\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
{\em Electronic Journal of Differential Equations},
Vol. 2007(2007), No. 121, pp. 1--11.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu  (login: ftp)}
\thanks{\copyright 2007 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2007/121\hfil Stepanov-like almost automorphic solutions]
{Stepanov-like almost automorphic solutions for nonautonomous
evolution equations}

\author[S. Fatajou,  N. V. Minh,, G. M. N'Gu\'er\'ekata,  A. Pankov
\hfil EJDE-2007/121\hfilneg]
{Samir Fatajou, Nguyen Van Minh, \\
 Gaston M. N'Gu\'er\'ekata, Alexander Pankov}  % in alphabetical order

\address{Samir Fatajou \newline
Universit\'e Cadi Ayyad, Facult\'e des Sciences Semlalia, D\'epartement
de math\'ematiques, B.P. 2390 Marrakech, Morocco}
\email{fatajou@hotmail.fr}

\address{Nguyen Van Minh \newline
Department of Mathematics, University of West Georgia, Carrollton,
GA 30018, USA}
\email{vnguyen@westga.edu}

\address{Gaston M. N'Gu\'er\'ekata \newline
Department of Mathematics, Morgan State University, 1700 E. Cold
Spring Lane, Baltimore, MD 21251, USA}
\email{gnguerek@morgan.edu}

\address{Alexander Pankov \newline
Department of Mathematics, Morgan State University, 1700 E. Cold Spring Lane,
Baltimore, MD 21251, USA}
\email{pankov@member.ams.org}

\thanks{Submitted August 1, 2007. Published September 14, 2007.}
\subjclass[2000]{43A60, 34G20}
\keywords{Stepanov-like, Almost automoprhic}

\begin{abstract}
 We study the convolution of Stepanov-like almost automorphic functions
 and $L^1$ functions. Also we consider nonautonomous evolution equations,
 with a periodic operator coefficient and Stepanov-like almost automorphic
 forcing, and show that, under certain assumptions, any bounded mild
 solution is almost automorphic.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{definition}[theorem]{Definition}
\newtheorem{example}[theorem]{Example}
\newtheorem{remark}[theorem]{Remark}

\section{Introduction}

The notion of almost periodic function was introduced by  Bohr in
1925. Shortly after, in 1926, Stepanov found a wider class of
almost periodic  functions that are commonly known now as Stepanov
almost periodic functions. This last notion is especially useful
in the theory of  evolution equations, both linear and nonlinear,
because spaces of Stepanov almost periodic functions are natural
counterparts of classical $L^p$ spaces (see, e.g., \cite{am-pr,p1}
 and references therein). On the other hand, in 1955,  Bochner
\cite{boc1} suggested another generalization of the concept of
almost periodicity - almost automorphy. This notion was also used
extensively in the theory of differential equations (see
\cite{NGu1}, \cite{NGu2}, and references therein). Therefore, it
seems to be natural to generalize the notion of almost automorphy
in the spirit of Stepanov. Surprisingly enough, this has been done
only very recently  by N'Gu\'er\'ekata and Pankov \cite{gaston1},
where the concept of Stepanov-like ($S^p$-) almost automorphy was
introduced. Such a notion was, subsequently, utilized to study the
existence of weak Stepanov-like almost automorphic solutions to
some parabolic evolution equations. Then Diagana and
N'Gu\'er\'ekata have studied in \cite{daga} the existence and
uniqueness of an almost automorphic solution to the semilinear
equation
\begin{equation}\label{XY}
u'(t)=Au(t)+F(t, u(t)),\quad t \in \mathbb{R},
\end{equation}
where $A: D(A) \subset \mathbb{X} \mapsto \mathbb{X}$ is a densely defined  closed
linear operator in a Banach space $\mathbb{X}$, which is also the
infinitesimal generator of an exponentially stable $C_0$-semigroup
$(T(t))_{t \geq 0}$ on $\mathbb{X}$ and $F: \mathbb{R} \times \mathbb{X} \mapsto \mathbb{X}$ is
$S^{p}$-almost automorphic for $p> 1$ and jointly continuous. This
result  generalizes the existence results obtained in
N'Gu\'er\'ekata \cite{NGu3}.

In the present paper, we study first the convolution of
Stepanov-like  almost automorphic functions and some applications
to evolution equations. Then we present  the conditions under
which any bounded mild solution to the nonautonomous equation
$$
x'(t)=A(t)x(t)+h(t),\quad t\in \mathbb{R},
$$
where $A(t)$ generates a periodic evolutionary process and $h$ is
a Stepanov-like forcing term, is almost automorphic. This main
result generalizes \cite[Theorem 3.2]{minh}.


\section{Almost Automorphy}

Throughout the rest of this paper, the spaces $(\mathbb{X}, \|\cdot\|)$,
$C(\mathbb{R}, \mathbb{X})$  and $BC(\mathbb{R}, \mathbb{X})$ stands for a Banach space, the
collection of all strongly continuous functions from $\mathbb{R}$ into
$\mathbb{X}$, and the collection of all bounded continuous functions from
$\mathbb{R}$ into $\mathbb{X}$, respectively. Note that $(BC(\mathbb{R}, \mathbb{X}),
\|\cdot\|_\infty),$ where $\|\cdot\|_\infty$ denotes the sup norm
$$
\|\varphi\|_{\infty} : = \sup_{t \in \mathbb{R}} \|\varphi(t)\|
$$
for each $\varphi \in BC(\mathbb{R}, \mathbb{X})$, is a Banach space.



\begin{definition}[Bochner]\label{DDD} \rm
A function $f\in C(\mathbb{R},\mathbb{X})$ is said to be almost
automorphic  in Bochner's sense if for every sequence of real
numbers $(s'_n)$, there   exists a subsequence $(s_n)$ such that
      $$
g(t):=\lim_{n\to\infty}f(t+s_n)
$$
 is well defined for each $t\in\mathbb{R}$, and
      $$
\lim_{n\to\infty}g(t-s_n)=f(t)
$$
   for each $t\in \mathbb{R}$.
\end{definition}

If the convergence above is uniform in $t\in \mathbb{R}$, then $f$
is  almost periodic in the classical Bochner's sense. Denote by
$AA(\mathbb{X})$ the collection of all almost automorphic functions
$\mathbb{R}\to \mathbb{X}$.

Among other things, almost automorphic functions satisfy the
following properties.



\begin{theorem}[{\cite[Theorem 2.1.3]{NGu1}}] \label{thm2.2}
If $f, f_1, f_2\in AA(\mathbb{X})$, then
\begin{itemize}

\item[(i)] $f_1+f_2\in AA(\mathbb{X})$,

\item[(ii)] $\lambda f\in AA(\mathbb{X})$ for any scalar $\lambda$,

\item[(iii)] $f_\alpha\in AA(\mathbb{X})$ where $f_\alpha:\mathbb{R}\to \mathbb{X}$
     is defined by $f_\alpha(\cdot)=f(\cdot+\alpha)$,

\item[(iv)] the range $\mathcal{R}_f:=\big\{f(t):t\in\mathbb{R}\big\}$
     is relatively  compact in $\mathbb{X}$, thus $f$ is bounded in norm,

\item[(v)] if $f_n\to f$ uniformly on $\mathbb{R}$ where each $f_n\in AA(\mathbb{X})$,
     then $f\in  AA(\mathbb{X})$ too.
\end{itemize}
\end{theorem}

\begin{theorem}[\cite{buga}] \label{thm2.3}
 If $g \in L^1(\mathbb{R})$, then $f \ast g \in AA(\mathbb{R})$, where
$f \ast g$ is the convolution of $f$ with $g$ on $\mathbb{R}$.
\end{theorem}

Note that $(AA(\mathbb{X}), \|\cdot\|_\infty)$ turns out to be a Banach space.

\begin{remark} \label{rmk2.4} \rm
The function $g$ in the Definition \ref{DDD} above is measurable,
but not necessarily continuous. Moreover, if $g$ is continuous,
then $f$ is uniformly   continuous, see details in
\cite[Theorem 2.6]{gaston}.
\end{remark}

\begin{example} \label{exa2.5} \rm
 A classical example of an almost automorphic function, which is not
almost periodic is the function defined by
$$
\varphi(t) = \cos\Big(\frac{1}{2+\sin\sqrt{2}t+\sin
t}\Big), \quad t \in \mathbb{R}.
$$
 It can be shown that $\varphi$ is not uniformly continuous, and
hence is not almost periodic.
\end{example}

Let $l^\infty(\mathbb{X})$ denote the space of all bounded (two-sided) sequence
in $\mathbb{X}$. It is equipped with its corresponding sup norm defined for
each sequence $x = (x_n)_{n\in \mathbb{Z}} \in l^\infty(\mathbb{X})$ by:
$ \|x\|_\infty := \sup_{n \in \mathbb{Z}} \|x_n\|$.



\begin{definition} \label{def2.6} \rm
A sequence $x =(x_n)_{n \in \mathbb{Z}} \in l^\infty(\mathbb{X})$ is said to be almost automorphic if for every sequence
of integers $(k'_n)$, there
   exists a subsequence $(k_n)$ such that
      $$
y_p :=\lim_{n\to\infty}x_{p+k_n}
$$
   is well defined for each $p \in \mathbb{Z}$, and
      $$
\lim_{n\to\infty}y_{p-k_n}=x_p
$$
   for each $p\in \mathbb{Z}$.
The collection of all these almost automorphic sequences is denoted
by $aa(\mathbb{X})$.
\end{definition}

In the sequel, we will denote by $AA_{u}(\mathbb{X})$  ($u$-a.a. for
short) the closed subspace of all functions $f\in AA(\mathbb{X})$ with
$g\in C(\mathbb{R},\mathbb{X})$. Equivalently, $f\in AA_{u}(\mathbb{X})$
 if and only if $f$ is a.a. and all convergences in Definition \ref{DDD}
are uniform on compact intervals; i.e., in the Fr\'echet space
$C(\mathbb{R},\mathbb{X})$. Indeed, if $f$ is a.a., then, by
\cite[Theorem 2.1.3 (iv)]{NGu1}, its range is relatively compact.



\begin{remark} \label{rmk2.7} \rm
Note that Definition \ref{DDD} as well as the above-mentioned definition
of $u$-a.a. functions makes sense for
functions with values in any metric space (see \cite{gal}).
\end{remark}

Obviously, the following inclusions hold:
$$
AP(\mathbb{X})\subset AA_{u}(\mathbb{X})\subset AA(\mathbb{X})\subset BC(\mathbb{X})\,,
$$
where $AP(\mathbb{X})$ stands for the collection of all $\mathbb{X}$-valued almost
periodic functions.


\begin{definition} \label{def2.8} \rm
   The Bochner transform $f^b(t,s)$, $t\in \mathbb{R}$, $s\in[0,1]$, of a
function $f(t)$ on    $\mathbb{R}$, with values in $\mathbb{X}$, is
defined by
      $$ f^b(t,s):=f(t+s).$$
\end{definition}


\begin{remark} \label{rmk2.9} \rm
A function $\varphi(t,s)$, $t\in \mathbb{R}$, $s \in [0,1]$, is
the Bochner transform of a certain unction $f(t)$,
$$
\varphi(t,s)=f^b(t,s)\,,
$$
if and only if
$$
\varphi(t+\tau, s-\tau)=\varphi(s,t)
$$
for all $t\in\mathbb{R}$, $s\in [0,1]$ and $\tau\in [s-1, s]$.
\end{remark}



\begin{definition}[see \cite{p1}] \label{def2.10} \rm
Let $p\in [1,\infty)$. The space $BS^p(\mathbb{X})$ of all Stepanov
bounded  functions, with the exponent $p$, consists of all
measurable functions $f$ on $\mathbb{R}$ with values in $\mathbb{X}$ such
that $f^b\in L^\infty\big(\mathbb{R}, L^p(0,1;\mathbb{X})\big)$. This is a
Banach space with the norm
      $$
\|f\|_{S^p}=\|f^b\|_{L^\infty(\mathbb{R},L^p)}
 =\sup_{t\in\mathbb{R}}\Big(\int_t^{t+1}\|f(\tau)\|^p\,d\tau\Big)^{1/p}.
$$
\end{definition}

\begin{definition}[\cite{gaston1}] \rm
The space $AS^p(\mathbb{X})$ of $S^p$-almost automorphic functions
(s$^p$-a.a. for short) consists of  all $f\in BS^p(\mathbb{X})$ such that
$f^b\in AA\big(L^p(0,1;\mathbb{X})\big)$.
\end{definition}

In other words, a function $f\in L^{p}_{\rm loc}(\mathbb R;\mathbb{X})$ is
said to be $S^{p}$-almost automorphic if its Bochner transform
$f^{b}: \mathbb R \to L^{p}(0,1;\mathbb{X})$ is almost automorphic in the
sense that for every sequence of real numbers $(s'_{n})$, there
exists a subsequence $(s_{n})$ and a function
$g\in L^{p}_{\rm loc}(\mathbb R;\mathbb{X})$ such that
\begin{gather*}
\Big(\int_{0}^{1}\|f(t+s_{n}+s)-g(t+s)\|^{p}ds\Big)^{1/p}\to 0,\\
\Big(\int_{0}^{1}\|g(t-s_{n}+s)-f(t+s)\|^{p}ds\Big)^{1/p}\to 0
\end{gather*}
as $n\to \infty$ pointwise on $\mathbb R$.


\begin{remark} \label{rmk2.12} \rm
It is clear that if $1\leq p<q<\infty$ and $f\in L^{q}_{\rm
loc}(\mathbb{R} ; \mathbb{X})$ is $S^{q}$-almost automorphic, then $f$ is
$S^{p}$-almost automorphic. Also if $f \in AA(\mathbb{X})$, then $f$ is
$S^{p}$-almost automorphic for any $1\leq p < \infty$. It is
easily seen that $f\in AA_{u}(\mathbb{X})$ if and only if $f^b\in
AA(L^\infty(0,1;\mathbb{X}))$. Thus, $AA_{u}(\mathbb{X})$ can be considered as
$AS^\infty(\mathbb{X})$.
\end{remark}



\begin{example}[\cite{gaston1}] \label{exam2.13} \rm
Let $x = (x_n)_{n \in \mathbb{Z}} \in l^\infty(\mathbb{X})$ be an almost automorphic
sequence and let $\varepsilon_0 \in (0, \frac{1}{2})$.
Let $f(t) = x_n$ if $t \in (n-\varepsilon_0,n+\varepsilon_0)$ and
$f(t) = 0,$ otherwise. Then $f \in AS^p(\mathbb{X})$ for $p \geq 1$ but $f \not \in
AA(\mathbb{X})$, as $f$ is discontinuous.
\end{example}


\begin{theorem}[\cite{gaston1}]
The following statements are equivalent:
\begin{itemize}
   \item[(i)] $f\in AS^p(\mathbb{X})$;
   \item[(ii)] $f^b\in AA_{u}(L^p(0,1;\mathbb{X}))$;
   \item[(iii)] for every sequence $(s'_n)$ of real numbers there exists a subsequence $(s_n)$ such
   that
   \begin{equation}
   g(t):=\lim_{n\to\infty}f(t+s_n)
   \end{equation}
   exists in the space $L^p_{\rm loc}(\mathbb{R};\mathbb{X})$ and
   \begin{equation}\label{e2.2}
    f(t)=\lim_{n\to\infty}g(t-s_n)
   \end{equation}
   in the sense of $L^p_{\rm loc}(\mathbb{R};\mathbb{X})$.
\end{itemize}
\end{theorem}

Let now $f,h:\mathbb{R} \to \mathbb{R}$ and consider the convolution
$$
(f\star h)(t):=\int_{\mathbb{R}}f(s)h(t-s)ds,\quad t\in \mathbb{R},
$$
if the integral exists.

\begin{remark} \label{rmk2.15} \rm
The operator $J: AS^{p}(\mathbb{X})\to AS^{p}(\mathbb{X})$ such that $(Jx)(t):=x(-t)$
is well-defined and linear.
Moreover it is an isometry and $J^2=I$.
\end{remark}

\begin{remark} \label{rmk2.16} \rm
The operator $T_{a}$ defined by $(T_{a}x)(t):=x(t+a)$ for a fixed $a\in \mathbb{R}$
leaves $AS^{p}(\mathbb{X})$ invariant.
\end{remark}

\begin{theorem} \label{thm2.17}
A linear combination of $S^p$-almost automorphic functions ($p\geq 1$) is
a $S^p$-almost automorphic function. Moreover if $\mathbb{X}$ is a Banach space
over the field $K=\mathbb{R}$, or $\mathbb{C}$ and $f\in AS^{p}(\mathbb{X})$, $\nu \in AA_u(K)$,
then $ \nu f \in AS^{p}(\mathbb{X})$.
\end{theorem}

The proof of this theorem is an immediate consequence of the
results above.

\begin{theorem} \label{thm2.18}
If a sequence $(f_k)_{k=1}^{\infty}$ of $S^{p}$ almost automorphic functions
is such that
$\|f_{k}-f\|_{S^p}\to \infty$, as $k\to \infty$, then $f\in AS^p$.
\end{theorem}

As in \cite{buga}, denote by $LM(\mathbb{R})$ the set of all Lebesgue
measurable  functions $\mathbb{R} \to \mathbb{R}$. We also denote by $S^p(\mathbb{R},\mathbb{X})$
the subspace of $BS^p(\mathbb{R},\mathbb{X})$ that consists of all $S^p$-almost
periodic functions \cite{p1}.


\section{$S^{p}-$almost automorphy of the convolution}

Let us now discuss conditions which do ensure the $S^{p}-$almost
automorphy of the convolution function $f\star h$ of $f$ with $h$
where $f$ is $S^{p}$-almost automorphic and $h$ is a Lebesgue
mesurable function satisfying additional assumptions.

Let $f:\mathbb{R}\to X$ and $h:\mathbb{R}\to \mathbb{R}$; the convolution function (if it
does exist) of $f$ with $h$ denoted $f\star h$ is defined by:
\begin{equation*}
(f\star h)(t):=  \int_{\mathbb{R}}f(\sigma )h(t-\sigma )d\sigma
=\int_{\mathbb{R}}f(t-\sigma )h(\sigma )d\sigma =(h\star f)(t), \quad
 \text{for all }t\in \mathbb{R}.
\end{equation*}
Hence, if $f\star h$ is well-defined, then $f\star h=h\star f$.

Let $\varphi\in L^1$ and $\lambda \in \mathbb{C}$. It is well-known that
the operator $A_{\varphi, \lambda}$ defined by
\begin{equation}
A_{\varphi, \lambda}u=\lambda u +\varphi \star u
\end{equation}
acts continuously in $BS^p$ for each $1\leq p <\infty$; i.e.,
there exists $K>0$ such that
\begin{equation}
\|A_{\varphi, \lambda}u\|_{S_p}\leq K \|u\|_{S^p}, \forall u\in
BS^p.
\end{equation}
Moreover $A_{\varphi, \lambda}$ leaves $S^p$ invariant (see \cite{pan}).

Now denote $\mathcal{M}:=\{AA(X), AA_{u}(X), AS^{p}(X)\}$.

\begin{theorem} \label{T1}
For every $1\leq p < \infty$, and $\Omega\in \mathcal{M}$,
$$
A_{\varphi, \lambda}(\Omega) \subset \Omega.
$$
\end{theorem}

\begin{proof} The case $\Omega= AA(X)$ is considered in \cite{buga}.
The two other cases follow from the
previous one, the identity $(\varphi\star f)^b=\varphi\star (f^b)$ and
the definitions of spaces $AA_u$ and $AS^p$, respectively.
\end{proof}

Now we present a result on invertibility of convolution operators
in spaces  of almost automorphic functions that complements
\cite[Theorem 1]{pan}. Let $a(\xi)=\lambda+\hat\varphi(\xi)$,
where $\hat\varphi(\xi)$ is the Fourier transform of $\varphi$, be
the \textit{symbol} of the operator $A_{\varphi,\lambda}$, with
$\varphi\in L^1(\mathbb{R})$. Since  $\lim_{\xi\to
\infty}\varphi(\xi)=0$, the symbol $a(\xi)$ is a well-defined
continuous function on
$\overline{\mathbb{R}}=\mathbb{R}\cup\{\infty\}$ and
$a(\infty)=\lambda$. Then we have the following

\begin{theorem} \label{thm3.2}
Suppose that $\varphi\in L^1(\mathbb{R})$. The following two statements
are equivalent:
\begin{itemize}
\item[(i)] $a(\xi)\neq 0$ for all $\xi\in\overline{\mathbb{R}}$;
\item[(ii)] the operator $A_{\varphi,\lambda}$ is invertible in any space $\Omega\in \mathcal{M}$.
\end{itemize}
\end{theorem}

\begin{proof}
Suppose that $a(\xi)\neq 0$ for all $\xi\in\overline{\mathbb{R}}$.
The function $\frac{1}{a(\xi)}$ is defined on
$\overline{\mathbb{R}}$ and, by classical Wiener's theorem, is of
the form
$$
\frac{1}{a(\xi)}=\frac{1}{\lambda}+\hat\psi(\xi),
$$
where $\psi\in L^1(\mathbb{R})$. Now it is easy to verify that the
operator $A_{\psi,\frac{1}{\lambda}}$ is the inverse operator to
$A_{\varphi,\lambda}$ and, by Theorem \ref{T1}, acts in all spaces
$\Omega\in \mathcal{M}$.

Conversely, suppose that $A=A_{\varphi,\lambda}$ is invertible in some
space $\Omega\in \mathcal{M}$.
Then we have that, with some $\alpha>0$,
$$
\alpha\|u\|_{\Omega}\leq\|Au\|_{\Omega}
$$
for all $u\in\Omega$. The function $u(t)=u_{\xi}(t)=\exp(i\xi t)$
belongs to $\Omega$ and it is easily seen that $\|u\|_{\Omega}=1$
and $Au=a(\xi)u$. Hence, $|a(\xi)|\geq\alpha$ and we conclude.
\end{proof}

Now we can complement \cite[Theorems 2 and 3]{pan} as follows. Let
$A=A_{\varphi,\lambda}$ and $\Omega$ be a functional space in
which the operator $A$ acts. We denote by $\|A|_{\Omega}\|$ the
norm of $A$ as a linear operator in $\Omega$.

\begin{theorem} \label{thm3.3}
Let $\varphi\in L^1(\mathbb{R})$, $A=A_{\varphi,\lambda}$ and $p\geq 1$. Then
\begin{gather*}
\|A|_{S^p}\|=\|A|_{AS^p}\|=\|A|_{BS^p}\|,\\
\|A|_{AP}\|=\|A|_{AA_u}\|=\|A|_{AA}\|=\|A|_{BC}\|.
\end{gather*}
\end{theorem}

\begin{proof}
We have the following chain of closed subspaces
$S^p\subset AS^p\subset BS^p$.
Hence,
$$
\|A|_{S^p}\|\leq\|A|_{AS^p}\|\leq\|A|_{BS^p}\|.
$$
By \cite[Theorem 2]{pan}, we have that $\|A|_{S^p}\|=\|A|_{BS^p}\|$.
This implies the first statement of the theorem.

The second statement is similar. We need only to refer to
\cite[Theorem 3]{pan}.
\end{proof}


\subsection*{Application: A Volterra-like Equation}

Consider the equation
\begin{equation} \label{e3.4}
x(t)=g(t)+\int_{-\infty}^{+\infty}a(t-\sigma)x(\sigma)d\sigma,\;t\in \mathbb{R},
\end{equation}
where $g: \mathbb{R} \to \mathbb{R}$ is a continuous function and $a\in
L^{1}(\mathbb{R})$.

\begin{theorem} \label{thm3.4}
Suppose $g\in AS^{p}(\mathbb{R})$ and $\|a\|_{L^{1}}<1$. Then \eqref{e3.4} above
has a unique $S^{p}$-almost automorphic solution.
\end{theorem}

\begin{proof}
It is clear that the operator
$$
x\in AS^p(X)\to \int_{-\infty}^{+\infty}a(t-\sigma)x(\sigma)d\sigma \in
AS^{p}(X)
$$
is well-defined. Now consider $\Gamma : AS^{p}(X) \to AS^{p}(X)$ such that
$$
(\Gamma x)(t)= g(t)+\int_{-\infty}^{+\infty}a(t-\sigma)x(\sigma)d\sigma,
\quad t\in \mathbb{R} .
$$
We can easily show that
$$
\|(\Gamma x)-(\Gamma y)\|\leq \|a\|_{L^1}\|x-y\|_{S^p}.
$$
The conclusion is immediate by the principle of contraction.
\end{proof}


\section{Almost Automorphic Solutions}

In this section, $X$ will be a Banach space which does not contain any
subspace isomorphic to $c_0$. We
consider the equation
\begin{equation}\label{e4.1}
x'(t)=A(t)x(t)+h(t),\quad t\in \mathbb{R},
\end{equation}
where $h\in AS^{p}(X) \cap C(\mathbb{R},X)$ , and $A(t)$ generates a $1$-periodic
exponentially bounded
evolutionary process $(U(t,s))_{t\ge s}$ in  $X$, that is, a two-parameter
family of bounded linear
operators that satisfies the following conditions:
\begin{enumerate}
\item   $U(t,t)=I$ for all $t\in \mathbb{R}$,
\item
$U(t,s)U(s,r)=U(t,r)$ for all $t\ge s\ge r$,
\item   The map
$(t,s)\mapsto U(t,s)x$ is continuous for every fixed $x \in X$,
\item   $U(t+1,s+1)=U(t,s)$ for all $t \ge s$ (\emph{
$1$-periodicity}),
\item  $\| U(t,s)\| \le K e^{\omega (t-s)} $ for some  $K>0,\;\omega>0 $ independent
of $t \ge s$.
\end{enumerate}
An $X$-valued continuous function $u$ on $\mathbb{R}$ is said to be a mild solution
of \eqref{e4.1} if
\begin{equation}\label{ieq}
x(t)= U(t,s)x(s)+\int^t_s U(t,\xi )h(\xi )d\xi , \quad \forall t\ge
s;\; t,s\in\mathbb{R} .
\end{equation}

\begin{lemma}\label{lem4.1}
Let $x$ be a bounded mild solution of \eqref{ieq} on $\mathbb{R}$ and
let $h$ be in $AS^p(X)\cap C(\mathbb{R},X)$. Then, $x\in
AA(X)$  if and only if the sequence $\{ x(n)\}_{n\in\mathbb{Z}}\in aa(X)$.
\end{lemma}

\begin{proof}
The proof is similar to \cite[Lemma 3.1]{minh}, with the necessary
adaptations.
The  necessity is obvious.
For the Sufficiency,  let the sequence $\{ x(n)\}_{n\in\mathbb{Z}}\in aa(X)$.
We need to prove that $x\in AA(X)$.
We divide the  proof  into two steps:

\noindent
\emph{Step 1}:  We first suppose that $\{ n'_k\}$ is a given
sequence of integers. Then there exist a subsequence $\{ n_k\}$
and a function $g\in L^{p}_{\rm loc}(\mathbb{R},X)$ such that
$$
y(n):=\lim_{k\to\infty} x(n+n_k)
$$
exists for each $n\in \mathbb{Z}$ and
$$
\lim_{k\to\infty} y(n-n_k)= x(n)
$$
for each $n\in \mathbb{Z} $, and
\begin{gather*}
\lim_{k\to\infty} \Big(\int_{0}^{1}\|h(t+n_k+s)- g(t+s)\|^{p}ds\Big)^{1/p}=0;\\
 \lim_{k\to\infty}
\Big(\int_{0}^{1}\|g(t-n_k+s)- h(t+s)\|^p ds\Big)^{1/p}=0,
\end{gather*}
for each $t\in \mathbb{R}$.

For every fixed $t\in \mathbb{R}$, let us denote by $[t]$ the integer part of $t$.
Then, define
$$
y(\eta ):= U(\eta ,[t])y([t]) + \int^\eta _{[t]} U(\eta ,\xi )
g(\xi )d\xi , \quad \eta \in [[t],[t]+1).
$$
In this way, we can define $y$ on the whole line $\mathbb{R}$. Now we show that
$$
\lim_{k\to\infty} x(t+n_k)=y(t).
$$
In fact,
$$
\lim_{k\to\infty} \| x(t+n_k)-y(t)\| \le \lim_{k\to\infty} I_1(t)
+ \lim_{k\to\infty} I_2(t)
$$
where
\begin{gather*}
I_1(t)=  \| U(t+n_k,[t]+n_k)x([t]+n_k) - U(t,[t])y([t]) \|, \\
I_2(t)=\int^t_{[t]} \| U(t,\eta )\| \| h(\eta +n_k)
-g(\eta )\| d\eta\,.
\end{gather*}
Now using the $1$-periodicity of $U(t,s)$ since $n_k \in \mathbb{Z}$
and boundedness of  $U(t,[t])$, we get
\begin{align*}
\lim_{k\to\infty} I_1(t)
&= \lim_{k\to\infty} \| U(t,[t])x([t]+n_k) - U(t,[t])y([t]) \| \\
&\le C_{t} \lim_{k\to\infty} \|x([t]+n_k)-y([t])\| =0,
\end{align*}
for each $t\in \mathbb{R}$.
Now for $k$ sufficiently large, we get
$$
I_2(t)\leq K \int^t_{[t]} e^{\omega (t-\eta)} \| h(\eta +n_k)
-g(\eta )\| d\eta \le C'_{t,\omega}\epsilon,
$$
which shows that
$$
\lim_{k\to\infty}
I_2(t)=0,\;for\;each\;t\in\mathbb{R}.
$$
Thus
$$\lim_{k\to\infty} \|x(t+n_k)-y(t)\|=0.$$
Similarly, we can show that
$$
\lim_{k\to\infty} \| y(t-n_k)-x(t)\| =0.
$$

\noindent
\emph{Step 2}: Now we consider the general case where $\{s'_k\}_{k\in\mathbb{Z}}$
may not be an integer sequence. The main lines are similar to those
in Step 1 combined with the strong continuity of the process.

Set $n'_k=[s'_k]$ for every $k$. Since $\{ t_k\}_{k\in\mathbb{Z}}$, where
$t_k:= s'_k-[s'_k]$, is a sequence in $[0,1)$ we can choose a
subsequence $\{ n_k\}$ from $\{n'_k\}$ such that
$\lim_{k\to \infty} t_k=t_0\in [0,1]$ and
$$
y(n):=\lim_{k\to\infty} x(n+n_k)$$ exists for each $n\in \mathbb{Z}$ and
$$
lim_{k\to\infty} y(n-n_k)= x(n)
$$
for each $n\in \mathbb{Z} $, for a function $y$, as shown in Step 1.

Let us first consider the case $0< t_0+t -[t_0+t] $. We show that
\begin{equation}\label{e2.5}
\lim_{k\to\infty} x(t_k+t+n_k)=\lim_{k\to\infty}x(t_0+t+n_k)=
y(t_0+t).
\end{equation}
In fact, for sufficiently large $k$, from the above assumption we
have $[t_0+t]=[t_k+t]$. Using the
$1$-periodicity of the process $(U(t,s))_{t\ge s}$ we have
\begin{equation}
\| x(t_k+t+n_k)-x(t_0+t+n_k)\| \le I_3(k)+I_4(k),
\end{equation}
where $I_3(t)$, $I_4(k)$ are defined and estimated as below.
By the $1$-periodicity of the process
$(U(t,s))_{t\ge s}$ we have
\begin{align*}
I_3(t)
&:=\| U(t_k+t+n_k,[t_k+t]+n_k)
x([t_k+t]+n_k)  \\
&\quad -U(t_0+t+n_k,[t_0+t]+n_k) x([t_0+t]+n_k)\| \\
&= \| U(t_k+t,[t_0+t]) x([t_0+t]+n_k) - U(t_0+t,[t_0+t])
x([t_0+t]+n_k)\| .
\end{align*}
Using the strong continuity of the process $(U(t,s))_{t\ge s}$ and
the boundedness of the range of  the
sequence $\{ x(n)\}_{n\in\mathbb{Z}}$ we have $ \lim_{k\to\infty}I_3(k)=0$.
 Next, we define
$$
I_4(k):=\|\int_{[t_k+t]+n_k}^{t_k+t+n_k} U(t_k+t+n_k,\eta)h(\eta
)d\eta -\int_{[t_0+t]+n_k}^{t_0+t+n_k}U(t_0+t+n_k,\eta)h(\eta
)d\eta \| .
$$
Using the Holder inequality we have
\begin{align*}
\| \int_{[t_k+t]+n_k}^{t_k+t+n_k}U(t_k+t+n_k,\eta)h(\eta
)d\eta\|
&\le K \int_{[t_k+t]+n_k}^{t_k+t+n_k}e^{\omega(t_k+t+n_k-\eta)}
\|h(\eta)\|d\eta\\
&\le K(\int_{0}^{1}e^{q\omega(t_k+t+n_k-\eta)}d\eta)^{\frac{1}{q}}(\|h\|_{S^p})\\
&=\frac{K}{q\omega}(e^{q\omega(t_k+t+n_k-1)}-e^{q\omega(t_k+t+n_k})
^\frac{1}{q}(\|h\|_{S^p}).
\end{align*}
By letting $k\to \infty$, we observe that the latter tends to zero since
$\omega <0$. The same treatment can be used for the second integral
in $I_4$, so that $\lim_{k\to\infty}I_4=0$.
So, in view of Step 1, we see that \eqref{e2.5} holds.

Next, we consider the case when $t_0+t-[t_0+t]=0$, that is, $t_0+t$ is
an integer. If $t_k+t \ge t_0+t$,
we can repeat the above argument. So, we omit the details. Now suppose
that $t_k+t < t_0+t$. Then
\begin{equation}
\| x(t_k+t+n_k)-x(t_0+t+n_k)\| \le I_5(k)+I_6(k),
\end{equation}
where $I_5(k)$ and $I_6(k)$ are defined and estimated as below.
\begin{align*}
I_5(k)&:=\| U(t_k+t+n_k,[t_k+t]+n_k)
x([t_k+t]+n_k)  \\
&\quad -U(t_0+t+n_k,t_0+t-1+n_k) x(t_0+t-1+n_k)\| \\
&= \| U(t_k+t,t_0+t-1) x(t_0+t-1+n_k) \\
&\quad - U(t_0+t,t_0+t-1) x(t_0+t-1+n_k)\| .
\end{align*}
Now using the strong continuity of the process $(U(t,s))_{t\ge s}$
and the precompactness of the range
of the sequence $\{ x(n)\}_{n\in\mathbb{Z}}$ we obtain $ \lim_{k\to\infty} I_5(k)=0$.
Finally we have
$$
I_6(k):= \| \int_{[t_k+t]+n_k}^{t_k+t+n_k}U(t_k+t+n_k,\eta)h(\eta )d\eta
-\int_{[t_0+t]+n_k-1}^{t_0+t+n_k}U(t_0+t+n_k,\eta)h(\eta )d\eta \|
$$
This can be treated as in the case
of $I_4$; i.e., $\lim_{k\to\infty}I_6(k)=0$.
The proof is now complete.
\end{proof}

\begin{theorem}
Let $A(t)$ in \eqref{e4.1} generate an exponentially bounded
$1$-periodic strongly continuous evolutionary process, and let
$h\in AS^{p}(X) \cap C(\mathbb{R},X)$  . Assume further that the space
$\mathbb{X}$ does not contain ny subspace isomorphic to $c_0$ and the part
of spectrum of the monodromy operator $U(1,0)$ on the unit circle
is countable. Then, every bounded mild solution of \eqref{e4.1} on
the real line is almost automorphic.
\end{theorem}

\begin{proof}
The theorem is an immediate consequence of \cite[Lemmas 2.12 and
2.13]{minh} and Lemma \ref{lem4.1} above. In fact, we need only to prove
the sufficiency. Let us consider the discrete equation
$$
x(n+1)= U(n+1,n)x(n)+ \int^{n+1}_n U(n+1,\xi )h(\xi )d\xi , \quad
n\in\mathbb{Z} .
$$
 From the $1$-periodicity of the process $(U(t,s))_{t\ge s}$, this
equation can be re-written in the form
\begin{equation}\label{dis}
u(n+1)= Bu(n)+ y_n, \quad n\in\mathbb{Z} ,
\end{equation}
where
$$
B:=U(1,0); \ y_n:=\int^{n+1}_n U(n+1,\xi )h(\xi )d\xi , \quad
n\in\mathbb{Z} .
$$
Note that $y_n$ is well-defined.

We are going to show that the sequence $\{y_n\}_{n\in\mathbb{Z}}$ defined
as above is almost automorphic. In fact, since $h\in AS^{p}(X) $ ,
for every sequence  $\{n'_k\}$ there exists a subsequence
$\{n_k\}$ and a function $g\in L^{p}_{\rm loc}(\mathbb{R};\mathbb{X})$ such that
\begin{gather*}
\Big(\int_{0}^{1}\|h(t+ \{n_k\}+s)-g(t+s)\|^{p}ds\Big)^{1/p}\to 0,\\
\Big(\int_{0}^{1}\|g(t-\{n_k\}+s)-h(t+s)\|^{p}ds\Big)^{1/p}\to 0
\end{gather*}
as $n\to \infty$ pointwise on $\mathbb{R}$.
Now let
$$
z_n=\int^{n+1}_{n}U(n,\xi )g(\xi )d\xi , \quad n\in\mathbb{Z}\,.
$$
Then, by the $1$-periodicity of $(U(t,s))_{t\ge s}$ and the Holder
inequality we have
\begin{align*}
&\|y_{n+n_k}-z_n\| \\
&=\| \int^{n+n_k+1}_{n+n_k}U(n,\xi )h(\xi
)d\xi - \int^{n+1}_{n}U(n,\xi )g(\xi)d\xi\|\\
&=\| \int^{1}_{0}U(n+n_k,\xi+n+n_k )h(\xi+n+n_k
)d\xi - \int^{1}_{0}U(n,\xi+n )g(\xi )d\xi\|\\
&=\| \int^{1}_{0}U(n,\xi+n)(h(\xi+n+n_k- g(\xi)d\xi\| \\
&\le \int^{1}_{0}\|U(n,\xi+n)\|h(\xi+n+n_k)-g(\xi)d\xi\|\\
&\le K \int^{1}_{0}e^{\omega t}\|h(\xi+n+n_k)-g(\xi)\|d\xi\\
&\le K (\int^{1}_{0}e^{-q\omega t} d\xi)^{\frac{1}{q}}
\Big(\int^{1}_{0}( \|h(\xi+n+n_k)-g(\xi)\|)^{p}d\xi\Big)^{1/p}
\to 0,\quad\text{as } k\to\infty
\end{align*}
By  \cite[Lemma 2.13]{minh}, since $\{ x(n)\}$ is a bounded solution
of \eqref{dis}, $\mathbb{X}$ does not contain any subspace isomorphic to $c_0$,
and the part of spectrum of $U(1,0)$ on the unit circle is
countable, $\{ x(n)\}\in aa(X)$. By Lemma \ref{lem4.1}, this yields that
the solution $x\in AA(X)$. The proof is
now complete.
\end{proof}

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\end{document}
