ respectively.
\begin{gather*}
y_1=\frac{r^u-D^l+\sqrt{(r^u-D^l)^2+4b^lD^up}}{2b^l},\\
y_2=\frac{(a^lp+d^lC_0^l+D^l-r^u)p}{D^u}
\end{gather*}
\begin{figure}[ht]
\begin{center}
\includegraphics[width=0.3\textwidth]{fig2} %2}
\end{center}
\caption{with $A(p,0),B(p,q),C(0,q),E(p,y_1),F(p,y_2),P(x^*,y^*)$}
\label{fig:figure2}
\end{figure}
The domain is enclosed by $OABCO$,   (see Fig. 2). By the sign of
$\dot x, \dot y$,  we can say that the trajectory starting from $(p,
q)$ of \eqref{e3.1} can not leave the confined set.
\begin{gather*}
\dot x\mid _{x=0}= D^u y>0,\\
\dot y\big|_{y=0}= D^u x>0,\\
\dot x\big|_{x=p}= p(r^u-Dl-d^lC_0^l-a^lp)+D^uy<0,\\
\dot y\big|_{y=q}= q(r^u-D^l-b^lq)+D^ux<0.
\end{gather*}


This completes the proof.
\end{proof}

\begin{theorem} \label{thm3.4}
For system \eqref{e3.1},
 if $r^u<D^l$ and $(D^u)^2< (D^l-r^u)(d^lC_0^l+D^l-r^u)$, then $(0,0)$ is
the unique nonnegative equilibrium,  it is globally asymptotically stable.
\end{theorem}

\begin{proof}
By theorem 3.3,  we can easily prove that in $OABCO$,
$$
\frac{\partial P}{\partial x}+\frac{\partial Q}{\partial y}
=-2r^u-2D^l-d^lC_0^l-2a^lx-2b^ly<0
$$
then by Poincare-Bendixon
theorem there are no limit cycles in $OABCO$,
 and $(0,0)$ is the unique
positive equilibrium which is stable node in $OABCO$, so it is
globally asymptotically stable.  This completes the
proof.\end{proof}

\begin{theorem} \label{thm3.5}
For system \eqref{e3.1}, if $r^u<D^l$ and
$(D^u)^2>(D^l-r^u)(d^lC_0^l+D^l-r^u)$,  or $r^u\geq D^l$ then $(x^*,y^*)$ is
the unique positive equilibrium, it is globally asymptotically
stable.
\end{theorem}

\begin{proof}
We construct the  Liapunov function
$$
V(x,y)=\alpha(x-x^*-x^*\ln\frac{x}{x^*})+\beta(y-y^*-y^*\ln\frac{y}{y^*}),
$$
where $\alpha,\beta$  are positive constants.  Calculating the
derivative of $V(x,y)$ along \eqref{e3.1}, we have
\begin{align*}
V'_{\eqref{e3.1}}(x,y)
&= \alpha(x-x^*)\frac{\dot x}{x}+\beta(y-y^*)\frac{\dot y}{y} \\
&= -\alpha a^l(x-x^*)^2-\beta b^l(y-y^*)^2\\
&\quad +\alpha
D^u(x-x^*)(\frac{y}{x}-\frac{y^*}{x^*})+\beta
D^u(y-y^*)(\frac{x}{y}-\frac{x^*}{y^*})\\
&= -x^* a^l(x-x^*)^2-y^* b^l(y-y^*)^2\\
&\quad - D^u[\sqrt{\frac{y}{x}}(x-x^*)-\sqrt{\frac{x}{y}}(y-y^*)]^2
\leq 0,
\end{align*}
In fact,  we choose that $\alpha=x^*$, $\beta=y^*$.   We can see that
in the domain $OABCO$, $V'_{\eqref{e3.1}}=0$ if and only if $x=x^*$,
$y=y^*$. Hence $(x^*,y^*)$ is globally asymptotically stable.
This completes the proof.
\end{proof}

The specific computation is similar to above-proved theorems, for
the system \eqref{e3.2}  has two equilibria $O(0,0)$ and
$(x^{**},y^{**})$.

\begin{theorem} \label{thm3.6}
The point $(0,0)$ is always an
equilibrium of system \eqref{e3.2}. If $r^l<D^u$,
$(D^l)^2<(D^u-r^l)(d^uC_0^u+D^u-r^l)$, then $(0,0)$ is the unique
nonnegative equilibrium,  which is a stable node and globally
asymptotically stable.
\end{theorem}

\begin{theorem} \label{thm3.7}
 If  $r^l<D^u$ and $(D^l)^2> (D^u-r^l)(d^uC_0^u+D^u-r^l)~$,
or $r^l\geq D^u$, then
there exists a unique positive equilibrium $(x^{*},y^{*})$ of system
\eqref{e3.2}
which is a stable node and globally asymptotically stable.
\end{theorem}

In other words,  for the systems \eqref{e3.1}, \eqref{e3.2},  when the only
nonnegative equilibrium $(0,0)$ exists,  it is stable node and is
globally asymptotically stable.  If the $(0,0)$ is unstable,  then
there exists a unique positive equilibrium which is globally
asymptotically stable.

\section{Permanence and Extinction}

In this section,  we study the permanence and extinction of
population of system \eqref{e2.3}.

\begin{theorem} \label{thm4.1}
 (1)   If $r^u<D^l$ and $(D^l)^2> (D^u-r^l)(d^uC_0^u+D^u-r^l)$,
 or $r^l\geq D^u$, then the system \eqref{e2.3} is permanent;
  (2) If $r^u<D^l$ and $(D^u)^2< (D^l-r^u)(d^lC_0^l+D^l-r^u)$,
  system \eqref{e2.3} goes to extinction.
\end{theorem}

\begin{proof}  From the conditions  $(1)$ of the theorem,  we
know that $r^l<D^u$  and $(D^u)^2>(D^ul-r^u)(d^lC_0^l+D^l-r^u)$,
or $r^u\geq D^l$  holds.  By the
above discussion of the theorem 3.5 and 3.7,  we know that the
system \eqref{e3.1} and \eqref{e3.2} have the globally asymptotically stable
positive equilibria $(x^*,y^*)$  and  $(x^{**},y^{**})$,
  the trivial equilibrium $(0,0)$  is unstable.
 We construct a positively invariant region for system  \eqref{e2.3}.

 \begin{figure}[ht]
\begin{center}
\includegraphics[width=0.3\textwidth]{fig3} %{3}
\end{center}
\caption{ The rectangle $ABCD$ with $A(p_1,q_1),$ $B(p_2,q_1),$
$C(p_2,q_2),$ $D(p_1,q_2)$  and $P(x^{**},y^{**}),$ $Q(x^*,y^*)$}
\label{fig:figure3}
\end{figure}
  where $p_1,p_2,q_1,q_2$ are
 positive constants satisfying
$$
 p_1<\min\{x^*,x^{**}\},\quad p_2>\max\{x^*,x^{**}\},
$$
\begin{align*}
& \frac{p_1}{D^l}(a^up_1+d^uC_0^u+D^u-r^l)\\
& <q_1\\
& <\min\{y^*,y^{**},  \frac{-(r^l-D^u)+\sqrt{(r^l-D^u)^2+4b^uD^lp_1}}{2b^u}\},
\end{align*}
and
\begin{align*}
 &\max\{y^*,y^{**},\frac{-(r^u-D^l)+\sqrt{(r^u-D^l)^2+4b^lD^up_2}}{2b^l}\}\\
 &<q_2\\
 &<\frac{p_2}{D^u}(a^lp_2+d^lC_0^l+D^l-r^u).
\end{align*}
Since
 \begin{gather*}
 \dot {x}(t)\big|_{x=p_1}\geq  p_1(r^l-D^u-d^uC_0^u+a^up_1)+D^ly\big|_{q_1\leq y\leq
 q_2}>0,\\
 \dot {x}(t)\big|_{x=p_2}\leq  p_2(r^u-D^l-d^lC_0^l+a^lp_2)+D^uy\big|_{q_1\leq y\leq q_2}<0,\\
 \dot {y}(t)\big|_{y=q_1}\geq  q_1(r^l-D^u-b^uq_1)+D^lx\big|_{p_1\leq x\leq p_2}>0,\\
\dot {y}(t)\big|_{y=q_2} \leq q_2(r^u-D^l-b^lq_2)+D^ux\big|_{p_1\leq
x\leq p_2}<0,
\end{gather*}
So the compact confined set $ABCD$ in $R^2_+$,  the phase
trajectories of the system \eqref{e2.3} starting from the boundary always
point into the enclosed domain.  According to the Kamke theorem and
definition \ref{def2.1},  for any positive solution $(x(t),y(t))$ of
\eqref{e2.3} with positive initial value,  there exists a time T, when
$(x(t),y(t))$ goes in the $ABCD$ and never leaves  for all $t>T$.
Hence the system \eqref{e2.3} is permanent.


Let $(x(t),y(t))$  be an arbitrary positive solution of system
\eqref{e2.3}  with the positive initial value;  $(x^*(t),y^*(t))$ and
$(x^{**}(t),y^{**}(t))$ are the same of systems \eqref{e3.1}  and \eqref{e3.2}
respectively.  Choose initial value
$x^{**}(0)=x(0)=x^*(0)$, $y^{**}(0)=y(0)=y^*(0)$,   If the condition
(2)  of the theorem exists,  then the conditions $r^l<D^u$ and
$(D^l)^2< (D^u-r^l)(d^uC_0^u+D^u-r^l)$ hold, according to the
Theorem \ref{thm3.4} and \ref{thm3.6},  we know that the systems \eqref{e3.1}
and \eqref{e3.2} have unique trivial equilibrium $(0,0)$ which is globally
asymptotically stable.  By the Kamke theorem,
$x^{**}(t)\leq x(t) \leq x^*(t)$,
$y^{**}(t)\leq y(t)\leq y^*(t)$, for $t\geq 0$.
Furthermore,  we have
$$
\lim_{t\to +\infty}x(t)=\lim_{t\to +\infty}y(t)=0,
$$
then  system \eqref{e2.3} is extinctive.
\end{proof}

\subsection*{Discussion}  The toxic of the polluted population comes from
the environment. Suppose environment of patch 1 is
polluted--non-protective patch, and patch 2 is the ecological
protective patch. In order to protect the existence of the polluted
population, we can use the artificial method, the one's own
purification function of the population, toxin in the body of the
individuals in patch 1 can be removed, then we will put them into
the protective patch. Set up ecological protective patch need a
large number of financial resources, material resources and
manpower, so when the scale of the protective patch is too large,
individuals of some populations are put back non-protective patch.
So, they will be polluted by the toxic in the patch1. The scale of
the protection zone can be regulated through diffusive coefficient
$D(t)$.

These conditions can simplify the mathematical model,  I supposed
that no toxic effects in the protective patch.  The nest step in
these investigations would be to consider systems in which there are
toxic in the protective patch.

\subsection*{Acknowledgements}
The authors are grateful to the referees for the valuable comments
and suggestions which have improved our representation in this
paper..

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