\documentclass[reqno]{amsart}
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\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2011 (2011), No. 27, pp. 1--19.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2011 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2011/27\hfil
Nonlinear Mecking-L\"ucke-Grilh\'e equation]
{Existence and stability of solutions for
nonlinear Mecking-L\"ucke-Grilh\'e equations}

\author[A. Alriyabi, S. Hilout\hfil EJDE-2011/27\hfilneg]
{Ali Alriyabi, Sa\"id Hilout}  % in alphabetical order

\address{Ali Alriyabi \newline
 Laboratoire de Math\'ematiques et Applications,
 Universit\'e de Poitiers, Boulevard Marie et Pierre Curie
 T\'el\'eport 2, BP 30179, 86962 Futuroscope
 Chasseneuil Cedex, France}
\email{alriyabi@math.univ-poitiers.fr}

\address{Sa\"id Hilout \newline
 Laboratoire de Math\'ematiques et Applications,
 Universit\'e de Poitiers, Boulevard Marie et Pierre Curie
 T\'el\'eport 2, BP 30179, 86962 Futuroscope
 Chasseneuil Cedex, France}
\email{said.hilout@math.univ-poitiers.fr}

\dedicatory{Dedicated to Jean Grilh\'e on his 73-th birthday}

\thanks{Submitted July 18, 2010 Published February 15, 2011.}
\subjclass[2000]{34A34, 34D05, 34D20, 34A45}
\keywords{Mecking-L\"ucke-Grilh\'e equation; plastic deformation;
\hfill\break\indent
 delay differential equations;  characteristic equation;
 dislocation; asymptotic stability}

\begin{abstract}
 In this article, we present the nonlinear Mecking-L\"ucke-Grilh\'e
 model describing  the  temporal evolution for simple and
 multi-instabilities of plastic deformation of stressed monocristal.
 This model extends the linear problem considered in \cite{GJT, Hi, Hil}.
 Using a nonlinear analysis,  we present some results of existence
 and  stability of the solution with respect to the characteristics
 of the material and the retarded times.
 Numerical examples validating the theoretical results  are also
 investigated in this study.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{corollary}[theorem]{Corollary}
\newtheorem{proposition}[theorem]{Proposition}
\newtheorem{remark}[theorem]{Remark}
\newtheorem{definition}[theorem]{Definition}
\allowdisplaybreaks


\section{Introduction}

The field of morphological change of solids has seen a considerable
development in metallurgical engineering and materials science
in the past few years.
The search for materials  of properties  always more  efficient
led to many studies of the mechanisms associated
to plastic deformation.
 The concept of the dislocation  was introduced by
Taylor \cite{Ta1,Ta2} to understand the mechanical behaviour of
materials in plasticity. The dislocations  help to explain the
phenomena of plastic deformations \cite{FRI,HL,NABA}, as well as
other properties of solids, such as crystal growth and the
electrical properties of semiconductors \cite{JOUF}.


Localization of plastic deformation in homogeneous materials can be
associated with instabilities of the stress-strain curves.
These curves present in several cases some rapid
oscillations due to the difficulties of creation or
propagation of dislocations.
This phenomenon can have very  different aspects:
Portevin-Le-Chatelier PLC effect,
twinning, avalanches of dislocations, thermo-mechanical effect,
 Piobert-L\"uders bands.
For Example, the PLC effect is observed during stress rate change
test of Al-Mg
alloys  at room temperature \cite{KUO}. Kuo et al. \cite{KUO}
show that the occurence of plastic instability is strongly
related to the retention time and applied stress rate,
and this instability could be justified as
the interactions between solid solution element,
magnesium, and dislocations.
Louchet and Brechet \cite{LOUCH} present the different types
of dislocations patterning during uniaxial deformation
as a function of significant physical parameters such as crystalline
structure; they shown that it  is determined by a competition
between dislocation production and rearrangements and they have
improved that this phenomenon is controlled by strain rate and temperature.
Sun et al. \cite{sun03} investigated the finite element method
to simulate the propagation of L\"uders band by the level of stress concentration and the
reduction of the thickness of corresponding element.
Graff et al. \cite{graff1, graff2}
 propose finite element simulations
and experimental observations
of PLC effect and L\"uders bands propagation
in notched and compact tensile specimens of aluminum using
the  macroscopic PLC constitutive model.
Some criteria for  localization of plastic deformation
and other studies in this field are
proposed in \cite{Anan,BRECH,CBC,Far,MIG,tranchant93,YT}.

In this paper, we are motivated by the works \cite{GJT, Hi, Hil}
restricted to the linear model. Consider a crystal subject to a mean stress.
Under uniaxial traction (or compression),
 the interactions between dislocations,
and the rotation of the traction-axis  led
 to an activation of  other  slip systems. Consequently
the plastic deformation instabilities
are observed and can be explained by a delay time in
 the system's response to solicitations.
 Grilh\'e et al. presented in \cite{GJT} an
 experimental study and a
 graphically analysis of the stability of the solution of this model.
 Using a linear analysis and Lambert's functions,
a complete mathematical study (existence,
uniqueness, asymptotic stability)
 of the model with a single delay  is presented in \cite{Hi}.
Hilout et al. \cite{Hil} present a new linear model describing the
temporal evolution for multi-instabilities of plastic deformation
of stressed monocristal. Here, we present the nonlinear
Mecking-L\"ucke-Grilh\'e equation NMLGE.
 Under some assumptions and  using a nonlinear analysis, we deduce a
differential equations with one and two delays respectively. In
the both cases,  we show the theoretical existence and  stability
of the solution according to the characteristics of the material
and the retarded times.


This article is presented as follows: In Section \ref{sec:2} we
present the mathematical modelling of the plastic deformation
instability. In Sections \ref{sec:3} and  \ref{sec:4}, we consider
the case of NMLGE with a single delay and two delays respectively.
We present in the both cases some results on existence and
stability of the solution according to the characteristics of the
material and the retarded  times. Numerical examples for stability
and instability of the material close to a
 mean stress  using the MATLAB software
 are also investigated.

\section{Mathematical modelling}\label{sec:2}

Consider a  crystal sample subject to a mean stress $\sigma _0$.
The material is placed between two traverses
(the first is fixed and the second is mobile).
We apply a variable force $\mathcal{F}$ on
the mobile traverse assuming a finite and constant velocity:
$$
\dot {\varepsilon } (t) = \dot {\varepsilon } _0 ={\rm constant}.
$$
The strain rate $ \dot {\varepsilon } $
is the sum of the plastic strain rate
$\dot {\varepsilon _p } $ of the specimen and of the
elastic strain rate $\dot {\varepsilon _e }=\dot{\sigma } /M$
of the combined sample and loading system (with a stiffness $M$)
\begin{equation}\label{totalstrain0}
  \dot {\varepsilon }(t)= \dot {\varepsilon }_p(t)
  + \dot {\varepsilon }_e(t).
\end{equation}
The plastic strain rate may be written as
\begin{equation}\label{pstrain0}
  \dot {\varepsilon }_p(t)=b \dot{\Sigma } (t)/V,
\end{equation}
where  $b$ is  the Burgers vector component along the tensile
axis, ${\Sigma } (t)$ is the area swept by the dislocations
and $V$ is the sample volume  which is supposed to remain constant.
The plastic deformation is controlled by the
 emission of dislocation loops from Frank-Read type sources model.
The equation (\eqref {pstrain0} can be written in the following
form \cite{ML}:
\begin{equation}\label{pstrain1}
  \dot {\varepsilon }_p(t)=b n(t) S
\end{equation}
where $n(t)$ denotes the number of loops arising at time $t$ in
the unit volume and during unit time and by $S$ the mean area
swept by the loops supposed constant during periods which are long
enough compared with the period of instabilities. The area $S$ in
\eqref{pstrain1} depends on the instantaneous density of the
forest and thus on the previous strain history of the sample. We
suppose that $S$ varies slowly. Note that the relation
\eqref{pstrain1} is established assuming that the area $S$ is
instantaneously swept by each dislocation as soon as it is emitted
\cite{ML, GJT}. Grilh\'e et al. \cite{GJT} suppose that the
plastic instability can be explained by a phase shift,
 characterized by a time delay between the nucleation
and the propagation of dislocations (see
 \cite{GJT, Hi, Hil} for more details).
After the flight-time $\tau '$, the mobile dislocation gets pinned
or reaches the free surface of the sample having covered a
constant area $S(\tau ')=S$ since it was emitted.
 Then only loops generated at a
time $t=t'$ with $0<t'<\tau '$,
 will contribute to the deformation at a time $t$.
Consequently, the equation \eqref{pstrain1} can be written as
follows:
\begin{equation}\label{pstrain2}
  \dot {\varepsilon }_p(t)=b
 \int_0^ {\tau '} n(t-s)\dot{S}(s)\, ds.
\end{equation}
To simplify the problem, Grilh\'e et al.
\cite{GJT} suppose that
\begin{equation}\label{surface}
  \dot {S}(t)=S \delta (t-\tau )
\end{equation}
where $\delta $ is Dirac's distribution and $\tau $ is the delay
given by
\begin{equation}\label{M10}
 \tau=\frac{\int_0^\infty\dot S(t)dt}{S}.
\end{equation}

\section{NMLGE with a single delay}\label{sec:3}

 The time lag given by relation \eqref{M10} can be interpreted by
the phase displacement between the time of loop nucleation and the
time at which the main strain is recorded and  approximation
\eqref{surface} amounts to replacing S(t) by a step function.
Under the assumption \eqref{surface}, we can rewrite
\eqref{totalstrain0} in the form
\begin{equation}\label{M11}
  \dot\varepsilon(t)=bSn(\sigma(t-\tau))+\frac{\dot\sigma(t)}{M},
\end{equation}
or
\begin{equation}\label{NL1}
  M\dot\varepsilon(t)=MbSn(\sigma(t-\tau))+\dot\sigma(t).
\end{equation}
Using the linear analysis we establish a differential-difference
equation with a single delay  (see \cite{Hi}) to describe the plasticity
of a solid becoming deformed by loops of dislocations or micro-twinning.
For long-time, it is necessary to use the nonlinear analysis
to investigate the stability of system strain-stress curves. Then we use
Taylor's expansion of second order of the function $n(\sigma-\tau)$
close to the value $\sigma _0$:
\begin{equation}\label{roses1}
\begin{aligned}
n(\sigma(t-\tau))
&=n(\sigma _0)+\frac{\partial n}{\partial \sigma}
(\sigma=\sigma _0)(\sigma(t-\tau)-\sigma _0)\\
&\quad
+\frac{1}{2}\frac{\partial^2 n}{\partial \sigma ^2}(\sigma =\sigma _0)
(\sigma(t-\tau)-\sigma _0)^2.
\end{aligned}
\end{equation}
Substituting \eqref{roses1} in \eqref{NL1} we obtain
\begin{equation}\label{1}
 \dot{\sigma }(t)+\beta \sigma ^2(t-\tau)+\theta\sigma(t-\tau) +\xi=0,
\end{equation}
where
\begin{gather*}
\theta=\alpha-2\beta\sigma _0,\quad
\xi=\beta\sigma _0^2-\alpha\sigma _0,\\
\alpha=MbS\frac{\partial n}{\partial \sigma }(\sigma _0)>0,\quad
\beta=\frac{1}{2}MbS\frac{\partial^2 n}{\partial\sigma ^2}(\sigma _0)<0.
\end{gather*}
The signs of $\alpha$ and $\beta$ respectively are justified by the
physical experiments \cite{GJT}.

In the sequel we denote the set
$$
\mathbb{C}^+=\{ \lambda\in \mathbb{C}:\operatorname{Re}(\lambda)\geq 0\}.
$$

\subsection{Existence and uniqueness}

Equation \eqref{1} is a nonlinear retarded differential difference
equation with delay time $\tau$.
 To define a function $\sigma$ in
\eqref{1} for $t\geq 0$, we impose an initial data on the interval
$[ -\tau,0]$ (e.g., we consider $\phi \equiv 1$ in $[ -\tau,0]$).
In fact, let $\phi$ be a given continuous function on
 $[ -\tau,0]$ ($\phi$ is called preshape function) and we consider
 the problem \eqref{1} with initial data $\phi$:
\begin{equation}\label{eq}
 \begin{gathered}
\dot{\sigma}(t)=-\beta \sigma ^2(t-\tau)-\theta\sigma(t-\tau) -\xi=f(\sigma _t),
\quad t\geq 0,\\
\sigma(t)=\phi(t),\quad t\in [ -\tau,0].
\end{gathered}
\end{equation}
 For fixed $c>0$, consider the region
 $$
 N=\{ t : |\sigma(t)|+|\sigma(t-\tau)|\leq c\}.
 $$

\begin{proposition} \label{prop3.1}
 Equation \eqref{eq} admits a unique solution through $(0,\phi)$
 defined on $[ -\tau,\infty)$.
\end{proposition}

\begin{proof}
Let $\phi_1,\phi_2\in \mathcal{C}\cap N$. Then
\begin{align*}
|f(\phi_1)-f(\phi_2)|
&\leq  |\beta||\phi_1^2-\phi_2^2|+|\theta||\phi_1-\phi_2|\\
&\leq  (|\beta||\phi_1+\phi_2|+|\theta|)|\phi_1-\phi_2|\\
&\leq  (2c|\beta|+|\theta|)|\phi_1-\phi_2|.
\end{align*}
Therefore, $f$ is locally Lipschitz in $\phi$, by \cite[theorem
2.3 p. 44]{KH} there exists a unique solution of \eqref{eq}
through $(0,\phi)$ defined on $[-\tau,\infty)$ by
\begin{equation}
 \begin{gathered}
\sigma(t)=\phi(t)\quad \text{for }   t\in [ -\tau,0],\\
\sigma(t)=\phi(0)+\int_{0}^{t}f(\sigma _s)ds \quad \text{for } t\geq0.
\end{gathered}
\end{equation}
\end{proof}

\subsection{Stability}

In this paragraph we  study the stability of the solution of
\eqref{eq}. So we take the associated homogeneous equation of
\eqref{eq}
\begin{equation}\label{nho1}
\begin{gathered}
\dot{\sigma }(t)+\theta\sigma(t-\tau)=-\beta\sigma ^2(t-\tau),\quad t\geq 0,\\
\sigma(t)=\phi(t),\quad t\in[-\tau,0].
\end{gathered}
\end{equation}
We denote
$$
m_\phi=|\phi|=\sup_{-\tau\leq t\leq 0}|\phi(t)|.
$$

\begin{theorem} \label{thm1}
For $m_\phi$ is sufficiently small, the solution of \eqref{nho1}
is asymptotically stable.
 \end{theorem}

\begin{proof}
By \cite[theorem A.5, p. 416]{KH}  the solution of the equation
\begin{equation}\label{ho1}
\begin{gathered}
\dot{\sigma }(t)=-\theta\sigma(t-\tau),\quad t\geq 0,\\
\sigma(t)=\phi(t),\quad t\in [ -\tau,0],
\end{gathered}
\end{equation}
is asymptotically stable if and only if
\begin{equation}\label{con}
 0<\tau\theta<\frac{\pi}{2}.
\end{equation}
Thus, under the condition \eqref{con}, we have
\begin{equation}\label{*}
 \lim_{t\to\infty}|\sigma ^0(t)|=0,
\end{equation}
 where $\sigma ^0(t)$ is the solution of \eqref{ho1}.
That is, under the condition \eqref{con}, all roots of the
characteristic equation
\begin{equation}\label{cara}
 h(\lambda)=\lambda+\theta e^{-\tau \lambda}=0,
\end{equation}
have negative real parts (cf. \cite{Hi}); i.e., \eqref{cara} has
no zeros in $\mathbb{C}^+$. Then if $s$ is a root of \eqref{cara},
since the equation is of retarded type, there is a positive number
$\lambda_1>0$ such that every characteristic root $s$ satisfies
$Re(s)<-\lambda_1$. By \cite[theorem 6.1, p. 23]{KH}, every
solution $\sigma ^0$ of \eqref{ho1} can be represented in the form
\begin{equation}
 \sigma ^0(t)=X(t)\phi(0)-\theta\int_{-\tau}^{0}X(t-\theta-\tau)\phi(\theta)d\theta.
\end{equation}
By \cite[theorem 5.2, p. 20]{KH}, there exists $c_2 >0$ such that
\begin{equation}
 |X(t)|\leq c_2e^{-\lambda_1 t},\quad t\geq 0.
\end{equation}
Consequently,
\begin{equation}
 |\sigma ^0(t)|\leq  c_3m_\phi e^{-\lambda_1 t},~~t\geq 0,
\end{equation}
where
$$
c_3=c_2+|\theta|c_2  \frac{1}{\lambda_1}(e^{\lambda_1\tau}-1).
$$
We want to show that for $m_\phi$  sufficiently small then the
solution of \eqref{nho1} satisfies
\begin{equation}\label{4}
 |\sigma(t)|<2c_3m_\phi e^{-\lambda_2 t}, \quad t\geq -\tau,
\end{equation}
where $0<\lambda_2<\lambda_1$.

 Let $t_0 $ be the first value such that $t_0>0$ and \eqref{4} is not true.
Then by the continuity of $\sigma $,
\begin{equation}\label{5}
 \sigma(t_0)=2c_3m_\phi e^{-\lambda_2 t_0}.
\end{equation}
On the other hand, the function
$f(\sigma(t),\sigma(t-\tau))=-\beta\sigma ^2(t-\tau)$
is continuous for $t\leq t_0$ together with
 $(\sigma(t),\sigma(t-\tau))\in N$.
By (\cite[paragraph 11.5]{Bel}),
\begin{equation}
  \sigma(t)=\sigma ^0(t)+\int_{0}^{t}X(t-s)f(\sigma(s),\sigma(s-\tau))ds,
  \quad 0<t\leq t_0.
\end{equation}
Furthermore,
$$
\lim_{|\sigma(s -\tau)|\to 0}\frac{|f(\sigma(s),\sigma(s-\tau))|}{|\sigma(s-\tau)|}
=\lim_{|\sigma(s-\tau)|\to 0}-\beta|\sigma(s-\tau)|=0.
$$
Therefore,
$$
|f(\sigma(s),\sigma(s-\tau))|\leq \epsilon|\sigma(s-\tau)|\leq 2\epsilon
c_3m_\phi e^{\lambda_2\tau}e^{-\lambda_2s},~~~0  \leq s-\tau\leq t_0
$$
and
\begin{align*}
|\sigma(t)|&< c_3m_\phi e^{-\lambda_2 t}+2c_2e^{-\lambda_2 t}
\int_{0}^{t}e^{\lambda_2s}\epsilon c_3m_\phi
 e^{\lambda_2 \tau}e^{-\lambda_2s}ds \\
& < c_3m_\phi e^{-\lambda_2 t}+2c_2\epsilon c_3m_\phi e^{\lambda_2 \tau}t_0e^{-\lambda_2 t}
\end{align*}
for $\epsilon$, $m_\phi$  sufficiently small and $0<t\leq t_0$.
We  can choose $\epsilon$ such that
$2 c_2 \epsilon e^{\lambda_2 \tau}t_0 <1$,
then
$$
|\sigma(t)|<2c_3m_\phi e^{-\lambda_2 t},\quad 0<t\leq t_0,
$$
This contradicts the relation  \eqref{5}. Hence for any $t\geq 0$
$$
|\sigma(t)|<2c_3m_\phi e^{-\lambda_2 t},
$$
then
$\lim_{t \to \infty}|\sigma(t)|=0$.
\end{proof}

\subsection{Numerical tests}

The numerical results (see Fig. \ref{fig1})  do not give the exact
solution of \eqref{nho1}, but they show the asymptotic stability
and instability of the solution of \eqref{nho1} according to the
parameter $\tau\theta$. Various calculations are made by using the
MATLAB software. These numerical results validate the theoretical
result obtained in Theorem \ref{thm1}.
 Figure \ref{fig1} (a) and (b) show the asymptotic stability of the
solution of \eqref{nho1} near to $\sigma _0$. The beginning of
phase instability of the solution of \eqref{nho1} is shown in
figure \ref{fig1} (c) and (d).

\begin{figure}[ht]
\begin{center}
\includegraphics[width=0.9\textwidth]{fig1} % chi2.eps
\end{center}
\caption{
(a): $\tau=1$ $m_\phi=0.05$, $\beta=-0.25$, $\theta=1.5$,
 the solution is stable.
(b): $\tau=1$, $m_\phi=0.005$, $\beta=-0.5$, $\theta=1.57$,
 the solution is stable.
(c): $\tau=1$, $m_\phi=0.005$, $\beta=-0.5$,
  $\theta=1.58$, the solution is unstable.
(d): $\tau=1$, $m_\phi=0.005$, $\beta=-0.5$, $\theta=1.573$,
 the solution is unstable} \label{fig1}
\end{figure}

\section{NMLGE with two delays}\label{sec:4}

In most deformation experiments, several
slip systems  are active and depend on their
 orientation with respect to the traction-axis.
Even when  system of deformation is active,
 the crystal undergoes a rotation  and a secondary
deformation-mechanisms  becomes active.
These slip mechanisms  with different activation values,
 correspond to  different  delays.
Our goal in this section is the modelling of  the plastic
 deformation instabilities  when several delays are introduced,
each corresponding to a system of deformation.
 Now we take  \eqref{surface} and we consider the general case
when several deformation-mechanisms occur simultaneously,
 leading to several delays.
We assume that two deformation-mechanisms
are active and $\tau _1$, $\tau _2$ are the
corresponding delays ($\tau _1 \neq  \tau _2 $).
Then, we can write
\begin{equation}\label{hi-bo}
 \dot {S} (t) = S_1  \delta (t- \tau _1 ) +
 S_2  \delta (t- \tau _2 ) \qquad text{and} \quad S=S_1 + S_2.
\end{equation}

Equation \eqref{totalstrain0} can be re-written as follows
($\tau ' > \max \{\tau _1, \tau _2\}$)
\begin{equation}\label{total-s0}
\begin{split}
  \dot {\varepsilon }(t)
 &= b \int_0^ {\tau '} n(\sigma (t-s))
 \Big(S_1 \delta (s - \tau _1 ) + S_2 \delta (s- \tau _2 )\Big)\, ds +
 \frac {\dot{\sigma } (t)}{M}  \\
 &= b  \Big(S_1 n(\sigma  (t - \tau _1 )) + S_2  n(\sigma
 (t - \tau _2 )) {\Big)} +    \frac {\dot{\sigma } (t)}{M} .
\end{split}
\end{equation}
Thus, we deduce the equation
\begin{equation}\label{M18}
 M\dot\varepsilon(t)=MbS_1n(\sigma(t-\tau_1))+MbS_2n(\sigma(t-\tau_2))+\dot\sigma(t).
\end{equation}
To investigate the stability of system strain-stress curves,
we take the Taylor's expansion of second order of the function
$n(\sigma-\tau_i)$, $i=1,2$, close to the value $\sigma _0$
 for $i=1,2$:
$$
n(\sigma(t-\tau_i))=n(\sigma _0)+\frac{\partial n}{\partial \sigma }
(\sigma =\sigma _0)(\sigma(t-\tau_i)-\sigma _0)+\frac{1}{2}
\frac{\partial^2 n}{\partial \sigma ^2}(\sigma
=\sigma _0)(\sigma(t-\tau_i)-\sigma _0)^2.
$$
Substituting in \eqref{M18},
\begin{align*}
Mbn(\sigma _0)(S_1+S_2)
&=MbS_1n(\sigma _0)+MbS_1\frac{\partial n}{\partial \sigma }
(\sigma =\sigma _0)(\sigma(t-\tau_1)-\sigma _0)\\
&\quad +\frac{1}{2}MbS_1\frac{\partial^2 n}{\partial \sigma ^2}
(\sigma =\sigma _0)(\sigma(t-\tau_1)-\sigma _0)^2
+MbS_2n(\sigma _0)\\
&\quad +MbS_2\frac{\partial n}{\partial \sigma }
(\sigma =\sigma _0)(\sigma(t-\tau_2)-\sigma _0)\\
&\quad +\frac{1}{2}MbS_2\frac{\partial^2 n}{\partial \sigma ^2}
(\sigma =\sigma _0)(\sigma(t-\tau_2)-\sigma _0)^2+\dot\sigma(t).
\end{align*}
Therefore,
\begin{equation}
 \dot\sigma(t)=-\beta_1\sigma ^2(t-\tau_1)-\beta_2\sigma ^2(t-\tau_2)
 -\theta_1\sigma(t-\tau_1)-\theta_2\sigma(t-\tau_2)+\gamma.
\end{equation}
where
\begin{gather*}
\beta_1=\frac{1}{2}MbS_1\frac{\partial^2 n}{\partial \sigma ^2}(\sigma _0)<0,\quad
\beta_2=\frac{1}{2}MbS_2\frac{\partial^2 n}{\partial \sigma ^2}(\sigma _0)<0,\quad
\alpha_1=MbS_1\frac{\partial n}{\partial \sigma }(\sigma _0)>0, \\
\alpha_2=MbS_2\frac{\partial n}{\partial \sigma }(\sigma _0)>0,\quad
\theta_1=\alpha_1-2\beta_1\sigma _0, \quad
\theta_2=\alpha_2-2\beta_2\sigma _0, \quad
\beta=\beta_1+\beta_2, \\
\alpha=\alpha_1+\alpha_2,\quad \gamma=\alpha\sigma _0-\beta\sigma _0^2.
\end{gather*}
Let $\tau=max\{ \tau_1,\tau_2\}$,
$\phi\in\mathcal{C}=\mathcal{C}([-\tau,0];\mathbb{R})$
such that $\sigma(t)=\phi(t)$ for
$t\in[-\tau,0]$. We obtain the system
\begin{equation}\label{n22}
\begin{gathered}
\dot\sigma(t)=f(\sigma _t(-\tau_1),\sigma _t(-\tau_2)),
 \quad \text{for } t\geq 0,\\
\sigma(t)=\phi(t), \quad \text{for } t\in[-\tau,0],
\end{gathered}
\end{equation}
where
$$
f(x,y)=-\beta_1x^2-\beta_2y^2-\theta_1x-\theta_2y+\gamma.
$$

\subsection{Existence and uniqueness}

As in \cite[lemma 1.1, p. 39]{KH}, we have the following result.

\begin{lemma} \label{lem4.1}
 Suppose that $\phi\in \mathcal{C}$,
$f:\mathcal{C}\times\mathcal{C}\to \mathbb{R}$ is a continuous
function. Then finding a solution of equation \eqref{n22} is
equivalent to solving the  integral equation
\begin{equation}
\begin{gathered}
 \sigma(t)=\phi(t),\quad t\in[-\tau,0],\\
\sigma(t)= \phi(0)+\int_{0}^{t} f(\sigma _s(-\tau_1),
\sigma _s(-\tau_2))ds, \quad t\geq0.
\end{gathered}
\end{equation}
\end{lemma}

\begin{theorem}
 Problem \eqref{n22} admits a unique solution on
$[-\tau,+\infty)$ through $(0,\phi)$.
\end{theorem}

\begin{proof}
 By \cite[theorem 1.1.1]{lad}, the existence is ensured.
Let $t\in I_\alpha=[0,\alpha],~\alpha>0$, and on take the region:
$$
N=\{ t;\,|\sigma(t)|+|\sigma(t-\tau_1)|+|\sigma(t-\tau_2)|\leq c\}.
$$
Let $x,y\in N$ be two solutions of \eqref{n22}.
Then for $t\geq 0$, we have
\begin{align*}
|x(t)-y(t)|
&\leq \int_0^t|f(x_s(-\tau_1),x_s(-\tau_2))-f(y_s(-\tau_1),y_s(-\tau_2))|ds\\
&\leq \int_0^t\Big( (-\beta_1|x(s-\tau_1)+y(s-\tau_1)|+\theta_1)|x(s-\tau_1)-y(s-\tau_1)|\\
&\quad +\big(-\beta_2|x(s-\tau_2)+y(s-\tau_2)|+\theta_2\big)
|x(s-\tau_2)-y(s-\tau_2)|\Big)ds.
\end{align*}

Since $x,y\in N$, then we can write $-\beta_i|x(s-\tau_i)
+y(s-\tau_i)|+\theta_i)\leq k_i$, where
 $k_i=-2c\beta_i+\theta_i,~i=1,2$. Let $k=max\{ k_1,k_2\} $,
then for $\alpha=\bar\alpha$ such that $k\bar\alpha<1$,
and $t\in I_{\bar\alpha}$, we find
$$
|x(t)-y(t)|\leq k\bar\alpha
\sup_{0\leq s\leq t}[|x(s-\tau_1)-y(s-\tau_1)|
+|x(s-\tau_2)-y(s-\tau_2)|],
$$
since $s-\tau_i\in[-\tau,0]$, $i=1,2$;
therefore, $x(s-\tau_i)=y(s-\tau_i)$, $i=1,2$.
Thus, $x(t)=y(t)$ for all $t\in I_{\bar\alpha}$.
One completes the proof of the theorem by successively stepping
intervals of length $\bar\alpha$.
\end{proof}

\begin{lemma}\label{n24}
 Consider the associated homogeneous equation with \eqref{n22}:
\begin{equation}\label{n29}
\begin{gathered}
\dot\sigma(t)=-\theta_1\sigma(t-\tau_1)-\theta_2\sigma(t-\tau_2),
\quad  t\geq 0,\\
\sigma(t)=\phi(t), \quad  t\in [-\tau,0],
\end{gathered}
\end{equation}
The solution of \eqref{n22} is exponentially bounded; i.e., there
exist   constants $a$ and $b$ such that
$$
|\sigma(t)|\leq am_\phi e^{bt},\quad t\geq 0,
$$
where $m_\phi=\sup_{-\tau\leq t\leq 0}|\phi|$.
\end{lemma}

\begin{proof}
We have
$$
\sigma(t)=\phi(0)+\int_{0}^{t}[-\theta_1\sigma(s-\tau_1)
-\theta_2\sigma(s-\tau_2)]ds,\quad t\geq 0.
$$
and $\sigma(t)=\phi(t)$ for all $t\in [-\tau,0]$, then for
$t\geq0$ we can write
\begin{align*}
|\sigma(t)|
&\leq m_\phi+\theta_1\int_{0}^{t}|\sigma(s-\tau_1)|ds
 +\theta_2\int_{0}^{t}|\sigma(s-\tau_2)|ds\\
&\leq m_\phi+\theta_1m_\phi\tau_1+\theta_2m_\phi\tau_2
 +(\theta_1+\theta_2)\int_{0}^{t}|\sigma(s)|ds\\
&\leq am_\phi+b\int_{0}^{t}|\sigma(s)|ds,
\end{align*}
where $a=1+\theta_1\tau_1+\theta_2\tau_2$,
$b=\theta_1+\theta_2$.
By Gr\"onwall's lemma,
$|\sigma(t)|\leq am_\phi e^{bt}$, $t\geq 0$.
\end{proof}

In the sequel we use the notation
$$
\int_{(c)}=\lim_{T\to \infty}\frac{1}{2\pi i}\int_{c-iT}^{c+iT},
$$
where $c$ is a real number.

\subsection{Stability}
First we define the Fundamental solution.
The  characteristic equation associated with  \eqref{n29} is
\begin{equation}\label{carac}
 h(\lambda)=\lambda+\theta_1 e^{-\lambda \tau_1}
+\theta_2e^{-\lambda \tau_2}=0.
\end{equation}

We are looking for the solution $X(t)$ of \eqref{n29} such that
its Laplace transform is $h^{-1}(\lambda)$ with the initial
condition
$$
X(t)=\begin{cases}
             0 &t<0,\\
             1 &t=0.
            \end{cases}
$$
By lemma \ref{n24} the Laplace transform of $X(t)$ has a sense. We
multiply \eqref{n29} by $e^{-\lambda t}$ and we integrate between
$0$ and $\infty$:
$$
\int_{0}^{\infty}e^{-\lambda t}\dot X(t)dt
=-\theta_1\int_{0}^{\infty}e^{-\lambda t}X(t-\tau_1)dt
-\theta_2\int_{0}^{\infty}e^{-\lambda t}X(t-\tau_2)dt.
$$
An integration by parts gives
$$
1=(-\lambda-\theta_1 e^{-\lambda \tau_1}
-\theta_2e^{-\lambda \tau_2})\int_{0}^{\infty}e^{-\lambda t}X(t)dt;
$$
therefore,
\begin{equation}\label{n27}
 \mathcal L (X)(\lambda)=h^{-1}(\lambda).
\end{equation}
The solution of \eqref{n29} which satisfies \eqref{n27} is called
\textit{the fundamental solution}. Since $X(t)$ is a function of
bounded variation on every compact and is continuous, then the
inversion theorem \cite{KH} allows us to write
$$
X(t)=\int_{(c)}e^{\lambda t}h^{-1}(\lambda)dt.
$$
By adapting the proof of \cite [Theorem 5.2]{KH},
we obtain the following result.

\begin{theorem}\label{n28.5}
For $\alpha>\alpha_0=\max\{ Re\lambda;~h(\lambda)=0\}$,
there exists a constant $k>0$ such that
$$
|X(t)|\leq ke^{\alpha t},\quad t\geq 0.
$$
Particularly, if $\alpha_0<0$, then we can choose
$\alpha_0<\alpha<0$ such that $X(t)\to 0$ when $t\to \infty$.
\end{theorem}

\begin{proof}
We have
\begin{equation}\label{n28}
 X(t)=\int_{(c)}e^{\lambda t}h^{-1}(\lambda)d\lambda,
\end{equation}
where $c$ is some sufficiently large real number.
We may take $c>\alpha$. We first want to prove that
\begin{equation}\label{n28.4}
 X(t)=\int_{(\alpha)}e^{\lambda t}h^{-1}(\lambda)d\lambda.
\end{equation}
We integrate  $e^{\lambda t}h^{-1}(\lambda)$ around the
boundary of the box $ABCD$ in the complex plane with
boundary $L_1M_1L_2M_2$ in the direction indicated
(see Fig. \ref{fig2}), where
\begin{gather*}
L_1=\{c+i\tau;  -T\leq \tau \leq T\}, \quad
L_2=\{\alpha+i\tau; - T\leq \tau \leq T\}, \\
 M_1=\{\sigma +iT; \alpha \leq \sigma \leq c\},  \quad
 M_2=\{\sigma -iT; \alpha \leq \sigma \leq c\} .
\end{gather*}
 Since $h(\lambda)$ has no zeros in the box, it follows that
the integral over the boundary is zero.
Therefore, relation \eqref{n28.4} will be verified if we show that
$$
\int_{M_1}e^{\lambda t}h^{-1}(\lambda)d\lambda,
\int_{M_2}e^{\lambda t}h^{-1}(\lambda)d\lambda   \to {0}\quad
\text{as } {T\to \infty}.
$$

\begin{figure}[ht]
\begin{center}
\includegraphics[width=0.5\textwidth]{fig2} % ali.eps
\end{center}
\caption{$\Gamma$: inside the rectangle $ABCD$}
\label{fig2}
\end{figure}

Choose $T_0$ such that
$$
(1+\frac{\alpha^2}{T_0^2})^{1/2}
-\frac{1}{T_0}(\theta_1e^{-\tau_1\alpha}
+\theta_2e^{-\tau_2\alpha})\geq \frac{1}{2}.
$$
If $T\geq T_0$ and $\lambda \in M_1$; that is,
$\lambda=\sigma +iT,~~\alpha\leq \sigma \leq c$, and $T\geq T_0$, then
$$
|h^{-1}(\lambda)|\leq \frac{1}{(\sigma ^2+T^2)^{1/2}
-\theta_1e^{-\tau_1\alpha}-\theta_2e^{-\tau_2\alpha}}
\leq \frac{2}{T}.
$$
Therefore, by letting $T\to \infty$,
$$
|\int_{M_1}e^{\lambda t}h^{-1}(\lambda)d\lambda|
\leq \frac{2}{T}e^{ct}(c-\alpha)\to 0 .
$$
The same arguments as previously prove that the integral
over $M_2$ go to $0$ by letting $T\to \infty$.
This proves the relation \eqref{n28.4}.

Suppose $T_0$ is as above.
 If $g(\lambda)=h^{-1}(\lambda)-(\lambda-\alpha)^{-1}$ then
for $\lambda=\alpha+iT;~~|T|\geq T_0$, and
\begin{align*}
g(\lambda)
&={|\frac{1}{\lambda-\theta_1e^{-\tau_1\alpha}
 -\theta_2e^{-\tau_2\alpha}}-\frac{1}{\lambda-\alpha_0}|}\\
&={|\frac{\theta_1e^{-\tau_1\alpha}+\theta_2e^{-\tau_2\alpha}
 -\alpha_0}{\lambda-\alpha_0}h^{-1}(\lambda)|}\\
&\leq {\frac{2}{T^2}(\theta_1e^{-\tau_1\alpha}
 +\theta_2e^{-\tau_2\alpha}+|\alpha_0|)}.
\end{align*}
Then
$$
\int_{(\alpha)}|g(\lambda)|d\lambda<\infty,\quad
\int_{(\alpha)}|e^{\lambda t}g(\lambda)|d\lambda
\leq k_1e^{\alpha t},\quad t>0,
$$
where $k_1$ is a constant. Consequently
$$
\int_{(\alpha)}e^{\lambda t}(\lambda-\alpha_0)^{-1}d\lambda
\leq k_2e^{\alpha t},\quad t>0,
$$
and
 $|X(t)|\leq ke^{\alpha t}$, $t>0$, $k=k_1+k_2$.
\end{proof}

\begin{theorem}\label{n30}
For $t\geq 0$, the solution of \eqref{n29} is given by
$$
\sigma(\phi,0)(t)=X(t)\phi(0)
-\theta_1\int_{-\tau_1}^{0}X(t-r-\tau_1)\phi(r)dr
-\theta_2\int_{-\tau_2}^{0}X(t-r-\tau_2)\phi(r)dr.
$$
\end{theorem}

\begin{proof}
Multiply \eqref{n29} by $e^{-\lambda t}$ and we integrate by
parts:
$$
-\phi(0)+h(\lambda)\mathcal{L}(\sigma )(\lambda)
=-\theta_1e^{-\lambda \tau_1}\int_{-\tau_1}^{0}
e^{-\lambda r}\phi(r)dr-\theta_2e^{-\lambda \tau_2}
\int_{-\tau_2}^{0}e^{-\lambda r}\phi(r)dr.
$$
Then, for $c$ is sufficiently large,
$$
\sigma(t)=\int_{(c)}h^{-1}(\lambda)[\phi(0)-\theta_1
e^{-\lambda \tau_1}\int_{-\tau_1}^{0}e^{-\lambda r}\phi(r)dr
-\theta_2e^{-\lambda \tau_2}\int_{-\tau_2}^{0}e^{-\lambda r}
\phi(r)dr]d\lambda.
$$
For $i=1,2$, we consider $w_i:[-\tau_i,\infty)\to [0,1]$ such
that $w_i(r)=0$ if $r\geq 0$ and $w_i(r)=1$, if $r<0$,
then we can define $\phi$ on $[-\tau,\infty)$ by $\phi(r)=\phi(0)$
for $r\geq 0$.

 For $i=1,2$, we have
\begin{align*}
e^{-\lambda \tau_i} \int_{-\tau_i}^{0}e^{-\lambda r}\phi(r)dr
&=\int_{0}^{\infty}e^{-\lambda s}\phi(-\tau_i+s)w_i(-\tau_i+s)ds \\
&=\mathcal{L}(\phi(-\tau_i+\cdot)w_i(-\tau_i+\cdot)).
\end{align*}
We can write
\begin{align*}
\sigma(t)&= X(t)\phi(0)-\theta_1  \int_{0}^{t}X(t-s)
\phi(-\tau_1+s)w(-\tau_1+s)ds\\
&\quad - \theta_2\int_{0}^{t}X(t-s)\phi(-\tau_2+s)w(-\tau_2+s)ds,
\end{align*}
and
$$
\sigma(t)=X(t)\phi(0)-\theta_1\int_{0}^{\tau_1}X(t-s)
\phi(-\tau_1+s)ds
-\theta_2\int_{0}^{\tau_2}X(t-s)\phi(-\tau_2+s)ds.
$$
Suppose that $r_i=-\tau_i+s$ for $i=1,2$. Then
$$
\sigma(t)=X(t)\phi(0)-\theta_1\int_{-\tau_1}^{0}X(t-r-\tau_1)\phi(r)dr
-\theta_2\int_{-\tau_2}^{0}X(t-r-\tau_2)\phi(r)dr.
$$
\end{proof}

\begin{corollary}\label{n31}
Let $\alpha_0=max\{Re(\lambda); h(\lambda)=0\}$ and
$\sigma(\phi)(t)$ is the solution of \eqref{n29}. Then, for all
$\alpha>\alpha_0$, there exists a constant $k=k(\alpha)$ such that
$$
|\sigma(\phi)(t)|\leq km_\phi e^{\alpha t},\quad
t\geq 0,~m_\phi=\sup_{-\tau\leq r\leq 0}|\phi(r)|.
$$
Particularly, if $\alpha_0<0$, then we can choose
$\alpha_0<\alpha<0$ such that any solution of \eqref{n29}
approaches 0, by letting $t\to \infty$.
\end{corollary}

\begin{proof}
By theorem \ref{n28.5}, there exists a constant $k_1>0$ such
that $|X(t)|\leq k_1e^{\alpha t}$. On the other hand,
By theorem \ref{n30} we can write
\begin{align*}
|\sigma(\phi)(t)|
&\leq |X(t)|m_\phi+\theta_1m_\phi\int_{-\tau_1}^{0}|X(t-r-\tau_1|dr
 +\theta_2m_\phi\int_{-\tau_2}^{0}|X(t-r-\tau_2|dr \\
& \leq  k_1m_\phi e^{\alpha t}+\theta_1k_1m_\phi\int_{-\tau_1}^{0}
 e^{\alpha(t-\tau_1-r)}dr+\theta_2k_1m_\phi\int_{-\tau_2}^{0}
 e^{\alpha(t-\tau_2-r)}dr \\
& \leq  m_\phi e^{\alpha t}[k_1+\frac{\theta_1}{\alpha}k_1(1
 +e^{-\alpha\tau_1})+\frac{\theta_2}{\alpha}k_1
 (1+e^{-\alpha\tau_2})]\\
& \leq  km_\phi e^{\alpha t}.
\end{align*}
\end{proof}

\begin{remark}\label{rem1} \rm
Consider
$$
f(\sigma(t-\tau_1),\sigma(t-\tau_2))
=-\beta_1\sigma ^2(t-\tau_1)-\beta_2\sigma ^2(t-\tau_2),
$$
and denote $u(t)=\sigma(t-\tau_1),~v(t)=\sigma(t-\tau_2)$. Then
 $$
f(u,v)=-\beta_1u^2-\beta_2v^2,\quad \beta_1<0,\; beta_2<0.
$$
One can easily show that, $f$ is a continuous function,
$f(0,0)=0$, and
\begin{align*}
|f(u_1,v_1)-f(u_2,v_2)|
& \leq  -\beta_1|u_1^2-u_2^2|-\beta_2|v_1^2-v_2^2|\\
& \leq k(|u_1|+|u_2|+|v_1|+|v_2|)(|u_1-u_2|+|v_1-v_2|),
\end{align*}
where $k=\max\{-\beta_1,-\beta_2\}$.
We take the region $N=\{t; |\sigma(t)|+|u(t)|+|v(t)|\leq c_1\}$,
suppose $c_2=2c_1k$, we choose $c_3=\epsilon c_1\leq c_1$,
($\epsilon$ small enough) such that $c_3$ satisfies the inequality
 $$
|u_1-u_2|+|v_1-v_2|\leq c_3.
$$
Then, $c_2\to 0$ as $c_3\to 0$.
Then $f$ is $c_2$-Lipschitz on $N$,
\begin{equation}\label{n32}
|f(u_1,v_1)-f(u_2,v_2)|\leq c_2(|u_1-u_2|+|v_1-v_2|).
\end{equation}
\end{remark}

\begin{remark} \rm
By \cite[proposition 3.2]{Hil} (see also \cite{Xi}),  if
$$
\tau_1\neq \frac{\pi}{2\theta_1}+\frac{2j\pi}{\theta_1},
\quad (j\in\mathbb{N}),~\tau_1>\frac{\pi}{2\theta_1},
$$
then, for $\tau_2>0$, there exists a constant $\delta>0$ such that
the solution of \eqref{n29} is unstable when
$\frac{\theta_2}{\theta_1}<\delta$.
\end{remark}

\begin{remark} \rm
 By \cite[propositions 3.1 et 3.3]{Hil} (see also \cite{Xi}),
we have the stability of the solution of \eqref{n29}
under the following conditions:
\begin{enumerate}
 \item \begin{equation}\label{n33}
\theta_2<\theta_1,\quad \tau_1\leq \frac{1}{\theta_1+\theta_2},\quad
\tau_2>0.
\end{equation}

\item
$$\theta_2>\theta_1 , \quad
\frac{\pi}{2\tau_1}<(\theta_1^2+\theta_2^2)^{1/2}<\frac{3\pi}{2\tau_1}
$$
and for all $\tau_2\in[0,\tau_{2,c}]$ such that
$\tau_{2,c}$ is the critical value which given as
$$
\tau_{2,c}=\frac{1}{\omega_0}\operatorname{arccos}
(-\frac{\theta_1\cos\omega_0\theta_1\tau_1}{\theta_2}),
$$
where $\omega_0$ is the unique solution of the equation
 $$
\frac{\omega^2+1-\theta_2^2/\theta_1^2}{2\omega}
=\sin\omega \theta_1\tau_1.
$$

\item  $\tau_1\in[\frac{1}{\theta_1+\theta_2},\frac{\pi}{2\theta_1}]$,
in this case the stability depends only on the critical value
$\tau_2$.

\item For $ \tau_1 $ as fixed $\tau_1>\frac{\pi}{2\theta_1}$,
there exists a value $\tau_{0,c}$ such that the solution
 of \eqref{n29} is stable for all $\tau_2\leq \tau_{0,c}$.
\end{enumerate}

  For each root $s$ of $h(\lambda)$ (see \cite{Hil, Xi}),
there exists $\lambda_0>0$ such that $Re(s)<-\lambda_0$.
By theorem \ref{n28.5}, there exists a constant $c_4$ such that
\begin{equation}\label{n34}
|X(t)|\leq c_4e^{-\lambda_0t},\quad t\leq 0.
\end{equation}
By Corollary \ref{n31}, we can find a constant $c_5$ such that
\begin{equation}\label{n35}
|\sigma _0(t)|\leq c_5m_\phi e^{-\lambda_0t},\quad t\geq 0,
\end{equation}
with $\sigma _0(t)$ is the solution of \eqref{n29}.
\end{remark}

Using the notation of Remark \ref{rem1}, we consider
\begin{equation}\label{n36}
\begin{gathered}
\dot\sigma(t)=-\theta_1\sigma(t-\tau_1)-\theta_2
\sigma(t-\tau_2)+f(u(t),v(t)),\quad t\geq 0,\\
 \sigma(t)=\phi(t),\quad t\in[-\tau,0].
 \end{gathered}
\end{equation}
We have the following result.

\begin{theorem}
Suppose that $m_\phi$ is sufficiently small. Then the solution of
\eqref{n36} is a continuous function on $[-\tau,\infty)$, given by
\begin{equation}\label{n37}
\begin{gathered}
\dot\sigma(t)=\sigma _0(t)+\int_{0}^{t}f(u(s),v(s))X(t-s)ds,\quad
 t\geq 0,\\
 \sigma(t)=\phi(t),\quad t\in[-\tau,0],
 \end{gathered}
\end{equation}
where $\sigma _0(t)$ is the solution of linear equation \eqref{n29},
and $X(t)$ is the fundamental solution of \eqref{n29}.
Therefore if $ m_\phi $ is sufficiently small, then
$\lim_{t\to \infty}|\sigma(t)|=0$.
\end{theorem}

\begin{proof}
We use ideas from \cite[Chapter 11]{Bel}.
Let $\{\sigma _n(t)\}_{n\geq 0}$ is a sequence defined by
\begin{equation}\label{n38}
\begin{gathered}
\sigma _{n+1}(t)=\sigma _0(t)+ \int_{0}^{t}f(u_n(s),v_n(s))X(t-s)ds,
\quad t\geq 0,\\
 \sigma _{n+1}(t)=\phi(t), \quad t\in[-\tau,0],
 \end{gathered}
\end{equation}
where $u_n(s)=\sigma _n(s-\tau_1)$, $v_n(s)=\sigma _n(s-\tau_2)$.
 We will show that this sequence is well defined; i.e.,
\begin{equation}\label{n39}
|\sigma _n(t)|\leq 2c_5m_\phi,\quad n=0,1,\dots,\; t\geq-\tau.
\end{equation}
For $n=0$,  \eqref{n39} is verified for all $t\in [-\tau,0]$, if we
take $c_5>1/2$. We proceed by recurrence.
 Let $t\geq0$, suppose that \eqref{n39} is verified.
We will show that
\begin{equation}
|\sigma _{n+1}(t)|\leq 2c_5m_\phi,\quad n=0,1,\dots,\; t\geq 0.
\end{equation}
For $m_\phi$ is sufficiently small, we can take $c_3=8c_5m_\phi$;
therefore,
$$
|\sigma _n(s-\tau_1)|+|\sigma _n(s-\tau_2)|\leq 4c_5m_\phi
\leq \frac{c_3}{2},\quad s\geq 0.
$$
By \eqref{n32}, we find that
\begin{align*}
|f(\sigma _n(s-\tau_1),\sigma _n(s-\tau_2))|
&\leq  c_2[|\sigma _n(s-\tau_1)|+|\sigma _n(s-\tau_2)|] \\
&\leq  \frac{1}{2}c_2c_3=4c_2c_5m_\phi.
\end{align*}
Then
\begin{align*}
|\sigma _{n+1}(t)|
&\leq  c_5m_\phi e^{-\lambda_0t}+4c_2c_4c_5m_\phi\int_{0}^{t}
 e^{-\lambda_0(t-s)}ds\\
&\leq  c_5m_\phi+4c_2c_4c_5m_\phi\int_{0}^{t}e^{-\lambda_0r}dr\\
&\leq  c_5m_\phi+4c_2c_4c_5m_\phi/\lambda_0.
\end{align*}
Since $c_2\to 0$ as $m_\phi\to 0$, we can choose $m_\phi$
such that $4c_2c_4/\lambda_0<1$. Then
$$
|\sigma _{n+1}(t)|\leq 2c_5m_\phi,\quad n=0,1,\dots,\; t\geq -\tau.
$$
The sequence $\{\sigma _n(t)\}_{n\geq 0}$ is well defined
for $t\geq -\tau$, and it is bounded uniformly.

Now we prove that $\{\sigma _n(t)\}_{n\geq 0}$ converges.
For $n\geq 1$, we find that
\begin{align*}
|\sigma _{n+1}(t)-\sigma _{n}(t)|
&\leq \int_{0}^{t}|f(\sigma _n(s-\tau_1),\sigma _n(s-\tau_2))\\
&\quad -f(\sigma _{n-1}(s-\tau_1),\sigma _{n-1}(s-\tau_2))|X(t-s)ds.
\end{align*}
By \eqref{n39}, we have
$$
|\sigma _{n}(t-\tau_1)-\sigma _{n-1}(t-\tau_1)|
+|\sigma _{n}(t-\tau_2)-\sigma _{n-1}(t-\tau_2)|\leq 8c_5m_\phi=c_3.
$$
Using \eqref{n32}, we find that
\begin{align*}
|\sigma _{n+1}(t)-\sigma _{n}(t)|
&\leq c_2c_4  \int_{0}^{t}[|\sigma _{n}(s-\tau_1)
 -\sigma _{n-1}(s-\tau_1)|\\
&\quad +|\sigma _{n}(s-\tau_2)-\sigma _{n-1}(s-\tau_2)|]
e^{-\lambda_0(t-s)}ds.
\end{align*}
Let
$$
m_n(t)=\sup_{-\tau\leq s\leq t}|\sigma _{n}(s)
-\sigma _{n-1}(s)|,~~~~n\geq 1.
$$
For $t\geq -\tau$, $n\geq 1$, we have
\begin{equation}\label{n40}
|\sigma _{n+1}(t)-\sigma _{n}(t)|\leq 2c_2c_4m_n(t)
\int_{0}^{t}e^{-\lambda_0(t-s)}ds.
\end{equation}
Since $\sigma _{n+1}(t)=\sigma _n(t)$ for $t\in[-\tau,0]$, we obtain
\begin{equation}\label{n41}
m_{n+1}(t)\leq c_6m_n(t),\quad t\geq-\tau,
\end{equation}
where $c_6=2c_2c_4\int_{0}^{t}e^{-\lambda_0(t-s)}ds$.
For $m_\phi$ is sufficiently small, we can take $c_6<1$,
because that $c_2\to 0$ as $c_3\to 0$.
Consequently,
\begin{equation}\label{n42}
\sum_{n=0}^{\infty}\sup_{-\tau\leq s\leq t}|\sigma _{n+1}(s)
-\sigma _{n}(s)|,
\end{equation}
is convergent, since it is bounded by
 $m_1(t)\sum_{n=0}^{\infty}c_6^n$,
where
$$
|m_1(t)|\leq \sup_{-\tau\leq s\leq t}|\sigma _1(s)|
+\sup_{-\tau\leq s\leq t}|\sigma _0(t)|\leq4c_5m_\phi.
$$
The convergence of  \eqref{n42} is uniform, then
$\{\sigma_n(t)\}_{n\geq 0}$ converges uniformly to $\sigma(t)$. By
\eqref{n38}, $\sigma(t)$ satisfies the condition
$\sigma(t)=\phi(t)$ for $t\in[-\tau,0]$. It also satisfies
\eqref{n37}. $\sigma(t)$  is a continuous function for all
$t\geq -\tau$. By \eqref{n37}, we have
\begin{gather*}
|\sigma(t)|\leq c_5m_\phi e^{-\lambda_0t}
 +c_2c_4\int_{0}^{t}[|\sigma(s-\tau_1)|
 +|\sigma(s-\tau_2)|]|X(t-s)|ds,\\
\begin{split}
|\sigma(t)|&\leq c_5m_\phi e^{-\lambda_0t}
 +c_2c_4\int_{-\tau_1}^{t-\tau_1}|\sigma(r)||X(t-r-\tau_1)|dr\\
&\quad +c_2c_4\int_{-\tau_2}^{t-\tau_2}|\sigma(r)||X(t-r-\tau_2)|dr,
\end{split}
\end{gather*}
Suppose that $k=2c_2c_4(e^{\lambda_0\tau}-1)/\lambda_0$, then
$$
|\sigma(t)|e^{\lambda_0t}\leq c_5m_\phi+km_\phi
+c_2c_4e^{\lambda_0\tau_1}\int_{0}^{t}|\sigma(r)|e^{\lambda_0r}dr
+c_2c_4e^{\lambda_0\tau_2}\int_{0}^{t}|\sigma(r)|e^{\lambda_0r}dr.
$$
Therefore,
$$
|\sigma(t)|e^{\lambda_0t}\leq c_5m_\phi+km_\phi+2c_2c_4
e^{\lambda_0\tau}\int_{0}^{t}|\sigma(r)|e^{\lambda_0r}dr.
$$
By  Gr\"onwall's lemma,
$$
|\sigma(t)|e^{\lambda_0t}\leq (c_5+k)m_\phi
\exp{(2c_2c_4e^{\lambda_0\tau})t},
$$
and
$$
|\sigma(t)|\leq (c_5+k)m_\phi
\exp{(-\lambda_0+2c_2c_4e^{\lambda_0\tau})t}.
$$
Since $c_2\to 0$ as $m_\phi\to 0$,  for $m_\phi$ is sufficiently small,
we obtain
$\lim_{t\to\infty}|\sigma(t)|=0$.
\end{proof}



\subsection{Numerical tests}

As in the previous section (Section \ref{sec:3}) we present some
numerical results  using  MATLAB  to show asymptotic stability and
instability of solution of \eqref{n36} according to the physical
parameters $\alpha_1$, $\alpha_2$, $\beta_1$, $\beta_2$, $\tau_1$ and
$\tau_2$; see Table \ref{table1}.

\begin{table}[ht]
\caption{Table of stability/instability/Hopf-bifurcation of the
material}
\label{table1}
\begin{center}
\renewcommand{\arraystretch}{1.5}
\begin{tabular}{|l|l|l|}
\hline
$ \theta_1>\theta_2$, $\tau_1\leq \frac{1}{\theta_1+\theta_2} $,
 $\tau _2 >0$ & Stability  &    Fig. \ref{ola1} (a) \\ \hline
$ \theta_1<\theta_2$, $\tau_1\leq \frac{1}{\theta_1+\theta_2}$,
 $\tau _2 >0$  & Instability  &  Fig. \ref{ola1} (b) \\  \hline
$ \theta_1>\theta_2$, $\tau_1\leq \frac{1}{\theta_1+\theta_2} $,
 $\tau _2 >0$  & Hopf-bifurcation &   Fig. \ref{ola1} (c) \\  \hline
 $\frac{\pi}{2\tau_1}<(\theta _1^2+\theta _2^2)^{1/2}
 <\frac{3\pi}{2\tau_1}$, $\theta_2>\theta_1$,
 $\tau _2 \in[0,\tau_{2,c}]$& Stability  &
   Fig. \ref{ola1} (d) \\ \hline
 $\frac{\pi}{2\tau_1}<(\theta_1^2+\theta_2^2)^{1/2}
 <\frac{3\pi}{2\tau_1}$, $\theta_2>\theta_1$ & Instability  &
   Fig. \ref{ola1} (e)  \\ \hline
$\frac{\pi}{2\tau_1}<(\theta_1^2+\theta_2^2)^{1/2}<\frac{3\pi}{2\tau_1}$,
$\theta_2>\theta_1$ & Hopf-bifurcation &  Fig. \ref{ola1} (f) \\ \hline
$\tau_1\in [\frac{1}{\theta_1+\theta_2},\frac{\pi}{2\theta_1}]$,
$\tau_2\in[0,\tau_{2,c}]$ & Stability &  Fig. \ref{ola2} (b) \\ \hline
$\tau_1\in [\frac{1}{\theta_1+\theta_2},\frac{\pi}{2\theta_1}]$
& Instability  &  Fig. \ref{ola2} (a) \\ \hline
$\tau_1\in [\frac{1}{\theta_1+\theta_2},\frac{\pi}{2\theta_1}]$
& Hopf-bifurcation  &  Fig.  \ref{ola2} (c) \\ \hline
 $\tau_1>\frac{\pi}{2\theta_1}$, $\tau_2\in[0,\tau_{0,c}] $
& Stability  &  Fig. \ref{ola2} (d)   \\ \hline
$\tau_1>\frac{\pi}{2\theta_1} $  & Instability  &
Fig. \ref{ola2} (e)   \\ \hline
$\tau_1>\frac{\pi}{2\theta_1} $  &
Hopf-bifurcation &  Fig. \ref{ola2} (f)   \\ \hline
\end{tabular}
\renewcommand{\arraystretch}{1}
\end{center}
\end{table}

\begin{figure}[ht]
\begin{center}
\includegraphics[width=0.9\textwidth]{fig3} % act1.eps
\end{center}
\caption{
(a): $(\theta_1,\theta_2)=(1.1,0.9)$,
 $(\beta_1,\beta_2)=(-0.01,-0.001)$, $m_\phi=0.05$.
(b): $(\theta_1,\theta_2)=(0.9,1.1)$, $(\beta_1,\beta_2)=(-0.01,-0.01)$,
 $m_\phi=0.005$.
(c): $(\theta_1,\theta_2)=(0.5,0.4999)$,
 $(\beta_1,\beta_2)=(-0.01,-0.01)$, $m_\phi=0.6$.
(d) and (e): $(\theta_1,\theta_2)=(0.8,1.1)$,
 $(\beta_1,\beta_2)=(-0.01,-0.01)$, $m_\phi=0.05$.
(f): $(\theta_1,\theta_2)=(0.9,1.1)$, $(\beta_1,\beta_2)=(-0.01,-0.01)$,
$m_\phi=0.05$}
\label{ola1}
\end{figure}

\begin{figure}[ht]
\begin{center}
\includegraphics[width=0.9\textwidth]{fig4} %act2.eps
\end{center}
\caption{
(a): $(\theta_1,\theta_2)=(0.6,0.8)$,
 $(\beta_1,\beta_2)=(-0.01,-0.01)$, $m_\phi=0.05$.
(b): $(\theta_1,\theta_2)=(0.8,0.6)$,
 $(\beta_1,\beta_2)=(-0.01,-0.01)$, $m_\phi=0.05$.
(c): $(\theta_1,\theta_2)=(0.1,0.9)$,
 $(\beta_1,\beta_2)=(-0.01,-0.01)$, $m_\phi=0.05$.
(d), (e) and (f): $(\theta_1,\theta_2)=(1.5,0.7)$,
 $(\beta_1,\beta_2)=(-0.02,-0.01)$, $m_\phi=0.5$.
}\label{ola2}
\end{figure}


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\end{document}
