\documentclass[reqno]{amsart}
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\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2014 (2014), No. 227, pp. 1--13.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2014 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2014/227\hfil A compactness lemma]
{A compactness lemma of Aubin type and its application to degenerate
parabolic equations}

\author[A. Meirmanov, S. Shmarev \hfil EJDE-2014/227\hfilneg]
{Anvarbek Meirmanov, Sergey Shmarev}  % in alphabetical order

\address{Anvarbek Meirmanov \newline
Department of mahtematics \\
Belgorod State University \\
ul.Pobedi 85, 308015 Belgorod, Russia}
\email{anvarbek@list.ru}

\address{Sergey Shmarev \newline
Department of Mathematics \\
University of Oviedo,
c/Calvo Sotelo s/n, 33007, Oviedo, Spain}
 \email{shmarev@uniovi.es}

\thanks{Submitted September 25, 2014. Published October 27, 2014.}
\subjclass[2000]{35B27, 46E35, 76R99}
\keywords{Compactness lemma; two-phase filtration;  nonlinear PDE;
\hfill\break\indent degenerate parabolic equations}

\begin{abstract}
 Let $\Omega\subset \mathbb{R}^{n}$ be a regular domain and
 $\Phi(s)\in C_{\rm loc}(\mathbb{R})$ be a given function.
 If $\mathfrak{M}\subset L_2(0,T;W^1_2(\Omega))
 \cap L_{\infty}(\Omega\times (0,T))$ is bounded
 and the set $\{\partial_t\Phi(v)|\,v\in \mathfrak{M}\}$ is bounded
 in $L_2(0,T;W^{-1}_2(\Omega))$, then there is a sequence
 $\{v_k\}\in \mathfrak{M}$ such that
 $v_k\rightharpoonup v \in L^2(0,T;W^1_2(\Omega))$, and
 $v_k\to v$, $\Phi(v_k)\to \Phi(v)$ a.e. in
 $\Omega_T=\Omega\times (0,T)$. This assertion is applied to prove solvability
 of the one-dimensional initial and boundary-value problem for a degenerate
 parabolic equation arising in the Buckley-Leverett model of two-phase filtration.
 We prove existence and uniqueness of a weak solution, establish the property
 of finite speed of propagation and construct a self-similar solution.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{definition}[theorem]{Definition}
\allowdisplaybreaks

\section{Introduction}

In the present work, we establish an Aubin-type compactness lemma
\cite{Aubin, JLL} with a nonlinear restriction and then apply it
to solving a nonlinear degenerate parabolic equation, which arises from a
special case of the one-dimensional Buckley-Leverett model of two-phase
filtration \cite{AKM,BL}. By now, there exist numerous compactness results of
this type, see, e.g., \cite{CJL} for a review of the available literature;
however none of them seems to be applicable to the problem which we address in
this note. The mathematical model consists of two Darcy's systems of filtration
\begin{gather*} 
 \mathbf{v}^{(1)}=-\frac{k^{(1)}(s)}{\mu^{(1)}}\nabla p^{(1)}, \quad
\frac{\partial s}{\partial t}+\nabla\cdot\mathbf{v}^{(1)}=0,
 \\
 \mathbf{v}^{(2)}=-\frac{k^{(2)}(s)}{\mu^{(2)}}\nabla p^{(2)}, \quad
-\frac{\partial s}{\partial t}+\nabla\cdot\mathbf{v}^{(2)}=0
\end{gather*}
for two immiscible fluids with velocities $\mathbf{v}^{(1)}$ and
$\mathbf{v}^{(2)}$, pressures $p^{(1)}$ and $p^{(2)}$, and viscosities
$\mu^{(1)}$ and $\mu^{(2)}$. The unknown  concentration $s$ of the first fluid
is defined from the state equation
\[ %\label{1.3}
 p^{(1)}-p^{(2)}=P_{c}(s),
\]
where $k^{(1)}(s)$, $k^{(2)}(s)$, and $P_{c}(s)$ are given functions. For example,
\begin{equation} \label{1.4}
k^{(1)}(s)=s,\quad k^{(2)}(s)=1-s,\quad P_{c}(s)=s.
\end{equation}
To simplify the problem, let us assume that in addition to \eqref{1.4},
\[ 
 \mu^{(1)}=\mu^{(2)}=1.
\]
Under this assumption, the one-dimensional system transforms into
\begin{gather}\label{1.6}
v^{(1)}=-s \frac{\partial p^{(1)}}{\partial x}, \quad
\frac{\partial s}{\partial t}+\frac{\partial v^{(1)}}{\partial x}=0, \\
\label{1.7}
  v^{(2)}=-(1-s) \frac{\partial p^{(2)}}{\partial x}, \quad
-\frac{\partial s}{\partial t}+\frac{\partial v^{(2)}}{\partial x}=0, \\
\label{1.8}
\frac{\partial p^{(1)}}{\partial x}- \frac{\partial p^{(2)}}{\partial x}=
\frac{\partial s}{\partial x}.
\end{gather}
Equations \eqref{1.6}-\eqref{1.8} lead to the relations
\begin{gather}\label{1.9}
v = v^{(1)}+v^{(2)}\equiv v(t), \\
\label{1.10}
v^{(1)}=-\frac{\partial u}{\partial x}+v(t)\,s,\quad
v^{(2)}=\frac{\partial u}{\partial x}+v(t)\,(1-s),
\end{gather}
in which
\[ %\label{1.11}
u=\Psi(s)=\int_0^{s}\xi\,(1-\xi)d\xi,\quad \frac{\partial u}{\partial
x}=s(1-s)\frac{\partial s}{\partial x}.
\]
Gathering these relations we arrive at the differential equation
\begin{equation}\label{1.12}
\frac{\partial s}{\partial t}=\frac{\partial }{\partial x}
\Big(\frac{\partial u}{\partial x}-v(t)\,s\Big)
\end{equation}
for the concentration $s$ of the first fluid.

Let us consider the problem of displacement of the second fluid by the first
one in the domain $\Omega=(-1,1)$. The physical
meaning of the problem imposes the following boundary and initial conditions:
\begin{gather}\label{1.13}
 v^{(1)}(-1,t)=v_0(t),\quad v^{(2)}(-1,t)=0,\quad t>0, \\
\label{1.14}
s(x,0)=s_0(x)\in [0,1],\quad -1<x<1.
\end{gather}
By  \eqref{1.9} and the boundary condition \eqref{1.14},
\begin{gather*} %\label{1.15}
 v(t)=v_0(t), \\
%\label{1.16}
 \frac{\partial u}{\partial x}(-1,t)+v_0(t)\,\left(1-s(-1,t)\right)=0.
\end{gather*}
In accordance with the general theory of second-order PDE, one has to impose
one more boundary condition for the concentration $s(x,t)$ on the boundary
$\{x=1\}$. To complete the mathematical formulation of the problem,
we set
\begin{equation}\label{1.17}
s(1,t)=0,\quad t>0,
\end{equation}
which means that the concentration of the first fluid equals zero on the right
end-point of the interval $(-1,1)$. Let us notice that although condition
\eqref{1.17} has a clear physical meaning, it can be substituted by other
physically reasonable conditions. Our choice of \eqref{1.17} is explained by
the simplicity of the resulting mathematical problem, as well as by the fact
that thus far none of the other possible boundary conditions on the line $x=1$
has been given a due justification.

We prove that problem \eqref{1.12}-\eqref{1.17} has a unique weak solution
$s(x,t)$, and that this solution possesses the property of finite speed of
propagation of disturbances from the data. A solution of problem
\eqref{1.12}-\eqref{1.17} is constructed as the limit of a sequence of
solutions of regularized nondegenerate problems.

The property of finite speed of propagation is intrinsic for solutions of
nonlinear degenerate parabolic equations and is not displayed by the solutions
of any linear equation. For the solutions of equation \eqref{1.12} this
property is described as follows: if $s(x,0)=0$ in some interval
$(x_0-R,x_0+R)\subset (-1,1)$, then there are functions $r^{\pm}(t)>0$ such
that $s(x,t)=0$ in the interval $(x_0-r^-(t),x_0+r^+(t))$ for all sufficiently
small $t$. Since \eqref{1.12} generates also at the level $s=1$, the same is
true for the set $\{s=1\}$.

An exhaustive analysis of the property of finite speed of propagation, as well
as a detailed review of the bibliography, can be found in
\cite{GK-2,GK-1,ADS}. The approach of \cite{GK-2,GK-1} is based on comparison
of solutions of a degenerate one-dimensional PDE with a family of travelling
wave solutions, the method developed in \cite{ADS} relies on the analysis of
ordinary differential inequalities for ``local energies'' associated with the
solutions of a PDE under study. Both methods are applicable to problem
\eqref{1.12}-\eqref{1.17}. In the general case when $0\leq s_0(x)\leq 1$ the
property of finite speed of propagation is proved by means of the local energy
method. In the special case when
\begin{equation}\label{ss}
\text{$s_0(x)=1$ in $(-1,0)$ and $s_0(x)=0$ in $(0,1)$}
\end{equation}
this property immediately follows from the existence of a self-similar
solution. Let the initial data satisfy \eqref{ss}. Then problem
\eqref{1.12}-\eqref{1.17} can be written as the boundary-value problem for the
second-order ordinary differential equation for the function
$\bar{w}(\xi)=s(x,t)$, which depends on the variable
\[
\xi=\frac{x}{\sqrt{t}}-\frac{1}{\sqrt{t}}\int_0^{t}v_0(\tau) d\tau.
\]
The problem for $\bar{w}(\xi)$ has the form
\begin{gather}\label{1.18}
\Psi''(\bar{w})+\frac{\xi}{2}\bar{w}'=0,\quad 0<\bar{w}<1\quad \text{for
$-\xi_{*}<\xi<\xi_{*}$}, \\
\label{1.19}
\bar{w}(-\xi_{*})=1,\quad\bar{w}(\xi_{*})=0,\quad \Psi'(\bar{w})(-
\xi_{*})=\Psi'(\bar{w})( \xi_{*})=0
\end{gather}
with a finite $\xi^\ast>0$ to be defined. Uniqueness of weak solution of
problem \eqref{1.12}-\eqref{1.17} means that $s(x,t)\equiv \bar{w}(\xi)$ for
$t\in (0,t_{*})$, where $t_{*}=\min\{t^{-},\,t^{+}\}$ with
\[
\int_0^{t^{-}}v_0(\tau) d\tau-\xi_{*}\sqrt{t^-}=-1,\quad
\int_0^{t^{+}}v_0(\tau) d\tau+\xi_{*}\sqrt{t^+}=1.
\]
The curves
\[
 x=R^{\pm}(t)\equiv \int_0^{t}v_0(\tau)
d\tau\pm\xi_{*}\sqrt{t}
\]
demarcate the domains where $s(x,t)\equiv 1$, $s(x,t)\in (0,1)$, or
$s(x,t)\equiv 0$. We failed to find any result regarding solvability of
problem \eqref{1.18}-\eqref{1.19} and provide the proof of existence and
uniqueness of self-similar solution in the concluding section of this work.

Throughout the text we use the traditional notation in \cite{LSU,JLL} for the
functional spaces and norms.

\section{Main results}

\begin{lemma}\label{lemma1}
Let $\Omega\subset \mathbb{R}^{n}$ be a smooth domain,
$\Omega_T=\Omega\times (0,T)$, and let $\Phi\in C_{\rm loc}(\mathbb{R})$
be a given function. Denote by
$\mathfrak{M}$ a bounded set in
$L_2(0,T;W^1_2(\Omega))\cap L_{\infty}(\Omega_T)$.
Assume that for every $v \in \mathfrak{M}$ and every
$\varphi \in L_2(0,T;{\mathaccent"7017 W}_2^1(\Omega))$ the function
$s(x,t)=\Phi\left(v(x,t)\right)$ satisfies the inequality
\begin{equation}\label{2.1}
\Big|\int_0^{T}\int_{\Omega}\frac{\partial s}{\partial t}\,\varphi
\,dx\,dt\Big| ^2\leqslant  M
\int_0^{T}\int_{\Omega}|\nabla\varphi|^2\,dx\,dt
\end{equation}
with an independent of $v\in \mathfrak{M}$ constant $M$. Then there exists a
sequence $\{v_{m}\}\subset \mathfrak{M}$, which converges weakly in
$L_2(0,T;W^1_2(\Omega))$ and almost everywhere in $\Omega_{T}$, and the
corresponding sequence $\{s_{m}\}$, $s_{m}=\Phi(v_{m})$, converges almost
everywhere in $\Omega_{T}$.
\end{lemma}

\begin{definition} \rm
We say that the pair of measurable and bounded in $\Omega_T$ functions $s$ and
$u=\Psi$ is a weak solution of problem \eqref{1.12}-\eqref{1.17}  if
\begin{equation}\label{2.2}
\begin{split}
&\int_0^{T}\int_{\Omega}  \Big(s\frac{\partial \varphi}{\partial t}+
u\frac{\partial^2 \varphi}{\partial x^2}+v_0(t)\,s \frac{\partial
\varphi}{\partial x}\Big)\,dx\,dt
\\
& = -\int_{\Omega}s_0(x)\varphi(x,0)\,dx-v_0(t)\int_0^{T}\varphi(-1,t)\,dt
\end{split}
\end{equation}
for every smooth function $\varphi$ satisfying the conditions
\[
\text{$\varphi(x,T)=0$ for $-1<x<1$},\quad \text{$\varphi(1,t)= \frac{\partial
\varphi}{\partial x}(-1,t)=0$ for $0<t<T$}.
\]
\end{definition}

\begin{theorem}\label{thm1}
Let $v_0(t)$ be a measurable bounded function. Then for every $T>0$ problem
\eqref{1.12}-\eqref{1.17} has at least one weak solution.
\end{theorem}

\begin{theorem}\label{thm2}
Under the conditions of Theorem \ref{thm1} the solution of problem
\eqref{1.12}-\eqref{1.17} is unique.
\end{theorem}

\begin{theorem}[Finite speed of propagation] \label{th:FSP}
 Under the conditions of Theorem \ref{thm1} the solution of problem
\eqref{1.12}-\eqref{1.17} possesses the property of finite speed of propagation:

(1) if $x_0$ and $R$ are such that $s(x,0)=0$ for a.e. $x\in (x_0-R,x_0+R)$,
then $s=0$ a.e. in the domain
\begin{equation}\label{eq:domain}
\Big|x-x_0+\int_0^{t}v(\theta)\,d\theta\Big|\leq
\Big(R^{1+\alpha}-\frac{C(1+\alpha)t^{1+\beta}}{1-\nu}(1+M)^{1-\nu}
\Big)^{\frac{1}{1+\alpha}}
\end{equation}
with the exponents $\nu={6}/{7}$, $\alpha={4}/{3}$, $\beta={3}/{7}$,
\begin{equation}
\label{eq:time}
t<t^{\ast}_{R}=\sup\big\{t>0:\;-1+R<x_0+\int_0^{t}v(\theta)\,d\theta<1-R\big\},
\end{equation}
and an independent of $s$ constant $C$;

(2) if $x_0$ and $R$ are such that $s(x,0)=1$ for a.e.
$x\in (x_0-R,x_0+R)\subset (-1,0]$, then $s=1$ a.e. in the
domain defined by formulas \eqref{eq:domain}-\eqref{eq:time}.
\end{theorem}

Finally, in Section \ref{sec:ss} we prove that in the special case when
the initial function satisfies \eqref{ss}, the unique solution of problem
\eqref{1.12}-\eqref{1.17} coincides
(for small times) with the unique self-similar solution, defines by conditions
\eqref{1.18}-\eqref{1.19}.

\section{Proof of Lemma \ref{lemma1}}

Boundedness of the set $\mathfrak{M}$ means that for all $v\in \mathfrak{M}$
\begin{equation}\label{3.1}
|s(x,t)|+|v(x,t)|\leq  L\quad\text{a.e. in }\Omega_{T}
\end{equation}
and
\begin{equation}\label{3.2}
\int_0^{T}\int_{\Omega}|\nabla\,v(x,t)|^2\,dx\,dt\leqslant  L
\end{equation}
with a finite constant $L$. By \eqref{3.2} there is a set $G$ of full measure
in $(0,T)$ such that for every $t\in G$,
\begin{equation}\label{3.3}
\int_{\Omega}|\nabla\,v(x,t)|^2dx\leq {M_0(t)}<\infty.
\end{equation}
Let $\mathcal{T}=\{t_{1}, t_2,\dots ,t_{k},\dots \}$ be a countable set
of points dense in $G$.
Using estimates \eqref{3.1}-\eqref{3.3} and the standard diagonal procedure
we may choose a sequence $\{v_{m}\}\subset \mathfrak{M}$ and a function
$v\in L_2\big((0,T);W^1_2(\Omega)\big)\cap
L_{\infty}\big((0,T);L_{\infty}(\Omega)\big)$ such that
\begin{equation}\label{3.4}
\text{$v_{m}(x,t_{k})\to v(x,t_{k})$ in $L_2(\Omega)$ and a.e. in
$\Omega$ as $m\to \infty$ for every $t_k\in \mathcal{T}$.}
\end{equation}
By the continuity of $\Phi$ and \eqref{3.4} $\Phi(v_m(x,t_k))\to \Phi(v(x,t_k))$ a.e.
in $\Omega$ as $m\to \infty$. Since the sequence
$\{(\Phi(v_m(x,t_k))-\Phi(v(x,t_k)))^2\}$
is uniformly bounded in $\Omega$ and tends to zero a.e. in $\Omega$,
it follows from the Lebesgue dominated convergence theorem that
\begin{equation}\label{3.5}
\text{$s_{m}(x,t_{k})=\Phi\left(v_{m}(x,t_{k})\right)\to
s(x,t_{k})=\Phi\left(v(x,t_{k})\right)$ in $L_2(\Omega)$ and a.e. in $\Omega$}
\end{equation}
as $m\to \infty$.

Let us fix an arbitrary point $t\in G$ and prove that
$s_{m}(x,t)\rightharpoonup s(x,t)$ in $L_2(\Omega)$.
Take $\varphi \in {\mathaccent"7017 W}_2^1(\Omega)$ and denote
\[
I_{r,m}(t)=\big|\int_{\Omega}\big(s_{m}(x,t)-s_{r}(x,t)\big)\varphi (x)dx\big|.
\]
For every $t_k\in \mathcal{T}$,
\begin{align*} %\label{3.6}
I_{r,m}(t)
& \leq \big|\int_{\Omega}\big(s_{m}(x,t)-s_{m}(x,t_{k})\big)\varphi(x)dx\big|
+\big|\int_{\Omega}\big(s_{m}(x,t_{k})-s_{r}(x,t_{k})\big)\varphi (x)dx\big|
\\
& \quad + \big|\int_{\Omega}\big(s_{r}(x,t_{k})-s_{r}(x,t)\big)\varphi (x)dx\big|
\\
& = \big|\int_{t}^{t_{k}}\int_{\Omega}\frac{\partial s_{m}}
 {\partial t}(x,\tau)\varphi (x)dxd\tau\big|
 + \big|\int_{\Omega}\big(s_{m}(x,t_{k})-s_{r}(x,t_{k})\big)\varphi
(x)dx\big|.
\end{align*}
Applying H\"older's inequality and using assumption \eqref{2.1} we continue
this inequality as follows:
\begin{equation} \label{3.6-bis}
I_{r,m}(t)
\leq M\Big(\int_{\Omega}|\nabla\varphi|^2dx\Big)^{1/2}|t-t_{k}|^{1/2}+
\big|\int_{\Omega}\left(s_{m}(x,t_{k})-s_{r}(x,t_{k})\right)\varphi
(x)dx\big|.
\end{equation}
Since $t\in G$ and $\mathcal{T}$ is dense in $G$, for every given $\varepsilon>0$ and
$\varphi\in {\mathaccent"7017 W}^1_2 (\Omega)$ we may find $t_{k}\in \mathcal{T}$
such that
\[
M\Big(\int_{\Omega}|\nabla\varphi|^2dx\Big)^{1/2}|t-t_{k}|^{1/2}
<\frac{\varepsilon}{2}.
\]
For this $t_{k}$ we now choose $N$ such that
\[
\big|\int_{\Omega}\left(s_{m}(x,t_{k})-s_{r}(x,t_{k})\right)\varphi
(x)dx\big|<\frac{\varepsilon}{2}
\]
for all $m,r>N$, which is always possible due to \eqref{3.5}.

It follows that for every $\varepsilon>0$ there is $N>0$ such that
$I_{r,m}(t)<\varepsilon$ for all $m,\,r>N$, whence
\[
\int_{\Omega}\left(s_m(x,t)-s(x,t)\right)\varphi(x)\,dx\to 0\quad
\text{as $m\to \infty$}
\]
for every $\varphi \in {\mathaccent"7017 W}_2^1(\Omega)$.
The conclusion remains true for
$\varphi\in L_2(\Omega)$ because ${\mathaccent"7017 W}_2^1(\Omega)$ is dense in
$L_2(\Omega)$.

It remains to identify the limit of $\{v_m\}$. Consider now the sequence
$\{v_{m}(x,t)\}$ with the same $t\in G$. By virtue of \eqref{3.3} there is a
subsequence $\{v_{m_{k}}(x,t)\}$ such that
\[
\text{$v_{m_k}(x,t)\to v(x,t)$ in $L_2(\Omega)$ and a.e. in $\Omega$}.
\]
Since
\[
\text{$s_{m_k}(x,t)\to s(x,t)\equiv \Phi(v(x,t))$ in $L_2(\Omega)$
and a.e. in $\Omega$},
\]
it is necessary that $v_m(x,t)\to v(x,t)$ in $L_2(\Omega)$ and a.e. in
$\Omega$. Finally, the inclusion $\{v_m\}\subset \mathfrak{M}$ yields the weak
convergence $v_{m_k}\rightharpoonup v$ in $L_2(0,T;W^1_2(\Omega))$.

\section{Proof of Theorem \ref{thm1}}

Let $s_0^{\varepsilon}(x)$ be a family of smooth functions which converges
to $s_0(x)$ a.e. in $\Omega$ as $\varepsilon\to 0$ and satisfies the
conditions $s_0^{\varepsilon}(1)=0$, $\varepsilon<s^{\varepsilon}_0(x)<1-\varepsilon$.
 Then for all $\varepsilon>0$ the problem
\begin{equation}\label{4.1}
\begin{gathered}
\frac{\partial s^{\varepsilon}}{\partial t}= \frac{\partial }{\partial
x}\Big(\frac{\partial u^{\varepsilon}}{\partial
x}-v(t)\,s^{\varepsilon}\Big),\quad (x,t)\in \Omega_{T},
\\
 \frac{\partial u^{\varepsilon}}{\partial
x}(0,t)+v_0(t)\,\left(1-s^{\varepsilon}(0,t)\right)=0,\quad t>0,
\\
 s^{\varepsilon}(1,t)=\varepsilon,\quad t>0,
\\
 s^{\varepsilon}(x,0)=s^{\varepsilon}_0(x),\quad -1<x<1,
\end{gathered}
\end{equation}
where
\[
u^{\varepsilon}=\Psi(s^{\varepsilon})=\int_0^{s^{\varepsilon}}\xi\,(1-\xi)d\xi,
\]
has a unique smooth solution $u^{\varepsilon}=\Psi(s^{\varepsilon})$. 
This solution satisfies the estimates
\begin{gather}\label{4.5}
0\leqslant s^{\varepsilon}(x,t) \leqslant 1,\quad (x,t)\in \Omega_{T},\\
\label{4.6}
\int_0^{T}\int_{\Omega}\big|\frac{\partial v^{\varepsilon}}{\partial
x}(x,t)\big|^2\,dx\,dt\leqslant M, \\
v^{\varepsilon}=\Phi^{-1}(s^{\varepsilon})
=\int_0^{^{\varepsilon}}\sqrt{\xi(1-\xi)}d\xi,\quad
s^{\varepsilon}=\Phi(v^{\varepsilon}), \\
\label{4.7}
\Big|\int_0^{T}\int_{\Omega}\frac{\partial s^{\varepsilon}}{\partial t}\,\varphi
\,\,dx\,dt\Big| ^2\leqslant  M \int_0^{T}\int_{\Omega}|\nabla\varphi|^2\,dx\,dt
\end{gather}
for any  $\varphi \in L_2((0,T);{\mathaccent"7017 W}_2^1(\Omega))$ with
an independent of $\varepsilon$ constant $M$.

The existence and uniqueness of a smooth solution follows from the classical
parabolic theory \cite{LSU}. Estimate \eqref{4.5} is an immediate consequence
of the maximum principle. The derive the energy estimate \eqref{4.6} we
multiply equation \eqref{4.1} by $(s^{\varepsilon}-\varepsilon)$ and integrate
by parts over $\Omega$. Finally, \eqref{4.7} follows from \eqref{4.1} after
multiplication by $\varphi \in
L_2((0,T);{\mathaccent"7017 W}_2^1(\Omega))$ and integration by parts.

By Lemma \ref{lemma1} there exist sequences of $\{s^{\varepsilon}\}$,
$\{v^{\varepsilon}\}$ and $\{u^{\varepsilon}\}$ (for the sake of simplicity
 we keep the same notation) such that
\[
\text{$s^{\varepsilon}(x,t)\to s$}, \quad \text{$v^{\varepsilon}\to v=\Phi^{-1}(s)$},
\quad
\text{$u^{\varepsilon}\to u=\Psi(s)$ a.e. in $\Omega_{T}$ as $\varepsilon \to 0$}.
\]
The pair $\{s^{\varepsilon}, u^{\varepsilon}\}$ satisfies the integral identity
\begin{equation}\label{4.8}
\begin{split}
&\int_0^{T}\int_{\Omega}  \Big(s^{\varepsilon}\frac{\partial \varphi}{\partial t}+
u^{\varepsilon}\frac{\partial^2 \varphi}{\partial x^2}+
v_0(t)s^{\varepsilon}\frac{\partial \varphi}{\partial x}\Big)\,dx\,dt
\\
&=  -\int_{\Omega}s^{\varepsilon}_0(x)\varphi(x,0)dx+
\Psi(\varepsilon)\int_0^{T}\frac{\partial \varphi}{\partial x}(1,t)dt
- v_0(t)\int_0^{T}\varphi(-1,t)dt
\end{split}
\end{equation}
for every smooth function $\varphi$ such that
\begin{equation}\label{test}
\text{$\varphi(x,T)=0$ for $-1<x<1$},\quad \text{$\varphi(1,t)= \frac{\partial
\varphi}{\partial x}(-1,t)=0$ for $0<t<T$}.
\end{equation}
Passing to the limit as $\varepsilon \to 0$ in identity \eqref{4.8},
we arrive at \eqref{2.2}.

\section{Proof of Theorem \ref{thm2}}

Let $\{s^{(1)}, u^{(1)}\}$ and $\{s^{(2)}, u^{(2)}\}$ be two
weak solutions of problem \eqref{1.12}--\eqref{1.17}. The difference
$\{s, u\}$, $s=s^{(1)}-s^{(2)}$, $u=u^{(1)}-u^{(2)}$ satisfies the
integral identity
\begin{equation}\label{5.1}
\int_0^{T}\int_{\Omega}s\Big(\frac{\partial \varphi}{\partial t}+
a(x,t)\frac{\partial^2 \varphi}{\partial x^2}+v_0(t)\frac{\partial
\varphi}{\partial x}\Big)\,dx\,dt=0
\end{equation}
for any smooth function $\varphi$ satisfying \eqref{test}.
The coefficient $a$ in \eqref{5.1} has the form
\[
a(x,t)=\frac{u^{(1)}-u^{(2)}}{s^{(1)}-s^{(2)}}=
\int_0^1\frac{d\Psi}{d\xi}\left((s^{(1)}-s^{(2)})\xi+s^{(2)}\right)d\xi,\quad
0 \leqslant a(x,t) \leqslant  1.
\]
Take an arbitrary smooth and finite in $\Omega_T$ function $f$ and consider
the sequence
$\{\varphi^{(\varepsilon)}\}$, $\varepsilon >0$, where
$\varphi^{(\varepsilon)}$ are solutions the equation
\begin{equation}\label{5.3}
\frac{\partial \varphi^{(\varepsilon)}}{\partial t}+
\left(a(x,t)+\varepsilon\right)\frac{\partial^2 \varphi^{(\varepsilon)}}{\partial
x^2}+ v_0(t)\frac{\partial \varphi^{(\varepsilon)}}{\partial x}=f(x,t)
\end{equation}
in $\Omega_{T}$ satisfying the initial and boundary conditions \eqref{test}.
The existence of such functions follows from \cite{LSU}.

Multiplication of \eqref{5.3} by $ \frac{\partial^2
\varphi^{(\varepsilon)}}{\partial x^2}$ and integration by parts
over the domain $\Omega$ lead to the equality
\begin{align*}
&-\frac{1}{2}\frac{d}{d t}\int_{\Omega}
\big|\frac{\partial \varphi^{(\varepsilon)}}{\partial x}(x,t)\big|^2dx
 + \int_{\Omega}(a+\varepsilon)\big|\frac{\partial
^2\varphi^{(\varepsilon)}}{\partial x^2}(x,t)\big|^2dx+
\frac{1}{2}v_0(t)\big|\frac{\partial \varphi^{(\varepsilon)}}{\partial
x}(1,t)\big|^2
\\
&=-\int_{\Omega}\frac{\partial \varphi^{(\varepsilon)}}{\partial x}(x,t) \frac{\partial
f}{\partial x}(x,t)dx.
\end{align*}
The above equality and the standard estimates for the solution of equation
\eqref{5.3} lead to the estimate
\begin{equation}\label{5.4}
\varepsilon\int_0^{T}\int_{\Omega}\big|\frac{\partial
^2\varphi^{(\varepsilon)}}{\partial x^2}(x,t)\big|^2dx \leqslant M
\end{equation}
for some constant $M$ independent of $\varepsilon$.

Finally, let us take $\varphi^{\epsilon}$ for the test-functions in \eqref{5.1}.
Straightforward computations lead to the equality
\[
\varepsilon\int_0^{T}\int_{\Omega}s\Big(f(x,t)+\varepsilon\, \frac{\partial
^2\varphi^{(\varepsilon)}}{\partial x^2}(x,t)\Big)\,dx\,dt=0.
\]
Simplifying and passing to the limit as $\varepsilon\to 0$ and taking into
account \eqref{5.4}, we obtain the identity
\[
\int_0^{T}\int_{\Omega}s\,f(x,t)\,dx\,dt=0
\]
for every smooth and finite in $\Omega_{T}$ function $f$. Thus, $s(x,t)=0$ a.e. in
$\Omega_{T}$.


\section{Proof of Theorem \ref{th:FSP}}
Let us rewrite equation \eqref{1.12} in the form
\begin{equation}
\label{6.1} \frac{\partial s}{\partial t}
= \frac{\partial }{\partial x}\Big(\frac{\partial
\Psi(s)}{\partial x}-v(t) s\Big),
\end{equation}
introduce the new variable
\[
y=x+\int_0^{t}v(\theta)\,d\theta
\]
and consider the function $w$ defined by the relation $w(y,t)=s(x,t)$.
It is straightforward to check that
\[
s_x(x,t)=w_x(y,t)=w_y(y,t)y_x=w_y,\quad s_t(x,t)=w_t(y,t)+w_y(y,t)v(t).
\]
Fix a point $x_0\in (0,1)$ and some $R>0$ such that $u_0(x)=0$ in
$(x_0-R,x_0+R)\subset (0,1)$. The change of variables $x\mapsto y$ transforms
the rectangle $(x_0-R,x_0+R)\times (0,T)$ in the plane of variables $(y,t)$
into the curvilinear domain $(x_+(t),x_-(t)\times (0,T)$ in the plane $(x,t)$
with the boundaries
\[
x_{\pm}(t)=x_0\pm R+\int_0^{t}v(\theta)\,d\theta.
\]
Let us denote $t^{\ast}_R=\sup\{t\in (0,T): \,x_+(t)<1,\;x_-(t)>-1\}$. By
\eqref{6.1}, $w$ is a solution of the equation
\[ %\label{6.2}
\frac{\partial w}{\partial t}= \frac{\partial^2
\Psi(w)}{\partial y^2},\quad (y,t)\in \mathcal{D}\equiv (x_0-R,x_0+R)\times
(0,t^\ast_{R}).
\]
By construction
\[
\int_{\mathcal{D}}
 \Big(w \frac{\partial \psi}{\partial t}+ \Psi(w)\frac{\partial^2
\psi}{\partial y^2}\Big)dydt=0
\]
for every regular test-function $\psi$ such that
$\operatorname{supp}\psi\subseteq \mathcal{D}$. By  \eqref{4.5},
\eqref{4.6}, \eqref{4.7} and because of the convergence
$(s^{\varepsilon})_t\rightharpoonup s_t$ in $L^2(0,T;W^{-1}_2(\Omega))$,
$u^{\varepsilon}_x\rightharpoonup u_x$ in $L^2(\Omega_T)$, we conclude that
$\Psi_t\in L^2(0,T;W^{-1}_2(\Omega))$. Let us fix some $\tau\in
(0,t^\ast)$, $\rho\in (0,R)$ and take for the test-function
$\psi=\Psi(w)\theta_{k}(t)\zeta_m(y)$ with
\begin{gather*}
\theta_k(t)=\begin{cases}
t/k & \text{if $t\in [0,1/k$)},\\
1 & \text{if $1/k\leq t<\tau-1/k$},\\
t-\tau & \text{if $\tau-1/k<t\leq \tau$},
\end{cases} \\
\zeta_m(y)=\begin{cases}
\frac{|y-x_0|-\rho}{m} & \text{if $\rho-\frac{1}{m}<|y-x_0|<\rho$},\\
1 & \text{if $|y-x_0|<\rho-\frac{1}{m}$},\\
0 & \text{if $|y-x_0|\geq \rho$}
\end{cases}
\quad k,m\in \mathbb{N}.
\end{gather*}
Integrating by parts and letting $m,k\to \infty$ we arrive at the equality
\begin{equation}\label{6.3}
\begin{split}
&\int_0^{t}  \int_{x_0-\rho}^{x_0+\rho}w_t\int_0^{w}\xi(1-\xi)\,d\xi\,dtdy
+\int_0^{t}\int_{x_0-\rho}^{x_0+\rho}(\Psi_{y}(w))^2\,dydt
\\
& =\int_0^{t}\Psi(w)\Psi_{y}(w)\,dt\big|_{x_0-\rho}^{x_0+\rho}.
\end{split}
\end{equation}
The first term on the right-hand side can be written in the form
\begin{align*}
\int_{x_0-\rho}^{x_0+\rho} \int_0^{t}\frac{\partial}{\partial
t}\Big(\int_0^{w}\int_0^{z}\xi(1-\xi)\,d\xi dz\Big)\,dt\,dy
&=\int_{x_0-\rho}^{x_0+\rho}\int_0^{w}\int_0^{z}\xi(1-\xi)\,d\xi dz dy\\
& = \int_{x_0-\rho}^{x_0+\rho}\frac{w^{3}}{6}\left(1-\frac{w}{2}\right)\,dy.
\end{align*}
A straightforward calculation leads to the inequality: for $w\in [0,1]$
\begin{align*}
\Psi(w)
& = \int_0^{w}\xi(1-\xi)\,d\xi
=\frac{w^2}{2}-\frac{w^3}{3}=\frac{w^2}{2}\big(1-\frac{2w}{3}\big)
\\
& = \frac{1}{2}\Big(w^3\big(1-\frac{2w}{3}\big)^{\frac{3}{2}}\Big)^{2/3}
\\
& \leq \frac{1}{2}\Big(w^3\big(1-\frac{2w}{3}\big)\Big)^{2/3}
\\
& \leq \frac{1}{2}\Big(w^3\big(1-\frac{w}{2}\big)\Big)^{2/3}=
\frac{6^{2/3}}{2}\Big(\frac{w^3}{6}\big(1-\frac{w}{2}\big)\Big)^{2/3}.
\end{align*}
It follows that
\[
\frac{w^3}{6}\big(1-\frac{w}{2}\big)\geq \frac{2^{1/2}}{3}\Psi^{\frac{3}{2}}(w)
\]
and inequality \eqref{6.3} transforms into the following one:
\begin{equation} \label{6.4}
\frac{2^{1/2}}{3}\int_{x_0-\rho}^{x_0+\rho}\Psi^{\frac{3}{2}}(w(y,t))\,dy
+\int_0^{t}\int_{x_0-\rho}^{x_0+\rho}\Psi^2_{y}(w)\,dy\,dt
\leq \int_0^{t}\Psi(w)\Psi_{y}(w)\,dt\big|_{x_0-\rho}^{x_0+\rho}.
\end{equation}
A detailed analysis of behavior of the functions satisfying inequalities of the type
\eqref{6.4} is given in \cite{ADS}. Let us introduce the energy functions
\begin{gather*}
 E(\rho,t)=\int_0^{t}\|\Psi_{y}(w(\cdot,t))\|_{L_2(B_{\rho}(x_0))}^2\,dt.
\\
 b(\rho,t)=\|\Psi(w(\cdot,t))\|_{L_{\frac{3}{2}}(B_\rho(x_0))}^{\frac{3}{2}}, \quad
\overline{b}(\rho,t)=\operatorname{ess}\sup_{(0,t)}b(\rho,t).
\end{gather*}
Inequality \eqref{6.4} has the form
\[
\frac{2^{1/2}}{3}\overline{b}(\rho,t)+E(\rho,t)\leq I(\rho,t), \quad
\text{where }
I(\rho,t):=\int_0^{t}\Psi(w)\Psi_{y}(w)\,dt\big|_{x_0-\rho}^{x_0+\rho}.
\]
Using the trace-interpolation inequalities of Gagliardo-Nirenberg-Sobolev
type we rewrite the last inequality in the form \cite[pp.126-128]{ADS}
\begin{equation} \label{eq:ODI-1}
 E^{\nu}(\rho,t)\leq (E+\overline{b})^{\nu}\leq
C\,t^{\beta}\rho^{-\alpha}E_{\rho}\quad \text{for $\rho(0,R)$},\quad E(0,t)=0
\end{equation}
with the exponents $\nu={6}/{7}$, $\alpha={4}/{3}$, $\beta={3}/{7}$ and an
independent of
$E$ and $b$ constant $C$.

The first assertion of Theorem \ref{th:FSP} follows by a straightforward
integration of this inequality in the interval $(\rho,R)$, see
\cite[Ch.3, Proposition 1.1]{ADS}. Every solution
$w$ with finite energy in $\mathcal{D}$
\[
\overline{b}(\rho,t)+E(\rho,t)\leq \overline{b}(1/2,t^{\ast})+E(1/2,t^{\ast})
\leq 1+M
\]
with the constant $M$ from estimate \eqref{4.6} possesses the following property:
\[
\text{$w=0$ for a.e. $|y-x_0|\leq \rho(t)$}
\]
with
\[
\rho^{1+\alpha}(t)=R^{1+\alpha}-\frac{C(1+\alpha)t^{1+\beta}}{1-\nu}(1+M)^{1-\nu}.
\]
The conclusion for $s(x,t)$ follows after reverting to the coordinates $(x,t)$.

The second assertion of Theorem \ref{th:FSP} follows in the same way after
the substitution $w\mapsto 1-w$.


\section{Existence of self-similar solutions}
\label{sec:ss}

\begin{lemma}\label{lemma2}
The problem \eqref{1.18}-\eqref{1.19} has a unique solution
$\{\bar{w},\,\xi_{*}\}$.
\end{lemma}

\begin{proof}
Notice first that since the problem has the symmetry property
\[
\bar{w}(\xi)+\bar{w}(-\xi)=1,
\]
we may restrict the further considerations to the domain $0<\xi<\xi_{*}$ with
the boundary conditions
\begin{equation}\label{7.1}
\bar{w}(0)=\frac{1}{2},\quad \bar{w}(\xi_{*})=(\bar{w})'(\xi_{*})=0.
\end{equation}
Let us consider the auxiliary Dirichlet problem
\begin{equation}\label{7.2}
u''+\frac{\xi}{2}s'=0,\; 0<\xi<a,\quad u=\Psi(s),\quad s(0)=\frac{1}{2},\quad
s(a)=0
\end{equation}
with some $a>0$. The solution of this problem depends on the parameter $a$:
$s(\xi)=\Gamma(a)$. We will show that $u'(a)<0$ for all sufficiently small
$a$, and  the existence of a finite number $\xi_{*}>0$ such that
$u'(a)<0$ for $a<\xi_{*}$ and $u'(a)\to 0$ as $a\to\xi_{*}$.
Then $\bar{w}(x,t)=\Gamma(\xi_{*})$.

It is standard to show that problem \eqref{7.2} can be solved for every $a>0$.
To this end we solve first the nondegenerate problem
\begin{equation}\label{7.3}
u_{\varepsilon}''+\frac{\xi}{2}s_{\varepsilon}'=0,\quad 0<\xi<a,\quad
s_{\varepsilon}(0)=\frac{1}{2},\quad s_{\varepsilon}(a)=\varepsilon.
\end{equation}
For every $a>0$ this problem has a unique solution
$\{s_{\varepsilon}, u_{\varepsilon}=\Psi(s_{\varepsilon})\}$ with the
following properties:
\begin{gather}\label{7.4}
\varepsilon< s_{\varepsilon}(\xi)< \frac{1}{2},\quad
s_{\varepsilon}'(\xi)<0,\quad u_{\varepsilon}'(\xi)< 0,\quad
u_{\varepsilon}''(\xi)> 0\quad \text{for $0< \xi<a$}, \\
\label{7.5}
u_{\varepsilon}'(\xi_{1})+\frac{\xi_{1}}{2}s_{\varepsilon}(\xi_{1})-
\frac{\xi_0}{2}s_{\varepsilon}(\xi_0)=
u_{\varepsilon}'(\xi_0)+\frac{1}{2}\int_{\xi_0}^{\xi_{1}}s_{\varepsilon}(\xi)d\xi,\\
\label{7.6}
u_{\varepsilon}(0)-u_{\varepsilon}(a)+\frac{a^2}{2}s_{\varepsilon}(a)=
-a\,u_{\varepsilon}'(a)+\int_0^{a}\xi\,s_{\varepsilon}(\xi)d\xi.
\end{gather}
Equality \eqref{7.5} follows after integration by parts of the differential
equation \eqref{7.3}, \eqref{7.6} results from integration by parts of
equation \eqref{7.3} multiplied by $\xi$.

Notice that equality \eqref{7.5} may be used as the definition of weak
solution of problem \eqref{7.3}.

Relations \eqref{7.4}--\eqref{7.6} yield boundedness of $\{u_{\varepsilon}\}$
in $C^1[0,a]$ and, consequently, compactness of $\{u_{\varepsilon}\}$ and
$\{s_{\varepsilon}\}$ in $C[0,a]$.  Relation \eqref{7.5} provides compactness
of $\{u_{\varepsilon}\}$  in $C^1[0,a]$. Let us denote
$u=\lim_{\varepsilon\to 0}u_{\varepsilon}$,
$s=\lim_{\varepsilon\to 0}s_{\varepsilon}$. Passing to the
limit as $\varepsilon\to 0$ in \eqref{7.4}--\eqref{7.6} we obtain
\begin{gather}\label{7.7}
 u=\Psi(s),\quad 0< s(\xi)< \frac{1}{2},\quad s'(\xi)<0,\quad u'(\xi)<
0\quad \text{for $0< \xi<a$}, \\
\label{7.8}
-u'(\xi_0)+\frac{\xi_{1}}{2}s(\xi_{1})-\frac{\xi_0}{2}s(\xi_0)=
-u'(\xi_{1})+\frac{1}{2}\int_{\xi_0}^{\xi_{1}}s(\xi)d\xi, \\
\label{7.9}
u(0)=-a\,u'(a)+\int_0^{a}\xi\,s(\xi)d\xi.
\end{gather}
It follows from equation \eqref{7.8} and the strong convergence of
$\{s_{\varepsilon}\}$ that
\begin{equation}\label{7.10}
u''+\frac{\xi}{2}s'=0,\; 0<\xi<a,\; s(0)=\frac{1}{2},\; s(a)=0.
\end{equation}

To prove uniqueness of the solution of \eqref{7.10} we consider two different
solutions $\{s_{1},u_{1}\}$ and $\{s_2,\,u_2\}$. Since the differences
 $s=s_{1}-s_2$ and $u=u_{1}-u_2$ are continuous, there exists an interval
$(\xi_0,\xi_{1})$  where either $s>0$, $u>0$, or $s<0$, $u<0$, and
$s(\xi_0)=s(\xi_{1})=u(\xi_0)=u(\xi_{1})=0$.
Subtracting equations \eqref{7.8} for $\{s_{1},\,u_{1}\}$ and $\{s_2,u_2\}$
we arrive at the equality
\begin{equation}\label{7.11}
(|u_{1}'(\xi_0)|-|u_2'(\xi_0)|)-(|u_{1}'(\xi_{1})|-|u_2'(\xi_{1})|)=
\frac{1}{2}\int_{\xi_0}^{\xi_{1}}\big(s_{1}(\xi)-s_2(\xi))d\xi.
\end{equation}
The simple analysis shows that the left-hand side of the last relation is
non-positive, while the right-hand side is strictly positive.
This contradiction proves that the solution of problem \eqref{7.10} is unique.

Equality \eqref{7.9} shows that for sufficiently small  $a$  the derivative
$u'(a)$ is strictly negative:
\[
u'(a)=-\frac{u(0)}{a}+\frac{1}{a}\int_0^{a}\xi\,s(\xi)d\xi=
-\frac{u(0)}{a}+\xi_{*}\,s(\xi_{*})\leqslant-\frac{u(0)}{a}+\frac{a}{2}.
\]
Here we have used the Mean Value Theorem for integrals with some
$0<\xi_{*}\leqslant a$.
If we prove that
\begin{equation}\label{7.12}
\int_0^{a}\xi\,s(\xi)d\xi \to \infty\quad \text{as $a \to \infty$},
\end{equation}
then combining \eqref{7.12} with \eqref{7.9} we may find
$\xi_{*}$ such that
\begin{equation}\label{7.13}
\int_0^{\xi_{*}}\xi\,s(\xi)d\xi=u(0),\quad u'(\xi_{*})=0.
\end{equation}
This provides the existence of at least one solution of the problem
\eqref{1.18}-\eqref{1.19}.

Let us prove \eqref{7.12}. Consider the barrier  function
$s_0=\frac{1}{2a}(a-\xi)$ which solves  the problem
\begin{gather*}
\left(s_0\,(1-s_0)\,s_0'\right)'+\frac{\xi}{2}s_0'=\frac{a}{4a^3}(1-a^2)\xi<0\quad
\text{for $a>1$}, \\
s_0(0)=\frac{1}{2},\quad s_0(a)=0.
\end{gather*}
By construction $s_0(a)=0$, $s(a)=0$,  and $  s_0'(a)=-\frac{1}{2a}$.
If $|u'(a)|>0$,  then
\[
|u'(a)|=\lim_{\xi\to  a}s(\xi)
\lim_{\xi\to a}|s'(\xi)| \quad \text{and}\quad |s'(\xi)|\to\infty \quad
\text{as } \xi\to a,
\]
whence $s(\xi)>s_0(\xi)$ near $\xi=a$. Let $(\xi_0,\xi_{1})$ be the interval
in $(0,a)$ where
\[
s(\xi)<s_0(\xi),\quad \xi_0<\xi<\xi_{1}, \quad s(\xi_0)=s_0(\xi_0),
\quad s(\xi_{1})=s_0(\xi_{1}).
\]
Arguing as before we conclude that
\begin{gather*} %\label{7.14}
\begin{aligned}
&-u'_0(\xi_0) +\frac{\xi_{1}}{2}s_0(\xi_{1})-\frac{\xi_0}{2}s_0(\xi_0)\\
&= -u'_0(\xi_{1}) +\frac{1}{2}\int_{\xi_0}^{\xi_{1}}s_0(\xi)d\xi
 +\frac{1}{8a^3}(1-a^2)(\xi_1^2-\xi_0^2),
\end{aligned}\\
\quad u'_0=\Psi(s_0).
\end{gather*}
Proceeding as in the derivation of \eqref{7.11} and comparing $s_0$ with
the solution $s$ of problem \eqref{7.2}, we arrive at a contradiction.
This means that
\begin{equation}\label{7.15}
s(\xi)\geqslant s_0(\xi)\quad\text{for $0<\xi<a$},
\end{equation}
and \eqref{7.12} follows. In fact,
\[
\int_0^{a}\xi\,s(\xi)d\xi \geqslant \int_0^{a}\xi\,s_0(\xi)d\xi=
\frac{1}{2a}\int_0^{a}\xi\,(a-\xi)d\xi=\frac{a^2}{12}\to \infty\quad
\text{as $a \to \infty$}.
\]

To prove that the solution of problem \eqref{1.18}-\eqref{1.19} is unique
we consider two possible solutions $\{\bar{w}^{(1)},\,\xi_{*}^{(1)}\}$ and
$\{\bar{w}^{(2)},\,\xi_{*}^{(2)}\}$ on the interval $(0, \infty)$ with the boundary
condition  \eqref{7.1}. Let us assume that $\xi_{*}^{(1)}<\xi_{*}^{(2)}$.
Then the function
\[
\Psi(\bar{w})=\begin{cases}
\Psi(\bar{w}^{(1)}) & \text{for $0<\xi<\xi_{*}^{(1)}$},\\
0 &  \text{for $\xi_{*}^{(1)}<\xi<\xi_{*}^{(2)}$}
\end{cases}
\]
belongs to $C^1[0, \xi_{*}^{(2)}]$ and the pair $\{\bar{w}, \Psi(\bar{w})\}$
solves \eqref{7.2} with $a=\xi_{*}^{(2)}$.

By construction, the pair  $\{\bar{w}^{(2)}, \Psi(\bar{w}^{(2)} )\}$
is a solution of the same problem on the same interval $(0, \xi_{*}^{(2)})$.
But the solution of this problem is
unique, whence $\bar{w}^{(1)}=\bar{w}^{(2)}$ for $0<\xi<\xi_{*}^{(1)}$ and
 $\bar{w}^{(2)}=0$ for $\xi_{*}^{(1)}<\xi<\xi_{*}^{(2)}$.
\end{proof}

\subsection*{Acknowledgments}
This research  was supported by the Russian Science Foundation, Grant 14-17-00556.


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