\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2009(2009), No. 157, pp. 1--12.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2009 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2009/157\hfil
A non-autonomous three-dimensional population system]
{Dynamics of a non-autonomous three-dimensional population system}

\author[T. H. Quang, T. V. Ton, N. T. H. Linh\hfil EJDE-2009/157\hfilneg]
{Ta Hong Quang, Ta Viet Ton, Nguyen Thi Hoai Linh}  % in alphabetical order

\address{Ta Hong Quang \newline
Faculty of Mathematics, Xuan Hoa Teacher Training University,
Vietnam}
\email{hongquangta12@yahoo.com}

\address{Ta Viet Ton \newline
Division of Precision Science \& Technology and Applied Physics,
Graduate School of Engineering, Osaka University, Japan}
\email{taviet.ton@ap.eng.osaka-u.ac.jp}

\address{Nguyen Thi Hoai Linh \newline
Vietnam Publishing House for Science and Technology, Vietnam}
\email{linha1t@yahoo.com}

\thanks{Submitted August 28, 2009. Published December 1, 2009.}
\subjclass[2000]{34C27, 34D05}
\keywords{Predator-prey model; survival; extinction; persistence;
\hfill\break\indent asymptotic stability; Liapunov function}

\begin{abstract}
 In this paper, we study a non-autonomous Lotka-Volterra model
 with two predators and one prey. The explorations involve the
 persistence, extinction and global asymptotic stability of a
 positive solution.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{definition}[theorem]{Definition}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{proposition}[theorem]{Proposition}
\allowdisplaybreaks


\section{Introduction}

The dynamics of Lotka-Volterra models and their permanence,
stability, global attractiveness, coexistence, extinction have
been studied by several authors. Takeu\-chi and Adachi \cite{TA}
showed that some chaotic motions may occur in the model of three
species.  Krikorian \cite{KR} considered an autonomous system of
three species and obtained some results on global boundedness and
stability. Korobeinikov and Wake  \cite{KW}, Korman  \cite{K}
investigated a model of two preys, one predator and another one of
two predators, one prey with constant coefficients, where direct
competition is absent. Ahmad \cite{A3} obtained necessary and
sufficient conditions for survival of species which rely on the
averages of the growth rates and the interaction of coefficients.
Besides, we also refer to \cite{A1,A2,T1,T2}.

In this paper, we consider the following Lotka-Volterra model  of
two predators and one prey
\begin{equation}\label{1}
\begin{gathered}
x_1'(t)=x_1(t)[ a_1(t)-b_{11}(t) x_1(t)-b_{12}(t) x_2(t)-b_{13}(t)
  x_3(t)],\\
x_2'(t)=x_2(t)[ -a_2(t)+b_{21}(t) x_1(t)-b_{22}(t) x_2(t)
 -b_{23}(t) x_3(t)],\\
x_3'(t)=x_3(t)[ -a_3(t)+b_{31}(t) x_1(t)-b_{32}(t)
x_2(t)-b_{33}(t) x_3(t)],
\end{gathered}
\end{equation}
where $x_i(t)$ represents the population density of species $X_i$
at time $t$ $(i\geq 1)$, $X_1$ is the prey and $ X_2, X_3$ are the
predators and they interact with each other. $a_i(t), b_{ij}(t)
(1\leq i,j\leq 3) $ are continuous functions on $\mathbb{R}$ that are
bounded above and below by some positive constants. At time $t$,
$a_1(t)$ is the intrinsic growth rate of  $X_1$, and $a_i(t)$ is
the death rate of $X_i  (i\geq 2)$; $\frac{b_{i1}(t)}{b_{1i}(t)}$
denotes the coefficient in conversion $X_1$ into new individual of
the $X_i (i\geq 2)$; $b_{ij}(t)$ measures the amount of
competition between $X_i$ and $X_j$ $(i\ne j, i,j\geq 2)$, and
$b_{ii}(t) (i\geq 1)$ measures the inhibiting effect of
environment on $X_i$.


This article is organized as follows. Section 2 provides some
definitions and notations. In Section 3, we state some results on
invariant set and asymptotic stability for problem \eqref{1}. In
Section 4, we assume that the coefficients $b_{ij}(t)$ $(1\leq
i,j\leq 3)$ are constants, then we give some inequalities,
involving the average of the coefficients, which guarantees
persistence of the system. Section 5 is a special case of Section
4 in which the coefficients $a_i(t)$  $(i\geq 1)$ are constants.
We also give some inequalities which imply non-persistence; more
specifically, extinction of the third species with small positive
initial values.

\section{Definitions and notation}

In this section we introduce some basic definitions and facts
which will be used in next sections. Let
$\mathbb{R}^3_+=\{(x_1,x_2,x_3) \in \mathbb{R}^3| x_i \geq 0,
i\geq1\}$. For a bounded continuous function $g(t)$ on
$\mathbb{R}$, we denote
$$
g^u= \sup_{t \in \mathbb{R}}\ g(t), \quad
g^l=\inf_{t \in \mathbb{R}} g(t).
$$

The  existence and uniqueness of the global solutions of system
\eqref{1} can be found in \cite{XCCC}. From the uniqueness theorem,
it is  easy to prove the following result.

\begin{lemma}\label{lem.1}
Both the non-negative and positive cones of $\mathbb{R}^3$ are
positively invariant for \eqref{1}.
\end{lemma}

In the remainder of this paper, for biological reasons, we only
consider the solutions $\left(x_1(t), x_2(t), x_3(t)\right)$ with
positive initial values; i.e., $x_i(t_0)>0, i\geq 1$.

\begin{definition} \label{def2.2} \rm
System \eqref{1} is said to be permanent if there exist positive
constants $\delta, \Delta$ with $0<\delta<\Delta$ such
that $\liminf_{t \to \infty}x_i(t)\geq \delta$,
$\limsup_{t \to \infty}x_i(t)\leq \Delta $ for all  $ i\ge1$.
System \eqref{1} is called persistent if $\limsup_{t \to \infty}x_i(t)>0$,
and strongly persistent if $\liminf_{t \to \infty}x_i(t)>0 $ for all
$ i\ge1$.
\end{definition}

\begin{definition} \label{def2.3} \rm
A set $A$ is called to be an ultimately bounded region of system
\eqref{1} if for any solution $(x_1(t), x_2(t), x_3(t))$ of
\eqref{1} with positive initial values, there exists $T_1>0$ such
that  $(x_1(t), x_2(t), x_3(t)) \in A$ for all $t \geq t_0+T_1$.
\end{definition}

\begin{definition} \label{def2.4} \rm
A bounded non-negative solution $(x_1^*(t), x_2^*(t), x_3^*(t))$
of \eqref{1} is said to be global asymptotic stable solution
(or global attractive solution) if any other solution
$(x_1(t), x_2(t), x_3(t))$ of \eqref{1} with positive initial
values satisfies
$$
\lim_{t \to \infty}\sum_{i=1}^3|x_i(t)-x_i^*(t)|=0.
$$
\end{definition}

\begin{remark} \label{rmk2.5} \rm
It is easy to see that if the system \eqref{1} has a global
asymptotic stable solution, then so are all solutions of \eqref{1}.
\end{remark}

\section{The model with general coefficients}

Let $\epsilon$ be a positive constant. We put
\begin{gather*}
M_1^\epsilon=\frac{a_1^u}{b_{11}^l}+\epsilon, \quad
M_2^\epsilon= \frac{-a_2^l+b_{21}^u M_1^\epsilon}{b_{22}^l},\\
M_3^\epsilon=\frac{-a_3^l+b_{31}^uM_1^\epsilon}{b_{33}^l},\quad
m_1^\epsilon=\frac{a_1^l-b_{12}^uM_2^\epsilon-b_{13}^uM_3^\epsilon}{b_{11}^u},\\
m_2^\epsilon=\frac{-a_2^u+b_{21}^lm_1^\epsilon-b_{23}^uM_3^\epsilon}{b_{22}^u},\quad
m_3^\epsilon=\frac{-a_3^u+b_{31}^l m_1^\epsilon-b_{32}^u M_2^\epsilon }{b_{33}^u},
\end{gather*}
\begin{equation} \label{3}
\begin{gathered}
B_1^\epsilon(t)=a_1(t)-2b_{11}(t)m_1^\epsilon-b_{12}(t)m_2^\epsilon-b_{13}(t)m_3^\epsilon+b_{21}(t)M_2^\epsilon+b_{31}(t)M_3^\epsilon,\\
B_2^\epsilon(t)=-a_2(t)+b_{21}(t)M_1^\epsilon-2b_{22}(t)m_2^\epsilon-b_{23}(t)m_3^\epsilon+b_{12}(t)M_1^\epsilon+b_{32}(t)M_3^\epsilon,\\
B_3^\epsilon(t)=-a_3(t)+b_{31}(t)M_1^\epsilon-2b_{33}(t)m_3^\epsilon-b_{32}(t)m_2^\epsilon+b_{13}(t)M_1^\epsilon+b_{23}(t)M_2^\epsilon.
\end{gathered}
\end{equation}
We have the following theorems.

\begin{theorem} \label{thm3.1}
If $m_i^\epsilon >0$ for all $ i\geq1$, then the set $\Gamma_\epsilon$
defined by
\[   %%% \label{2}
\Gamma_\epsilon=\{(x_1, x_2, x_3) \in \mathbb{R}^3|\ m_i^\epsilon
\leq x \leq M_i^\epsilon, i\geq1\}
\]
is positively invariant with respect to system \eqref{1}.
\end{theorem}

\begin{proof}
We know that the logistic equation
$$
X'(t)=AX(t) [B-X(t)] \quad (A, B \in \mathbb{R}, B \neq 0)
$$
has a unique solution
\[
X(t) = \frac{BX_0 \exp\{AB(t-t_0)\}}{X_0\exp\{AB(t-t_0)\}+B-X_0},
\]
where $X_0=X(t_0)$.

We now consider the solution of system \eqref{1} with the initial
values $(x^0_1, x^0_2, x^0_3)$ $ \in \Gamma_\epsilon$.
By Lemma \ref{lem.1}, we have $x_i(t)>0$ for all $t\geq t_0$
and $i\geq 1$. We have
\begin{align*}
x_1'(t) &\leq x_1(t)[a_1(t)-b_{11}(t)x_1(t)]\\
&\leq x_1(t)[a_1^u-b_{11}^lx_1(t)]\\
&=b_{11}^lx_1(t)[M_1^0-x_1(t)].
\end{align*}
Using the comparison theorem, we obtain that
\begin{equation} \label{4}
\begin{aligned}
x_1(t) &\leq \frac{x^0_1 M_1^0 \exp\{a_1^u(t-t_0)\}}{x^0_1
\big[\exp\{a_1^u(t-t_0)\}-1\big] +M_1^0} \\
&\leq \frac{x^0_1 M_1^\epsilon \exp\{a_1^u(t-t_0)\}}{x^0_1
\big[\exp\{a_1^u(t-t_0)\}-1\big] +M_1^\epsilon}\cdot
\end{aligned}
\end{equation}
Then, it follows from $x^0_1\leq M_1^\epsilon$ that $x_1(t)\leq
M_1^\epsilon$ for all $ t \geq t_0$. On the other hand, from
$x^0_2\leq M_2^\epsilon$ and
$$
 x_2'(t) \leq x_2(t) [-a_2^l+b_{21}^u M_1^\epsilon-b_{22}^l x_2(t)]
 =b_{22}^lx_3(t) [M_2^\epsilon-x_2(t)],
$$
it implies that $ x_2(t)\leq M_2^\epsilon $  for all $t \geq t_0$.
Similarly, we can prove that $x_3(t)\leq M_3^\epsilon$ for all
$ t \geq t_0$. From the above results, we have
$$
x_1'(t) \geq x_1(t)[a_1^l-b_{12}^uM_2^\epsilon-b_{13}^uM_3^\epsilon
-b_{11}^u x_1(t)]=b_{11}^ux_1(t)[m_1^\epsilon-x_1(t)].
$$
It follows from $x^0_1\geq m_1^\epsilon$ that
$$
x_1(t) \geq \frac{m_1^\epsilon x^0_1
\exp\{b_{11}^u m_1^\epsilon(t-t_0)\}}{x^0_1
\big[\exp\{b_{11}^um_1^\epsilon(t-t_0)\}-1\big]+m_1^\epsilon}\geq m_1^\epsilon\quad
 \text{for all } t \geq t_0.
$$
Similarly, it is easy to see that $x_2(t)\geq m_2^\epsilon, x_3(t)\geq
m_3^\epsilon$ for all $ t \geq t_0$. The proof is complete.
\end{proof}

\begin{theorem}\label{thm2.2}
If $m_i^\epsilon>0\, (i\geq 1)$, then the set $\Gamma_\epsilon$ is an
ultimately bounded region, i.e., system \eqref{1} is permanent.
\end{theorem}

\begin{proof}
 From \eqref{4} we have $\limsup_{t\to \infty} x_1(t) \leq
M_1^\epsilon$. Thus, there exist $\epsilon>0$ and $t_1\geq t_0$ such that
$x_1(t) \leq M_1^\epsilon$ for all $t\geq t_1$. By the same argument
in Theorem \ref{thm3.1}, it can be shown that $\limsup_{t\to
\infty} x_i(t) \leq M_i^\epsilon $ and $\liminf_{t\to \infty} x_i(t)
\geq m_i^\epsilon (i\geq 2)$. Then $\Gamma_\epsilon$ is an ultimately
bounded region with a sufficiently small $\epsilon>0$.
\end{proof}

In the following theorem, we give some conditions which ensure
the extinction of the predators

\begin{theorem} \label{thm3.3}
If $M_i^0<0$ then $\lim_{t\to \infty} x_i(t)=0, i\geq 2$.
\end{theorem}

\begin{proof}
We see that if  $M_i^0<0$ then $M_i^\epsilon<0$  with  a sufficiently
small $\epsilon$. Similarly as in the proof of Theorem \ref{thm3.1},
we get
\begin{equation} \label{5}
x_i'(t) \leq b_{ii}^lx_i(t) [M_i^\epsilon-x_i(t)]<0, i\geq 2.
\end{equation}
Therefore, $0<x_i(t)\leq x_i(t_0)$ for $t\geq t_0$ and there
exists $c\geq 0$ with $\lim_{t\to \infty}x_i(t)=c$.
If $c>0$
then $0<c\leq x_i(t)\leq x_i(t_0), t\geq t_0$. From \eqref{5},
there exists $\nu>0$ such that $x_i'(t)<-\nu$ for all $t\geq t_0$.
It follows $x_i(t)<-\nu (t-t_0)+x_i(t_0)$ and $\lim_{t\to \infty}
x_i(t)=-\infty$ which contradicts the inequality $x_i(t)>0$ for
all $t\geq t_0$. Hence, $\lim_{t\to \infty} x_i(t)=0$.
\end{proof}

Now,  to consider the global asymptotic stability of a solution,
we need the following result, called Barbalat's lemma (see \cite{B})

\begin{lemma}\label{lem.2}
Let $h$ be a real number and $f$ be a non-negative function
defined on $[h, +\infty)$ such that $f$ is integrable on $[h,
+\infty)$ and uniformly continuous on $[h, +\infty)$. Then
$\lim_{t \to \infty}f(t)=0$.
\end{lemma}

\begin{proof}
We suppose that $f(t) \not\to 0$ as $t \to \infty$.
There exists a sequence $(t_{n}), t_n\geq h$ such that
$t_{n} \to \infty$ as $n \to \infty$ and $f(t_{n}) \geq \varepsilon$
for all $n \in \mathbb{N}$. By the uniform continuity of $f$,
there exists a $\delta > 0$ such that, for all $n \in \mathbb{N}$
and $t \in [t_{n}, t_{n}+\delta]$,
$ |f(t_{n}) - f(t)| \leq \frac{\varepsilon}{2}$.
Thus, for all $t \in [t_{n}, t_{n}+\delta]$ and $n \in \mathbb{N}$
we have
\[
 f(t)=|f(t_{n}) - [f(t_{n})- f(t)]| \geq |f(t_{n})| - |f(t_{n})- f(t)|
\geq \varepsilon - \frac{\varepsilon}{2} = \frac{\varepsilon}{2}.
\]
Therefore,
$$
 \int_{t_{n}}^{t_{n}+\delta} f(t) dt = \int_{t_{n}}^{t_{n}+\delta} f(t) dt
\geq \frac{\varepsilon \delta}{2} > 0
$$
 for each $n \in \mathbb{N}$. By the existence of the Riemann integral
$\int_{h}^{\infty} f(t) dt$, the left hand side of the above
inequality converges to 0 as $n \to \infty$ yielding a contradiction.
\end{proof}

\begin{theorem}   \label{thm3.4}
Let $(x_1^*(t), x_2^*(t), x_3^*(t))$ be a solution of system \eqref{1}.
If $m_i^\epsilon>0$ and  $\limsup_{t\to \infty}B_i^\epsilon(t)<0$ for all
$i\geq 1$, then $(x_1^*(t), x_2^*(t), x_3^*(t))$ is globally
asymptotically stable.
\end{theorem}

\begin{proof}
 From the assumptions, there exists $t_1>t_0$ such that
$\sup_{t\geq t_1}B_i^\epsilon(t)<0$, $i\geq 1$.
 Let $(x_1(t), x_2(t), x_3(t))$ be any solution of positive
initial value system
\eqref{1}. Since $\Gamma_\epsilon$ is an ultimately bounded region,
there exists $T_1>t_1$ such, that for all $t\geq T_1$,
\[
(x_1(t), x_2(t), x_3(t)), (x_1^*(t), x_2^*(t), x_3^*(t)) \in \Gamma_\epsilon.
\]
Now, we consider a Liapunov function defined by
$V(t)=\sum_{i=1}^3|x_i(t)-x_i^*(t)|, t\geq T_1$. For brevity, we
denote $x_i(t), x_i^*(t), a_i(t)$ and $b_{ij}(t)$ by $x_i$,
$x_i^*$, $a_i$ and $b_{ij}$, respectively. A direct calculation of
the right derivative $D^+V(t)$ of $V(t)$ along the solution of
system \eqref{1} gives
\begin{align*}
D^{+}V(t)=&\sum_{i=1}^3 \mathop{\rm sgn}(x_i-x_i^{*}) [{x_i}'-{x^*_i}']
\\
=&\mathop{\rm sgn}(x_1-x_1^{*}) [x_1(a_1-\sum_{j=1}^3 b_{1j} x_j)-x_1^*
(a_1-\sum_{j=1}^3 b_{1j}x_j^*)]
\\
&+\sum_{i=2}^3  \Big[x_i(-a_i+b_{i1}x_1-\sum_{j=2}^3 b_{ij} x_j) \\
&-x_i^*(-a_i+b_{i1}x_1^*-\sum_{j=1}^3 b_{ij}x_j^*)\Big]\mathop{\rm sgn}(x_i-x_i^{*}) \\
=&[a_1-b_{11}(x_1+x_1^*)]|x_1-x_1^*| \\
&-\mathop{\rm sgn}(x_1-x_1^*)\sum_{j=2}^3 b_{1j}(x_1x_j-x_1^*x_j^*) \\
&+\sum_{i=2}^3[-a_i-b_{ii}(x_i+x_i^*)]|x_i-x_i^*| \\
&+\mathop{\rm sgn}(x_2-x_2^*)[b_{21}(x_1x_2-x_1^*x_2^*)-b_{23}(x_2x_3-x_2^*x_3^*)]  \\
&+\mathop{\rm sgn}(x_3-x_3^*)[b_{31}(x_1x_3-x_1^*x_3^*)-b_{32}(x_2x_3-x_2^*x_3^*)]  \\
%%%%%%%%%%%
=&[a_1-b_{11}(x_1+x_1^*)-b_{12}x_2-b_{13}x_3]|x_1-x_1^*| \\
&+[-a_2+b_{21}x_1-b_{22}(x_2+x_2^*)-b_{23}x_3^*]|x_2-x_2^*| \\
&+[-a_3+b_{31}x_1-b_{33}(x_3+x_3^*)-b_{32}x_2^*]|x_3-x_3^*| \\
&-\mathop{\rm sgn}(x_1-x_1^*) \sum_{j=2}^3b_{1j}x_1^*(x_j-x_j^*) \\
&+\mathop{\rm sgn} (x_2-x_2^*)[b_{21}x_2^*(x_1-x_1^*)-b_{23}x_2(x_3-x_3^*)] \\
&+\mathop{\rm sgn} (x_3-x_3^*)[b_{31}x_3^*(x_1-x_1^*)-b_{32}x_3(x_2-x_2^*)] \\
\leq & [a_1-b_{11}(x_1+x_1^*)-b_{12}x_2-b_{13}x_3+b_{21}x_2^*+b_{31}x_3^*]|x_1-x_1^*| \\
&+[-a_2+b_{21}x_1-b_{22}(x_2+x_2^*)-b_{23}x_3^*+b_{12}x_1^*+b_{32}x_3]|x_2-x_2^*| \\
&+[-a_3+b_{31}x_1-b_{33}(x_3+x_3^*)-b_{32}x_2^*+b_{13}x_1^*+b_{23}x_2]|x_3-x_3^*| \\
\leq & [a_1-2b_{11}m_1^\epsilon-b_{12}m_2^\epsilon-b_{13}m_3^\epsilon+b_{21}M_2^\epsilon+b_{31}M_3^\epsilon]|x_1-x_1^*| \\
&+[-a_2+b_{21}M_1^\epsilon-2b_{22}m_2^\epsilon-b_{23}m_3^\epsilon+b_{12}M_1^\epsilon+b_{32}M_3^\epsilon]|x_2-x_2^*| \\
&+[-a_3+b_{31}M_1^\epsilon-2b_{33}m_3^\epsilon-b_{32}m_2^\epsilon+b_{13}M_1^\epsilon+b_{23}M_2^\epsilon]|x_3-x_3^*| \\
=&\sum_{i=1}^3 B_i^\epsilon(t) |x_i-x_i^*|.
\end{align*}
 From the above arguments, there exists a positive constant $\mu>0$
such that
\begin{equation} \label{8}
D^+V(t)\leq -\mu \sum_{i=1}^3 |x_i(t)-x_i^*(t)| \quad
\text{for all } t\geq T_1.
\end{equation}
Integrating both sides of \eqref{8} from $T_1$ to $t$, we obtain
$$
V(t)+\mu \int_{T_1}^t
\Big[\sum_{i=1}^3 |x_i(t)-x_i^*(t)|\Big]dt \leq V(T_1)<+\infty, t\geq T_1.
$$
Then
$$
\int_{T_1}^t \Big[\sum_{i=1}^3 |x_i(t)-x_i^*(t)|\Big]dt
 \leq \frac{1}{\mu} V(T_1)<+\infty, \quad t\geq T_1.
$$
Hence, $\sum_{i=1}^3 |x_i(t)-x_i^*(t)| \in L^1([T_1, +\infty))$.

On the other hand, the ultimate boundedness of $x_i$ and $x_i^*$
imply that both $x_i$ and $x_i^* (i\geq 1)$ have bounded derivatives
for $t \geq T_1$. As a consequence $ \sum_{i=1}^3 |x_i(t)-x_i^*(t)|$
is uniformly continuous on $[T_1, +\infty)$. By Lemma \ref{lem.2} we have
$$
\lim_{t \to \infty} \sum_{i=1}^3 |x_i(t)-x_i^*(t)|=0
$$
which completes the proof.
\end{proof}

\section{The model with constant interaction coefficients}

In this section, we assume that the coefficients $b_{ij}$,
$1\leq i,j\leq 3$ in system \eqref{1} are positive constants and
the limit
\[
M[a_i]=\lim_{T \to \infty} \frac{1}{T} \int_{t_0}^{t_0+T} a_i(t)dt
\]
exists uniformly with respect to $t_0$ in $(-\infty, \infty)$.
First, we consider a predator-prey system
\begin{equation} \label{10}
\begin{gathered}
x_1'(t)=x_1(t)[ a_1(t)-b_{11} x_1(t)-b_{12} x_2(t)],\\
x_2'(t)=x_2(t)[-a_2(t)+b_{21} x_1(t)-b_{22}x_2(t)].
\end{gathered}
\end{equation}
Put $Z_i(T)=\frac{1}{T} \int_{t_0}^{t_0+T} z_i(t)dt$. We have the
following theorem.

\begin{theorem} \label{thm4.1}
Assume that
$b_{11}b_{12}a_2^l+b_{11}b_{22}a_1^l-b_{12}b_{21}a_1^u>0$. Then
$\inf_{t\geq t_0} x_1(t)$ $>0$. Furthermore,
\begin{itemize}
\item[(i)]
If
$M[a_2]<\frac{b_{21}}{b_{11}} M[a_1]$ then $\inf_{t\geq t_0} x_2(t)>0$  and
$$
\lim_{T\to \infty} X_1(T)=\frac{b_{22}M[a_1]+b_{12}M[a_2]}{b_{12}b_{21}
 +b_{11}b_{22}},\quad
\lim_{T\to \infty} X_2(T)=\frac{b_{21}M[a_1]-b_{11}M[a_2]}
 {b_{12}b_{21}+b_{11}b_{22}}.
$$

\item[ii)] If $M[a_2]>\frac{b_{21}}{b_{11}} M[a_1]$ then
$$
\lim_{T\to \infty} X_1(T)=\frac{M[a_1]}{b_{11}},\quad
\lim_{T\to \infty} X_2(T)=0.
$$
\end{itemize}
\end{theorem}

\begin{proof}
The proof for the first statement is similar to that of Theorem
\ref{thm3.1}. Let $\epsilon>0$ be a sufficiently small constant. From
the comparison theorem and
$x_1'(t)\leq x_1(t)[a_1^u-b_{11}x_1(t)]$, it is easy to see that
$\limsup_{t\to \infty} x_1(t) \leq \frac{a_1^u}{b_{11}}$.
Then there exists
$T_1>t_0$ such that $x_1(t)< P_1^\epsilon=\frac{a_1^u}{b_{11}}+\epsilon$
for all $t\geq T_1$. Thus
\begin{equation} \label{4.2}
x_2'(t)<x_2(t)[-a_2^l+b_{21}P_1^\epsilon-b_{22} x_2(t)]\quad
\text{for }t\geq T_1.
\end{equation}
Let us consider two cases:

{\bf Case 1.}
There exists $\epsilon>0$ such that $-a_2^l+b_{21}P_1^\epsilon<0$.
 From \eqref{4.2}, it follows that $\lim_{t\to \infty} x_2(t)=0$.
Therefore, there exists $T_2>T_1$ such that
 $a_1(t)-b_{12}x_2(t)>\frac{1}{2} a_1^l$. It follows from the
first equation of the system \eqref{10} that
$$
x_1'(t)\geq x_1(t)\big[\frac{1}{2}a_1^l-b_{11} x_1(t)\big] \quad
\text{for } t\geq T_2.
$$
Using the comparison theorem, we have $\liminf_{t\to \infty}
x_1(t)\geq a_1^l/ 2b_{11}$.

{\bf Case 2.} $-a_2^l+b_{21}P_1^0\geq 0$.
It follows from \eqref{4.2}  that $\limsup_{t\to\infty} x_2(t)\leq
P_2^\epsilon=\frac{-a_2^l+b_{21}P_1^\epsilon}{b_{22}}$. Then, we can
choose a sufficiently small positive $\epsilon$ and $T_3>T_1$ such
that $x_1(t)\leq P_1^\epsilon, x_2(t)\leq P_2^\epsilon$ for all $t\geq
T_3$. From the first equation of the system \eqref{10}, we have
$x_1'(t)\geq x_1(t)[a_1^l-b_{12}P_2^\epsilon-b_{11}x_1(t)]
\text{ for } t\geq T_3$. Because of our assumption
$b_{11}b_{12}a_2^l+b_{11}b_{22}a_1^l$ $-b_{12}b_{21}a_1^u>0$,
there exists a sufficiently small positive $\epsilon$ such that
$$
a_1^l-b_{12}P_2^\epsilon=\frac{b_{11}b_{12}a_2^l+b_{11}
b_{22}a_1^l-b_{12}b_{21}a_1^u}{b_{11}b_{22}}
-\epsilon \frac{b_{12}b_{21}}{b_{22}}>0.
$$
Then $\liminf_{t\to \infty} x_1(t)>0$.

The conclusions of two above cases implies that
$\inf_{t\geq t_0} x_1(t)>0$. Then there exists $c_1>0$ such that
\begin{equation} \label{11}
c_1< x_1(t)<d_1 \text{ for all } t\geq t_0.
\end{equation}
To prove Part i), first, we show that it is impossible to have
\begin{equation} \label{12}
\lim_{t\to \infty} x_2(t)=0.
\end{equation}
Assuming the contrary, from \eqref{11} and \eqref{12} we get
$$
\lim_{T\to \infty} \frac{1}{T}\ln\big[\frac{x_1(t_0+T)}{x_1(t_0)}\big]=0,
\quad
\lim_{T\to \infty}\frac{1}{T} \int_{t_0}^{t_0+T} x_2(s)ds=0.
$$
Then, from the first equation of \eqref{10} we have
\begin{equation} \label{13}
\begin{aligned}
&\lim_{T\to \infty}\frac{1}{T} \int_{t_0}^{t_0+T} b_{11}x_1(s)ds\\
&=\lim_{T\to \infty} \frac{1}{T}\Big[\int_{t_0}^{t_0+T}
 a_{1}(s)ds-\int_{t_0}^{t_0+T} b_{12}x_2(s)ds
-\ln[\frac{x_1(t_0+T)}{x_1(t_0)}] \Big]\\
&=M[a_1].
\end{aligned}
\end{equation}
It follows from \eqref{12} that
$\frac{1}{T}\ln[\frac{x_2(t_0+T)}{x_2(t_0)}]<0$ for
large values of $T$. By \eqref{13}, we find
\begin{align*}
-M[a_2]+b_{21}\frac{M[a_1]}{b_{11}}
&=\lim_{T\to \infty} \frac{1}{T}
 \Big[ -\int_{t_0}^{t_0+T} a_{2}(s)ds+b_{21}\int_{t_0}^{t_0+T}x_1(s)ds\Big]\\
&=\lim_{T\to \infty}\frac{1}{T}
 \Big[ \ln[\frac{x_2(t_0+T)}{x_2(t_0)}]+ b_{22}\int_{t_0}^{t_0+T}x_2(s)
 ds\Big]
\leq 0,
\end{align*}
which contradicts our assumption. This contradiction proves that
$$
\limsup_{t\to \infty} x_2(t)=d>0.
$$
 If, contrary to the assertion of the theorem,
$\inf_{t\geq t_0} x_2(t)=0$, then there exists a sequence of numbers
$\{s_n\}_1^\infty$ such that $s_n\geq t_0, s_n\to \infty$ as
$n\to \infty$ and $x_2(s_n)\to 0$ as $n\to \infty$. Put
$$
c=\frac{1}{2}\liminf_{T\to \infty} \frac{1}{T}
\int_{t_0}^{t_0+T} x_2(t)dt.
$$

Since $x_2(t)>c$ for arbitrarily large values of $t$ and since
$s_n\to \infty$ and $x_2(s_n)\to 0$ as $n\to \infty$, there exist
sequences $\{p_n\}_1^\infty, \{q_n\}_1^\infty$ and
$\{\tau_n\}_1^\infty$ such that for all $n\geq 1,
t_0<p_n<\tau_n<q_n<p_{n+1}, x_2(p_n)=x_2(q_n)=c$ and
$0<x_2(\tau_n)<\frac{c}{n} \exp\{-b_{21}d_1n\}$. Further, there
exist sequences $\{t_n\}_1^\infty$ and $\{t_n^*\}_1^\infty$ such
that for $n\geq 1$, $t_n<\tau_n<t_n^*$,
\begin{equation}\label{4.4.1}
x_2(t_n)=x_2(t_n^*)=\frac{c}{n},\quad
x_2(t)\leq \frac{c}{n}\quad \text{for } t\in [t_n,t_n^*].
\end{equation}
Thus
\begin{equation} \label{4.4.2}
0<\frac{1}{t_n^*-t_n} \int_{t_n}^{t_n^*} x_2(t)dt
\leq \frac{c}{n} \to 0 \quad \text{as } n\to \infty.
\end{equation}
We show that the following inequalities hold:
\begin{equation} \label{4.4.3}
t_n^*-t_n> t_n^*-\tau_n\geq n \quad \text {for } n\geq 1.
\end{equation}
In fact,
$x_2'(t)=x_2(t)[-a_2(t)+b_{21} x_1(t)-b_{22}x_2(t)]<b_{21}d_1 x_2(t)$
for all $t\geq t_0$, then for $t\geq \tau_n$,
\begin{equation} \label{4.4.4}
\begin{aligned}
x_2(t)=&x_2(\tau_n) \exp \{\int_{\tau_n}^t [-a_2(s)+b_{21} x_1(s)-b_{22}x_2(s)]ds\}\\
\leq &\frac{c}{n}\exp\{-b_{21}d_1n\}\exp\{b_{21}d_1(t-\tau_n)\}\\
=&\frac{c}{n}\exp\{b_{21}d_1(t-\tau_n-n)\}.
\end{aligned}
\end{equation}
 From \eqref{4.4.4} and \eqref{4.4.1}, we obtain $t_n^*-\tau_n\geq n$.
It follows from \eqref{4.4.3} that
$$
M[a_i]=\lim_{n\to \infty} \frac{1}{t_n^*-t_n}\int_{t_n}^{t_n^*} a_i(t)dt,
\quad i=1,2.
$$
Using the first equation of system \eqref{10} we get
\[
\frac{1}{t_n^*-t_n}\ln \big[\frac{x_1(t_n^*)}{x_1(t_n)}\big]
=\frac{1}{t_n^*-t_n}\Big[  \int_{t_n}^{t_n^*} a_1(t)dt-b_{11}
 \int_{t_n}^{t_n^*} x_1(t)dt
-b_{12}\int_{t_n}^{t_n^*} x_2(t)dt\Big].
\]
Then, it follows from \eqref{11}, \eqref{4.4.2} and \eqref{4.4.3} that
\begin{equation} \label{4.4.5}
\lim_{n\to \infty} \frac{1}{t_n^*-t_n}
\int_{t_n}^{t_n^*} x_1(t)dt=\frac{M[a_1]}{b_{11}}\cdot
\end{equation}
Similarly, from the second equation of the system  \eqref{10} we have
\[
\frac{1}{t_n^*-t_n}\ln[\frac{x_2(t_n^*)}{x_2(t_n)}]
=\frac{1}{t_n^*-t_n}\Big[  -\int_{t_n}^{t_n^*} a_2(t)dt
 +b_{21}\int_{t_n}^{t_n^*} x_1(t)dt
-b_{22}\int_{t_n}^{t_n^*} x_2(t)dt\Big].
\]
Taking into account the above relations, \eqref{4.4.1}, \eqref{4.4.2}
and \eqref{4.4.5} we get
$$
-M[a_2]+ \frac{b_{21}}{b_{11}} M[a_1]=0.
$$
Since this contradicts our assumption, we obtain
$\inf_{t\geq t_0} x_2(t)>0$. Therefore, there exists $c_2>0$ such that
\begin{equation} \label{4.6}
c_2<x_2(t)<d_2 \quad \text{for all } t\geq t_0.
\end{equation}
Now, by \eqref{10}, for all $T>0$, we have
\begin{gather*}
\frac{1}{T} \ln \frac{x_1(t_0+T)}{x_1(t_0)}
=A_1(T) -b_{11}X_1(T)-b_{12} X_2(T),
\\
\frac{1}{T} \ln \frac{x_2(t_0+T)}{x_2(t_0)}
=-A_2(T) +b_{21}X_1(T)-b_{22} X_2(T).
\end{gather*}
Then
\begin{equation} \label{4.7}
\begin{gathered}
X_1(T)=\frac{b_{22}[A_1(T)-\frac{1}{T}
\ln \frac{x_1(t_0+T)}{x_1(t_0)}]+b_{12}[\frac{1}{T}
\ln \frac{x_2(t_0+T)}{x_2(t_0)}+A_2(T)]}{b_{12}b_{21}+b_{11}b_{22}}\,,\\
X_2(T)=\frac{b_{21}[A_1(T)-\frac{1}{T} \ln \frac{x_1(t_0+T)}{x_1(t_0)}]
 -b_{11}[\frac{1}{T} \ln \frac{x_2(t_0+T)}{x_2(t_0)}
 +A_2(T)]}{b_{12}b_{21}+b_{11}b_{22}}\,.
\end{gathered}
\end{equation}
It follows from \eqref{11} and \eqref{4.6} that
$$
\lim_{T\to \infty} \frac{1}{T} \ln \frac{x_i(t_0+T)}{x_i(t_0)}=0 \quad
 (i=1,2).
$$
Then
\begin{gather*}
\lim_{T\to \infty} X_1(T)=\frac{b_{22}M[a_1]
+b_{12}M[a_2]}{b_{12}b_{21}+b_{11}b_{22}}, \\
\lim_{T\to \infty} X_2(T)=\frac{b_{21}M[a_1]-b_{11}M[a_2]}{b_{12}
b_{21}+b_{11}b_{22}}\,.
\end{gather*}
To prove Part (ii), first, we show that $\lim_{t\to \infty} x_2(t)=0$.
Assuming the contrary we can find $\delta>0$ and a sequence of
numbers $\{T_n\}_1^\infty, T_n>0, T_n\to \infty (n\to \infty)$
such that $\delta<x_2(t_0+T_n)<d_2$ for all $n$. Then, from the second
equation of \eqref{4.7}, we get
$$
\lim_{n\to \infty} X_2(T_n)
 =\frac{b_{21}M[a_1]-b_{11}M[a_2]}{b_{12}b_{21}+b_{11}b_{22}}<0,
$$
which contradicts $X_2(T)\geq 0$  for all $T>0$. This implies that
$\lim_{t\to \infty} x_2(t)=0$ and then $\lim_{T\to \infty}
X_2(T)=0$. It follows from the first equation of \eqref{4.7} that
$\lim_{T\to \infty} X_1(T)=\frac{M[a_1]}{b_{11}}$.
\end{proof}

Now, we consider the  system
\begin{equation}\label{4.8}
\begin{gathered}
x_1'(t)=x_1(t)[ a_1(t)-b_{11} x_1(t)-b_{12} x_2(t)-b_{13} x_3(t)],\\
x_2'(t)=x_2(t)[ -a_2(t)+b_{21}x_1(t)-b_{22} x_2(t)-b_{23}x_3(t)],\\
x_3'(t)=x_3(t)[ -a_3(t)+b_{31} x_1(t)-b_{32} x_2(t)-b_{33}
x_3(t)].
\end{gathered}
\end{equation}

\begin{proposition} \label{thm4.2}
If
\begin{equation} \label{4.9}
\begin{gathered}
b_{11}b_{12}a_2^l+b_{11}b_{22}a_1^l-b_{12}b_{21}a_1^u>0,\\
M[a_2]<\frac{b_{21}}{b_{11}} M[a_1],\\
M[a_3]<\frac{(b_{31}b_{22}-b_{32}b_{21})M[a_1]
 +(b_{31}b_{12}+b_{11}b_{32})M[a_2]}{b_{12}b_{21}+b_{11}b_{22}},
\end{gathered}
\end{equation}
then $\limsup_{t\to \infty} x_3(t)>0$.
\end{proposition}

\begin{proof}
We assume that $\lim_{t\to \infty} x_3(t)=0$. Then
\begin{equation} \label{4.9.1}
\lim_{T\to \infty} X_3(T)=0.
\end{equation}
Replacing $t_0$ by a larger number, if necessary, we may assume
that $a_1(t)-b_{13} x_3(t)>0$ for $t\geq t_0-1$. We put,
\begin{gather*}
a_1^*(t)= \begin{cases}
a_1(t)-b_{13} x_3(t), & t\geq t_0,\\
a_1(t)-(t-t_0+1) b_{13} x_3(t), &t_0-1 \leq t < t_0,\\
a_1(t), & t<t_0-1,
\end{cases}\\
a_2^*(t)= \begin{cases}
a_2(t)+b_{23} x_3(t), &t\geq t_0,\\
a_2(t)+(t-t_0+1) b_{23} x_3(t), &t_0-1 \leq t < t_0,\\
a_2(t), &t<t_0-1\,.
\end{cases}
\end{gather*}
Then $a_i^*$ is continuous on $\mathbb{R}, a_i^{*l}>0, a_i^{*u}<\infty$
for $ i=1,2$. Moreover, since $\lim_{t\to \infty} x_3(t)=0$,
the limit
$$
M[a_i^*]=\lim_{T\to \infty} \frac{1}{T}\int_{t_*}^{t_*+T} a_i^*(t) dt
=\lim_{T\to \infty}\frac{1}{T} \int_{t_*}^{t_*+T} a_i(t) dt=M[a_i]
$$
exists uniformly with respect to $t_*\in \mathbb{R}$ and $i=1,2$.
Then for $t\geq t_0$, $(x_1(t), x_2(t))$ is a solution of the following
competitive system
\begin{gather*}
x_1'(t)=x_1(t)\big[ a_1^*(t)-b_{11} x_1(t)-b_{12} x_2(t)\big],\\
x_2'(t)=x_2(t)\big[ -a_2^*(t)-b_{21}x_1(t)-b_{22} x_2(t)\big].
\end{gather*}
By condition \eqref{4.9} and Theorem \ref{thm4.1}, we have
\begin{equation} \label{4.9.3}
\begin{gathered}
\lim_{T\to \infty} X_1(T)=\frac{b_{22}M[a_1]
 +b_{12}M[a_2]}{b_{12}b_{21}+b_{11}b_{22}},\\
\lim_{T\to \infty} X_2(T)=\frac{b_{21}M[a_1]
 -b_{11}M[a_2]}{b_{12}b_{21}+b_{11}b_{22}}.
\end{gathered}
\end{equation}
 From the third equation of the system \eqref{4.8} we have
$$
\frac{1}{T}\ln\big[\frac{x_3(t_0+T)}{x_3(t_0)}\big]
=-A_3(T)+b_{31}X_1(T)-b_{32}X_2(T)-b_{33}X_3(T).
$$
Then $-A_3(T)+b_{31}X_1(T)-b_{32}X_2(T)-b_{33}X_3(T)<0$ for
$T$ sufficiently large. Letting $T\to \infty$ and using
 \eqref{4.9.1} and \eqref{4.9.3} we obtain
$$
-M[a_3]+\frac{(b_{31}b_{22}-b_{32}b_{21})M[a_1]+(b_{12}b_{31}
+b_{11}b_{32})M[a_2]}{b_{12}b_{21}+b_{11}b_{22}}\leq 0,
$$
which contradicts \eqref{4.9}. This proves the proposition.
\end{proof}

\begin{proposition} \label{thm4.3}
If the following conditions hold
\begin{equation} \label{4.10}
\begin{gathered}
b_{11}b_{13}a_3^l+b_{11}b_{33}a_1^l-b_{13}b_{31}a_1^u>0,\\
M[a_3]<\frac{b_{31}}{b_{11}} M[a_1],\\
M[a_3]<\frac{(b_{31}b_{33}-b_{23}b_{31})M[a_1]
 +(b_{31}b_{13}+b_{11}b_{23})M[a_3]}{b_{13}b_{31}+b_{11}b_{33}}
\end{gathered}
\end{equation}
then $\limsup_{t\to \infty} x_2(t)>0$.
\end{proposition}

The proof of the above proposition is similar to that of
Proposition \ref {thm4.2}, and it is omitted.

\begin{theorem} \label{thm4.5}
If conditions \eqref{4.9} and \eqref{4.10} hold, then
system \eqref{4.8} is persistent.
\end{theorem}

\begin{proof}
 From Propositions \ref{thm4.2} and \ref{thm4.3}, we have
\begin{equation} \label{4.11}
\limsup_{t\to \infty} x_i(t)>0, \quad i= 2,3.
\end{equation}
Now, we show that $\limsup_{t\to \infty} x_1(t)>0$. Assume the
contrary, then there exist $t_1>t_0$ and  two positive numbers
$b_2, b_3$ such that
$$
-a_i+b_{i1} x_1(t)<-b_i, \quad \text{for all } t\geq t_1, i=2, 3.
$$
Then for $i=2, 3$ and $t\geq t_1$, $x_i'(t)\leq x_i(t)[-b_i-b_{ii}
x_i(t)]$. By the comparison theorem, it follows that
$\lim_{t\to \infty} x_i(t)=0$ which contradicts \eqref{4.11}.
The proof is complete.
\end{proof}

\section{The model with the constant intrinsic growth rates}

In this section, we consider system \eqref{1} under the
condition $a_i, b_{ij}, 1\leq i,j \leq 3$ are constants,
then \eqref{1} becomes
\begin{equation}\label{5.1}
\begin{gathered}
x_1'(t)=x_1(t)[ a_1-b_{11} x_1(t)-b_{12} x_2(t)-b_{13} x_3(t)],\\
x_2'(t)=x_2(t)[-a_2+b_{21}x_1(t)-b_{22} x_2(t)-b_{23}x_3(t)],\\
x_3'(t)=x_3(t)[ -a_3+b_{31} x_1(t)-b_{32} x_2(t)-b_{33}
x_3(t)].
\end{gathered}
\end{equation}
Put
$$
x_1^*=\frac{a_1b_{22}+a_2b_{12}}{b_{11}b_{22}+b_{12}b_{21}},\quad
x_2^*=\frac{a_1b_{21}-a_2b_{11}}{b_{11}b_{22}+b_{12}b_{21}}.
$$

\begin{theorem} \label{thm4.6}
If
\[
a_2<\frac{b_{21}}{b_{11}} a_1\quad\text{and}\quad
-a_3+b_{31}x_1^*-b_{32}x_2^*<0,
\]
then the stationary solution $(x_1^*, x_2^*, 0)$ of  \eqref{5.1}
is locally asymptotically stable. It means that if
$(x_1(t), x_2(t), x_3(t))$ is a solution of \eqref{5.1} such
that $(x_1(t_0),x_2(t_0))$ is close to $(x_1^*,x_2^*)$ and $x_3(t_0)$
is sufficiently small and positive, then
$\lim_{t\to \infty} x_1(t)=x_1^*$,
$\lim_{t\to \infty} x_2(t)=x_2^*$, $\lim_{t\to \infty} x_3(t)=0$.
\end{theorem}

\begin{proof}
It is easy to see that $x_1^*>0, x_2^*>0$ and $(x_1^*, x_2^*, 0)$
is a stationary solution of system \eqref{5.1}. Put
\begin{gather*}
f_1(x_1,x_2,x_3)=x_1(a_1-b_{11} x_1-b_{12} x_2-b_{13} x_3), \\
f_2(x_1,x_2,x_3)=x_2(-a_2+b_{21} x_1-b_{22} x_2-b_{23} x_3), \\
f_3(x_1,x_2,x_3)=x_3(-a_3+b_{31} x_1-b_{32} x_2-b_{33} x_3),
\end{gather*}
then system \eqref{5.1} becomes $x_i'=f_i(x_1,x_2,x_3)$ and
$f_i(x_1^*, x_2^*, 0)=0$, $i\geq1$. Consider
\[
A= \begin{bmatrix}
\frac{\partial f_1}{\partial x_1}& \frac{\partial f_1}{\partial x_2} & \frac{\partial f_1}{\partial x_3}\\
\frac{\partial f_2}{\partial x_1}&\frac{\partial f_2}{\partial x_2}& \frac{\partial f_2}{\partial x_3}\\
\frac{\partial f_3}{\partial x_1}&\frac{\partial f_3}{\partial x_2}&\frac{\partial f_3}{\partial x_3}
\end{bmatrix}
(x_1^*, x_2^*, 0)=
\begin{bmatrix}
-b_{11} x_1^*& -b_{12} x_1^* & -b_{13} x_1^*\\
b_{21} x_2^*& -b_{22} x_2^*& -b_{23} x_2^*\\
0& 0& -a_3+b_{31}x_1^*-b_{32}x_2^*
\end{bmatrix}.
\]
Since
\[
\det (A-\lambda I)
=(-a_3+b_{31} x_1^*-b_{32} x_2^*-\lambda)\big[\lambda^2
 +(b_{11}x_1^*+b_{22} x_2^*) \lambda
 +(b_{11} b_{22}+b_{12}b_{21})x_1^*x_2^*\big],
\]
 it follows that all eigenvalues of $A$ are less than zero.
Therefore, $(x_1^*, x_2^*, 0)$ is locally asymptotically stable.
\end{proof}

\subsection*{Acknowledgements}
The authors would like to thank the anonymous referee for his/her
suggestions. We also would like to thank Prof. Pham Ky Anh for his
help in improving the presentation of this paper.

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