
\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
{\em Electronic Journal of Differential Equations},
Vol. 2006(2006), No. 18, pp. 1--12.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu  (login: ftp)}
\thanks{\copyright 2006 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2006/18\hfil Oscillation for higher order ODEs]
{Oscillation for higher order nonlinear
ordinary differential equations with impulses}
\author[C. Zhang, W. Feng\hfil EJDE-2006/18\hfilneg]
{Chaolong Zhang, Weizhen Feng}  

\address{Chaolong Zhang \hfill\break
 Department of Computation Science,\\
 Zhongkai University of Agriculture and Technology,
 Guangzhou, 510225, China}
\email{zhcl88@126.com}

\address{Weizhen Feng \hfill\break
 School of Mathematical Sciences \\
 South China Normal University, Guangzhou 510631, China}
\email{wsy@scnu.edu.cn}


\date{}
\thanks{Submitted October 19, 2005. Published February 2, 2006.}
\thanks{Supported by grant 011471 from the Natural Science
Foundation of Guangdong, \hfill\break\indent
grant 0120 from the Natural Science
Foundation of Guangdong Higher Education, \hfill\break\indent
and grant Z03052 from the Natural Science Foundation of
Guangdong Education Bureau.}
\subjclass[2000]{34A37, 34K06, 34K11, 34K25}
\keywords{Higher order; impulses; oscillation; ODE}

\begin{abstract}
 In this paper, we study the oscillation of solutions to
 higher order nonlinear ordinary differential equations
 with impulses.  Several criteria for the oscillations of
 solutions are given. We find some suitable impulse functions
 such that all  solutions are oscillatory under the impulse
 control.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{corollary}[theorem]{Corollary}
\newtheorem{definition}[theorem]{Definition}
\allowdisplaybreaks

\section{Introduction}

 There are many publication on the oscillation of solutions to classical
second order nonlinear ordinary differential equations; see for example
\cite{a1,b1,b2,k1,k2,k3,t1,w1,w2,w3}. There are also some publications on
the oscillation of second order ODEs with impulses \cite{c1,h1,l2}, and some
on higher order \cite{c2,f1}.  In this paper, we study higher order
nonlinear ODEs with impulses. Under conditions (A) (B) (C) stated below,
we can always find some suitable impulse functions such that all
the solutions of the equation become oscillatory under the impulse
control. We believe that this oscillation result, under the impulse
control, is significant both for the theory and the applications.

\section{Main results}
We consider the system
\begin{equation} \label{e1}
\begin{gathered}
 x^{(2n)}(t)+f(t,x(t))=0,  \quad  t\geq t_0,\; t\neq t_k,\\
 x^{(i)}(t_k^+)=g_{k(i)}(x^{(i)}(t_k)),\quad i=0,1,\dots,2n-1,\;
   k=1,2\dots,\\
 x^{(i)}(t^+_0)=x^{(i)}_0,
\end{gathered}
\end{equation}
where
\begin{gather*}
x^{(i)}(t_k)=\lim_{h\to 0^{-}}\frac{x^{(i-1)}(t_k+h)-x^{(i-1)}(t_k)}{h},
\\
x^{(i)}(t^+_k)=\lim_{h\to 0^{+}}\frac{x^{(i-1)}(t_k+h)-x^{(i-1)}(t^+_k)}{h}\,,
\end{gather*}
$ 0<t_0<t_1<t_2<\dots<t_k<\dots$, $k=1,2,\dots$,
$\lim_{k\to \infty}t_k=+\infty$, $x^{(0)}(t)=x(t)$, and $n$ is
a natural number. In this article, we assume that the following conditions:
\begin{itemize}
\item[(A)]  $f(t,x)$ is continuous on
$[t_0,+\infty)\times(-\infty,+\infty)$;  $xf(t,x)>0$ for $x\neq0$;
$\frac{f(t,x)}{\varphi(x)}\geq p(t)$ for $x\neq 0$, where $p(t)$ is
positive and continuous on $[t_0,+\infty)$;
$x\varphi(x)>0$ for $x\neq 0$;  $\varphi'(x)\geq0$.

\item[(B)] $g_{k(i)}(x)$ is continuous on $(-\infty,+\infty)$, and
there exist  positive numbers $a^{(i)}_k,b^{(i)}_k$ such that
$$
a^{(i)}_k\leq \frac{g_{k(i)}(x)}{x}\leq b^{(i)}_k,i=0,1,\dots,2n-1.
$$
\item[(C)]
      \begin{equation} \label{e2}
\begin{aligned}
 &(t_1-t_0)+\frac{a^{(i)}_1}{b^{(i-1)}_1}(t_2-t_1)+\frac{a^{(i)}_1a^{(i)}_2}
      {b^{(i-1)}_1b^{(i-1)}_2}(t_3-t_2)\\
  &+\dots+\frac{a^{(i)}_1a^{(i)}_2\dots a^{(i)}_m}
      {b^{(i-1)}_1b^{(i-1)}_2\dots b^{(i-1)}_m}(t_{m+1}-t_m)+\dots=+\infty,
\end{aligned}
      \end{equation}
\end{itemize}

\begin{definition} \label{def1} \rm
A function $x:[t_0,t_0+\alpha)\to \mathbb{R}$, $t_0>0$, $\alpha>0$
is said to be a solution of \eqref{e1}, if
\begin{itemize}
\item[(i)] $x^{(i)}(t^+_0)=x^{(i)}_0$, $i=0,1,\dots 2n-1$
\item[(ii)]  for $t\in[t_0,t_0+\alpha)$ and $t\neq t_k$, $x(t)$ satisfies
$ x^{(2n)}(t) +f(t,x(t))=0$
\item[(iii)]  $x^{(i)}(t)$ is left continuous on
$t_k\in[t_0,t_0+\alpha)$, and
 $x^{(i)}(t^+_k)=g_{k(i)}x^{(i)}(t_k)$, $i=0,1,\dots 2n-1$.
\end{itemize}
\end{definition}

\begin{definition} \label{def2} \rm
 A solution of \eqref{e1} is said to be non-oscillatory
if it is eventually positive or eventually negative. Otherwise,this
solution is said to be oscillatory.
\end{definition}

Since \eqref{e1} can be transformed into
a first-order impulsive differential system, theorems on the
existence of solutions, the uniqueness of solutions and the
existence of global solutions can be seen in \cite{l1}. In the
following, we always assume the solutions of \eqref{e1} exists on
$[t_0,+\infty)$.

\begin{lemma} \label{lem1}
Let $x(t)$ be a solution of \eqref{e1}, and conditions
(A), (B), (C) be satisfied. Suppose that there exists an
$i\in\{{1,2,\dots,2n-1\}}$ and  some $T\geq t_0$, such that
$x^{(i)}(t)>0$ $(<0)$, $x^{(i+1)}(t)\geq0$ $(\leq0)$ for $t\geq T$.
Then there exists some $T_1\geq T$, such that $x^{(i-1)}(t)>0$ $(<0)$,
for $t\geq T_1$.
\end{lemma}

\begin{proof}
 Without loss of generality, let $T=t_0$, $x^{(i)}(t)>0$,
$x^{(i+1)}(t)\geq 0$ for $t\geq T$.
 Assume that for any $t_k>T$, $x^{(i-1)}(t_k)<0$.
By $x^{(i+1)}(t)\geq0$, $x^{(i)}(t)>0$, $t\in(t_k,t_{k+1}]$,
 we have that $x^{(i)}(t)$ is monotonically nondecreasing  on
$(t_k,t_{k+1}]$. For $t\in(t_1,t_2]$, we have
$$
x^{(i)}(t)\geq x^{(i)}(t^+_1)
$$
Integrating the above inequality, we have
\begin{equation} \label{e3}
x^{(i-1)}(t_2)\geq x^{(i-1)}(t^+_1)+x^{(i)}(t^+_1)(t_2-t_1)
\end{equation}
Similarly,
\begin{equation} \label{e4}
x^{(i-1)}(t_3)\geq x^{(i-1)}(t^+_2)+x^{(i)}(t^+_2)(t_3-t_2)
\end{equation}
 From $x^{(i)}(t_2)\geq x^{(i)}(t^+_1)$ and \eqref{e3}, \eqref{e4},
we have
\begin{align*}
&x^{(i-1)}(t_3)\geq x^{(i-1)}(t^+_2)+x^{(i)}(t^+_2)(t_3-t_2)\\
&\geq b^{(i-1)}_2x^{(i-1)}(t_2)+a^{(i)}_2x^{(i)}(t_2)(t_3-t_2)\\
&\geq b^{(i-1)}_2[x^{(i-1)}(t^+_1)+x^{(i)}(t^+_1)(t_2-t_1)]+a^{(i)}_2
                x^{(i)}(t_2)(t_3-t_2)\\
&\geq b^{(i-1)}_2[x^{(i-1)}(t^+_1)+x^{(i)}(t^+_1)(t_2-t_1)+\frac
                 {a^{(i)}_2}{b^{(i-1)}_2}x^{(i)}(t^+_1)(t_3-t_2)]\\
\end{align*}
Applying induction, we have that for any natural number $m$,
\begin{equation} \label{e5}
\begin{aligned}
x^{(i-1)}(t_m)
&\geq b^{(i-1)}_{m-1}\dots
b^{(i-1)}_3b^{(i-1)}_2\big\{x^{(i-1)}(t^+_1)
+x^{(i)}(t^+_1)[(t_2-t_1)\\
&\quad +\frac {a^{(i)}_2}{b^{(i-1)}_2}(t_3-t_2)+\dots+\frac
{a^{(i)}_2a^{(i)}_3 \dots a^{(i)}_{m-1}}
{b^{(i-1)}_2b^{(i-1)}_3\dots b^{(i-1)}_{m-1}}(t_m-t_{m-1})]\big\}
\end{aligned}
\end{equation}
By condition (C) and $a^{(i)}_k>0$, $b^{(i-1)}_k>0$, for all
sufficiently large $m$,  we have $x^{(i-1)}(t_m)>0$. Which is
contrary to the assumption.
 Hence, there exists some $j$ such that $t_j>T$ and $x^{(i-1)}(t_j)\geq0$.
Then
$$
x^{(i-1)}(t^+_j)\geq a^{(i-1)}_jx^{(i-1)}(t_j)\geq0.
$$
Note that $x^{(i)}(t)>0$ yields  $x^{(i-1)}(t)$ being monotonically
increasing on $(t_j,t_{j+1}]$. For $t\in(t_j,t_{j+1}]$, we have
$$
x^{(i-1)}(t)> x^{(i-1)}(t^+_j)\geq0.
$$
Especially,
$$
x^{(i-1)}(t_{j+1})>x^{(i-1)}(t^+_j)>0.
$$
Similarly, for $t\in(t_{j+1},t_{j+2}]$, we have
$$
x^{(i-1)}(t)>x^{(i-1)}(t^+_{j+1})\geq a^{(i-1)}_{j+1}x^{(i-1)}(t_{j+1})>0.
$$
By induction,for $t\in(t_{j+m-1},t_{j+m}]$, we have
$x^{(i-1)}(t)>0$. So for $t\geq t_{j+1}$, we have
$$
x^{(i-1)}(t)>0.
$$
Summing up the above discussion, there exists
some $T_1\geq T$ such that $x^{(i-1)}(t)>0$, $t\geq T_1$.
The proof of the other case in this theorem is similar;
so we omit it. The proof of Lemma \ref{lem1} is complete.
\end{proof}


\begin{lemma} \label{lem2}
Let $x(t)$ be a solution of \eqref{e1} and conditions
(A), (B), (C) be satisfied. Suppose that there exist an
$i\in\{1,2,\dots,2n\}$ and some $T\geq t_0$ such that
$x(t)>0$, $x^{(i)}(t)\leq0$, for $t\geq T$, and $x^{(i)}(t)$ is not
always equal to 0 in  $[t,+\infty)$.
Then $x^{(i-1)}(t)>0$ for all sufficiently large $t$.
\end{lemma}

\begin{proof}  Without loss of
generality, let $T=t_0$. We claim that
$x^{(i-1)}(t_k)>0$ for any $t_k\geq T$.
If it is not true, then there exists some $t_j\geq T$, such that
$x^{(i-1)}(t_j)\leq0$. Since $x^{(i)}(t)\leq0$, $x^{(i-1)}(t)$ is
monotonically non-increasing in $(t_k,t_{k+1}]$ for $k\geq j$.
Also because $x^{(i)}(t)$ is not always equal to 0 in $[t,+\infty)$,
there exists some $t_l\geq t_j$ such that $x^{(i)}(t)$ is not
always equal to 0 in $(t_l,t_{l+1}]$. Without loss of
generality, we can assume $l=j$,  that is, $x^{(i)}(t)$ is not
always equal to 0 in $(t_j,t_{j+1}]$. So we have
$$
x^{(i-1)}(t_{j+1})<x^{(i-1)}(t^+_j)\leq a^{(i-1)}_jx^{(i-1)}(t_j)\leq0.
$$
For $t\in(t_{j+1},t_{j+2}]$, we have
$$
x^{(i-1)}(t_{j+2})< x^{(i-1)}(t^+_{j+1})
\leq a^{(i-1)}_{j+1}x^{(i-1)}(t_{j+1})<0.
$$
By induction, for $t\in(t_{j+m},t_{j+m+1}]$, we have
$x^{(i-1)}(t)<0$. So we have
$x^{(i-1)}(t)<0,x^{(i)}(t)\leq0$, $t\in(t_{j+1},+\infty)$.
By Lemma \ref{lem1},for all sufficiently large $t$,we have $x^{(i-2)}(t)<0$.
Similarly, we can conclude, using Lemma \ref{lem1} repeatedly, that for all
sufficiently large $t$, we have $x(t)<0$. This is a contradiction to
$x(t)>0$ ($t\geq T$). Hence, we have $x^{(i-1)}(t_k)>0$ for any
$t_k\geq T$. So we have $x^{(i-1)}(t)>0$ for all sufficiently large
$t$. The proof of Lemma \ref{lem2} is complete.
\end{proof}


\begin{lemma} \label{lem3}
 Let $x(t)$ be a solution of \eqref{e1} and conditions
(A), (B), (C) be satisfied. Suppose $T\geq t_0$, $x(t)>0$ for
$t\geq T$. Then there exist some
  $T'\geq T$ and $l\in\{1,3,\dots,2n-1\}$ such that for $t\geq T'$,
   \begin{equation} \label{e6}
\begin{gathered}
  x^{(i)}(t)>0,\quad i=0,1,\dots,l;\\
  (-1)^{i-1}x^{(i)}(t)>0,\quad i=l+1,\dots,2n-1;\\
  x^{(2n)}(t)\leq 0.
  \end{gathered}
  \end{equation}
\end{lemma}

\begin{proof}
Let $T=t_0$. Since $x(t)>0(t\geq t_0)$, by \eqref{e1} and
that $p(t)$ is nonnegative and is not always equal to 0 in any
$(t,+\infty)$, we have
$$
x^{(2n)}(t)=-f(t,x(t))\leq-p(t)\varphi(x(t))\leq0
$$
and $x^{(2n)}(t)$ is not always equal to 0 in $(t,+\infty)$.
By Lemma \ref{lem2}, we have $x^{(2n-1)}(t)>0$. Without loss of generality,
let $x^{(2n-1)}(t)>0$ for $t\geq t_0$. So $x^{(2n-2)}(t)>0$ is
monotonically nondecreasing on $(t_k,t_{k+1}]$. If for any
$t_k$, $x^{(2n-2)}(t_k)<0$, then $x^{(2n-2)}(t)<0(t\geq t_0)$. If
there exists some $t_j$ such that
$x^{(2n-2)}(t_j)\geq0$, by that $x^{(2n-2)}(t)$ is monotonically
increasing and $a^{(2n-2)}_k>0$,we get $x^{(2n-2)}(t)  >0$ for
$t>t_j$. So there exists some $T_1\geq T$, such that one of the following
statements hold
\begin{gather}
x^{(2n-1)}(t)>0,\quad x^{(2n-2)}(t)>0,\quad\mbox{for } t\geq T_1 \label{A1}\\
x^{(2n-1)}(t)>0, \quad x^{(2n-2)}(t)<0,\quad\mbox{for } t\geq T_1 \label{B1}
\end{gather}
  When \eqref{A1} holds, Lemma \ref{lem1} yields that $x^{(2n-3)}(t)>0$ for all
sufficiently large $t$. Using Lemma \ref{lem1} repeatedly,
  for all sufficiently large $t$,we can conclude that
$$
x^{(2n-1)}(t)>0,\quad x^{(2n-2)}(t)>0,\dots ,x'(t)>0,\quad x(t)>0.
$$
  When \eqref{B1} holds, by Lemma \ref{lem2}, we have $x^{(2n-3)}(t)>0$,
for all sufficiently large $t$.
 Hence,there exists some $T_2\geq T_1$ such that
\begin{gather}
 x^{(2n-3)}(t)>0,\quad x^{(2n-4)}(t)>0,\quad\mbox{for }t\geq T_2
\label{A2} \\
x^{(2n-3)}(t)>0,\quad x^{(2n-4)}(t)<0,\quad\mbox{for }t\geq T_2
\label{B2}
\end{gather}
  Repeating the discussion above, we can get, eventually, that there
exist some $T'\geq T$ and $l\in\{1,3,\dots,2n-1\}$,
  such that for $t\geq T'$,
\begin{gather*}
  x^{(i)}(t)>0,\quad i=0,1,\dots ,l;\\
  (-1)^{i-1}x^{(i)}(t)>0,\quad i=l+1,l+2,\dots,2n-1;\\
   x^{(2n)}(t)\leq 0.
\end{gather*}
The proof of Lemma \ref{lem3} is complete.
\end{proof}

We remark that if $x(t)$ is an eventually negative solution of \eqref{e1},
then there are conclusions similar to Lemma \ref{lem2} and Lemma \ref{lem3}.


\begin{theorem} \label{thm1}
If  conditions (A),(B),(C) hold, $a^{(0)}_k\geq1$ and
\begin{equation} \label{e7}
\begin{aligned}
&\int^{t_1}_{t_0}p(t)dt+\frac{1}{b^{(2n-1)}_1}\int^{t_2}_{t_1}p(t)dt+
      \frac{1}{b^{(2n-1)}_1b^{(2n-1)}_2}
      \int^{t_3}_{t_2} p(t)dt+\dots\\
&+\frac{1}{b^{(2n-1)}_1b^{(2n-1)}_2
      \dots b^{(2n-1)}_{m}}
      \int^{t_{m+1}}_{t_{m}}p(t)dt+\dots=+\infty
   \end{aligned}
   \end{equation}
then every solution of \eqref{e1} is oscillatory.
\end{theorem}

\begin{proof}
 Let $x(t)$ be a non-oscillatory solution of \eqref{e1}.
Without loss of generality, let $x(t)>0(t\geq t_0)$, By Lemma \ref{lem3}
 and  \eqref{e1}, there exists $T'\geq t_0$ such that,
for $t\geq T'$, we have
$$
x^{(2n)}(t)\leq 0,\quad x^{(2n-1)}(t)>0,\quad x'(t)>0,\quad x(t)>0.
$$
 So $x^{(2n-1)}(t)$ is monotonically non-increasing on $(t_k,t_{k+1}]$
 and $x(t)$ is monotonically increasing on $(t_k,t_{k+1}]$. Let
 $$
u(t)=\frac{x^{(2n-1)}(t)}{\varphi(x(t))}.
$$
 Then $u(t^+_k)\geq0$ ($k=1,2,\dots$), $u(t)\geq0$ ($t\geq t_0$).
Since $\varphi'(x)\geq0$, for $t\neq t_k$,
\begin{gather}
 u'(t)=-\frac{f(t,x(t))}{\varphi(x(t))}-\Big[\frac{x^{(2n-1)}(t)x'(t)}
 {\varphi^{2}(x(t))}\Big]\varphi'(x(t)) \leq-p(t) \label{e8}
\\
u(t^+_k)=\frac{x^{(2n-1)}(t^+_k)}{\varphi(x(t^+_k))}
  \leq\frac{b^{(2n-1)}_kx^{(2n-1)}(t_k)}{\varphi(a^{(0)}_kx(t_k))}
  \leq\frac{b^{(2n-1)}_kx^{(2n-1)}(t_k)}{\varphi(x(t_k))}
  \leq b^{(2n-1)}_ku(t_k)
\label{e9}
\end{gather}
 Integrating \eqref{e8} from $t_0$ to $t_1$ we have
 \begin{gather}
  u(t_1)\leq u(t^+_0)-\int^{t_1}_{t_0}p(t)dt \,,\label{e10}\\
  u(t^+_1)\leq b^{(2n-1)}_1u(t_1)\leq b^{(2n-1)}_1[u(t^+_0)
-\int^{t_1}_{t_0}p(t)dt] \,. \label{e11}
 \end{gather}
 Similar to the above inequality, we have
  \begin{equation} \label{e12}
\begin{aligned}
  u(t^+_2)&\leq b^{(2n-1)}_2u(t_2)\\
&\leq b^{(2n-1)}_2[u(t^+_1)-\int^{t_2}_{t_1}p(t)dt] \\
&\leq b^{(2n-1)}_2[b^{(2n-1)}_1u(t^+_0)-b^{(2n-1)}_1\int^{t_1}_{t_0}p(t)dt
          -\int^{t_2}_{t_1}p(t)dt]\\
&\leq b^{(2n-1)}_1b^{(2n-1)}_2[u(t^+_0)-\int^{t_1}_{t_0}p(t)dt-
          \frac{1}{b^{(2n-1)}_1}\int^{t_2}_{t_1}p(t)dt]
\end{aligned}
\end{equation}
By induction,  for any natural number $m$, we have
 \begin{equation} \label{e13}
\begin{aligned}
 u(t^+_m)
&\leq b^{(2n-1)}_1b^{(2n-1)}_2\dots b^{(2n-1)}_m
          [u(t^+_0)-\int^{t_1}_{t_0}p(t)dt-\frac{1}{b^{(2n-1)}_1}
          \int^{t_2}_{t_1}p(t)dt\\
&-\dots-\frac{1}
          {b^{(2n-1)}_1b^{(2n-1)}_2\dots b^{(2n-1)}_{m-2}}\int^{t_{m-1}}_{t_{m-2}}p(t)dt\\
&-\frac{1}{b^{(2n-1)}_1b^{(2n-1)}_2\dots b^{(2n-1)}_{m-2}b^{(2n-1)}_{m-1}}
          \int^{t_m}_{t_{m-1}}p(t)dt]
\end{aligned}
\end{equation}
By \eqref{e7} and \eqref{e13}, for all sufficiently large $m$,
$u(t^+_m)<0$. This contradicts $u(t^+_m)\geq0$. So every solution
of \eqref{e1} is oscillatory. The proof of Theorem \ref{thm1} is complete.
\end{proof}

\begin{theorem} \label{thm2}
If  conditions (A), (B), (C) hold,
$b_k^{(i)}\leq1$, $a_k^{(0)}\geq1$, $b_k^{(0)}\geq1$
($i=1,2,\dots,2n-1,\; k=1,2,\dots$) and
$\int^{+\infty}t^{2n-1}p(t)dt=+\infty$,
then every bounded solution of \eqref{e1} is oscillatory.
\end{theorem}

\begin{proof}
Let $x(t)$ be a non-oscillatory solution of
\eqref{e1}. Without loss of generality, let $x(t)>0$ for $t\geq t_0$.
By Lemma \ref{lem3}, we can divided \eqref{e6} into two cases:\\
Case (i): If $l=1$, then $x(t)>0$, $x'(t)>0$,
$x''(t)<0$, $x'''(t)>0$, $x^{(4)}(t)<0$, \dots, $x^{(2n-1)}(t)>0$,
$x^{(2n)}(t)\leq0$.\\
Case (ii): If $l\geq3$, then
$x(t)>0$, $x'(t)>0$, $x''(t)>0$, $x'''(t)>0$, \dots, $x^{(l)}(t)>0$,
$x^{(l+1)}(t)<0$, \dots, $x^{(2n-1)}(t)>0$, $x^{(2n)}(t)\leq0$.\\
Both cases tells us that
$x'(t)>0$, $t\in(t_k,t_{k+1}]$, $k=1,2,\dots.$ So $x(t)$ is
monotonically increasing on $(t_k,t_{k+1}]$.
Since $a^{(0)}_k\geq1$,  $x(t)$ is monotonically increasing on
$[t_0,+\infty)$, that is, $x(t)\geq x(t_0)$ for $ t\geq t_0$. By
\eqref{e1}, we have
\begin{equation} \label{e14}
x^{(2n)}(s)=-f(s,x(s))\leq-p(s)\varphi(x(t_0))=-cp(s),\quad
s\in(t_k,t_{k+1}]
\end{equation}
where $c=\varphi(x(t_0))>0$. Multiplying \eqref{e14} by $s^{2n-1}$ and
then integrating it from $t_k$ to $t$, we have
\begin{equation} \label{e15}
\int^{t}_{t_k}s^{2n-1}x^{(2n)}(s)ds<-c\int^{t}_{t_k}s^{2n-1}p(s)ds,\quad
t\in(t_k,t_{k+1}]\,.
\end{equation}
We will consider the following two cases:

\noindent{\bf (a)} if the case (i) holds, then for $t\in(t_k,t_{k+1}]$ we
have,
\begin{align*}
&\int^{t}_{t_k}s^{2n-1}x^{(2n)}(s)ds\\
&=\int^{t}_{t_k}s^{2n-1}dx^{(2n-1)}(s)\\
&=t^{2n-1}x^{(2n-1)}(t)
-t^{2n-1}_{k}x^{(2n-1)}(t^+_k)-(2n-1)\int^{t}_{t_k}s^{2n-2}x^{(2n-1)}(s)ds\\
&=\dots\\
&=\sum^{2n-1}_{i=0}(-1)^{i+1}\frac{(2n-1)!}{i!}t^{i}x^{(i)}(t)+
\sum^{2n-1}_{i=0}(-1)^{i}\frac{(2n-1)!}{i!}t^{i}_{k}x^{(i)}(t^+_k).
\end{align*}
Especially, for any natural number $k$,
\begin{align*}
&\int^{t_{k+1}}_{t_k}s^{2n-1}x^{(2n)}(s)ds\\
&=\sum^{2n-1}_{i=0}(-1)^{i+1}\frac{(2n-1)!}{i!}t^{i}_{k+1}x^{(i)}(t_{k+1})
+\sum^{2n-1}_{i=0}(-1)^{i}\frac{(2n-1)!}{i!}t^{i}_{k}x^{(i)}(t^+_k).
\end{align*}
No matter if $i$ is odd or even, for $i=1,2,\dots2n-1$,
$$
(-1)^{i}(x^{(i)}(t^+_k)-x^{(i)}(t_k))
\geq(-1)^{i}(b^{(i)}_k-1)x^{(i)}(t_k)\geq0.
$$
For any natural number $m$ and $t\in(t_m,t_{m+1}]$, we have
\begin{align*}
&\int^{t}_{t_1}s^{2n-1}x^{(2n)}(s)ds\\
&=\int^{t_2}_{t_1}s^{2n-1}x^{(2n)}(s)ds+\int^{t_3}_{t_2}s^{2n-1}x^{(2n)}(s)ds\\
&\quad+\dots+\int^{t_m}_{t_{m-1}}s^{2n-1}x^{(2n)}(s)ds+\int^{t}_{t_m}s^{2n-1}x^{(2n)}(s)ds\\
&=\sum^{2n-1}_{i=0}(-1)^{i+1}\frac{(2n-1)!}{i!}t^{i}x^{(i)}(t)
 +\sum^{2n-1}_{i=0}(-1)^{i}\frac{(2n-1)!}{i!}t^{i}_{1}x^{(i)}(t^+_1)\\
&\quad+\sum^{m}_{k=2}\sum^{2n-1}_{i=0}(-1)^{i}\frac{(2n-1)!}{i!}t^{i}_{k}
(x^{(i)}(t^+_k)-x^{(i)}(t_k))\\
&\geq-(2n-1)!x(t)+\sum^{2n-1}_{i=0}(-1)^{i}\frac{(2n-1)!}{i!}t^{i}_{1}x^{(i)}(t^+_1)\\
&\quad+\sum^{m}_{k=2}\sum^{2n-1}_{i=0}(-1)^{i}\frac{(2n-1)!}{i!}t^{i}_{k}
(b^{(i)}_k-1)x^{(i)}(t_k)\\
&\geq-(2n-1)!x(t)+\sum^{2n-1}_{i=0}(-1)^{i}\frac{(2n-1)!}{i!}
t^{i}_{1}x^{(i)}(t^+_1).
\end{align*}
Combining the inequality above and \eqref{e15}, we have
$$
-(2n-1)!x(t)+\sum^{2n-1}_{i=0}(-1)^{i}\frac{(2n-1)!}{i!}t^{i}_{1}x^{(i)}
(t^+_1)
\leq-c\int^{t}_{t_1}s^{2n-1}p(s)ds.
$$
So $x(t)\to +\infty,$ as $t\to +\infty$. This contradicts that $x(t)$
is bounded.

\noindent{\bf (b)} If the case (ii) holds, then
 $x(t)$ is non-negative and strictly increasing on $t\in[t_1,+\infty)$.
Hence, for any natural number $m$, we have
\begin{gather*}
x(t)=x(t^+_m)+\int^{t}_{t_{m}}x'(s)ds,\quad t\in(t_m,t_{m+1}],\\
x(t_m)=x(t^+_{m-1})+\int^{t_m}_{t_{m-1}}x'(s)ds, \\
\dots\\
x(t_2)=x(t^+_1)+\int^{t_2}_{t_1}x'(s)ds
\end{gather*}
and
\begin{equation} \label{e16}
x(t)=\sum^{m}_{k=2}(x(t^+_k)-x(t_k))+x(t^+_1)+\sum^{m-1}_{k=1}
\int^{t_{k+1}}_{t_k} x'(s)ds+\int^{t}_{t_m}x'(s)ds
\end{equation}
Since $x''(t)>0,t\in(t_k,t_{k+1}],k\geq1$, we can get
\begin{gather*}
x'(t)>x'(t^+_1)\geq a^{(1)}_1x'(t_1),\quad t\in(t_1,t_2]\\
x'(t)>x'(t^+_2)\geq a^{(1)}_2x'(t_2)>a^{(1)}_2a^{(1)}_1x'(t_1),
\quad t\in(t_2,t_3]\,.
\end{gather*}
Applying  induction, for any natural number $k$,
$$
x'(t)>x'(t^+_k)\geq a^{(1)}_{k}a^{(1)}_{k-1}\dots a^{(1)}_1x'(t_1),
\quad t\in(t_k,t_{k+1}]\,.
$$
Combining  \eqref{e16} and $a^{(0)}_k\geq1$, we have
$$
x(t)>x'(t_1)\sum^{m-1}_{k=1}a^{(1)}_{k}a^{(1)}_{k-1}\dots
a^{(1)}_1(t_{k+1}-t_k),\quad t\in(t_m,t_{m+1}]
$$
From the condition (C) and $b^{(0)}_k\geq1$, we have
$$
\sum^{+\infty}_{k=1}a^{(1)}_{k}a^{(1)}_{k-1}\dots a^{(1)}_1(t_{k+1}-t_k)
=+\infty
$$
Then $x(t)\to +\infty$ ($t\to +\infty$), which contradicts that
$x(t)$ is bounded. Therefore, every solution of \eqref{e1} is
oscillatory. The proof of Theorem \ref{thm2} is complete.
\end{proof}

\begin{theorem} \label{thm3}
If  conditions (A), (B), (C) hold,
$\prod^{m}_{k=1}a^{(0)}_{k}>b>0$ ($m=1,2,\dots$),
 $b_k^{(2n-1)}\leq1$, and for any $\delta>0$,
 \begin{equation} \label{e17}
\big|\int^{+\infty}\inf_{\delta\leq|x|<+\infty}
f(t,x)\,dt\big|=+\infty
\end{equation}
then every  solution of \eqref{e1} is oscillatory.
\end{theorem}

\begin{proof}
Let $x(t)$ be a non-oscillatory solution of \eqref{e1}. Without loss of
generality, let $x(t)>0$, $t\geq t_0$. By Lemma \ref{lem3},
$x'(t)\geq0$, $t\geq t_0$. So $x(t)$ is monotonically
nondecreasing on $(t_0,+\infty)$.
\begin{gather*}
x(t_1)\geq x(t^+_0),x(t_2)\geq x(t^+_1)
\geq a^{(0)}_1x(t_1)\geq a^{(0)}_1x(t^+_0),\\
x(t_3)\geq x(t^+_2)\geq a^{(0)}_2x(t_2)\geq a^{(0)}_2a^{(0)}_1x(t^+_0)
\end{gather*}
By induction, we have
$$
x(t_{m+1})\geq x(t^+_{m})\geq a^{(0)}_{m}x(t_{m})
\geq\dots\geq a^{(0)}_1a^{(0)}_2\dots a^{(0)}_{m} x(t^+_0)>bx(t^+_0).
$$
We can assume that $x(t)\geq bx(t^+_0)$, $t\in(t_0,+\infty)$.
By \eqref{e17}, as $t\to +\infty$, we have
$$
\int^{t}_{t_0} f(s,x(s))ds\geq\int^{t}_{t_0}\inf_{bx(t^+_0)\leq|x|
<+\infty} f(s,x)ds\to +\infty\,;
$$
that is, $\int^{t}_{t_0} f(s,x(s))ds\to +\infty$.
Integrating \eqref{e1} from $t_0$ to $t_1$, we have
$$
x^{(2n-1)}{(t_1)}+\int^{t_1}_{t_0} f(s,x(s))ds=x^{(2n-1)}{(t_0^+)}
$$
Similar to the above formula, for any natural number integrating
\eqref{e1} from $t_{k-1}$ to $t_k$, we have
$$
x^{(2n-1)}{(t_k)}+\int^{t_k}_{t_{k-1}} f(s,x(s))ds=x^{(2n-1)}{(t_{k-1}^+)}$$
So, we have
\begin{gather*}
x^{(2n-1)}{(t_1)}+\int^{t_1}_{t_0} f(s,x(s))ds=x^{(2n-1)}{(t_0^+)},\\
x^{(2n-1)}{(t_2)}+\int^{t_2}_{t_1} f(s,x(s))ds=x^{(2n-1)}{(t_1^+)},\\
\dots\\
x^{(2n-1)}{(t_m)}+\int^{t_m}_{t_{m-1}} f(s,x(s))ds=x^{(2n-1)}{(t_{m-1}^+)},\\
x^{(2n-1)}{(t)}+\int^{t}_{t_m} f(s,x(s))ds=x^{(2n-1)}{(t_m^+)}\,.
\end{gather*}
For $t\in(t_m,t_{m+1}]$, we have
$$
x^{(2n-1)}{(t)}+\sum^{m}_{i=1}x^{(2n-1)}{(t_i)}+\int^{t}_{t_0} f(s,x(s))ds
=\sum^{m}_{i=0}x^{(2n-1)}{(t_i^+)}.
$$
Then
$$
x^{(2n-1)}{(t)}+\sum^{m}_{i=1}\big(x^{(2n-1)}{(t_i)}
-x^{(2n-1)}{(t_i^+)}\big)+\int^{t}_{t_0} f(s,x(s))ds=x^{(2n-1)}{(t^+_0)}\,.
$$
Lemma \ref{lem3} shows that $x^{(2n-1)}(t)>0$ for sufficiently large $t$.
Hence,
\begin{equation} \label{e18}
x^{(2n-1)}{(t)}
\leq-\sum^{m}_{i=1}\Big((1-b_k^{(2n-1)})x^{(2n-1)}{(t_i)}\Big)
-\int^{t}_{t_0}f(s,x(s))ds+x^{(2n-1)}{(t^+_0)}
\end{equation}
By condition $b_k^{(2n-1)}\leq1$ and \eqref{e18}, we have
$x^{(2n-1)}{(t)}\leq -\int^{t}_{t_0}
f(s,x(s))ds+x^{(2n-1)}{(t^+_0)}\to -\infty$ as $t\to +\infty$.
So, for all sufficiently large $t$, $x^{(2n-1)}(t)<0$.
This contradicts that $x^{(2n-1)}(t)>0$. So every solution of \eqref{e1}
is oscillatory.
The proof of Theorem \ref{thm3}  is complete.
\end{proof}

\begin{corollary} \label{coro1}
Assume the conditions (A), (B), (C) hold,
and $a_k^{(0)}\geq1$, $b_k^{(2n-1)}\leq1$. If
$\int^{+\infty}p(t)dt=+\infty$, then every solution of \eqref{e1} is
oscillatory.
\end{corollary}

\begin{proof}  By $b_k^{(2n-1)}\leq1$, we have
\begin{align*}
&\int^{t_1}_{t_0}p(t)dt+\frac{1}{b^{(2n-1)}_1}\int^{t_2}_{t_1}p(t)dt+
  \frac{1}{b^{(2n-1)}_1b^{(2n-1)}_2}\int^{t_3}_{t_2} p(t)dt+\dots\\
 &+\frac{1}{b^{(2n-1)}_1b^{(2n-1)}_2\dots b^{(2n-1)}_{m}}
  \int^{t_{m+1}}_{t_{m}}p(t)dt\\
 &\geq\int^{t_1}_{t_0}p(t)dt+\int^{t_2}_{t_1}p(t)dt+\int^{t_3}_{t_2} p(t)dt
+\dots  +\int^{t_{m+1}}_{t_{m}}p(t)dt\\
&=\int^{t_{m+1}}_{t_0}p(t)dt\\
\end{align*}
and  $\int^{t_{m+1}}_{t_0}p(t)dt\to +\infty$ as $m\to +\infty$.
Then \eqref{e7} holds. By Theorem \ref{thm1},
every solution of \eqref{e1} is oscillatory.
\end{proof}

\begin{corollary} \label{coro2}
Assume conditions (A), (B), (C) hold,
and that there exists a positive number $\alpha>0$, such that
$a^{(0)}_k\geq1$, $\frac{1}{b_k^{(2n-1)}}\geq(\frac{t_{k+1}}{t_k})^{\alpha}$.
If $\int^{+\infty}t^{\alpha}p(t)dt=+\infty$, then every solution
of \eqref{e1} is oscillatory.
\end{corollary}

\begin{proof} By $\frac{1}{b_k^{(2n-1)}}\geq(\frac{t_{k+1}}{t_k})^{\alpha}$,
we have
\begin{align*}
&\int^{t_1}_{t_0}p(t)dt+\frac{1}{b^{(2n-1)}_1}\int^{t_2}_{t_1}p(t)dt+
      \frac{1}{b^{(2n-1)}_1b^{(2n-1)}_2}\int^{t_3}_{t_2} p(t)dt+\dots\\
&+\frac{1}{b^{(2n-1)}_1b^{(2n-1)}_2\dots b^{(2n-1)}_{m}}
      \int^{t_{m+1}}_{t_{m}}p(t)dt\\
&\geq\frac{1}{b^{(2n-1)}_1}\int^{t_2}_{t_1}p(t)dt+
      \frac{1}{b^{(2n-1)}_1b^{(2n-1)}_2}\int^{t_3}_{t_2} p(t)dt+\dots\\
&\quad +\frac{1}{b^{(2n-1)}_1b^{(2n-1)}_2\dots b^{(2n-1)}_{m}}
      \int^{t_{m+1}}_{t_{m}}p(t)dt\\
&\geq\frac{1}{t^{\alpha}_{1}}[\int^{t_2}_{t_1}t^{\alpha}_{2}p(t)dt
      +\int^{t_3}_{t_2}t^{\alpha}_{3}p(t)dt
      +\dots+\int^{t_{m+1}}_{t_{m}}t^{\alpha}_{m+1}p(t)dt]\\
&\geq\frac{1}{t^{\alpha}_{1}}[\int^{t_2}_{t_1}t^{\alpha}p(t)dt
      +\int^{t_3}_{t_2}t^{\alpha}p(t)dt
      +\dots+\int^{t_{m+1}}_{t_{m}}t^{\alpha}p(t)dt]\\
&=\frac{1}{t^\alpha_1}\int^{t_{m+1}}_{t_1}t^{\alpha}p(t)dt
\end{align*}
and $\int^{t_{m+1}}_{t_1}p(t)dt\to +\infty$ as $m\to +\infty$.
Then \eqref{e7} holds. By Theorem \ref{thm1}, we every solution of \eqref{e1}
is oscillatory.
\end{proof}

\section{Examples}
subsection*{Example 3.1}  Consider the equation
 \begin{equation} \label{e19}
 \begin{gathered}
 x^{(2n)}(t) +\frac{1}{4t}x^{3}=0, \quad t\geq \frac{1}{2},\;
t\neq k,\; k=1,2,\dots\\
 x(k^+)=\frac{k+1}{k}x(k),\quad  x^{(i)}(k^+)=x^{(i)}(k),\quad
i=1,\dots,2n-1,\\
 x(\frac{1}{2})=x_0,x^{(i)}(\frac{1}{2})=x^{(i)}_0,\
\end{gathered}
\end{equation}
where
$a^{(0)}_{k}=b^{(0)}_{k}=\frac{k+1}{k}>1$,
$a^{(i)}_{k}=b^{(i)}_{k}=1$, $i=1,2,\dots,2n-1$,
$p(t)=\frac{1}{4t}$, $\varphi(x)=x^{3}$,
$f(t,x)=\frac{1}{4t}x^{3}$, $t_k=k$, $t_0=\frac{1}{2}$.
It is obvious that the conditions (A) and (B) are satisfied.
For condition (C),we have:
For $i>1$, $a^{(i)}_{k}=b^{(i-1)}_{k}=1$,
\begin{align*}
&(t_1-t_0)+(t_2-t_1)+(t_3-t_2)+\dots+(t_{m+1}-t_m)+\dots\\
&=\frac{1}{2}+1+\dots+1+\dots=+\infty.
\end{align*}
For $i=1$, $a^{(1)}_{k}=1$, $b^{(0)}_{k}=\frac{k+1}{k}$,
\begin{align*}
&(t_1-t_0)+\frac{1}{2}(t_2-t_1)+\frac{1}{3}(t_3-t_2)+\dots
+\frac{1}{m+1}(t_{m+1}-t_m)+\dots\\
&=\frac{1}{2}+\frac{1}{2}+\frac{1}{3}+\dots+\frac{1}{m+1}+\dots=+\infty.
\end{align*}
Therefore, condition $(C)$ holds.
Since $b^{(2n-1)}_k=1$, we have
\begin{align*}
 &\int^{t_1}_{t_0}p(t)dt+\frac{1}{b^{(2n-1)}_1}\int^{t_2}_{t_1}p(t)dt+
      \frac{1}{b^{(2n-1)}_1b^{(2n-1)}_2}
      \int^{t_3}_{t_2} p(t)dt+\dots\\
 &+\frac{1}
      {b^{(2n-1)}_1b^{(2n-1)}_2
      \dots b^{(2n-1)}_{m}}
      \int^{t_{m+1}}_{t_{m}}p(t)dt\\
      &=\int^{t_1}_{t_0}p(t)dt+\int^{t_2}_{t_1}p(t)dt+\int^{t_3}_{t_2} p(t)dt+\dots
     +\int^{t_{m+1}}_{t_{m}}p(t)dt\\
 &=\int^{t_{m+1}}_{t_0}p(t)dt=\int^{t_{m+1}}_{t_0}\frac{1}{4t}dt \\
 &=\frac{1}{4}\ln t|^{t_{m+1}}_{t_0}=\frac{1}{4}(\ln t_{m+1}-\ln t_0)
\end{align*}
Since $\ln t_{m+1}\to +\infty$ as $m\to +\infty$, we get that the
condition of Theorem \ref{thm1} hold. So  every solution of
\eqref{e19} is oscillatory.

\subsection*{Example 3.2}
 Consider the sub-linear system
\begin{equation} \label{e20}
   \begin{gathered}
x^{(2n)}(t) +\frac{1}{t^2}x^{\frac{1}{3}}=0, \quad t\geq \frac{1}{2},\;
   t\neq k,k=1,2,\dots\,,\\
x(k^+)=x(k), x^{(i)}(k^+)=\frac{k}{k+1}x^{(i)}(k),\quad i=1,\dots,2n-1\,,\\
x(\frac{1}{2})=x_0,\quad x^{(i)}(\frac{1}{2})=x^{(i)}_0,
  \end{gathered}
\end{equation}
where
$a^{(0)}_{k}=b^{(0)}_{k}=1$, $a^{(i)}_{k}=b^{(i)}_{k}=\frac{k}{k+1}$,
$i=1,2,\dots,2n-1$, $p(t)=\frac{1}{t^2}$, $t_k=k$,
$\varphi(x)=x^{\frac{1}{3}}$, $f(t,x(t))=\frac{1}{t^2}x^{\frac{1}{3}}(t)$,
$t_0=\frac{1}{2}$.
It is obvious that the condition (A) and (B) hold. For condition (C),
we have:
For $i>1$ and $a^{(i)}_{k}=b^{(i-1)}_{k}=\frac{k}{k+1}$,
$$
(t_1-t_0)+(t_2-t_1)+(t_3-t_2)+\dots+(t_{m+1}-t_m)+\dots
=\frac{1}{2}+1+\dots+1+\dots=+\infty.
$$
For $i=1$ and $a^{(1)}_{k}=\frac{k}{k+1},b^{(0)}_{k}=1$,
\begin{align*}
&(t_1-t_0)+\frac{1}{2}(t_2-t_1)+\frac{1}{3}(t_3-t_2)
  +\dots+\frac{1}{m+1}(t_{m+1}-t_m)+\dots\\
&=\frac{1}{2}+\frac{1}{2}+\frac{1}{3}+\dots+\frac{1}{m+1}+\dots=+\infty.
\end{align*}
So,  condition $(C)$ holds. Let
$\alpha=1$. Then
$$
\frac{1}{b^{(2n-1)}_k}=\frac{k+1}{k}\geq
\frac{t_{k+1}}{t_k}=\frac{k+1}{k}
\int^{+\infty}tp(t)dt=\int^{+\infty}t\frac{1}{t^2}dt
=\int^{+\infty}\frac{1}{t}dt=+\infty\,.
$$
Therefore, the conditions of  Corollary \ref{coro2} are satisfied.
Then every solution of $(3.2)$ is oscillatory.

\subsection*{Acknowledgements}
 The authors are grateful to the anonymous referee for his (her)
suggestions and comments on the original  manuscript.

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\end{document}




\end{document}
