\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
{\em Electronic Journal of Differential Equations},
Vol. 2007(2007), No. 67, pp. 1--21.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu  (login: ftp)}
\thanks{\copyright 2007 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2007/67\hfil Radial selfsimilar solutions]
{Radial selfsimilar solutions of a nonlinear Ornstein-Uhlenbeck
equation}

\author[A. Bouzelmate,  A. Gmira, G. Reyes\hfil EJDE-2007/67\hfilneg]
{Arij Bouzelmate,  Abdelilah Gmira, Guillermo Reyes}  % in alphabetical order

\address{Arij Bouzelmate\newline
D\'epartement de Math\'ematiques  et Informatique\\
Facult\'e des Sciences, BP 2121, T\'etouan, Maroc}
\email{bouzelmatearij@yahoo.fr}

\address{Abdelilah Gmira \newline
D\'epartement de Math\'ematiques  et Informatique\\
Facult\'e des Sciences, BP 2121, T\'etouan, Maroc}
\email{gmira@fst.ac.ma    or gmira.i@menara.ma}

\address{Guillermo Reyes \newline
Departamento de Matem\' aticas\\
Universidad Carlos III de Madrid, Legan\'es, Madrid 28911, Spain}
\email{greyes@math.uc3m.es}

\thanks{Submitted January 11, 2007. Published May 9, 2007.}
\subjclass[2000]{34L30, 35K55, 35K65}
\keywords{$p$-laplacian; Ornstein-Uhlenbeck diffusion equations;\hfill\break\indent
 self-similar solutions; shooting technique}

\begin{abstract}
 This paper concerns the existence, uniqueness and
 asymptotic properties (as $r=|x|\to\infty$) of radial self-similar
 solutions to the nonlinear Ornstein-Uhlenbeck  equation
 \[
 v_t=\Delta_p  v+x\cdot\nabla (|v|^{q-1}v)
 \]
 in $\mathbb{R}^N\times (0, +\infty)$. Here $q>p-1>1$, $N\geq 1$,
 and $\Delta_p$  denotes the $p$-Laplacian operator.
 These solutions are of the form
 \[
 v(x,t)=t^{-\gamma} U(cxt^{-\sigma}),
 \]
 where $\gamma$ and $\sigma$ are fixed powers given by the
 invariance properties of differential equation, while $U$ is a radial
 function, $U(y)=u(r)$, $r=|y|$. With the choice $c=(q-1)^{-1/p}$,
 the radial profile $u$ satisfies the nonlinear ordinary differential
 equation
 $$
 (|u'|^{p-2}u')'+\frac{N-1}r |u'|^{p-2}u'+\frac{q+1-p}{p} r u'+(q-1)
 r(|u|^{q-1}u)'+u=0
 $$
in $\mathbb{R}_+$. We carry out a careful analysis of this equation and
deduce the corresponding consequences for the Ornstein-Uhlenbeck  equation.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{remark}[theorem]{Remark}


\section{Introduction and Main Results} \label{sect-intro}

 We are interested in  radial, selfsimilar
solutions of the nonlinear degenerate parabolic equation
\begin{equation}\label{EI1}
v_t=\Delta _p v+x\cdot\nabla (|v| ^{q-1}v),
\end{equation}
posed in $ \mathbb{R}^N\times (0,+\infty )$, where  $q>p-1>1$,
$N\geq 1$. As usual, $ \nabla$ denotes the spatial gradient,
while $ \Delta_p v= \mathop{\rm div}(| \nabla v|^{p-2}\nabla v)$
stands for the $p$-Laplacian operator.
Equation \eqref{EI1} can be considered as  a nonlinear version of
the Ornstein-Uhlenbeck equation (see for example \cite{L} and
\cite{WF}), which is an important model of diffusion.

The study of radial self-similar solutions is motivated by the
role that they have played in the general theory for related
equations. Thus, it is well known that for the purely
$p$-laplacian equation, the so called Barenblatt solutions having
the same (invariant) norm $\|U(t)\|_{L^1}$ describe the
asymptotics of general solutions with integrable data, see
\cite{KV}. In the same spirit, in the papers \cite{Z,KY}
it is proved that the long time behaviour of solutions to the
diffusion-absorption equation
$$
v_t=\Delta_p v-v^q
$$
is also given by a family of radial self-similar solutions of the
equation itself or of some reduced equation. The particular member
of the family depends on the behaviour of initial data at
infinity. The same questions for related equations can be found in
\cite{BG1,BG2,QW1,QW2,Q}. The
radial self-similar solutions to \eqref{EI1} constructed in the
present paper are also related to the long time behaviour of
solutions to the initial value problem. The authors intend to
report on this in a forthcoming paper.

We show that, under certain assumptions on $p,q$ and $ N$,
the equation \eqref{EI1} admits a family of radial self-similar
solutions of the form
\begin{equation}
v(x,t)=t^{-\gamma}U(c xt^{-\sigma}),\label{EI2}
\end{equation}
defined for $x\in \mathbb{R}^N$ and $t>0$. 
Here $U:\mathbb{R}^N\to \mathbb{R}$, is a
radial function. The scaling powers $ \gamma,\sigma$ are
determined by the equation in the usual manner (dimensional
analysis):
\begin{equation}
\gamma=\frac{1}{q-1},\quad \sigma=\frac{q+1-p}{p (q-1)}. \label{EI3}
\end{equation}
 With the choice of the scaling constant
$c=(q-1)^{-1/p}$, it can be easily checked that $U$ satisfies
the degenerate elliptic equation
\[
\Delta _p U+\frac{q+1-p}p x\cdot\nabla U+ (q-1)x\cdot\nabla
(|U| ^{q-1}U)+U=0
\]
in $ \mathbb{R}^N$. If we put $ U(x)=u(|x|)$, it is
easy to see that $ u:\mathbb{R}^{+}\to \mathbb{R}$ is a solution of
the ODE
\begin{equation}
( | u'| ^{p-2}u')'+ \frac{N-1}r |u'|^{p-2}u'+\frac{q+1-p}{ p}  ru'+
 (q-1)r (|u|^{q-1}u)'+u=0. \label{EI4}
\end{equation}
We study this equation by classical methods, suitably
modified in order to deal with its degenerate character at
$r=0$ as well as at points where $ u'=0$. This is particularly
important for local existence, since we are interested in radial
solutions and it is natural to impose $ u'(0)=0$. Actually, we
will deal with a more general equation, containing \eqref{EI4} as
a particular case. Thus, consider the following initial value
problem.


\subsection*{Problem (P)}
 Find a function $u$, defined on $[0,+\infty[$ such that
$|u'|^{p-2}u'$ is in $C^1([0,+\infty[)$ and
\begin{gather}
(|u'|^{p-2}u')'+\frac{N-1}r |u'|^{p-2}u'+\alpha r u'
 +\beta r (|u|^{q-1}u)'+u=0\quad\textrm{in }]0,+\infty[, \label{E1} \\
u(0)=A,\quad u'(0)=0,  \label{E2}
\end{gather}
where $q>p-1>1$, $N\geq 1$, $\alpha\ge 0$, $\beta>0$, $A\neq 0$.
Note that in the application to the nonlinear
Ornstein-Uhlenbeck equation \eqref{EI1}  the choice of parameters
is
\begin{equation} \label{EI5}
\alpha =\frac{q+1-p}p,\quad \beta =(q-1).
\end{equation}

Our results concerning problem (P) can be summarized as
follows. For this brief account we assume that $ A>0$,
for the sake of clarity.

By reducing the initial value problem (P) to a fixed point
problem for a suitable integral operator, we prove that for each
$A\neq 0$ there exists a unique function $ u(\cdot, A)$ defined
in $[0,+\infty[$ satisfying
\eqref{E1}and \eqref{E2}. This is the content of Theorem \ref{EP1}.

Once these basic facts are established, we perform a careful
analysis of the qualitative properties of the solutions to (P).
First, we prove that the solutions are ordered. Moreover, we show that
they are strictly ordered while the smaller is positive.
See Theorem \ref{EP2}.

Next, we consider the behavior of solutions as $ r\to +\infty$.
It turns out that this behaviour strongly depends on the size
of $ \alpha$.

More precisely, we show that
$\displaystyle\lim_{r\to +\infty}u(r)=\displaystyle\lim_{r\to+\infty}u'(r)=0$. If
$\alpha>0$, we prove that there exists the finite limit
$ L:=\displaystyle\lim_{r\to+\infty}r^{1/\alpha }u(r)\ge 0$. Moreover, $ L>0$
if $\alpha N>1$. See Theorems \ref{AP1},
\ref{AP3} and \ref{AP4} for the precise statements.

Concerning the sign of $ u$, we prove that (i) if
$\alpha N\ge1 $, then solutions are strictly positive,
whereas (ii) if $0<\alpha N<1$  solutions with small data change sign, while
those with large data are strictly positive. As a direct
consequence, we obtain the existence and uniqueness of a compactly supported
solution in this range. See
Theorems \ref{AP5}, \ref{CP1}, \ref{CP2} and \ref{CP4}.

This paper is organized as follows: Section~\ref{sect-exist} is
devoted to basic theory: we prove local existence, uniqueness and
extendability of solutions for problem (P), as well as
monotonicity of solutions with respect to the datum $A$. In
Section \ref{sect-ab} we describe the asymptotic behavior of
positive solutions as $r\to\infty$. In Section \ref{sect-cs} we
give a fairly complete classification of solutions according to
their behaviour at infinity (strictly positive, compactly
supported or oscillating), depending on the parameters
$\alpha$, and $\beta$. Finally, in Section~\ref{sect-ou}, we
apply the obtained results to the original equation, taking into
account the relations (\ref{EI5}).


\section{Basic Theory} \label{sect-exist}

Unless otherwise specified, we assume throughout that
$$
q>p-1>1,\quad N\geq 1,\quad \alpha\ge 0,\quad \beta>0.
$$
Moreover, we restrict ourselves to the case $ A> 0$ in \eqref{E2},
since equation \eqref{E1} is invariant under the change of unknown
$u\to v=-u$; i.e., if $u$ solves (P) with
$u(0)=A $, then $v=-u$ solves the same problem with
$v(0)=-A$. We start with existence and uniqueness result.

\begin{theorem}\label{EP1}
Problem {\rm (P)} has a unique
 solution $ u(\cdot,A,\alpha,\beta)$. Moreover,
\begin{equation}
(|u'|^{p-2}u')'(0)=-A/N. \label{EU1}
\end{equation}
\end{theorem}

 Some ideas for the proof are inspired by \cite{BG1} and
\cite{BG2}.

\begin{proof}
The proof will be done in three steps.

\noindent\textbf{Step 1:}  Existence of a local solution.
Integrating \eqref{E1}twice from $ 0$ to $ r$ and taking
into account \eqref{E2}, we see that problem (P) is equivalent
to the integral equation
\begin{equation}
u(r)=A-\int_0^rG(F[u](s)) \,ds,  \label{EU2}
\end{equation}
where
\begin{equation}
G(s)=|s|^{(2-p)/(p-1)}s,  \quad  s\in \mathbb{R}\label{EU3}
\end{equation}
and the nonlinear
mapping $F$ is given by the formula
\begin{equation}
F[\varphi] (s)=\alpha s\varphi (s) + \beta s| \varphi| ^{q-1}\varphi (s) +
s^{1-N}  \int_0^s  \sigma ^{N-1}  [-\beta
N|\varphi| ^{q-1}(\sigma ) + (1 - N\alpha)] \varphi (\sigma )d\sigma.
\label{EU4}
\end{equation}
Let us introduce the functional setting. For $ R>0$ we denote
by $C([0,R])$, the Banach space of real
continuous functions on $[0,R]$ with the uniform
norm, denoted by $ \|\cdot\|_0$. Then $ F[\varphi]$ is well
defined as an operator from $C([0,R])$ into
itself. Given $ A,M>0$ we consider the  complete
metric space
\begin{equation}
E_{A,M;R}=\big\{ \varphi \in C([0,R] ):\|
\varphi -A\| _0\leq M\big\}.  \label{EU5}
\end{equation}
 Next we define the mapping $\mathcal{T}$\ on $E_{A,M;R}$ by
\begin{equation}
\mathcal{T}[\varphi](r)=A-\int_0^rG(F[\phi](s))ds.
\label{EU6}
\end{equation}


\noindent\textbf{Claim 1:} $\mathcal{T}$ maps $E_{A,M;R}$
into itself for some small $M$ and $R>0$.

\begin{proof}
Obviously $\mathcal{T}[\varphi]\in C( [0,R])$. Let
us first choose $ M$. From the definition of the space
$E_{A,M;R}$, $\varphi (r)\in [A-M,A+M]$, for any
$ r\in [0,R]$. Simple calculations show the
existence of $ M_1$ with $ 0<M_1<A$, such that for any
$ M\in [0,M_1]$, $ F[\varphi] $ has a
constant sign in $ [0,R]$ for every
$\varphi\in E_{A,M;R}$. Fix one such $ M$. Moreover, there exists a constant
$ K>0$, depending on $ p,q,N,A,R,M,\alpha$ and $ \beta $, such that
\begin{equation}
|F[\varphi] (s)|\geq Ks\quad\textrm{for all }s\in
[0,R] .  \label{EU7}
\end{equation}
Taking into account that the function $ r\to G(r)/r$
is decreasing on $( 0,+\infty )$, we have
\[
|\mathcal{T}[\varphi](r)-A|\leq
\int_0^r\frac{G(F[\varphi] (s))}{F[\varphi] (s)}|F[\varphi]
(s)|ds\le \int_0^r\frac{G(Ks)}{Ks}|
F[\varphi] (s)|ds
\]
for $ r\in (0,R)$. On the other hand,
\[
|F[\varphi] (s)|\;\leq Cs,\quad
C=[|\alpha |+| 1/N-\alpha| +2\beta(M+A)^{q-1}] (M+A).
\]
We thus get
\[
|\mathcal{T}[\varphi](r)-A|\le
\frac{p-1}pCK^{\frac{2-p}{p-1}} r^{\frac p{p-1}}
\]
 for every $ r\in (0,R)$. Choose $R$ small enough such
that
\begin{equation}
|\mathcal{T}[\varphi](r)-A|\leq M,\quad\textrm{for }\varphi \in E_{A,M;R},
\label{EU8}
\end{equation}
and thereby $\mathcal{T}[\varphi]\in E_{A,M,R}$ (observe that the
value of $ K$ may be kept fixed). The claim is thus proved.
\end{proof}


\noindent\textbf{Claim 2:} $\mathcal{T}$ is a contraction
in some interval $ [0,r_A]$.

\begin{proof}
  According to Claim 1, if $r_A$ is small enough, the space $ E_{A,M;r_A}$
applies into itself. For such $ r_A$ and any
$\varphi , \psi \in E_{A,M_A;r_A}$ we have
\begin{equation}
|\mathcal{T}[\varphi](r)-T[\psi](r)|\leq
\int_0^r|G(F[\varphi] (s))-G(F[\psi] (s))|ds
\label{EU9}
\end{equation}
 where $F[\varphi] $ is given by \eqref{EU4}. Next, let
\[
\Phi (s)=\min (|F[\varphi] (s)|,|F[\psi](s)|).
\]
 As a consequence of estimate \eqref{EU7} (which is
also valid for $F[\psi] (s)$), we have
\[
\Phi (s)\geq K s\quad\textrm{for }0\leq s\leq r<r_A
\]
and then
\begin{equation}
\begin{aligned}
|G(F[\varphi] (s))-G(F[\psi] (s))|
&\leq {\frac{G(\Phi (s))}{\Phi (s)}|F[\varphi] (s)-F[\psi] (s)|}\\
&\leq \frac{G(Ks)}{Ks}|F[\varphi] (s)-F[\psi] (s)|.
\end{aligned}\label{EU10}
\end{equation}
Moreover,
\begin{equation}
|F[\varphi] (s)-F[\psi] (s)|\leq C'\|\varphi
-\psi \| _0s;\quad  C'=[|\alpha |+|1/N-\alpha| +6\beta(M+A)^{q-1}].
\label{EU11}
\end{equation}
 Combining \eqref{EU9}, \eqref{EU10} and \eqref{EU11}, we have
\[
|\mathcal{T}[\varphi](r)-\mathcal{T}[\psi] (r)|\le
\frac{p-1} pC'K^{\frac{2-p}{p-1}} r^{\frac p{p-1}}\|\varphi -\psi \| _0
\]
for any $r\in [0,r_A]$. Choosing $ r_{A}$
small enough, $\mathcal{T}$, is a contraction. This proves the
claim.
\end{proof}


The Banach Fixed Point Theorem then implies the existence of a
unique fixed point of $ \mathcal{T}$ in $ E_{A,M;r_A}$,
which is a solution of \eqref{EU2} and, consequently, of problem
(P). As usual, this solution can be extended to a maximal
interval $ [0,r_{\rm max}[$, $0<r_{\rm max}\le +\infty$.




\noindent\textbf{Step 2:} Existence of a global solution.
We define the energy function
\begin{equation}
E(r)=\frac{p-1}p|u'|^p(r)+\frac 12u^2(r).  \label{EU12}
\end{equation}
According to equation \eqref{E1}, the energy satisfies
\begin{equation}
E'(r)=-ru^{\prime 2}\{ \frac{N-1}{r^2}|u'|^{p-2}(r)+\alpha +\beta q|u|^{q-1}\}.
\label{EU13}
\end{equation}
From our hypothesis it follows that $ E$ is decreasing, hence
it is bounded. Consequently, $ u$ and $ u'$ are also
bounded and the local solution constructed above can be extended
to $ \mathbb{R}_{+}$.



\noindent \textbf{Step 3:}  $(|u'|^{p-2}u')'(0)=-A/N$.
Taking the first derivative in
\eqref{EU2}, inverting the function $G$ , dividing both members
by $r$ and passing to the limit as $r\to 0$ gives, after a
standard application of L'Hopital's rule,
\begin{equation}
\lim_{r\to 0}\frac{|u'|^{p-2}u'(r)}r=-\frac AN,
\label{EU14}
\end{equation}
as desired. The proof of Theorem~\ref{EP1} is complete.
\end{proof}

\begin{remark}  \label{rmk2.1} \rm
(i) It is not difficult to see that the
solutions of (P) are $C^\infty $ functions in the set
$\{r>0:  u'(r)\neq 0\}$. However, we only have $u\in
C^{1+1/(p-1)}$ as global regularity, see \eqref{EU15} and
\eqref{EC17} below. This is exactly the regularity of the
Barenblatt solutions to the pure $p$-laplacian equation.

(ii) It is easy to see from \eqref{E1} that local minima (resp.
maxima) of the function $ u$ can take place only at points
where $ u\le 0$ (resp. $ u\ge 0$).
\end{remark}

\begin{remark} \label{rmk2.2} \rm
In the general case, near the origin we have
$ E'(r)\sim -\frac{N-1}{r}|u'|^{p}(r)$.
\end{remark}

\begin{remark} \label{rmk2.3} \rm
Since the vector field  ${\mathbf F}(r, X, Y)$, is locally
Lipschitz continuous in the set
$$
\{ (r,X,Y)\in \mathbb{R}_{+}^{*}\times \mathbb{R}^{*}\times
\mathbb{R}^{*}\},
$$
there exists a unique solution of $(\ref{EU11})$ in a neighborhood
of $ (r_0, A,B)$ if $r_0>0$, $A,B \neq 0$. The
same method above can be used to extend this result to the cases
$r_0=0$ or $ B=0$.
\end{remark}

\begin{remark} \label{rmk2.4} \rm
Local existence holds with $\beta\le 0$, $\alpha<0$ and the same
proof applies.
\end{remark}

The following result concerns monotonicity of solutions with
respect to the initial data.


\begin{theorem}\label{EP2}
Let $u(\cdot,A)$ and $u(\cdot,B)$ be two solutions of problem {\rm (P)} with
$0 <A < B$. Then $u(\cdot,A)$ and $ u(\cdot,B)$ can
not intersect each other before their first zero.
\end{theorem}

Before  giving the proof of theorem~\ref{EP2}, we need an asymptotic
 expansion near $r=0$, which is given by the following lemma.


\begin{lemma} \label{lem2.1}
Let $u$ be the solution to (P) with $A>0$. There holds
\begin{equation} \label{EU15}
u(r)=A-C_1r^{p/(p-1)}+C_2r^{2p/(p-1)}+o(r^{2p/(p-1)})\quad\textrm{as\
\ }r\to 0
\end{equation}
with
$$
C_1=\frac{p-1}{p}\left(\frac{A}{N}\right)^{1/(p-1)};\quad
C_2=\frac{C_1^2\kappa N}{2A(N+p\kappa)}[\beta pq\kappa A^{q-1}+\alpha
p\kappa+1]
$$
and $\kappa:=1/(p-1)$.
\end{lemma}

\begin{proof} It follows from \eqref{EU14} that, as
$r\to 0$,
$$
-u'(r)=\big(\frac{A}{N}\big)^{\kappa}r^{\kappa}+o(r^{\kappa}).
$$
Integrating on $[0,r]$ we obtain
\begin{equation}
\label{EU16} u(r)=A-C_1r^{p\kappa}+\dots
\end{equation}
with $C_1$ as above (in the sequel we omit the $o 's$ for
simplicity). L'Hopital's rule and the integral equation
(\ref{EU1}) imply
$$
C_2:=\lim_{r\to
0}\frac{u(r)-A+C_1r^{p\kappa}}{r^{2p\kappa}}=\lim_{r\to
0}\frac{C_1p\kappa r^{\kappa}-G(F_u(r))}{2p\kappa r^{2p\kappa -1}}.
$$
Write
$$
F_u(r)=\alpha ru+\beta ru^q+H(r);\quad
H(r):=r^{1-N}\int_0^r\sigma^{N-1}[-\beta
Nu^q(\sigma)+(1-N\alpha)u(\sigma)]  d\sigma.
$$
Again, l'Hopital's rule and the fact that $u(r)\to A$ as $r\to 0$ imply
\begin{align*}
\lim_{r\to 0}\frac{H(r)}{r}
&=\lim_{r\to 0}\frac{\int_0^r\sigma^{N-1}[-\beta
Nu^q(\sigma)+(1-N\alpha)u(\sigma)]  d\sigma}{r^N}\\
&=\frac{-\beta NA^q+(1-N\alpha)A}{N}=:C'.
\end{align*}
This information does not allow to find the value of $C_2$, since
the leading order of the numerator is still unknown. We need the
next term. Toward this end, we compute
$$
H(r)-C' r=[\beta NC_1qA^{q-1}-C_1(1-N\alpha)]r^{1-N}\int_0^r\sigma^{N+\kappa}
d\sigma+\dots=C''r^{(2p-1)\kappa}+\dots,
$$
where
$$
C'':=\frac{[\beta NC_1qA^{q-1}-C_1(1-N\alpha)]}{N+p\kappa}.
$$
(here we have used \eqref{EU16}). Consequently,
$H(r)=C'r+C''r^{(2p-1)\kappa}+\dots$. Plugging this expansion into
$F_u$ and using again  \eqref{EU16} we obtain
$$
F_u(r)=\frac{A}{N}r+C'''r^{(2p-1)\kappa}+\dots;\quad
C'''=C''-\alpha C_1-\beta C_1qA^{q-1}.
$$
Therefore, since $F_u(r)>0$ for $r\sim 0$,
$$
G(F_u(r))=C_1p\kappa r^\kappa+\frac{C_1C'''p\kappa^2 N}{A}r^{2p\kappa-1}+\dots
$$
where $G$ is given by \eqref{EU3} and then
$$
C_2=-\frac{C_1C'''\kappa N}{2A}=\frac{C_1^2\kappa}{2A(N+p\kappa)}[\beta
pq\kappa A^{q-1}+\alpha p\kappa+1].
$$
This concludes the proof of the Lemma.
\end{proof}

\begin{proof}[Proof of Theorem~\ref{EP2}]
Let $R_1$ (resp. $R_2$) denote the first zero of
$u(\cdot, A)$ (resp. $ u(\cdot,B)$) or $R_1=+\infty$ (resp
$R_2=+\infty$) if $u(\cdot,A)>0$ $\in \mathbb{R}_{+} $(resp.
$u(\cdot,B)>0$ $\in \mathbb{R}_{+}$). For ease of notation, we
write $ u(r)=u(r,A)$ and $ v(r)=u(r,B)$.

We argue by contradiction. Suppose there exists
$ R_0\in ]0,\;\min
(R_1,R_2)[$ such that
$ u(r)<v(r)$ for $ r\in [0,R_0[$and $ u(R_0)=v(R_0)$.
For $ k>0$ we define
\begin{equation}
u_k(r)=k^{-\frac{p}{p-2}}u(kr). \label{EU17}
\end{equation}
Since $ u$ is decreasing, we can choose $ k\in ]0,1[$ such that
$ u_k(r)>v(r)$ for $ r\in [0,R_0]$.  Set
\[
K=\sup \big\{ 0<k<1: u_k(r)>v(r)\quad\textrm{for }r\in [0,R_0] \big\} .
%\label{EU22}
\]
We claim that $ u_K(r)\geq v(r)$ for $ r\in[0 ,R_0]$. Indeed, assume
there exists $ r_1\in[0,R_0]$ such that $ u_K(r_1)<v(r_1)$. Since the function
$ k\to u_k(r_1)$ is continuous, there exists  $ \varepsilon>0$ such that
$ u_{k}(r_1)<v(r_1)$ for $ K-\varepsilon<k<K$, contrary
to the  definition of $ K$. Hence $ u_K(r)\geq v(r)$ for
$ r\in [0,R_0]$.

Moreover $u_K(R_0)>v(R_0)$, and $ u_K(0)>v(0)$. In fact, observe first
that if  $u_K(R_0)=v(R_0)=u(R_0)$,
then $K=1$, this contradicts  $ u(r)<v(r)$ for
$0<r<R_0$. Secondly assume $ u_K(0)=v(0)=B$. Then $u_K$ solves
the same problem as $v$ but for a different value of $\beta$. Put
$\beta_K:=\beta K^{\frac{p(q-1)}{p-2}}<\beta$ (recall that $K<1$).
Applying the lemma above to $u_K$ and $v$ we have
\begin{gather*}
u_K(r)=B-C_1r^{p/(p-1)}+\widetilde C_2r^{2p/(p-1)}+\dots\\
v(r)=B-C_1r^{p/(p-1)}+C_2r^{2p/(p-1)}+\dots,
\end{gather*}
where $\widetilde C_2<C_2$, since $\beta_K<\beta$. Thus $u_K<v$ in
a right neighborhood of $r=0$, a contradiction. Then necessarily
$u_K(0)>v(0)$.


Next, we claim that there exists $ R\in ]0,R_0[$ such that $ u_K(R)=v(R)$.
Assume the opposite. Then there
would exist $ \varepsilon>0$ such that $u_K-v>\varepsilon$ on $ [0,R_0]$ and
therefore, by continuity of $ k\to u_k$ as a map from
$]0,1[$ to $ C[0,R_0]$, the same would hold with $ K$ replaced by
$ k,K<k<K+\delta$, for some $\delta(\varepsilon)>0$, contradicting
the definition of $ K$.
This proves the claim.


Clearly, $ u_K'(R)= v'(R)$, since otherwise one
would have $ u_K< v$ on some one-sided neighborhood of $
R$, which is impossible. Thus the function $ \varphi=u_K-v$
has a local minimum at $ R$. On the other hand,  it is easy to
see that $ u_K$ satisfies the equation
\[
( |u_K'|^{p-2}u_K') '+\frac{N-1}{r}|u_K'|^{p-2}u_K'+\alpha ru_K'+u_K+\beta
K^{\frac{p(q-1)}{p-2}}r(u_K^q)'=0.
%\label{EU2}
\]
Subtracting this equation from the one satisfied by $ v$ we
obtain at  $ r=R$:
\[
(p-1)|v'|^{p-2}(R)\varphi^{\prime \prime
}(R)+\beta [K^{\frac{p(q-1)}{p-2}}-1]R(u_K^q)'=0.
%\label{EU24}
\]
Since $ K<1 $, $ \beta >0$, $ u_K(R)=v(R)>0$ and $
u_K'(R)=v'(R)<0$, we deduce $ \varphi''(R)<0$, thus
contradicting the fact that $ \varphi$ has a local minimum at
$ R$. The obtained contradiction proves the assertion.
This completes the proof of the theorem.
\end{proof}


\section{Behaviour at infinity} \label{sect-ab}

This section deals with some qualitative properties of solutions
of problem (P).

\begin{theorem}\label{AP1}
Let $u$ be a solution of  (P). Then,
$$
\lim_{r\to+\infty}u(r)=\lim_{r\to +\infty}u'(r)=0.
$$
\end{theorem}

\begin{proof} By \eqref{EU12}, it is enough to show that
$\lim_{r\to +\infty}E(r)=0$.
 Since $ E'(r)\leq 0$ and $ E(r)\geq 0$ for all $ r>0$, there exists a constant
$ l\geq 0$ such that $ \lim_{r\to+ \infty}E(r)=l$. Suppose $l>0$.
Then, there exists $r_1>0$, such that
\begin{equation}
E(r)\geq l/2\quad\textrm{for  }r\geq r_1. \label{EA1}
\end{equation}
Now consider the function
\begin{align*}
D(r)&={E(r)+\frac{N-1}{2r}|u'|
^{p-2}u'(r)u(r)+\frac{\alpha (N-1)}4u^2(r)} \\
&+\frac{q\beta (N-1)}{2(q+1)}|u|
^{q+1}+\alpha\int_0^rsu'^{2}(s)ds.
\end{align*}
Then
\[
D'(r)=-q\beta r|u|^{q-1}u'^{2}-\frac{(N-1)}{2r}[| u'| ^p+\frac Nr|u'|^{p-2}u'u+u^2] .
\]
Since $ \beta>0$, we have
\[
D'(r)\leq -\frac{N-1}{2r}[|u'|
^p+u^2+\frac Nr|u'|^{p-2}u'u] .
\]
Recalling that $ u$ and $ u'$ are bounded,
\[
\lim_{r\to+\infty }\frac{|u'|
^{p-2}u'\;u(r)}r=0.
\]
Moreover, by \eqref{EA1} we have
\[
|u'(r)|^p+u^2(r)\geq\frac{p-1}p|u'(r)|^p+\frac
{u^2(r)}{2} = E(r)>l/2 \quad \textrm{for  }r\geq r_1.
\]
Consequently, there exist two constants $c>0$ and $\;r_2\geq r_1$
such that
\[
D'(r)\leq - c/r\quad\textrm{for  }r\geq r_2.
%\label{EA6}
\]
 Integrating this last inequality between $r_2$ and $r,\;$we get
\[
D(r)\leq D(r_2)-c\;\ln (r/r_2)\quad\textrm{for }r\geq r_2.
%\label {EA7}
\]
 In particular we obtain  $\lim_{r\to+\infty }D(r)=-\infty $. Since
\[
E(r)+\frac{N-1}{2r}|u'|^{p-2}u'u(r)\leq D(r),
\]
we get $\lim_{r\to +\infty }E(r)=-\infty$. This is impossible,
hence the conclusion.
\end{proof}


\begin{theorem} \label{AP2}
Let $ P_u:=\{r>0:  u(r)>0\}$. Then $u'<0$ in the connected component of
$ P_u$ containing a right neighborhood of $ r=0$.
\end{theorem}

\begin{proof} We argue by contradiction. Let
$ r_0>0$ be the first zero of $ u'$ in the
connected component of $ P_u$ containing a right neighborhood
of $ r=0$. Then, it follows from \eqref{E1}that
$(|u'|^{p-2}u') '(r_0)=-u(r_0)<0$. On the other hand, we know
from \eqref{EU14} that $ u'<0$ for $ r\sim 0$. By continuity and the
definition of $ r_0$, there exists a left neighborhood
$] r_0-\varepsilon ,r_0[$ (for some $\varepsilon>0$) where $ u'$ is
strictly increasing
and strictly negative, that is $( |u'|^{p-2}u') '(r)>0$ for any
$r\in $ $] r_0-\varepsilon ,r_0[$; hence by letting
$r\to r_0$ we get $ ( |u'|^{p-2}u') '(r_0)\geq 0$, a
contradiction.
\end{proof}

\begin{theorem}\label{AP3}
Assume $ \alpha >0$. Let $ u$ be a strictly
positive solution of (P). Then
$\lim_{r\to+\infty}r^{1/\alpha}u(r)=L$
 exists and lies in $[0,+\infty [$.
\end{theorem}

 We postpone the proof of this theorem until establishing
some preliminary results.

\begin{lemma} \label{LP1}
Assume $ \alpha >0$. Let $ u$ be a strictly
positive solution of (P). Suppose there are some $ \sigma
\geq 0$and $ r_0>0$ such that
\begin{equation}
u(r)\leq K (1+r)^{-\sigma }\quad\textrm{for }r\geq r_0.
\label{EA2}
\end{equation}
Then, there exists a constant $ M$ depending on $ K,\sigma $, and
 $ r_0$ such that
\begin{equation}
|u'(r)|\leq M (1+r)^{-\sigma -1}\quad
\textrm{for }r\geq r_0.  \label{EA3}
\end{equation}
\end{lemma}

\begin{proof} Consider the function $ \rho$ defined by
\[
\rho (r)=\exp [\frac \alpha {p-1}\int_{r_0}^rs|
u'(s)|^{2-p}ds].
%\label{EA19}
\]
Note that the function $u'$ is strictly negative and then
$\rho (r)$ is well defined for  $ r\geq r_0$ and it is an
increasing $ C^\infty$ function. Set
\[
F(r)=(p-1)u'(r) r^{\frac{N-1}{p-1}}\rho(r)\quad\textrm{for } r\geq r_0.
\]
Using the fact that $\rho '(r)=\frac \alpha {p-1}r|u'(r)|^{2-p}\rho (r)$
and equation \eqref{E1}, we deduce that, for any $ r\geq r_0$,
\[
F'(r)=-\frac{p-1}\alpha r^{\frac{N-p}{p-1}}\rho '(r)[u(r)
+\beta qru(r)^{q-1}u'(r)]
\]
Integrating this last equation in $( r_0,r)$ with $ r>r_0$ and using
the expression of $F(r)$, we get
\[
u'(r)=\frac{r^{\frac{1-N}{p-1}}}{\rho (r)}u'(r_0)r_0^{\frac{N-1}{p-1}}
-\frac 1\alpha \frac{r^{\frac{1-N}{p-1}}}{\rho (r)}
\int_{r_0}^rs^{\frac{N-p}{p-1}}\rho '(s)[u(s)+\beta
qsu(s)^{q-1}u'(s)] ds .
\]
Since $ u'(r)<0,\alpha >0,\beta>0$ and $\rho '(r)>0$ it follows that
\begin{equation}
|u'(r)|\leq \frac{r^{\frac{1-N}{p-1}}}{\rho
(r)}r_0^{\frac{N-1}{p-1}}|u'(r_0)|+\frac
1\alpha \frac{r^{\frac{1-N}{p-1}}}{\rho (r)}I\quad\textrm{for }
r\ge r_0, \label{EA4}
\end{equation}
where
\[
I=\int_{r_0}^rs^{\frac{N-p}{p-1}}\rho '(s)u(s)ds.
\]
Since $ u'$ is continuous in $ ] 0,+\infty[$ and
$ \lim_{r\to+\infty }u'(r)=0$ (from Theorem \ref{AP1}),
there exists a constant $ K_0$ depending
on $ r_0$ such that
\begin{equation}
|u'(r)|^{2-p}\geq K_0\quad\textrm{for }r\geq r_0. \label{EA5}
\end{equation}
As a consequence,
\begin{equation}
\rho (r)\geq K_2\exp (K_1r^2)\quad\textrm{for }r\geq r_0,
\label{EA6}
\end{equation}
where $ K_1=\frac \alpha {2(p-1)}K_0$ and
$K_2=\exp [-K_1r_0^2]$. Therefore, the first term in
the right hand side of $(\ref{EA4})$ can be estimated as
\begin{equation}
\frac{r^{\frac{1-N}{p-1}}}{\rho (r)}r_0^{\frac{N-1}{p-1}}|
u'(r_0)|\leq \frac 1{K_2}|u'(r_0)|\exp (-K_1r^2). \label{EA7}
\end{equation}

Next we estimate the second term in the right-hand side of \eqref{EA4}. It
follows from \eqref{EA2} that, for $ r\ge 2r_0$,
\begin{equation}
I\leq C\int_{r_0}^{\frac r2}s^{\frac{N-p}{p-1}}\rho '(s)(1+s)^{-\sigma }ds
+C\int_{r/2}^rs^{\frac{N-p}{p-1}}\rho'(s)(1+s)^{-\sigma }ds.  \label{EA8}
\end{equation}
Plainly,
\begin{equation}
\int_{r_0}^{\frac{r}2}s^{\frac{N-p}{p-1}}\rho '(s)(1+s)^{-\sigma}ds\leq (1+r_0)^{-\sigma}\max_{(r_0,
r/2)}(s^{\frac{N-p}{p-1}}) \rho (r/2), \label{EA9}
\end{equation}
and
\begin{equation}
\int_{r/2}^rs^{\frac{N-p}{p-1}}\rho '(s)(1+s)^{-\sigma }ds\leq
(1+r/2)^{-\sigma }\max_{(r/2,
r)}(s^{\frac{N-p}{p-1} })\rho (r). \label{EA10}
\end{equation}
Now note that
\begin{equation}
\frac{\rho (r/2)}{\rho (r)}=\exp \big[-\frac \alpha
{p-1}\int_{r/2}^rs|u'(s)|
^{2-p}ds\big] \leq \exp (-K_3r^2), \label{EA11}
\end{equation}
where $  K_3=\frac{3\alpha }{8(p-1)}K_0$. Combining
\eqref{EA8}---\eqref{EA11}, we  obtain
\begin{equation}
\frac 1\alpha \frac{r^{\frac{1-N}{p-1}}}{\rho (r)}I\leq
C(1+r)^{-\sigma -1}+Cr^{\frac{1-N}{p-1}}\max_{(r_0,\frac
r2)}(s^{\frac{N-p}{p-1}})\exp (-K_3r^2),  \label{EA12}
\end{equation}
where $ C>0$ is a constant depending on $ r_0,p,N$
and $ \sigma$. Putting together \eqref{EA7} and
(\ref{EA12}) the desired estimate \eqref{EA3} follows.
\end{proof}

\begin{lemma} \label{LP2}
Assume $ \alpha >0$. Let $ u$ be a strictly
positive solution of (P). Then
\begin{equation}
u(r)\leq C\;r^{-1/\alpha }\quad\textrm{for large }r.
\label{EA13}
\end{equation}
\end{lemma}

\begin{proof}
Multiplying the equation \eqref{E1} by $ u/r$ and rearranging we obtain
\[
\frac{u^2(r)}r=\frac{|u'|^p}r-\alpha uu'-\frac N{r^2}u|u'|
^{p-2}u'-[\frac{ u|u'|^{p-2}u'}r] '-\beta qu^qu'(r).
%\label{EA34}
\]
Recalling the definition of the energy function given by
\eqref{EU12} we have the inequality
\[
\frac{E(r)}r\leq \frac{3p-2}{2p}\frac{|u'|
^p}r-\frac \alpha 2uu'+\frac N{2r^2}u|u'|^{p-1}-\frac 12\big[\frac{u|u'|
^{p-2}u'}r\big] '-\frac \beta 2qu^qu'(r).
\]
By Theorem~\ref{AP2}, $ u'<0$. Integrating the last
inequality on some interval $ (r,R)$ we obtain
\begin{align*}
{\int_r^R\frac{E(s)}s  ds}
&{\leq \frac{3p-2}{2p}\int_r^R\frac{|u'(s)|^p}s
ds+\frac N2\int_r^R\frac{u(s)|u'(s)|^{p-1}}{s^2}ds} \\
&\quad {+\frac{u(R)|u'(R)|^{p-1}}{2R}+\frac \alpha
4{u^2(r)} +\frac{q\beta}{2(q+1)}u^{q+1}(r).}
\end{align*}
Since  $E$ is strictly decreasing and converges to zero when
$ r\to\infty$, we deduce that $ E'\in L^1(]r_0,\infty [)$ for any $ r_0>0$.
Thereby $ |u'|^p/r\in L^1(] r_0,\infty [)$. Letting $ R\to +\infty $
the following inequality holds
\begin{equation}
\begin{aligned}
{\int_r^\infty \frac{E(s)}s  ds}
 &{\leq \frac \alpha 4{u^2(r)}+\frac{3p-2}{2p} \int_r^\infty \frac{|
u'(s)|^p}s  ds +}\\
&\quad {+\frac N2\int_r^\infty \frac{u(s)|
u'(s)|^{p-1}}{s^2}ds +\frac{q\beta
}{2(q+1)}u^{q+1}(r).}
\end{aligned} \label{EA14}
\end{equation}
Set
\begin{equation}
H(r)=\int_r^\infty \frac{E(s)}s  ds.  \label{EA15}
\end{equation}
From the expression of $E(r)$, we have $ u^2(r)\leq 2E(r)$,
then inequality \eqref{EA14} gives
\begin{equation}
\begin{aligned}
{H(r)+\frac \alpha 2rH'(r)}
&{\leq \frac{3p-2}{2p}\int_r^\infty \frac{
|u'(s)|^p}s  ds+\frac N2\int_r^\infty \frac{u(s)|
u'(s)|^{p-1}}{s^2}  ds}\\
&\quad {+\frac{q\beta }{2(q+1)}u^{q+1}(r)}.
\end{aligned} \label{EA16}
\end{equation}
Assume now that $u$ satisfies
\begin{equation}
u(r)\leq Cr^{-\sigma }\quad\textrm{for }r\geq 1
\label{EA17}
\end{equation}
with some fixed $ \sigma \geq 0$ and some constant $ C>0$
(this is possible because $ u(r)\leq A$\ for  $ r\geq 0$).
Then Lemma \eqref{LP1} implies $|u'(r)|\leq Cr^{-\sigma -1}$, for large
 $r$, and then \eqref{EA16}
and \eqref{EA17} imply
\begin{equation}
[r^{2/\alpha }H(r)]'\leq Cr^{-p(1+\sigma )+2/\alpha -1}+
Cr^{-\sigma(q+1)+ 2/\alpha -1}. \label{EA18}
\end{equation}
We claim that
\begin{equation}
u(r)\leq Cr^{-m}\quad\text{for large }r,  \label{EA19}
\end{equation}
with
\[
m=\min \big\{\frac 1\alpha ,\frac {\sigma(p+2)+p}{4},\frac
{\sigma (1+\frac{q+1}{2})}{2}\big\}.
\]
In fact, we have to distinguish two cases.\\
Case (I): $ [2/\alpha -p(1+\sigma )][ 2/\alpha
-\sigma(q+1)]\neq 0$. Using (\ref{EA18}) there holds
\begin{equation}
H(r)\leq Cr^{-2/\alpha }+Cr^{-p(1+\sigma )\;}+Cr^{-\sigma (q+1)}
\quad\textrm{for large }r. \label{EA20}
\end{equation}
Case (II): $[2/\alpha -p(1+\sigma )][ 2/\alpha
-\sigma(q+1)]= 0$. Here we have three subcases:\\
Case (IIa): $2/\alpha =p(1+\sigma )$ and $2/\alpha \neq\sigma(q+1)$. Then
\begin{equation}
H(r)\leq Cr^{\frac{-\sigma(p+2)- p}{2}\;}+Cr^{-\sigma(q+1)}
\quad\textrm{for large }r. \label{EA21}
\end{equation}
Case (IIb): $2/\alpha \neq p(1+\sigma )$ and $2/\alpha =
\sigma(q+1)$. Then
\begin{equation}
H(r)\leq Cr^{-p(\sigma+1)} + Cr^{-\sigma(1 +\frac{q+1}{2})}
\quad\textrm{for large }r. \label{EA22}
\end{equation}
Case (IIc): $2/\alpha = p(1+\sigma )$ and
$2/\alpha = \sigma(q+1)$. Then
\begin{equation}
H(r)\leq Cr^{\frac{-\sigma(p+2)- p}{2}} \quad\textrm{for large }r. \label{EA23}
\end{equation}
Now using the inequality
\begin{equation}
H(r)\geq \int_r^{2r}\frac{E(s)}sds\geq \frac{E(2r)}2\geq
\frac{u^2(2r)}4, \label{EA24}
\end{equation}
and combining $(\ref{EA20})$, $(\ref{EA21})$, $(\ref{EA22})$, $(\ref{EA23})$ and $(\ref{EA24})$, the estimate $(\ref{EA19})$ follows. \\
If $ m=1/\alpha$ we have exactly the estimate $(\ref{EA13})$.
Otherwise, observe that $ m>\sigma$ and $(\ref{EA13})$
follows by induction starting with $ \sigma =\min \big\{\frac
{\sigma(p+2)+p}{4},\frac {\sigma [1+(q+1)/2]}{2}\big\}$. This
finishes the proof of the lemma.
\end{proof}

 Now we turn to the proof of Theorem~\ref{AP3}.

\begin{proof}[Proof of Theorem~\ref{AP3}]. Let $ u$ be the solution of (P). Set
\begin{equation}
I(r)=r^{1/\alpha }[ u+\frac 1{\alpha r}|u'|
^{p-2}u'].  \label{EA25}
\end{equation}
By a simple computation we get
\[
I'(r)=-\frac{1}\alpha  r^{1/\alpha }[ (N-1/\alpha )
\frac{|u'|^{p-2}u'(r)}{r^2}+\beta
(u^q)'(r)]
\]
By lemmas \ref{LP1} and \ref{LP2}, the functions
$ r\to r^{1/\alpha }(u^q)'(r)$ and $
r\to r^{1/\alpha -2}|u'(r)|^{p-1}$ belong to $ L^1(] r_0,\infty [)$ for any $
r_0>0$; therefore $ I'(r)\in L^1(] r_0,\infty
[)$, and consequently, the limit
\begin{equation}
 \lim_{r\to +\infty}I(r)=\int_{r_0}^\infty
I'(r)dr+I(r_0) \label{EA26}
\end{equation}
exists and is finite. Again $(\ref{EA13})$ and \eqref{EA3}
imply
\begin{equation}
 r^{1/\alpha -1}|u'|^{p-1} \leq Cr^{- (p-2)/\alpha-p} \label{EA27}
\end{equation}
for large $ r$. As a consequence,  $ \lim_{r\to
+\infty}r^{1/\alpha }u(r)=L$ exists and is finite, thus
concluding the proof.
\end{proof}

\begin{theorem} \label{AP4} Assume $L=0$\ in Theorem~\ref{AP4}. Then
 $ r^mu(r)\to 0$\ and $r^mu'(r)\to 0$\ as $r\to +\infty $ for all
 positive integers $ m$.
\end{theorem}

\begin{proof} Since $ L= \lim_{r\to +\infty}
r^{1/\alpha }u(r)=0$, $ \lim_{r\to +\infty}I(r)=0$
(where $I$ is given by $(\ref{EA25})$). Hence
$I(r)=-\int_r^{+\infty }I'(t)dt$. This yields
\begin{equation}
\label{EA28}
\begin{aligned}
u(r) &{\leq \frac 1{\alpha r}|u'|^{p-1}+\frac{q\beta }\alpha r^{-1/\alpha }\int_r^{+\infty
}s^{1/\alpha }u^{q-1}|u'|(s)  ds} \\
&\quad {+\frac 1\alpha  | N-\frac 1\alpha |
r^{-1/\alpha }\int_r^{+\infty }s^{1/\alpha -2}|u'(s)|^{p-1}ds }
\end{aligned}
\end{equation}
In view of Lemma~\ref{LP2},
\[
u(r)\leq C(r^{-p-(p-1)/\alpha}+r^{-q/\alpha }),
\]
for some $ C>0$. If we define the sequence
$ \{m_k\}_{k\in \mathbb{N}}$ by
\[
\left\{
\begin{array}{l}
m_0=\frac 1\alpha \\[4pt]
m_k=\min\left\{p+(p-1)m_{k-1},\; qm_{k-1}\right\};\quad k\ge 1,
\end{array}
\right.
\]
then $\lim_{r\to +\infty}m_k=+\infty $, and the theorem
follows by induction starting with $ m_0= 1/\alpha$. This
completes the proof.
\end{proof}

\begin{theorem} \label{AP5}
Suppose $ \alpha N\ge1$. Then any solution of (P) is strictly
positive.
\end{theorem}

\begin{proof}
We argue by contradiction. Thus, assume that $u  (r_0)=0$ (where $ r_0>0$ is the first zero of $ u$).
Then $ u'(r_0)\leq 0$. On the other hand, multiplying
the equation  $ (E_1)$ by $ r^{N-1}$ and integrating on
$ (0,r_0)$ we get
\begin{equation}
r_0^{N-1}|u'(r_0)|^{p-2}u'(r_0)=(\alpha N-1)\int_0^{r_0}s^{N-1}u(s)ds+\beta
N\int_0^{r_0}s^{N-1}u^q(s)ds. \label{EA29}
\end{equation}
Under our hypotheses, the right-hand side of $(\ref{EA29})$ is
strictly positive. The obtained sign contradiction proves our
assertion.
\end{proof}

Next, we consider the function
\begin{equation}
J(r)=[ u(r)+\frac 1{\alpha r}|u'(r)|
^{p-2}u'(r)] r^N.\label{EA30}
\end{equation}

\begin{lemma} \label{LP3}
 Let the hypotheses in Theorem~\ref{AP5} hold. Then the
function $ J$ is strictly positive for any $ r>0$.
\end{lemma}

\begin{proof} It easy to see that
\begin{equation}
J'(r)=\frac 1\alpha r^{N-1}[\alpha N-1-q\beta
ru^{q-2}(r)u'(r)] u(r).  \label{EA31}
\end{equation}
Since $ u'$ is strictly negative, $ J(r)$ is
strictly increasing for $ r>0$. On the other hand,
$ (|u'|^{p-2}u')'(0)$ is finite
($=-A/N$), hence $ J(0)=0$. Consequently, $ J(r)>0$ for
 $r>0$, concluding the proof.
\end{proof}

\begin{theorem} \label{AP6}
Assume $ \alpha N>1$. Then
$L=\lim_{r\to+\infty}r^{1/\alpha }u(r)>0$.
\end{theorem}

\begin{proof} By Theorem \ref{AP5}, solutions are strictly positive.
Then, by Theorem \ref{AP3}, the limit $ L\in [0,+\infty[$ exists.
Suppose $ L=0$. By Theorem~\ref{AP4}  we have
$$
\lim_{r\to +\infty}r^mu(r)=\lim_{r\to +\infty}r^mu'(r)=0
$$
for any $ m>0$ and thereby $ \lim_{r\to +\infty}J(r)=0$,
in contradiction with the fact that $ J$
is strictly increasing and strictly positive. The theorem is
proved.
\end{proof}


\section{Classification of Solutions} \label{sect-cs}

In this section we give a classification of solutions of problem
(P), according to whether they are strictly positive, change
sign or are compactly supported. We define the following sets:
\begin{gather*}
\mathcal{S}_{+}=\left\{ A>0: u(r,A)>0\textrm{ for }r>0\right\};
\\
\mathcal{S}_{-}=\left\{ A>0: \exists r_0>0:  u(r_0,
A)=0\textrm{ and } u'(r_0;  A)<0\right\}; \\
\mathcal{S}_{C}=\left\{ A>0: \exists r_0>0:  u(r,A)>0\textrm{ for }
 r\in[0,r_0[\textrm{ and }u(r,A) =0 \textrm{ for }r\ge r_0\right\},
\end{gather*}
corresponding respectively to strictly positive, changing sign and
compactly supported solutions.

Observe that $\mathbb{R}_+=\mathcal{S}_{-}\cup\mathcal{S}_{+}\cup\mathcal{S}_{C}$.
Indeed, let $A>0$ be given. Suppose  $A\notin \mathcal{S}_{+}$.
Then there exists $ r_0$ such that $u(r)>0$, for
$0\le r<r_0$, and $ u(r_0)=0$. If $ u'(r_0)<0,$, then $ u$
changes sign and $A\in \mathcal{S}_{-}$. Assume now $u'(r_0)=0$.
Since the energy function given by \eqref{EU12} is non-negative
and decreasing, we get $ u(r)= 0$ for any $ r\geq r_0$ and
$ A\in \mathcal{S}_{C}$.

\begin{remark} \rm
Theorem~\ref{AP5} can be reformulated as:
If $ \alpha N\ge1$\,then $\mathcal{S}_{+}=\mathbb{R}_+$.
\label{rem1}
\end{remark}

Next, we investigate the range $ 0<\alpha N<1$. It turns out
that in this range non of the sets $\mathcal{S}_{+}$,
$\mathcal{S}_{-}$, $\mathcal{S}_{C}$ is empty. To show this, we
apply below the well known shooting technique.

\begin{theorem} \label{CP1}
Assume $ 0<\alpha N<1$. Then $\mathcal{S}_{-}$ is an
open nonempty set.
\end{theorem}

\begin{proof}
\textbf{Step 1.} First, we prove that
$ \mathcal{S}_{-}\neq\textrm{\O}$. More precisely, we claim that
there exists a constant $ A_0>0$ such that for each
$ A\in (0,A_0)$, the solution $ u(\cdot,A)$ changes sign.
To this end, we make the following scaling transformation
\[
u(r)=Av(\zeta ),\quad \textrm{where\ \ }\zeta
=A^{-\frac{p-2}p}r.
\]
Then $ v$ solves the problem
\begin{equation}
\begin{gathered}
{( |v'|^{p-2}v') '+\frac{ N-1}\zeta |v'|
^{p-2}v'+\alpha \zeta v'+v+\beta qA^{q-1}\zeta |v|^{q-1}v'=0
\quad \zeta>0;} \\
v(0)=1,\quad v'(0)=0.
\end{gathered} \label{EC1}
\end{equation}
Recall that the energy function
given by \eqref{EU12} is positive and decreasing. Then
\[
E(r)\le E(0)= \frac{A^2}2,
\]
 which implies
\[
|u(r)|\le A  \quad  \textrm {and} \quad
  |u'(r)|\le (\frac{p}{2(p-1)})^{1/p}A^\frac{2}{p}.
\]
 Therefore, $ v$ and $ v'$ are bounded. More precisely
\[
|v(\zeta)|\le 1   \quad \textrm {and} \quad
   |v'(\zeta)|\le (\frac{p}{2(p-1)})^{1/p}.
\]
 Consequently, for small $A$, the problem $(\ref{EC1})$ can be seen
as a perturbation of the problem
\begin{equation}
\begin{gathered}
{( |w'|^{p-2}w') '+\frac{ N-1}\zeta |w'|
^{p-2}w'(\zeta )+\alpha \zeta
w'+w=0\quad\textrm{for }\zeta >0;} \\
w(0)=1,\quad w'(0)=0.
\end{gathered}  \label{EC2}
\end{equation}
The first equation of the last problem can be written as
\[
[\zeta ^{N-1}|w'|^{p-2}w'+\alpha \zeta ^Nw] '=(\alpha N-1)\zeta
^{N-1}w(\zeta ).
\]
We claim that $ w$ changes sign. In fact, if $ w$ were
strictly positive, we would have $ w'<0$. On the other
hand, as $ \alpha N<1$, the function
\[
\varphi :\zeta \to \zeta ^{N-1}|w'|
^{p-2}w'+\alpha \zeta ^Nw
\]
is strictly decreasing; hence
$ \varphi (\zeta )\leq \varphi (0)=0$ for $ \zeta >0$. That is,
\[
|w'|^{p-2}w'(\zeta )\leq -\alpha
\zeta w(\zeta ),
\]
which gives
\[
\frac{p-1}{p-2}(w^{\frac{p-2}{p-1}})'(\zeta )\leq
-\frac{p-1} p\alpha ^{\frac 1{p-1}}\big( \zeta ^{\frac
p{p-1}}\big) ',
\]
and after integration,
\[
w^{\frac{p-2}{p-1}}(\zeta )\leq 1-\frac{p-2}p\alpha ^{\frac
1{p-1}}\zeta ^{\frac p{p-1}}.
\]
By letting $ \zeta \to +\infty$, we get a contradiction.
Thereby $ w$ and also $ u$ change sign. That is,
$u\in \mathcal{S}_{-}$.



\noindent\textbf{Step 2.} $ \mathcal{S}_{-}$ is open. This
follows easily from local continuous dependence of solutions on
the initial value. The proof is concluded.
\end{proof}


\begin{theorem} \label{CP2} Assume $ 0 <\alpha N <1$. Then
$ \mathcal{S}_{+}$ is an open nonempty set.
\end{theorem}

 The proof of the theorem will be done in several lemmas.

\begin{lemma} \label{LC1} Assume $ \alpha > 0$. Then,
for  large initial data $ A$, the solution
$ u(\cdot, A)$ is strictly positive.
\end{lemma}

\begin{proof}
As in the previous theorem, we introduce a new function $ v$
defined by
\[
u(r)=Av(\zeta ),\quad\textrm{where }\zeta =A^{\frac{q+1-p}p}r.
\]
It is easy to see that $v$ solves the problem
\begin{equation}
\begin{gathered}
{( |v'|^{p-2}v') '+\frac{ N-1}\zeta |v'|
^{p-2}v'+\beta \zeta \left( |v|
^{q-1}v\right) '+A^{1-q}(\alpha \zeta v'+v)=0, \quad\zeta>0;}\\
v(0)=1,\quad v'(0)=0.
\end{gathered}  \label{EC3}
\end{equation}
 Similarly, we have
\[
|v(\zeta)|\le 1  \quad  \textrm {and} \quad
   |v'(\zeta)|\le (\frac{p}{2(p-1)})^{1/p}A^\frac{1-q}{p}.
\]
 Then, for large $A>0$, $(\ref{EC3})$ is a perturbation of
the  problem
\begin{equation}
\begin{gathered}
{( |w'|^{p-2}w') '+\frac{ N-1}\zeta |w'|
^{p-2}w'+\beta \zeta \left(
|w|^{q-1}w\right) '=0\quad\textrm{for }\zeta >0;} \\
w(0)=1,\quad w'(0)=0.
\end{gathered} \label{EC4}
\end{equation}
We claim that $ w$ is strictly positive. Otherwise,
let $r_0$ the first zero of $ w$. Then $ w'(r_0)\leq
0$. On the other hand, multiplying the equation in $(\ref{EC4})$ by
$ \zeta^{N-1}$ and integrating on $ (0,r_0)$ we obtain
\[
r_0^{N-1}|w'|^{p-2}w'(r_0)=\beta
N\int_0^{r_0}\zeta ^{N-1}w^q(\zeta )d\zeta,
\]
which is impossible. Consequently, $u(\cdot,A)\in\mathcal{S}_{+}$.
\end{proof}

Proving that $ \mathcal{S}_{+}$ is open requires much more
effort. For $c>0$, define the function
\begin{equation}
E_c(r) = cu(r)+ru'(r),\quad  r>0. \label{EC5}
\end{equation}
 Note that if $ E_c(r_0)=0$ for some  $ r_0>0$,
equation \eqref{E1} gives
\begin{equation}
\begin{aligned}
&(p-1)|u'|^{p-2}(r_0)E_c'(r_0)\\
&=r_0u(r_0)\Big[\alpha c-1+c\beta q|u|^{q-1}(r_0)
+c^{p-1}(p-1)(\frac{N-p}{p-1}-c)\frac{|u|^{p-2}(r_0)}{r_0^p}\Big].
\end{aligned} \label{EC6}
\end{equation}
from which the sign of $ E_c(r)$ for large $ r$ can be
obtained.

\begin{theorem} \label{CP3}
Let $ u$ be a strictly positive solution  of (P) and $ \alpha>0  $.
Then, for large $ r$, $E_c(r)$ has a
constant sign in the following cases.
\begin{itemize}
\item[(i)] $ c\neq\frac{1}{\alpha}$;
\item[(ii)] $c=\frac{1}{\alpha}=\frac{N-p}{p-1}$;
\item[(iii)] $c=\frac{1}{\alpha}\neq\frac{N-p}{p-1}$, and
$\lim_{r\to +\infty}r^{1/\alpha }u(r)=0$.
\end{itemize}
\end{theorem}

\begin{proof}
Assume there is a sequence $ \{r_n\}$ with $ r_n\to +\infty$ and such that
$ E_c(r)>0$ for $ r_{2k}<r<r_{2k+1}$ and $ E_c(r)<0$ for
$ r_{2k+1}<r<r_{2k+2}$, ($k=0,1,\dots$).
(i) Since $ \lim_{r\to +\infty}u(r)=0$ and
according to $(\ref{EC6})$, we have $ E'_c(r_n)>0$
(respectively $ E'_c(r_n)<0$) for $c>1/\alpha$ (respectively
$  c<1/\alpha$) and large $ n$. On the other hand, it is clear that
$E'_c(r_{2k+1})\le 0$ (respectively $ E'_c(r_{2k})\ge 0$).
The obtained contradiction proves our
assertion for $c\neq1/\alpha$.

When $c=1/\alpha$, equation $(\ref{EC6})$ at point $r=r_n$ becomes
\begin{align*}
&{(p-1)|u'|^{p-2}(r_n)E'_{1/\alpha }(r_n)}\\
&{=r_nu^q(r_n)\Big[\frac{\beta q}{\alpha}}+\big(\frac 1\alpha
\big)^{p-1}(p-1)(\frac{N-p}{p-1}-\frac 1\alpha)
\frac{u^{p-1-q}(r_n)}{r_n^p}\Big].
\end{align*}
 Then, if $\frac 1\alpha= \frac{N-p}{p-1}$, the
leading term of the right hand of the above equality is
$\frac{\beta q}{\alpha}r_nu^q(r_n)$. Hence (ii) follows.

\smallskip
Finally, for (iii), recalling Theorem~\ref{AP4}, we get that
$ E'_{1/\alpha }(r_n)$ has the same sign as
\[
(p-1)\left(\frac 1\alpha
\right)^{p-1}\left(\frac{N-p}{p-1}-\frac
1\alpha\right)\frac{u^{p-1}(r_n)}{r_n^{p-1}}.
\]
 This completes the proof.
\end{proof}

Next we introduce the following auxiliary function:
\begin{equation}
g(r)=u(r)+|u'|^{p-2}u'(r).
\label{EC7}
\end{equation}
\begin{lemma}
\label{LC2} Assume $\alpha > 0 $. Let $u$ be a
strictly positive solution of (P). Then the function $
g(r)$ is strictly positive for large $ r$.
\end{lemma}

\begin{proof} From Theorem~\ref{AP3}  we know that
$ \lim_{r\to +\infty}r^{1/\alpha }u(r)=L\in [0,+\infty [$.

\noindent\textbf{Case A.} $ L>0$. Then $ u(r)\sim
Lr^{-1/\alpha }$ as $ r\to\ +\infty$ and, by
Lemma~\ref{LP1},  $ \lim_{r\to +\infty}r^{1/\alpha }|u'|^{p-2}u'=0$.
Hence, for large $ r$, $g(r)\sim u(r)\sim Lr^{-1/\alpha }$ and thereby
$g$ is strictly positive.

\noindent\textbf{Case B.} $ L=0$. The proof will be done in two
steps.

\noindent\textbf{Step 1.}  $g$ is not negative for large $ r$.
Suppose the opposite holds; i.e., that there exists a large
$R_1$ such that $ g(r)\leq 0$ for $ r\geq R_1$.
Integrating this inequality   on $ (R_1,r)$, we get
\[
u^{\frac{p-2}{p-1}}(r)\leq
u^{\frac{p-2}{p-1}}(R_1)-\frac{p-2}{p-1}r+ \frac{p-2}{p-1}R_1.
\]
By letting $ r\to +\infty$, we obtain a contradiction.

\noindent\textbf{Step 2.}  $ g(r)$ is monotone for large $ r$.
First note that for any $ r>0$,
\[
g'(r)=u'(r)-\frac{N-1}r|u'|
^{p-2}u'-\beta qru^{q-1}u'-\alpha ru'-u.
\]
By (ii) of Theorem~\ref{CP3}, $ E_{1/\alpha}(r)$ has a constant
sign for large $ r$, while $ u$
and $ u'$, go to zero  as $ r\to +\infty$. This
implies  $ g'(r)\sim -\alpha E_{1/\alpha }(r)$ as
$ r\to +\infty$. Consequently, the function $ g$
is monotone for large $ r$. Combining  steps 1 and 2 we get the
desired result.
\end{proof}

 Now we use the phase plane arguments introduced by
\cite{BPT}. For this purpose we consider the equivalent
non-autonomous first order system in the plane $(X,Y)$:
\begin{equation}
\begin{gathered}
X'=|Y|^{-\frac{p-2}{p-1}}Y, \\
{Y'=-\frac{N-1}rY-\alpha r|Y|
^{-\frac{p-2}{p-1} }Y-\beta qr|X|^{q-1}|
Y|^{-\frac{p-2}{p-1}}Y-X,}
\end{gathered} \label{EC8}
\end{equation}
where $ X=u$, $ Y=|u'|^{p-2}u'$, and $'$ is the derivative $d/dr$.

For $ \lambda >0$, we consider the following triangular
subset of the $ (X,Y)$- plane:
\begin{equation}
\mathcal{L}_\lambda =\left\{ (X,Y): 0<X<1,\; -\lambda
X<Y<0\right\} \label{EC9}
\end{equation}

\begin{lemma} \label{LC3} For any $ \lambda >0$ let
$r_\lambda =\frac \lambda \alpha (1+\lambda ^{-\frac p{p-1}})$. If
$(X(r_\lambda ),Y(r_\lambda ))\in
\mathcal{L}_\lambda$
then the semi-orbit $ (X(r), Y(r))_{r\ge r_\lambda}$   of
\eqref{EC8} can leave $ \mathcal{L} _\lambda$ only through
$ (1,0)$.
\end{lemma}

\begin{proof}  We shall show that if $ r\ge r_\lambda $,
then the vector field determined by $(\ref{EC8})$ points into
$ \mathcal{L}_\lambda$. Indeed, on the line $Y=-\lambda X$,
\begin{align*}
\frac{Y'}{X'} &=\frac{Y'}{| Y|^{- \frac{p-2}{p-1}}Y}=-\frac{N-1}r|Y|
^{\frac{p-2}{p-1}}-\alpha r-\frac XY|Y|
^{\frac{p-2}{p-1}}-q\beta r|X|^{q-1}
\\
&= -\frac{N-1}r\lambda ^{\frac{p-2}{p-1}}|X|^{\frac{p-2}{p-1}%
}-\alpha r+\lambda ^{-\frac 1{p-1}}|X|
^{\frac{p-2}{p-1}}-q\beta r|X|^{q-1}.
\end{align*}
To have $ Y'/X'<-\lambda $ it
suffices that $ -\alpha r+\lambda ^{-\frac 1{p-1}}<-\lambda$
or, equivalently,  $ r>r_\lambda$.

On the top $ (Y=0)$,
\[
Y' =-\frac{N-1}rY-\alpha r|Y|
^{-\frac{p-2}{p-1} }Y-X-\beta qr|Y|
^{-\frac{p-2}{p-1}}Y|X|^{q-1}=-X<0
\]
for all $ r>0$. Consequently, if the  orbit leaves
$\mathcal{L}_\lambda, $ it must be through the point $(1,0)$.
The proof is complete.
\end{proof}

\begin{remark} \label{rem2}\rm
 As a consequence of the previous Lemma, the orbits
$(X(r), Y(r))$ corresponding to strictly positive solutions
(hence strictly decreasing), can not leave $
\mathcal{L}_\lambda$.
\end{remark}

\begin{proof}[Proof of Theorem~\ref{CP2}].
First, note that from
Lemma~\ref{LC1}, the set $\mathcal{S}_{+}$ is non empty. To prove
that $ \mathcal{S}_{+}$ is open, take
$ A_0\in \mathcal{S}_{+}$ and fix $ r_0>0$ large, such that
$ u(r_0,A_0)<1$ and $ g(r_0)=u(r_0,A_0)+|u'|^{p-2}u'(r_0,A_0)>0$
(this is possible by virtue of Lemma~\ref{LC2}). Then, by continuous
dependence of solutions on the initial data, there is a neighborhood
$\mathcal{O}(A_0)$ of $A_0$ such that
\begin{equation}\label{EC10}
0<u(r_0,A)<1;\quad
g(r_0)=u(r_0,A)+|u'|^{p-2}u'(r_0,A)>0,
\end{equation}
for any $ A\in \mathcal{O}(A_0)$. In terms of the first order
system (\ref{EC8}), (\ref{EC10}) reads $ 0<X(r_0)<1$ and
$(X+Y)(r_0)>0$; i.e.,  $ (X,Y)(r_0)\in \mathcal{L}_1$.
By  Remark~\ref{rem2}, $ (X,Y)(r)\in \mathcal{L}_1$ for
$ r\ge r_0$. Thus in particular $ X(r)=u(r,A)>0$ for any
$ r\geq r_0$ and $ A\in O(A_0)$. Consequently,
$O(A_0)\subset \mathcal{S}_{+}$. The proof is complete.
\end{proof}


\begin{theorem} \label{CP4}
Assume $ 0<\alpha N<1$. Then there exists a unique
 $ A>0$ such that $ u(\cdot,A)$ has compact support;
 i.e., $\mathcal{S}_c\neq\emptyset$.
\end{theorem}

Existence follows easily from Theorem~\ref{CP1} and Theorem~\ref{CP2}.
For the proof of uniqueness the keystone is to compute series development
of a generic compactly supported solution around the point where
it vanishes. which is the content of the following lemma.

\begin{lemma} \label{LC4} Assume $ 0<\alpha N<1$ and $ \beta> 0$.  Let
$ u$ be a solution with compact support $ [0,R]$.
\begin{itemize}
\item[(i)] If $\frac{kp-(2k-1)}{p-1}<q<\frac{(k+1)p-(2k+1)}{p-1}$,
$(k=1,2,3,\dots)$, then
\begin{equation} \label{EC11}
\frac{|u'|^{p-1}}u(r)=\sum_{i=0}^{k-1}C_{i}(R-r)^i+\tilde
C(R-r)^{(q-1)(p-1)/(p-2)}+\dots \end{equation}

\item[(ii)] If $ q=\frac{kp-(2k-1)}{p-1}$ $ (k=2,3,\dots)$,
then
\begin{equation} \label{EC12}
\frac{|u'|^{p-1}}u(r)=\sum_{i=0}^{k-1}D_{i}(R-r)^i+\dots
\end{equation}
\end{itemize}
where
\begin{itemize}
\item[(a)] $C_i=D_i$ for $i=0,1,\dots k-2$ and depend on $p,
N,\alpha,R$;
\item[(b)] $C_{k-1}$ depends on $p, N, \alpha,R$ for $k\ge 2$;
\item[(c)] $\tilde C= \beta RC^{q-1}$, $
C=\big(\frac{p-2}{p-1}\big)^{(p-1)/(p-2)};$
\item[(d)]$ D_{k-1}=C_{k-1}+\tilde C$ for $k\ge 2$,
\end{itemize}
and the dots denote higher order infinitesimals as $r\to R$.
\end{lemma}

\begin{proof}
For the sake of simplicity and clarity, we give the proof for
$k=1$ and $k=2$.
From this it will be clear how to proceed by induction.
Let $\varepsilon>0$ be small. By integrating equation \eqref{E1} on
$ (r,R)\subset (R-\varepsilon ,R)$, we get
\begin{equation}
{r^{N-1}|u'|^{p-1}(r) = \alpha r^Nu(r)+\beta r^Nu^q(r)-
\int_r^R   [1-\alpha N-\beta Nu^{q-1}(s)] s^{N-1}u(s)  ds.}\label{EC13}
\end{equation}
Dividing both sides by $ r^{N-1}u(r)$,
\begin{equation} \label{EC14}
\frac{|u'|^{p-1}(r)}{u(r)}=\alpha r+\beta ru^{q-1}(r)-\frac
1{r^{N-1}u(r)}\int_r^R[1-\alpha N-\beta
Nu^{q-1}(s)]s^{N-1}u(s) \, ds.
\end{equation}
Note that, as $ 0<\alpha N<1$ and $ u(R)=0$, then
$ 1-\alpha N-\beta Nu^{q-1}(s)>0$ in $ (r,R)$ if
$ \varepsilon$ is sufficiently small. Thereby,
\begin{equation}
\frac{|u'|^{p-1}(r)}{u(r)}<\alpha r+\beta ru^{q-1}(r) \label{EC15}
\end{equation}
and
\begin{equation}
\frac{|u'|^{p-1}(r)}{u(r)}\geq\alpha r+\beta
ru^{q-1}(r)-\frac 1{r^{N-1}u(r)}\int_r^R[1-\alpha N+|\beta |
Nu^{q-1}(s)] s^{N-1}u(s)ds  \label{EC16}
\end{equation}
Since $ 0<u(s)<u(r)$ for $ s\in (r,R)$, by
letting $ r\to R$ in $(\ref{EC15})$ and $(\ref{EC16})$, it
follows that
$$
 \frac{|u'|^{p-1}}u(r)=C_0+o(1);\quad C_0=\alpha R,
$$
as $r\to R$. Integrating this equation, we get
\begin{equation}
\label{EC17}
u(r)=C(R-r)^{(p-1)/(p-2)}+o((R-r)^{(p-1)/(p-2)}),
\end{equation}
with $C$ as in $(c)$ above. Plugging this expression in
(\ref{EC14}) and taking into account that $\alpha r=\alpha
R-\alpha (R-r)$ and
$$
{|\frac 1{r^{N-1}u(r)}\int_r^R[1-\alpha N-
\beta  Nu^{q-1}(s)] s^{N-1}u(s)  ds|\le C'(R-r)}
$$
for $r\sim R$, part $(i)$ of the assertion follows for $k=1$. For
part $(ii)$  we need to refine the last estimate. An application
of L'Hopital's rule gives
$$
\lim_{r\to R}\frac{\int_r^R[1-\alpha N- \beta
Nu^{q-1}(s)] s^{N-1}u(s)
ds}{uR^{N-1}(R-r)}=C'':=\frac{(1-\alpha N)(p-2)}{2p-3},
$$
and therefore in case (ii) with $k=1$ we get the desired result
$$
\frac{|u'|^{p-1}(r)}{u(r)}=\alpha R+[\tilde
C-(\alpha+C'')](R-r)+\dots=D_0+D_1(R-r)+\dots,
$$
since $(q-1)(p-1)/(p-2)=1$.

Assume now $k=2$. In case (i), the previous calculations give
$$
\frac{|u'|^{p-1}(r)}{u(r)}=\alpha
R-(\alpha+C'')(R-r)+\dots=C_0+C_1(R-r)+\dots,
$$
which is not enough for our purposes, since the dependence on
$\beta$ is still unknown. Integrating the last equality, we get
the more precise development
$$
u(r)=C(R-r)^{(p-1)/(p-2)}+D (R-r)^{(p-1)/(p-2)+1}+\dots; \quad
D=\frac{C C_1}{2C_0(p-2)}.
$$
Using this last formula and the assumption $q>(2p-3)/(p-1)$, we
compute
\begin{align*}
&{\lim_{r\to R}}{\frac{\int_r^R[1-\alpha N- \beta
Nu^{q-1}(s)] s^{N-1}u(s)
ds-C''R^{N-1}(R-r)u}{uR^{N-1}(R-r)^2}=}\\
&={C''':=-\frac{(3p-5)C''DR-(p-2)(1-\alpha
N)DR+(p-2)(N-1)(1-\alpha N)C}{(3p-5)CR}.}
\end{align*}
Since  $q<(3p-5)/(p-1)$, we have $(q-1)(p-1)/(p-2)<2$  and
therefore
\begin{align*}
{\frac{|u'|^{p-1}(r)}{u(r)}}
&=\alpha R-(\alpha+C'')(R-r)+\tilde
C(R-r)^{(q-1)(p-1)/(p-2)}+\dots\\
&=C_0+C_1(R-r)+\tilde C(R-r)^{(q-1)(p-1)/(p-2)}+\dots
\end{align*}
If (ii) holds, $(q-1)(p-1)/(p-2)=2$ and the last formula is
replaced by
\begin{align*}
{\frac{|u'|^{p-1}(r)}{u(r)}}
&=\alpha R-(\alpha+C'')(R-r)+(\tilde C+C''')(R-r)^2+\dots\\
&=D_0+D_1(R-r)+D_2(R-r)^2+\dots
\end{align*}
\end{proof}

 Now we are able to establish Theorem \ref{CP4}.

\begin{proof}[Poof of Theorem~\ref{CP4}]
Since $\mathcal{S}_{+}$ and $\mathcal{S}_{-}$ are
nonempty, open and disjoint, the connectedness of $\mathbb{R}^+$ implies
that there exists
$A\in\mathbb{R}^+\setminus(\mathcal{S}_{+}\cup\mathcal{S}_{-})=\mathcal{S}_{c}$.
This settles the existence question.

For uniqueness we use the same ideas of the proof of Theorem~\ref{EP2}.
For this purpose let $u=u(\cdot,A)$ and $v=u(\cdot,B)$ be two solutions
of problem (P) with $0< A < B$, $\mathop{\rm supp }   u=[0,R]$,
$\mathop{\rm supp} v=[0,R_1]$. Much
as in the aforementioned proof, consider the rescaled versions of
$u$ given by (\ref{EU17}). By Theorem~\ref{EP2}, we know that
$u<v$ in $[0,R[$. Hence $R\le R_1$.

Define $K$ as in that proof. The same arguments allow to conclude
that $u_K\ge v$ on $[0,R_1]$ and that there exists $R_0\in
]0,R_1]$ such that $u_K(R_0)= v(R_0)$.

 If $R=R_1$, then $R_0=R$ is easily discarded, thus necessarily
$R_0\in ]0,R[$ and the proof concludes exactly as that of
Theorem~\ref{EP2}.

 If, on the contrary, $R<R_1$, then $R_0=R_1$. Hence, both $u_K$ and $v$ are
supported on $[0,R_1]$. Applying to them the lemma above, and
taking into account the equation satisfied by $u_K$
\begin{equation} \label{EC18}
( |u_K'|^{p-2}u_K') '+\frac{N-1}{r}|u_K'|^{p-2}u_K'
+\alpha ru_K'+u_K+\tilde\beta r(u_K^q)'=0,
\end{equation}
where $\tilde\beta=\beta K^{\frac{p(q-1)}{p-2}}<\beta$, we
conclude that, in some left neighborhood of $r=R_1$,
$$
\frac{(-u_K')^{p-1}}{u_K}<\frac{(-v')^{p-1}}{v}.
$$
Equivalently, $(u_K^{(p-2)/(p-1)})'>(v^{(p-2)/(p-1)})'$.
Integrating on $[r,R_1]$ with $r$ sufficiently close to $R_1$,
we obtain $u_K(r)<v(r)$. This is impossible, hence $R_0\neq R_1$
and we conclude as in the proof of Theorem~\ref{EP2}.
\end{proof}


\section{Results for the Ornstein-Uhlenbeck equation}
\label{sect-ou}

In this section we apply the results obtained in the previous
sections with the particular choice of the constants
$(\ref{EI5})$, related to the Ornstein-Uhlenbeck equation
$\eqref{EI1}$.


\begin{theorem}\label{OU1}
Let $ q\ge p (1+1/N)-1$. Then, for every $ A>0$ equation $\eqref{EI1}$
admits a radial, strictly positive
self-similar solution $U_A(x,t)$, of the form
(\ref{EI2})--(\ref{EI3}), with $A=U_A(0,1)$. Moreover,
$|x|^{p/(q+1-p)}U_A(x,t)$ is bounded for each $t>0$
and there exists $ L(A)\ge 0$ such that
\begin{equation} \label{initialdata}
 \lim_{t\to 0^+}U_A(x,t)=L(A)|x|^{-p/(q+1-p)}\quad \textrm{for each } x\neq 0.
\end{equation}
If $ q> p(1+1/N)-1$, then $ L(A)>0$. If $ L(A)=0$,
$|x|^m U(x,t)$ is bounded for every $ t>0$ and $ m>0$.
\end{theorem}

\begin{theorem} \label{OU2} Let $p-1<q<p (1+1/N)-1$. Then,
for every $ A>0$ equation $\eqref{EI1}$ admits a  radial,
self-similar solution
$U_A(x,t)$, of the form (\ref{EI2})--(\ref{EI3}), with
$A=U_A(0,1)$. These solutions change sign for small $ A$
and are strictly positive for large $ A$.  In the later case,
$ |x|^{p/(q+1-p)}U(x,t)$ is bounded for each
$t>0$ and there exists $ L(A)\ge 0$ such that
$(\ref{initialdata})$ holds. Moreover, there exists a unique
non-negative and compactly supported element $U_{A_0}$ in the
family with support
\begin{equation} \label{support}
\mathop{\rm supp} U_{A_0}(\cdot,t)=\big\{x\in \mathbb{R}^N:
|x| <Ct^{(q+1-p)/p(q-1)}\big\},\quad C>0.
\end{equation}
\end{theorem}

\begin{proof}[Proof of Theorem~\ref{OU1}]
 Put $U_A(x,t)=t^{-1/(q-1)}u(|x|t^{-(q+1-p)/p(q-1)})$,
where $ u(r)$ is the solution of (P). This range of $
p, q$ corresponds to $\alpha\ge 1/N,$, $\beta>0$.
Existence and uniqueness follow from Theorems~\ref{EP1}.
Positivity follows from Theorem~\ref{AP5}. By
Lemma~\ref{LP2},
$$
|x|^{p/(q+1-p)}U_A(x,t)=t^{-1/(q-1)}r^{p/(q+1-p)}u(rt^{-(q+1-p)/p(q-1)})\le C
$$
for each $ t>0$. Moreover, by Theorem~\ref{AP3} we have
$$
\lim_{t\to 0^+}U_A(x,t)=\lim_{y\to
+\infty}y^{-p/(q+1-p)}u(y)=L(A)\ge 0.
$$
The remaining assertions follow at once from Theorems~\ref{AP6}
and \ref{AP4}.
\end{proof}

The proof of Theorem~\ref{OU2} is completely
analogous to the proof above, and we omit it.

\begin{remark} \rm
It is worth mentioning that the compactly supported
solution $ U_{A_0}$ from Theorem~\ref{OU2} is \emph{very
singular} in the sense of \cite{BPT}. Indeed, since $ q>p-1$,
the support $(\ref{support})$ shrinks to $\{0\}$ as $t\to 0^+$,
while an easy calculation shows that
$$
\|U_{A_0}(t)\|_{L^1(\mathbb{R}^N)}=C_1t^{\frac{N(q+1-p)-p}{p(q-1)}}\to
+\infty
$$
as $t\to 0^+$.
\end{remark}

\subsection*{Acknowledgment} The authors would like to express
their deep gratitude to Prof. J. L. V\' azquez, who kindly
suggested the idea of the paper and  supported them through many
fruitful discussions.

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\end{document}
