\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2010(2010), No. 92, pp. 1--10.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2010 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2010/92\hfil Fractional differential inclusions]
{Existence of solutions for fractional differential inclusions with
boundary conditions}

\author[D. Yang\hfil EJDE-2010/92\hfilneg]
{Dandan Yang}

\address{Dandan Yang  \newline
School of Mathematical Science\\
Huaiyin Normal University \\
Huaian 223300, China}
\email{yangdandan2600@sina.com}

\thanks{Submitted March 18, 2010. Published July 7, 2010.}
\subjclass[2000]{34A60}
\keywords{Fractional differential inclusions; boundary value conditions;
 \hfill\break\indent
fixed point theorem; multi-valued maps}

\begin{abstract}
 This article concerns the existence of solutions for
 fractional-order differential inclusions with  boundary-value
 conditions. The main tools are based on fixed point theorems
 due to Bohnerblust-Karlin and Leray-Schauder together with
 a continuous selection theorem for upper semi-continuous
 multi-valued maps.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{corollary}[theorem]{Corollary}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{example}[theorem]{Example}
\newtheorem{definition}[theorem]{Definition}
\allowdisplaybreaks


\section{Introduction}

This article concerns  the existence of solutions to
 the  fractional-order differential inclusions with
 boundary-value conditions
 \begin{gather}
 ^{c}D_{0^{+}}^{\alpha}y(t)\in
F(t,y(t)),\quad t\in[0,1], \; \alpha\in(1,2),
  \label{e1.1} \\
 y(0)=0,\quad y(1)=\sum_{i=1}^{m-2}k_i y(\xi_i),
  \label{e1.2}
\end{gather}
where  $ ^{c}D_{0^{+}}^{\alpha}$ is the Caputo
fractional derivative, $F:[0,1]\times \mathbb{R}\to
\mathcal{P}(\mathbb{R})$ is a multi-valued map defined on $[0,1]$,
$\mathcal{P}(\mathbb{R})$ is the family of all nonempty subsets of
$\mathbb{R}$, $k_i>0$, $\xi_i \in [0,1]$ with
$0<\xi_1<\xi_2<\dots <\xi_{m-2}<1$.

Fractional differential equations play a important role in
understanding many phenomena in science and engineering. Such as
electrochemistry, control, viscoelasticity, porousmedia,
electromagnetic and so on. For details two wonderful books
\cite{p,s1} on the subject of fractional differential equations,
summarizing much of fractional calculus and its applications. In
recent years, much attention has been paid to the existence of
solutions fractional differential equations with boundary value
conditions. For instance, Bai and L\"{u}\cite{b1}, Bai \cite{b2},
Stojanovi\'{c}\cite{s2}, Yu and Gao \cite{y}, Zhang \cite{z}.
Following this trend, fractional differential inclusion has got
focus. In 2007 , Ouahab \cite{o} investigated the existence of
solutions
 for $\alpha$-fractional differential inclusions
   by means of selection theorem together  with a fixed point theorem.
   Very recently, Chang and Nieto \cite{c} established some new  existence results for fractional
differential inclusions due to fixed point theorem of multi-valued
maps. About other results on fractional differential inclusions, we
refer the reader to \cite{h}. To the best of our knowledge, for
fractional differential inclusions , very few results are obtained.
In order to fill this gap, motivated by the above mentioned works,
existence of solutions criterion for fractional differential
inclusions are given for \eqref{e1.1} and \eqref{e1.2}. This paper
is organized as follows. In  next section, we present some basic
definitions and notations about fractional calculus and multi-valued
maps. Section 3 is devoted to the existence results for fractional
differential inclusions. In the last section, an example is given to
illustrate our main result.


\section{Preliminaries}

In this section, we recall some notation, definitions and
preliminaries about fractional calculus (see \cite{e,p,s1}) and
multi-valued maps (see\cite{c1,d1,r}) that will be used in the
remainder.

\begin{definition} \label{def2.1}\rm
The $\alpha$th fractional order
integral of the  function $u:(0,\infty)\mapsto R$ is defined by
$$
I^{\alpha}_{0^{+}}u(t)=\frac{1}{\Gamma(\alpha)}
\int_0^{t}(t-s)^{\alpha-1}u(s)ds,
$$
 where $\alpha>0$, $\Gamma$ is the gamma function, provided
the right side  is pointwise defined on $(0,\infty)$.
\end{definition}

 \begin{definition} \label{def2.2}\rm
 The $\alpha$th fractional order derivative of
  a continuous function $u:(0,\infty)\mapsto R$ is defined by
$$
D^{\alpha}_{0^{+}}u(t)= \frac{1}{\Gamma(n-\alpha)}
 (\frac{d}{dt})^{n}\int_0^{t}(t-s)^{n-\alpha-1}u(s)ds,
$$
where $\alpha>0$, $n=[\alpha]+1$, provided that the right side is
pointwise defined on $(0,\infty)$.
\end{definition}

 \begin{definition} \label{def2.3}\rm
 Caputo fractional derivative of order $\alpha>0$ for a function $u$
 defined on $[0,\infty)$ is given by
$$
^{c}D^{\alpha}_{0^{+}}u(t)= \frac{1}
 {\Gamma(n-\alpha)}\int_0^{t}(t-s)^{n-\alpha-1}u^{(n)}(s)ds,
$$
 where  $n=[\alpha]+1$, provided that the right side is
pointwise defined on $(0,\infty)$.
\end{definition}

\begin{lemma}[cite{du}] \label{lem2.1}
 Let $\varepsilon$, $\eta$ are two positive constants, then
\begin{itemize}
\item[(i)] $I^{\varepsilon}_{0^{+}}:L^{1}(J,R)\to
 L^{1}(J,R)$.

\item[(ii)] $I^{\varepsilon}_{0^{+}}I^{\eta}_{0^{+}}f(t)=I^{\varepsilon+
 \eta}_{0^{+}}f(t)$, $f(t)\in L^{1}(J,R)$.

\item[(iii)] $\lim_{\varepsilon\to n}I^{\varepsilon}_{0^{+}}f(t)
=I^{n}_{0^{+}}f(t)$,
 $n=1,2,\dots $, $I^{1}_{0^{+}}f(t)=
 \int_{0}^{t}f(s)ds$.
\end{itemize}
\end{lemma}

Let $C([0,1],\mathbb{R})$ be the Banach space consisting of
 continuous functions $y$ from $[0, 1]$ to
$\mathbb{R}$ with the norm
\[
\|y\|_{\infty}:=\sup\{|y|:t \in[0, 1]\}.
\]
 and $L^{1}([0,1],\mathbb{R})$ represent the functions
$y:[0,1]\to X$ which are Lebesgue integrable and
$$
\|y\|_{L^{1}}=\int_0^{1}|y(t)|dt.
$$
Let $(X,| \cdot |)$ be a Banach space. Then a multi-valued
map $\Theta: X \to \mathcal{P}(X)$ is convex (closed) value
if $\Theta(x)$ is convex (closed) for all $x\in X$. $\Theta$
is bounded on bounded sets if $\Theta(B)=\bigcup_{x\in
B}\Theta(x)$ is bounded in $X$ for any bounded set $B$ of $X$ (i.e.
$\sup_{x\in B}\{\sup\{|y|:y\in \Theta(x)\}\}<\infty$).

 We call $\Theta$ is called upper semi-continuous (u.s.c.)
on $X$ if for each
$x_0\in X$, the set $\Theta(x_0)$ is a nonempty closed subset of
$X$, and if for each open set $B$ of $X$ containing $\Theta(x_0)$,
there exists an open neighborhood $V$ of $x_0$ such that
$\Theta(V)\subseteq B$.
$\Theta $ is said to be completely continuous if $\Theta$ is u.s.c.
if and only if $\Theta$ has a closed graph, i.e.,
$$
x_n\to x_{*},\quad y_n\to y_{*},\quad y_n\in \Theta x_n
\quad \text{imply } y_{*}\in \Theta x_{*}.
$$
Let $CC(X)$ be the set of all nonempty
compact-convex subsets of $X$. For each $y\in C([0,1],\mathbb{R})$,
let $S_{F,y}$ be the set of selections of $F$ defined by
$$
S_{F,y}=\{f\in L^{1}([0,1],\mathbb{R}):f\in F(t,y(t))\quad\text{a.e. }
t\in [0,1]\}.
$$

\begin{definition}\label{def2.5} \rm
A function $y\in C([0,1],\mathbb{R})$ is
said to be a solution of \eqref{e1.1} and \eqref{e1.2} if $y$
satisfies the fractional differential inclusion \eqref{e1.1} on $
[0, 1]$ and the boundary value condition \eqref{e1.2}.
\end{definition}

To set the frame for our main results, we introduce the following
lemmas.

\begin{lemma}[Bohnerblust-Karlin, \cite{b3}]\label{lem2.6}
Let $X$ be a Banach space, D a nonempty subset of $X$, which is bounded,
closed, and convex. Suppose $G: D\to \mathcal{P}(X)\setminus\{0\}$ is
 u.s.c. with closed, convex values, and such that $G(D)\subset D$ and
 $\overline{G(D)} $ compact. Then $G$ has a fixed point.
\end{lemma}


\begin{lemma}[Leray-Schauder Nonlinear Alternative, \cite{d2}]
\label{lem2.7}
Let Let $X$ be a Banach space, with
$C\subset X$ convex. Assume $V$ is a relatively open subset of $C$
with $0\in V$ and $G: \overline V\to \mathcal{P}(C)$ is a compact
multivalued map, u.s.c. with convex closed values. Then either
\begin{itemize}
\item[(i)] $G$ has a fixed point in $\overline V;$ or

\item[(ii)] there exists a point $v \in \partial V$ such that $v\in \lambda
G(v)$ for some $\lambda \in (0,1)$.
\end{itemize}
\end{lemma}

\begin{lemma}[\cite{l}]\label{lem2.8}
 Let $X$ be a Banach space. Let
$F: [a,b]\times X\to CC(X); (t,y)\mapsto F(t,y)$ measurable with
respect to t for any $y\in X$ and u.s.c. with respect to $y$ for
a.e. $t\in [a,b]$ and $S_{F,y}\neq \emptyset $ for any $y\in
C([a,b], X)$ and let $\Lambda$ be a linear continuous mapping from
$L^{1}([a,b],X)$ to $C([a,b],X)$, then the operator
$\Lambda \circ S_{F}:C([a,b],X) \to CC(C([a,b],X))$
$y\mapsto (\Lambda\circ S_{F})(y):=\Lambda(S_{F,y})$
is a closed graph operator in $C([a,b],X)\times C([a,b],X) $.
\end{lemma}

 Now we are in the position to state and prove our
main results.

\section{Main results}

Let us list the following assumptions:
\begin{itemize}
\item[(A1)] $\sum_{i=1}^{m-2}k_i \xi_{i}\neq 1$.

\item[(A2)] $F: [0,1]\times \mathbb{R} \to CC(\mathbb{R})$, $t \mapsto
F(t,y)$ is measurable for each $ y\in \mathbb{R}$, $y\mapsto F(t,y)$
is u.s.c. for a.e. $t\in [0,1]$.

\item[(A3)] For each $r>0$, there exists a function $\varphi_r\in
L^{1}([0,1], \mathbb{R}_{+})$ such that
$$
\|F(t,y)\|=\sup \{|f|: f\in F(t,y)\} \le \varphi_r(t),
$$
for $(t,y)\in [0,1]\times \mathbb{R}$
with $|y|\le r$, and
$$
\lim \inf _{r\to \infty}\frac{1}{r}\int_0^{1}
\varphi_r(t) dt=\mu.
$$

\item[(A4)] There exist a continuous nondecreasing function
$\phi:[0,\infty)\to [0,\infty)$, a function
$q\in L^{1}([0, 1],\mathbb{R}_{+})$ and a positive constant
$M$ such that
$$
\|F(t,y)\|\le q(t) \phi(|y|)
$$
for each $(t,y) \in [0,1]\times \mathbb{R}$, and
$$
\frac{M}{\Big(1+\frac{1}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}
+\frac{1\sum_{i=1}^{m-2}k_i\xi_i}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}\Big)
\phi(M)\int_0^{1}q(s)ds}> 1.
$$
\end{itemize}

We notice that, for each $y \in C([0,1], \mathbb{R})$, by \cite{r},
the set $S_{F, y}$ is nonempty. The following lemmas are basic
results for the fractional differential equations.

\begin{lemma}[\cite{e}]\label{lem3.1}
 Let $\alpha>0$. then the fractional
differential equation
$$^{c}D^{\alpha}_{0^{+}}y(t)=0$$
 has a solution
$$y(t)=c_0+c_1t+c_2t^2+\dots +c_nt^{n-1},$$
and $c_i\in \mathbb{R}$, $i=1,2,\dots ,n$, $n=[\alpha]+1$.
\end{lemma}


\begin{lemma}[\cite{e}]\label{lem3.2}
 Let $\alpha>0$. Then
$$
I_{0^+}^{\alpha c} D^{\alpha}_{0^{+}}y(t)
=y(t)+c_0+c_1t+c_2t^2+\dots +c_nt^{n-1},
$$
 for some $c_i\in \mathbb{R}$, $i=1,2,\dots ,n$, and
$n=[\alpha]+1$.
\end{lemma}

By Lemma \ref{lem3.1} and Lemma \ref{lem3.2}, it is easy to obtain
the following lemma.

 \begin{lemma} \label{lem3.3}
Suppose {\rm (A1)} holds, and  $g\in C([0,1],\mathbb{R})$.
Then $y(t)$ is a solution of the problem
\begin{gather}
^{c}D^{\alpha}_{0^{+}}y(t)=g(t),\quad t\in
[0,1],\quad1<\alpha<2.\label{e3.1}
\\
y(0)=0,\quad y(1)=\sum_{i=1}^{m-2}k_{i}y(\xi_i),\label{e3.2}
\end{gather}
if and only if
 \begin{equation}
 \begin{aligned}
y(t)&=\frac{1}{\Gamma(\alpha)}\int_{0}^{t}(t-s)^{\alpha-1}g(s)ds
-\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
 \int_0^{1}(1-s)^{\alpha-1}g(s)ds\\
&\quad +\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
\sum_{i=1}^{m-2}k_i\int_{0}^{\xi_i}(\xi_i-s)^{\alpha-1}g(s)
ds.\label{e3.3}
\end{aligned}
\end{equation}
\end{lemma}

\begin{proof}
If $y(t)$ is a solution of  \eqref{e3.1}-\eqref{e3.2},
then
\begin{equation}
^{c}D^{\alpha}_{0^{+}}y(t)=g(t),\label{e3.4}
\end{equation}
 Lemma \ref{lem3.2} implies
\begin{equation}
y(t)=\frac{1}{\Gamma(\alpha)}\int_0^{t}(t-s)^{\alpha-1}g(s)ds+c_1+c_2t.
\label{e3.5}
\end{equation}
 By the boundary condition $y(0)=0$, we have
\begin{equation}
c_1=0. \label{e3.6}
\end{equation}
Furthermore, by $y(1)=\sum_{i=1}^{m-2}k_{i}y(\xi_i)$ and
\eqref{e3.5}, we obtain
\begin{equation}
\frac{1}{\Gamma(\alpha)}\int_{0}^{1}(1-s)^{\alpha-1}g(s)ds+c_2=\frac{1}{\Gamma(\alpha)}
\sum_{i=1}^{m-2}k_{i}\int_0^{\xi_i}(\xi_i-s)^{\alpha-1}g(s)ds+\sum_{i=1}^{m-2}k_{i}\xi_ic_2.
\label{e3.7}
\end{equation}
 After a rearrangement of \eqref{e3.7}, we obtain
\begin{equation}
(1-\sum_{i=1}^{m-2}k_{i}\xi_i)c_2=\frac{1}{\Gamma(\alpha)}
\sum_{i=1}^{m-2}k_{i}\int_0^{\xi_i}(\xi_i-s)^{\alpha-1}g(s)ds
-\frac{1}{\Gamma(\alpha)}\int_{0}^{1}(1-s)^{\alpha-1}g(s)ds.\label{e3.8}
\end{equation}
 That is,
\begin{equation}
\begin{aligned}
c_2&=\frac{1}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_{i}\xi_i)}
\sum_{i=1}^{m-2}k_{i}\int_0^{\xi_i}(\xi_i-s)^{\alpha-1}g(s)ds\\
&\quad -\frac{1}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_{i}\xi_i)}
\int_{0}^{1}(1-s)^{\alpha-1}g(s)ds.
\end{aligned} \label{e3.9}
\end{equation}
 Substituting \eqref{e3.6} and \eqref{e3.9} into \eqref{e3.5},
we have that
\eqref{e3.1}-\eqref{e3.2} has a unique solution
\begin{equation}
\begin{aligned}
y(t)&=\frac{1}{\Gamma(\alpha)}\int_{0}^{t}(t-s)^{\alpha-1}g(s)ds
-\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}\int_0^{1}(1-s)^{\alpha-1}g(s)ds\\
&\quad +\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
\sum_{i=1}^{m-2}k_i\int_{0}^{\xi_i}(\xi_i-s)^{\alpha-1}g(s)
ds.\end{aligned}\label{e3.10}
\end{equation}
If $y(t)$ is defined as in \eqref{e3.3}, it is easy to check that
$y(t)$ satisfies \eqref{e3.1}-\eqref{e3.2}, which completes the
proof.
\end{proof}

Next, we shall present and prove our main results on the existence
of solutions to fractional differential inclusion
\eqref{e1.1}-\eqref{e1.2}.


 \begin{theorem}\label{thm3.1}
Assume {\rm (A1)--(A3)} hold. Furthermore,
if
\begin{equation}
\frac{1}{\Gamma(\alpha)}\bigg(1+\frac{1}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}
+\frac{\sum_{i=1}^{m-2}k_i\xi_i}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}\bigg)\mu
<1,\label{e3.11}
\end{equation}
Then problem \eqref{e1.1}-\eqref{e1.2} has at least one solution
on $[0,1]$.
\end{theorem}

\begin{proof}
Consider the operator $N : C([0, 1],\mathbb{R})\to \mathcal{P}(C([0,
1],\mathbb{R}))$ defined by
\begin{equation}
 \begin{aligned} N (y)&=\{h\in C([0, 1],\mathbb{R}):h(t)=
 \frac{1}{\Gamma(\alpha)}\int_{0}^{t}(t-s)^{\alpha-1}f(y(s))ds\\
 &\quad-\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}\int_0^{1}(1-s)^{\alpha-1}f(y(s))ds\\
&\quad +\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}\sum_{i=1}^{m-2}k_i\int_{0}^{\xi_i}
(\xi_i-s)^{\alpha-1}f(y(s))ds, \quad f\in S_{F,y}
\}.\end{aligned}
\label{e3.12}
\end{equation}
 It is obvious that the fixed points of $N$ are solutions
to the problem \eqref{e1.1}-\eqref{e1.2}. Then, we shall prove $N$
satisfies all the assumptions of Lemma \ref{lem2.6}, which is broken
into several steps.

Step 1. $N(y)$ is convex for each $y\in C([0,1],\mathbb{R})$.
In fact, if $h_1, h_2\in N(y)$, then there exist $f_1,f_2\in
S_{F,y}$ such that for each $t\in [0,1]$ we have
\begin{align*}
&h_{\eta}(t)\\
&=\frac{1}{\Gamma(\alpha)}\int_{0}^{t}(t-s)^{\alpha-1}
 f_{\eta}(y(s))ds-\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
 \int_0^{1}(1-s)^{\alpha-1}f_{\eta}(y(s))ds\\
&\quad +\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
\sum_{i=1}^{m-2}k_i\int_{0}^{\xi_i}(\xi_i-s)^{\alpha-1}f_{\eta}(y(s))ds,\quad
\eta=1,2.
\end{align*}
Let $0\le \varepsilon \le 1$, for $t\in [0, 1]$. We have
\begin{align*}
&(\varepsilon h_1+(1-\varepsilon)h_2)(t)\\
&=\frac{1}{\Gamma(\alpha)}\int_{0}^{t}(t-s)^{\alpha-1}(\varepsilon
f_1+(1-\varepsilon)f_2)(y(s))ds\\
&\quad -\frac{t}{\Gamma(\alpha)
(1-\sum_{i=1}^{m-2}k_i\xi_i)}\int_0^{1}(1-s)^{\alpha-1}
(\varepsilon f_1+(1-\varepsilon)f_2)(y(s))ds\\
&\quad +\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
\sum_{i=1}^{m-2}k_i\int_{0}^{\xi_i}(\xi_i-s)^{\alpha-1}(\varepsilon
f_1+(1-\varepsilon)f_2)(y(s))ds,
\end{align*}
 Since $S_{F,y}$ is convex ($F$ has convex values), we have
$$
\varepsilon h_1+(1-\varepsilon)h_2\in N(y).
$$

 Step 2. $N$ maps bounded sets into bounded sets.
 Let $B_r=\{y\in C([0,1],\mathbb{R}): \|y\|\le r\}$. Then $B_r$ is a bounded
closed
 convex set in $C([0,1],\mathbb{R})$. We shall prove that there exists a
 positive number $r'$ such that $N(B_r')\subseteq B_r'$. If not, for each
 positive number $r$, there exists a function $y_{r}(\cdot)\in
 B_{r}$, however, $\|N(y_{r})\|>r$ for some $t\in [0,1]$, and
\begin{align*}
&h_r(t)\\
&=\frac{1}{\Gamma(\alpha)}\int_{0}^{t}(t-s)^{\alpha-1}f_r(y(s))ds
-\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
\int_0^{1}(1-s)^{\alpha-1}f_r(y(s))ds\\
&\quad +\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
\sum_{i=1}^{m-2}k_i\int_{0}^{\xi_i}(\xi_i-s)^{\alpha-1}f_r(y(s))ds.
\end{align*}
for some $f_{r}\in S_{F,y_r}$. On the other hand, we have
\begin{equation}
\begin{aligned}
r&<\|N(y_r)\|\\
&\le\frac{1}{\Gamma(\alpha)} \Big(\int_0^{1 }\varphi_{r}(s)ds
+\frac{1}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}\int_0^{1
}\varphi_{r}(s)ds \\
&\quad +\frac{1}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}
 \sum_{i=1}^{m-2}k_i\int_{0}^{1}\xi_i \varphi_{r}(s)ds\Big)\\
&\le\frac{1}{\Gamma(\alpha)}
\Big(1+\frac{1}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}
+\frac{1\sum_{i=1}^{m-2}k_i\xi_i}
{|1-\sum_{i=1}^{m-2}k_i\xi_i|}\Big)\int_0^{1}\varphi_{r}(s)ds.
\end{aligned} \label{e3.13}
\end{equation}
Dividing both sides of \eqref{e3.13} by $r$, then taking the lower
limit as $r\to \infty$, we obtain
$$
\frac{1}{\Gamma(\alpha)}\bigg(1+\frac{1}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}
+\frac{\sum_{i=1}^{m-2}k_i\xi_i}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}\bigg)\mu
\ge 1,
$$
 which contradicts \eqref{e3.11}. It implies for some positive
number $r'$, we conclude that $N(B_{r'})\subseteq B_{r'}$.

Step 3. The family $\{Ny:y\in B_{r'}\}$ is a family of
equicontinuous functions.
Let $t_1, t_2\in [0,1]$, $t_1\le t_2$ and $y \in B_{r'}$ for each
$h\in N(y)$, we have
\begin{equation}
\begin{aligned}
| h(t_2)-h(t_1)|
&\le \frac{1}{\Gamma(\alpha)}
\Big|\int_{0}^{t_1}(t_2-s)^{\alpha-1}-(t_1-s)^{\alpha-1}f(y(s))ds\Big|\\
&\quad + \frac{1}{\Gamma(\alpha)}
\Big|\int_{t_1}^{t_2}(t_2-s)^{\alpha-1}f(y(s))ds\Big|\\
&\quad+\frac{t_2-t_1}{\Gamma(\alpha)|1-\sum_{i=1}^{m-2}k_i\xi_i|}
 \int_{0}^{1}(1-s)^{\alpha-1}f(y(s))ds\\
&\quad +\frac{t_2-t_1}{\Gamma(\alpha)|1-\sum_{i=1}^{m-2}k_i\xi_i|}
 \sum_{i=1}^{m-2}
k_i\Big(\int_0^{\xi_i}(\xi_i-s)^{\alpha-1}f(y(s))\Big)ds\\
&\le\frac{1}{\Gamma(\alpha)}\int_{0}^{t_1}|(t_2-s)^{\alpha-1}-(t_1-s)^{\alpha-1}|\varphi(s)ds\\
&\quad + \frac{1}{\Gamma(\alpha)}
\int_{t_1}^{t_2}\varphi(s)ds+\frac{t_2-t_1}{\Gamma(\alpha)|1-\sum_{i=1}^{m-2}k_i\xi_i|}\int_{0}^{1}\varphi(s)ds\\
&\quad +\frac{t_2-t_1}{\Gamma(\alpha)|1-\sum_{i=1}^{m-2}k_i\xi_i|}
 \sum_{i=1}^{m-2}
k_i\xi_i\Big(\int_0^{\xi_i}\varphi(s)\Big)ds
\end{aligned} \label{e3.14}
\end{equation}
 The right hand of \eqref{e3.14} tends to $0$ as $t_2\to t_1$.
Therefore, the set $\{Ny: y\in B_{r'}\}$ is equicontinuous.

Combining Steps $1$, $2$ and $3$ with Ascoli-Arzela theorem, we
claim that $N$ is  a compact valued map.

Step 4. $N(y)$ is closed for each $y\in C([0,1], \mathbb{R})$.
Let $\{h_n\}_{n\ge 0}\in N(y)$ be such that  $h_n\to h_* (n\to
\infty)$ in $C([0,1],\mathbb{R})$. Then,
$h_*\in C([0,1],\mathbb{R})$ and there exist $f_n\in S_{F, y_n}$,
such that for each $t\in[0,1]$,
\begin{align*}
&h_n(t)\\
&=\frac{1}{\Gamma(\alpha)}\int_{0}^{t}(t-s)^{\alpha-1}f_n(y(s))ds
-\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}\int_0^{1}(1-s)^{\alpha-1}f_n(y(s))ds\\
&\quad +\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}\sum_{i=1}^{m-2}
k_i\int_{0}^{\xi_i}(\xi_i-s)^{\alpha-1}f_n(y(s))ds.
\end{align*}
Using the fact that $N$ has compact values, we shall pass to a
subsequence if necessary to obtain that $f_n\to f$ in
$L^{1}([0,1],\mathbb{R})$ and therefore $f\in S_{F,y}$, then we have
for each $t\in [0,1]$,
\begin{align*}
h_n\to
h_{*}(t)&=\frac{1}{\Gamma(\alpha)}\int_{0}^{t}
(t-s)^{\alpha-1}f_{*}(y(s))ds\\
&\quad -\frac{t}
{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
\int_0^{1}(1-s)^{\alpha-1}f_{*}(y(s))ds\\
&\quad +\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
\sum_{i=1}^{m-2}k_i\int_{0}^{\xi_i}(\xi_i-s)^{\alpha-1}f_{*}(y(s))ds.
\end{align*}
Thus, $h_* \in N(y)$.

Step 5. $N$ has closed graph.
Let $y_n\to y_*$, $h_n\in N(y_n)$ and $h_n\to h_*$ as $n\to \infty$.
Consider the continuous linear operator
$\Gamma : L^{1}([0,1],\mathbb{R})\to
C([0,1],\mathbb{R})$,
\begin{align*}
f\mapsto \Gamma(f)(t)
&=\frac{1}{\Gamma(\alpha)}\int_{0}^{t}(t-s)^{\alpha-1}f(y(s))ds\\
&\quad -\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
 \int_0^{1}(1-s)^{\alpha-1}f(y(s))ds\\
&\quad +\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
 \sum_{i=1}^{m-2}k_i\int_{0}^{\xi_i}(\xi_i-s)
^{\alpha-1}f(y(s))ds.
\end{align*}
 From Lemma \ref{lem2.8}, then $\Gamma \circ S_{F}$ is a
closed graph operator. Moreover, we have
$h_n\in \Gamma(S_{F,y_n})$.
Since $y_n \to y_{*}$ as $n\to \infty$. Lemma
\ref{lem2.8} implies there exists $h_{*}$ such that
\begin{align*}
&h_{*}(t)\\
&=\frac{1}{\Gamma(\alpha)}
 \int_{0}^{t}(t-s)^{\alpha-1}f_{*}(y(s))ds
-\frac{t}{\Gamma(1-\sum_{i=1}^{m-2}k_i\xi_i)}
 \int_0^{1}(1-s)^{\alpha-1}f_{*}(y(s))ds\\
&\quad +\frac{t}{\Gamma(1-\sum_{i=1}^{m-2}k_i\xi_i)}
\sum_{i=1}^{m-2}k_i\int_{0}^{\xi_i}(\xi_i-s)^{\alpha-1}f_{*}(y(s))ds
\end{align*}
 for some $f_{*}\in S_{F,y_{*}}$. Hence, we conclude that $N$ is
a compact multi-valued map, u.s.c.
with convex closed values. In view of Lemma \ref{lem2.6}, we deduce
that $N$ has a fixed point which is a solution to problem
\eqref{e1.1}-\eqref{e1.2}.
\end{proof}

\begin{theorem}\label{thm3.2}
Assume that {\rm (A1), (A2), (A4)} hold. Then
the problem \eqref{e1.1} and \eqref{e1.2} has at least one solution
on $[0,1]$.
\end{theorem}

\begin{proof}
Define the operator
$N : C([0,1],\mathbb{R})\to \mathcal{P}(C([0,1],\mathbb{R}))$ as
\eqref{e3.12}. Let $y \in \lambda N(y)$ for some $\lambda \in
(0,1)$. Then there exists a function $f\in S_{F,y}$ such that for
each $t\in [0, 1]$, we obtain
\begin{equation}
\begin{aligned}
y(t)
&=\frac{\lambda}{\Gamma(\alpha)}
\int_{0}^{t}(t-s)^{\alpha-1}f(y(s))ds\\
&\quad -\frac{\lambda t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
\int_0^{1}(1-s)^{\alpha-1}f(y(s))ds\\
&\quad +\frac{\lambda
t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
\sum_{i=1}^{m-2}k_i\int_{0}^{\xi_i}(\xi_i-s)^{\alpha-1}f(y(s))ds.
\end{aligned}
\end{equation}
 It from (A4), for each $t\in [0,1]$,
\begin{equation}
\begin{aligned}
|y(t)|&\le \frac{1}{\Gamma(\alpha)}
\int_{0}^{t}(t-s)^{\alpha-1}|f(s)|ds+\frac{t}{\Gamma(\alpha)
(1-\sum_{i=1}^{m-2}k_i\xi_i)}\int_0^{1}(1-s)^{\alpha-1}|f(s)|ds\\
&\quad +\frac{t}{\Gamma(\alpha)(1-\sum_{i=1}^{m-2}k_i\xi_i)}
\sum_{i=1}^{m-2} k_i\int_{0}^{\xi_i}(\xi_i-s)^{\alpha-1}|f(s)|ds\\
&\le\frac{1}{\Gamma(\alpha)}
\bigg(1+\frac{1}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}
+\frac{\sum_{i=1}^{m-2}k_i\xi_i}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}\bigg)
 \int_0^{1}|f(s)|ds\\
& \le\frac{1}{\Gamma(\alpha)}
\bigg(1+\frac{1}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}
+\frac{\sum_{i=1}^{m-2}k_i\xi_i}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}\bigg)
\phi(\|y\|)\int_0^{1}q(s)ds.
\end{aligned}
\end{equation}
Hence,
$$
\frac{\|y\|}{\Big(1+\frac{1}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}
+\frac{\sum_{i=1}^{m-2}k_i\xi_i}{|1-\sum_{i=1}^{m-2}k_i\xi_i|}\Big)
\phi(\|y\|)\int_0^{1}q(s)ds}\le 1.
$$
Then by (A4), there exists $M$ such that $\|y\|\neq M$.
Define
$$
V=\{y\in C([0,1],\mathbb{R}): \|y\|<M\}.
$$
Proceed as the proof of Theorem \ref{thm3.1}, we claim that the
operator $N: \overline {V}\to \mathcal{P}(C([0,1],\mathbb{R}))$ is a
compact multi-valued map, u.s.c. with convex closed values. From the
choice of $V$, there is no $y\in \partial V$ such that
$y\in \lambda N(y) $ for some $\lambda \in (0,1)$. As a consequence of
Lemma\ref{lem2.7}, we conclude that $N$ has a fixed point $y$ which
is a solution of the problem \eqref{e1.1} and
\eqref{e1.2}.
\end{proof}

\section{Applications}

In this section, we present an example to illustrate our main
results.
 Consider the  fractional
differential inclusions with boundary-value conditions
\begin{gather}
y^{6/5}(t)\in F(t,y(t)),\quad t\in [0,1],\label{e4.1}\\
y(0)=0, \quad y(1)=\frac{1}{3}y(\frac{1}{5})+\frac{1}{9}y(\frac{1}{25}),
\label{e4.2}
\end{gather}
where $ k_1=\frac{1}{3}$, $k_2=\frac{1}{9}$, $ \xi_1=\frac{1}{25}$,
$\xi_2=\frac{1}{5}$, $F:\mathbb{R}\to \mathcal{P}(\mathbb{R})$ is a
multi-valued map defined by
\begin{equation}
u\to F(t,u):=[\frac{u^{5}}{u^{5}+3}+t^5+3,\frac{u}{u+1}+t+1].
\end{equation}
 It is clear that (A1) is satisfied, and $F$ satisfies
(A2). let $f\in F$, then
$$
|f|\le \max\big(\frac{u^{5}}{u^{5}+3}+t^5+3,\frac{u}{u+1}+t+1\big)
\le 5,\quad u\in\mathbb{R}.
$$
 Thus,
$$
\|F(t,u)\|:=\sup \{|v|:v\in F(t,u)\}\le
5:=q(t)\phi(|u|), \quad u\in \mathbb{R},
$$
 where $q(t)=1$, $\phi(|u|)=5$. We could find a positive
real number $M$ such that
\begin{gather*}
\frac{M}{\Gamma(\alpha)\left(1+\frac{1}{|1-(k_1\xi_1+k_2\xi_2)|}
+\frac{(k_1\xi_1+k_2\xi_2)}{|1-(k_1\xi_1+k_2\xi_2)|}\right)
\phi(M)\int_0^{1}q(s)ds}> 1,
\\
\frac{M}{\Gamma(6/5)5\left(1+\frac{1}{|1-\frac{3}{25}|}
+\frac{3}{25|1-\frac{3}{25}|}\right)}> 1;
\end{gather*}
that is, $M>10.43$.
Thus, all the assumptions of Theorem \ref{thm3.2} are satisfied. We
conclude that fractional differential inclusion
\eqref{e4.1}-\eqref{e4.2} has at least one solution.

\subsection*{Acknowledgements}
The author is deeply indebted to the anonymous referee for his/her
valuable suggestions, which improve the presentation of this paper.
The work is supported by grant 10771212 from
the National Natural Science Foundation.


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\end{document}
