\documentclass[reqno]{amsart}
\usepackage{hyperref}

\AtBeginDocument{{\noindent\small
\emph{Electronic Journal of Differential Equations},
Vol. 2015 (2015), No. 71, pp. 1--12.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2015 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document}
\title[\hfilneg EJDE-2015/71\hfil Theorems of Kiguradze-type and Belohorec-type]
{Theorems of Kiguradze-type and Belohorec-type revisited on time scales}

\author[H. Wu, B. Jia, L. Erbe \hfil EJDE-2015/71\hfilneg]
{Hongwu Wu, Baoguo Jia, Lynn Erbe}

\address{Hongwu Wu \newline
School of Mathematics, South China University of Technology,
Guangzhou 510640, China. \newline
Department of Mathematics, University of Nebraska-Lincoln,
Lincoln, NE 68588-0130, USA}
\email{hwwu@scut.edu.cn}

\address{Baoguo Jia \newline
School of Mathematics and Computer Science,
Zhongshan University, Guangzhou 510275, China. \newline
Department of Mathematics, University of Nebraska-Lincoln,
Lincoln, NE 68588-0130, USA}
\email{mcsjbg@mail.sysu.edu.cn}

\address{Lynn Erbe \newline
Department of Mathematics, University of Nebraska-Lincoln,
Lincoln, NE 68588-0130, USA}
\email{lerbe@unl.edu}

\thanks{Submitted December 14, 2014. Published March 24, 2015.}
\subjclass[2000]{34K11, 39A10, 39A99}
\keywords{Superlinear; sublinear; time scales; second order;
 oscillation}

\begin{abstract}
 This article concerns the  oscillation of second-order nonlinear dynamic
 equations. By using generalized Riccati transformations, Kiguradze-type and
 Belohorec-type oscillation theorems are obtained on an arbitrary time scale.
 Our results cover those for differential equations and difference equations,
 and provide new oscillation criteria for irregular time scales.
 Some examples are given to illustrate our results.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\newtheorem{example}[theorem]{Example}
\allowdisplaybreaks


\section{Introduction}

 Consider the second-order nonlinear dynamic equation
\begin{equation} \label{Superlinear}
 \big(r(t)x^{\Delta}(t)\big)^{\Delta}+p(t)f(x^\sigma(t))=0,\quad
t\geq t_0,
\end{equation}
where the independent variable is in a time scale $\mathbb{T}$.

Since we are interested in the oscillatory behavior of solutions
near infinity, we assume that $\sup\mathbb{T}=\infty$. Recall that
a solution to \eqref{Superlinear} is a nontrivial real
function $x(t)$ such that $x(t)\in C^{1}_{rd}[t_0,\infty)$, and
$ r(t)x^{\Delta}(t)\in
C^{1}_{rd}[t_0,\infty)$ and satisfying \eqref{Superlinear} on
$[t_0,\infty)$, where $C_{rd}$ is the space of real-valued right-dense
continuous functions (see \cite[p. 7]{bp}). Throughout this paper, we
shall restrict attention to those solutions of
 \eqref{Superlinear} which exist on some half line $[t_0,\infty)$
and satisfy $\sup\{|x(t)|:t>t_0\}>0$. For
simplicity of notation in the lemmas, theorems, and examples that
follow, we use
$[t_0,\infty):=[t_0,\infty)_{\mathbb{R}}\cap\mathbb{T}$,
$ x^{\alpha}(\sigma(t))=\big(x^{\sigma}\big)^{\alpha}=x^{\alpha^{\sigma}}$  and 
$ \left(x^{\alpha}(t)\right)^{\Delta}=\left(x^{\alpha}\right)^{\Delta}
=x^{\alpha^{\Delta}}$, and so on.

We recall that a solution of \eqref{Superlinear} is called oscillatory if
 it has arbitrarily large zeros,
otherwise, it is called nonoscillatory. 
Equation \eqref{Superlinear} is said to be oscillatory if every function 
that satisfies the equation eventually, that is, on the interval 
$[{t}_0,\,\infty)$, has
arbitrarily large zeros. It is not sufficient only to know that some solutions
have this behavior. The oscillation theory of dynamic equations has been developed
extensively during the past several years. We refer the reader to
the monographs \cite{RP1,bp} and the references cited therein. Recently,
there has been an increasing interest in studying the oscillation of
nonlinear differential equations on time scales [2,4-16,19-22]. The
oscillation problem for \eqref{Superlinear} and its various
particular cases has been considered by many authors.  For
completeness, we review some earlier results:

In 1955, Atkinson \cite{Atkinson} considered the  second-order
nonlinear differential equation
\begin{gather}\label{Atkinson}
 x''(t)+p(t)| x(t)|^{\alpha-1}x(t)=0,\quad t\geq t_0,
\end{gather}
and established the following necessary and sufficient condition
for the oscillation of \eqref{Atkinson}.

\begin{theorem}\label{Belohorec1}
 Let $\alpha > 1$ and $p(t)\geq0$. Then \eqref{Atkinson} is oscillatory 
if and only if
\begin{equation} \label{Kiguradze}
\int_{t_0}^{\infty}sp(s)ds=\infty.
\end{equation}
\end{theorem}

If $p(t)$ is allowed to take on negative values,
Kiguradze \cite{Kiguradze} proved that condition \eqref{Kiguradze} is still
sufficient for all solutions of \eqref{Atkinson} to be
oscillatory for the same case considered by Atkinson.

In 1961, Belohorec \cite{Bel1} considered the sublinear case of \eqref{Atkinson},
and obtained the following result.

\begin{theorem}\label{Belohorec2}
 Let $0<\alpha<1$ and $p(t)\geq0$. Then \eqref{Atkinson} is oscillatory 
if and only if
\begin{equation}\label{1.3}
\int^{\infty}_{t_0} s^{\alpha}p(s)ds=\infty.
\end{equation}
 \end{theorem}
If $p(t)$ is allowed to take on negative values, Belohorec \cite{Bel2}
 proved that \eqref{1.3} is sufficient for \eqref{Atkinson} to be oscillatory. 
These results have been further extended by Kwong and Wong \cite{Kwong}.

In 1983, Hooker and Patula \cite{Hooker} considered the following second-order 
nonlinear difference equation
\begin{gather}\label{difference}
{\Delta}^2x(n)+p(n)| x(n+1)|^{\alpha-1}x(n+1)=0,\quad
t\in \mathbb{N}.
\end{gather}
and established the following necessary and sufficient condition
for the oscillation of \eqref{difference}.

\begin{theorem}\label{Belohorec3} 
 Let $\alpha>1$ and $p(t)\geq0$. Then \eqref{difference} is oscillatory
 if and only if
\begin{equation}\label{Kiguradze2}
 \sum^{\infty}_{n=1}np(n)=\infty.
\end{equation}
\end{theorem} 

For the sublinear analog, Mingarelli \cite{Mingarelli} proved the
following result.

\begin{theorem}\label{Belohorec4} 
 Let $0<\alpha<1$ be a quotient of odd positive integers,
 and $p(n)\geq0$. Then \eqref{difference} is oscillatory if and only if
\begin{equation}\label{1.4}
 \sum^{\infty}_{n=1}n^{\alpha}p(n)=\infty.
\end{equation} 
\end{theorem}

In 2011, Jia et al \cite{Jiak} considered the following second-order
superlinear dynamic equation
\begin{gather}\label{dynamic}
 x^{\Delta\Delta}(t)+p(t)f(x^\sigma(t))=0,\quad t\in \mathbb{T},
\end{gather}
and obtained Kiguradze-type oscillation theorems for the dynamic
equation \eqref{dynamic}. Jia et al
\cite{Jiab} considered the following second-order sublinear dynamic
equation
\begin{equation} \label{ts}
 x^{\Delta\Delta}(t)+p(t)x^{\alpha}(\sigma(t))=0,\quad t\in \mathbb{T}.
\end{equation}
where $0<\alpha<1$ is a quotient of odd positive integers and $p(t)$
is allowed to take on negative values. It was noted, more generally
in \cite{Jiab} that \eqref{ts} is oscillatory if there exists a
real number $\beta$ satisfying $0<\beta\leq 1$, such that
\[
\int^\infty_{t_0} \sigma^{\alpha\beta}(s) p(s)\Delta t =\infty.
\]

However,  these results of Jia et al \cite{Jiak,Jiab} were obtained
for the case that $\mathbb{T}$ is a \emph{regular} time scale.  Let us
recall that $\mathbb{T}$ is said to be a regular time scale provided
it is a time scale with $\inf\mathbb{T}=t_0$ and
$\sup\mathbb{T}=\infty$, and $\mathbb{T}$ is either an isolated time
scale (all points in $\mathbb{T}$ are isolated) or $\mathbb{T}$ is
the real interval $[t_0,\infty)$.
An important tool in the study of the oscillatory behavior of
solutions is the Riccati transformation
\begin{equation}\label{technique1}
\omega(t)=r(t)\frac{x'(t)}{x(t)},\quad t\in\mathbb{R},
\end{equation}
which goes back as far as the classical results of Kamenev
\cite{Kamenev} and Philos \cite{Philos}. It is also a very useful
tool for the half-linear or nonlinear differential equations when
the coefficient function is nonnegative \cite{w1,w3}.

In this article, we  consider more general dynamic equations on
arbitrary time scales when $p(t)$ is allowed to take on negative
values. Our purpose here, is to establish oscillation criteria for
all time scales. That is, we will not assume that $\mathbb{T}$ is a
regular time scale. We will use the Riccati transformation
 \eqref{technique1} which, as noted above, is still applicable, even
when the coefficient function is allowed to take on negative values.
In the next section, we shall give some lemmas, which will be used
to prove our main theorems. In Section 3, we shall give the
Kiguradze-type oscillation theorems for \eqref{Superlinear}
which can be applied to any time scale. We also obtain some new
oscillation criteria for all bounded solutions of
 \eqref{Superlinear}. In Section 4, we shall establish the
Belohorec-type oscillation theorems which are also valid for all
time scales.  Finally, in Section 5, by means of several examples,
we illustrate our results.

\section{Some lemmas}

 On an arbitrary time scale $\mathbb{T}$, the usual chain rule from calculus 
is no longer valid. One form of the extended chain rule,
due to  Keller \cite{Keller} and generalized to measure chains by 
 P\"otzsche \cite{Chain}, is as follows.

\begin{lemma}\label{Lem2.1}
Assume $G :\mathbb{T}\to\mathbb{R}$ is delta differentiable on $\mathbb{T}$. 
Assume further that $F :\mathbb{R}\to\mathbb{R}$ is continuously differentiable. 
Then $F\circ G :\mathbb{T}\to\mathbb{R}$ is delta differentiable and satisfies
\[
[F\circ G]^{\Delta}(t)
=\Big\{\int_0^{1}F'(G(t)+h\mu(t)G^{\Delta}(t))dh\Big\}G^{\Delta}(t).
\]
\end{lemma}

We shall need the following second mean value theorem (see \cite{Jiak,Jiab})
 and the differential inequality, which will be useful tools in the 
following proofs and  which we formulate as follows.

\begin{lemma}\label{Jia} 
Let $h$ be a bounded function that is integrable on $[a,b] $.
Let $ m_H$ and $ M_H$ be the infimum and supremum, respectively, of the
function $ H(t):=\int^t_ah(s)\Delta s$ on $[a,b] $. 
Suppose that $g$ is nonincreasing with
  $g(t)\geq 0$ on $[a,b] $. Then there is some number $\Lambda$ with
  $ m_H\leq \Lambda \leq M_H$ such that 
\[
\int^b_ah(t)g(t)\Delta t=g(a)\Lambda.
\]
\end{lemma}

\begin{lemma}\label{Wu}
Assume $G :\mathbb{T}\to\mathbb{R}$ is delta differentiable on $\mathbb{T}$. 
Assume further that
$F :\mathbb{R}\to\mathbb{R}$ and $F''$ is continuous. If the function $F$ satisfies
$F'(u)\geq0$ and $F''(u)\leq0$. Then
\[
F'(G^{\sigma}(t))G^{\Delta}(t)\leq[F\circ G]^{\Delta}(t)\leq F'(G(t))G^{\Delta}(t).
\]
\end{lemma}

\begin{proof} 
Using Lemma 2.1, we obtain
\begin{equation}\label{2-1}
[F\circ G]^{\Delta}(t)
=\Big\{\int_0^{1}F'(G(t)+h\mu(t)G^{\Delta}(t))dh\Big\}G^{\Delta}(t).
\end{equation}
If $G^{\Delta}(t)\geq0$, it is easy to see that
\begin{equation}\label{2-2}
G^{\sigma}(t)\geq G(t)+h\mu(t)G^{\Delta}(t)\geq G(t)\quad
\text{for all }0\leq h\leq1.
\end{equation}
From \eqref{2-2} and $F''(u)\leq0$, we have
\begin{equation}\label{2-3}
F'(G^{\sigma}(t))\leq F'\left(G(t)+h\mu(t)G^{\Delta}(t)\right)
\leq F'(G(t))\quad \text{for all }0\leq h\leq1.
\end{equation}
From \eqref{2-3}, $F'(u)\geq0$ and $G^{\Delta}(t)\geq0$, we obtain
\[
F'(G^{\sigma}(t))G^{\Delta}(t)
\leq\Big\{\int_0^{1}F'(G(t)+h\mu(t)G^{\Delta}(t))dh\Big\}G^{\Delta}(t)
\leq F'(G(t))G^{\Delta}(t).
\]
Therefore, from \eqref{2-1}, we obtain
\[
F'(G^{\sigma}(t))G^{\Delta}(t)\leq[F\circ G]^{\Delta}(t)\leq F'(G(t))G^{\Delta}(t).
\]
If $G^{\Delta}(t)\leq0$, by a similar analysis, we obtain the same
conclusion. This completes the proof.
\end{proof}

\section{Kiguradze-type oscillation theorems}

In this section, with respect to \eqref{Superlinear} we shall assume 
the following conditions hold:
\begin{itemize}
\item[(H1)] $p\in C_{rd}(\mathbb{T},\mathbb{R})$ and 
$ 1/r\in C_{rd}(\mathbb{T},\mathbb{R}^+)$ (see e.g. \cite{Rehak});

\item[(H2)] $f\in C(\mathbb{R},\mathbb{R})$
satisfies $f'(x)\geq0$, and $xf(x)>0$ for $x\neq0$;

\item[(H3)]  The superlinearity conditions: 
\[
0<\int_{\varepsilon}^{\infty}\frac{1}{f(u)}du,quad
 \int_{-\varepsilon}^{-\infty}\frac{1}{f(u)}du<+\infty
\]
for all $\varepsilon>0$.
\end{itemize}

\begin{theorem}\label{MainTheorem}
Assume that conditions {\rm (H1)--(H3)} hold. If there exists a function 
$\phi>0$ satisfying $\phi^{\Delta}\geq0$ and $[\phi^\Delta r]^{\Delta}\leq0$ 
such that
\begin{equation}\label{condition1}
\int_{t_0}^{\infty}\frac{1}{\phi(s)r(s)}\Delta
s=\infty\quad \text{and}\quad
\int^\infty_{t_0} \phi^\sigma(s) p(s)\Delta s=\infty.
\end{equation}
Then \eqref{Superlinear} is oscillatory.
\end{theorem}

\begin{proof} 
Suppose that $x(t)$ is a nonoscillatory solution of \eqref{Superlinear} 
on $[t_0,\infty)$.
Without loss of generality, we may assume that $x(t)> 0$ for 
$t\ge t_1\ge t_0$. By condition (H2), we shall only consider this case,
since the substitution $z(t)=-x(t)$ transforms \eqref{Superlinear} 
into an equation of the same form.
Define the following generalized Riccati transformation:
\begin{equation}\label{omega}
\omega(t):=\phi(t)\frac{r(t)x^{\Delta}(t)}{f(x(t))}
\quad\text{for }  t\ge{t}_{1}.
\end{equation}
By the product rule and the quotient rule, we obtain
\begin{align*}
\omega^{\Delta}&=[rx^{\Delta}]^{\Delta}
[\frac{\phi}{{f\circ x}}]^{\sigma}+rx^{\Delta}
[\frac{\phi}{{f\circ x}}]^{\Delta} \\
&=\phi^{\sigma}\frac{[rx^{\Delta}]^{\Delta}}{{f\circ x^{\sigma}}}+rx^{\Delta}
[\frac{\phi^{\Delta}}{f\circ x^{\sigma}}-\frac{\phi[{f\circ x}]^{\Delta}}
{{[f\circ x]}[f\circ x^{\sigma}]}] \\
&=-\phi^{\sigma}p+\phi^{\Delta}r
\frac{x^{\Delta}}{f\circ x^{\sigma}}-\frac{\phi rx^{\Delta}[{f\circ x}]^{\Delta}}
{{[f\circ x]}[f\circ x^{\sigma}]}.
\end{align*}
Integrating the above equation from $t_1$ to $t$, we obtain that
\begin{equation} \label{omegad22}
\omega(t)-\omega(t_1)=-\int^t_{t_1}\phi^{\sigma}p\Delta s
+\int^t_{t_1}\phi^{\Delta}r \frac{x^{\Delta}}{f\circ x^{\sigma}}\Delta s
-\int^t_{t_1}\frac{\phi rx^{\Delta}[{f\circ x}]^{\Delta}}
{{[f\circ x]}[f\circ x^{\sigma}]}\Delta s.
\end{equation}
From Lemma \ref{Lem2.1}, we obtain
\[
[f(x(t))]^{\Delta}=\Big\{\int_0^{1}f'(x(t)+h\mu(t)x^{\Delta}(t))dh\Big\}
x^{\Delta}(t).
\]
So, from condition (H2), we  have
\begin{equation}\label{Lemme3-33}
 x^{\Delta}(t)[f(x(t))]^{\Delta}\geq0.
\end{equation}
From condition (H1) and Lemma \ref{Jia}, we obtain
 \begin{equation}\label{2.5}
 \int^t_{t_1}\phi^{\Delta}r
\frac{x^{\Delta}}{f\circ x^{\sigma}}\Delta s
=\phi^\Delta(s)r(s)|_{s=t_1} \Lambda(t)\quad\text{for }  t\in[t_1,\infty),
 \end{equation}
where $m_x\leq \Lambda(t) \leq M_x$, and $m_x$ and $M_x$ denote the infimum
and supremum, respectively, of the function
 $\int^s_{t_1}\frac{x^\Delta(\xi)}{f(x^\sigma(\xi))}\Delta \xi$ for $s\in[t_1,t]$.
Letting
\[
F(u)= \int_{\varepsilon}^{u}\frac{1}{f(v)}dv
\]
 and $G(\xi)=x(\xi)$,
by Lemma \ref{Wu},  for all $\varepsilon>0$, we have
\begin{equation}\label{etheoremad2}
 [F(G(\xi))]^{\Delta}
=\Big[\int_{\varepsilon}^{x(\xi)}\frac{1}{f(v)}dv\Big]^{\Delta}
\geq\frac{x^{\Delta}(\xi)}{f(x^{\sigma}(\xi))}.
\end{equation}
Integrating the above equation from $t_1$ to $s$, we obtain
\begin{equation}\label{superEnlarge}
\begin{aligned}
 \int_{t_1}^{s}\frac{x^{\Delta}(\xi)}{f(x^{\sigma}(\xi))}\Delta \xi
&\leq\int_{\varepsilon}^{x(s)}\frac{1}{f(v)}dv-\int_{\varepsilon}^{x(t_1)}
 \frac{1}{f(v)}dv\\
&=\int_{x(t_1)}^{x(s)}\frac{1}{f(v)}dv
<\int_{x(t_1)}^{\infty}\frac{1}{f(v)}dv.
\end{aligned}
\end{equation}
 So, from condition (H3) and \eqref{superEnlarge}, we have
\begin{equation}\label{2.133}
 \Lambda(t)\leq M_x\leq M(t_1):=\int_{x(t_1)}^{\infty}\frac{1}{f(v)}dv,\quad
\text{for } t\in[t_1,\infty).
 \end{equation}
From \eqref{omegad22}, \eqref{2.5}, and \eqref{2.133}, we have that
\begin{equation} \label{omegad33}
\omega(t)-\omega(t_1)
\leq-\int^t_{t_1}\phi^{\sigma}p\Delta s
-\int^t_{t_1}\frac{\phi rx^{\Delta}[{f\circ x}]^{\Delta}}
{{[f\circ x]}[f\circ x^{\sigma}]}\Delta s+\phi^\Delta(t_1)r(t_1)M(t_1).
\end{equation}
Since $\int_{t_0}^{\infty}\phi^\sigma(s) p(s)\Delta s=\infty$,
from \eqref{Lemme3-33} and \eqref{omegad33}, it is easy to see that
 there exists a sufficiently large $t_2\geq t_1$, such that for $t\geq t_2$
\begin{equation} \label{2.15}
\begin{aligned}
\omega(t)+\int^t_{t_2}\frac{\phi rx^{\Delta}[{f\circ x}]^{\Delta}}
{{[f\circ x]}[f\circ x^{\sigma}]}\Delta s
&\leq\omega(t)+\int^t_{t_1}\frac{\phi rx^{\Delta}[{f\circ x}]^{\Delta}}
{{[f\circ x]}[f\circ x^{\sigma}]}\Delta s \\
&\leq\omega(t_1)-\int^t_{t_1}\phi^{\sigma}p\Delta s+\phi^\Delta(t_1)r(t_1)M(t_1)\\
&<-1.
\end{aligned}
\end{equation}
In particular, from \eqref{Lemme3-33} and \eqref{2.15}, we have
\begin{equation}\label{2.16}
x^\Delta(t)<0,\quad \text{for } t\geq t_2.
\end{equation}
Define
\begin{equation}\label{al}
 y(t):=1+\int^t_{t_2}\frac{\phi rx^{\Delta}[{f\circ x}]^{\Delta}}
{{[f\circ x]}[f\circ x^{\sigma}]}\Delta s.
\end{equation}
Obviously, $y(t_2)=1$. From \eqref{2.15}, we obtain
\begin{equation}\label{2.20}
 -\omega(t)\geq y(t).
\end{equation}
 From \eqref{2.16}, \eqref{al}  and \eqref{2.20}  we have
\begin{equation}\label{asas}
y^\Delta(t)=\frac{ \phi(t) r(t)x^\Delta(t)
[f(x(t))]^{\Delta}} {f(x(t))f(x(\sigma(t)))}>-y(t)\frac{[f(x(t))]^{\Delta}
}{f(x(\sigma(t)))}.
\end{equation}
It follows that $ y^{\Delta}(t)f(x^{\sigma}( t))+y(t)[f(x( t))]^{\Delta}>0$.
That is $[y(t)f(x( t))]^{\Delta}>0$. From \eqref{2.20}, we obtain
\[
-\frac{\phi(t) r(t)x^{\Delta}(t)}{f(x( t))}
\geq y(t)>\frac{y(t_2)f(x(t_2))}{f(x( t))},\quad \text{for } t\geq t_2.
\]
Therefore, we obtain
\[
x^{\Delta}(t)<-\frac{y(t_2)f(x(t_2))}{\phi(t)r(t)}.
\]
Integrating the above equation from $t_2$ to $t$, we obtain
\[
x(t)-x(t_2)<-\int_{t_2}^{t}\frac{y(t_2)f(x(t_2))}{\phi(s)r(s) }\Delta
s\to-\infty,\quad\text{as } t\to\infty,
\]
which contradicts $x(t)>0$. This completes the proof of Theorem \ref{MainTheorem}.
\end{proof}

Let $\phi(s)=s^\beta$. As a consequence of Theorem \ref{MainTheorem}, 
we can get the following theorem which is the main result of Jia et al \cite{Jiak}
on a regular time scale when $r(t)=1$.

\begin{theorem} \label{t2.1}
Assume that conditions {\rm (H1)--(H3)} hold. Suppose
there exists a real number $\beta$ satisfying $0<\beta\leq 1$, such
that $ \int^\infty_{t_0} \sigma^\beta(s) p(s)\Delta t =\infty$. 
Then \eqref{Superlinear} with $r(t)=1$ is oscillatory.
\end{theorem}

If we do not assume the superlinearity condition (H3) in the
previous theorems, then from \eqref{superEnlarge}, we can conclude
that all bounded solutions are oscillatory which also includes the
sublinear case. That is,  we can state the following theorem.

\begin{theorem}\label{MainTheorem1}
Assume that conditions {\rm(H1)--(H2)} hold. If there exists a function
 $\phi>0$ satisfying $\phi^{\Delta}\geq0$ and 
$[\phi^\Delta r]^{\Delta}\leq0$ such that
\begin{equation} \label{Integral}
\int_{t_0}^{\infty}\frac{1}{\phi(s)r(s)}\Delta s=\infty\quad
\text{and}\quad
\int^\infty_{t_0} \phi^\sigma(s) p(s)\Delta s=\infty.
\end{equation}
Then all bounded solutions of \eqref{Superlinear} are oscillatory.
\end{theorem}

\section{Belohorec-type oscillation theorems}

 In this section, we consider the  second-order sublinear dynamic equation
\begin{equation} \label{Sublinear}
 \big(r(t)x^{\Delta}(t)\big)^{\Delta}+p(t)x^{\alpha}(\sigma(t))=0,\quad
t\geq t_0,
\end{equation}
where the independent variable is in a time scale $\mathbb{T}$,
 $0<\alpha<1$ is a quotient of odd positive integers,
$ p\in C_{rd}(\mathbb{T},\mathbb{R})$ and $ 1/r\in C_{rd}(\mathbb{T},\mathbb{R}^+)$.

\begin{theorem}\label{MainTheorem2}
If there exists a function $\phi>0$ satisfying $\phi^{\Delta}\geq0$ 
and $[r\phi^\Delta]^{\Delta}\leq0$ such that
\begin{equation}\label{condition2}
\int_{t_0}^{\infty}\frac{1}{r(s)\phi(s)}\Delta s=\infty\quad
\text{and}\quad
\int_{t_0}^{\infty} \phi^\alpha(\sigma(s)) p(s)\Delta s=\infty.
\end{equation}
Then \eqref{Sublinear} is oscillatory.
\end{theorem}

\begin{proof} 
Suppose that $x(t)$ is a nonoscillatory solution of \eqref{Sublinear} 
on $[t_0,\,\infty)$.
Without loss of generality, we may assume that $x(t)> 0$ 
for $t\ge t_1\ge t_0$. By condition (H2), we shall only consider this case,
since the substitution $z(t)=-x(t)$ transforms \eqref{Sublinear} 
into an equation of the same form.
Let us make the substitution $x(t)=\phi(t)u(t)$ and define
\begin{equation}\label{omega2}
\omega(t):= \frac{r(t)x^{\Delta}(t)}{x^{\alpha}(t)} \quad\text{for }
 t\ge{t}_{1}.
\end{equation}
It follows that
\begin{equation}\label{1omega}
\omega(t)=\frac{r(\phi u)^{\Delta}}{(\phi u)^{\alpha}}
=\frac{r\phi u^{\Delta}}{\phi^{\alpha}u^{\alpha}}
 +\frac{r\phi^{\Delta}u^{\sigma}}{\phi^{\alpha}u^{\alpha}}
\geq\frac{r\phi u^{\Delta}}{\phi^{\alpha}u^{\alpha}}.
\end{equation}
By the product rule and the quotient rule, from \eqref{1omega} 
and \eqref{Sublinear}, we obtain
\begin{equation} \label{omegad1}
\begin{aligned}
\omega^{\Delta}
&=[rx^{\Delta}]^{\Delta} [\frac{1}{{x^{\alpha}}}]^{\sigma}
 +rx^{\Delta}[\frac{1}{{x^{\alpha}}}]^{\Delta}\\
&=[rx^{\Delta}]^{\Delta} [\frac{1}{{x^{\alpha}}}]^{\sigma}
 -rx^{\Delta}\frac{[{{x^{\alpha}}}]^{\Delta}}{{{x^{\alpha}}}{x^{\alpha^{\sigma}}}}\\
&=-p-rx^{\Delta}\frac{[{{x^{\alpha}}}]^{\Delta}}{{{x^{\alpha}}}{x^{\alpha^{\sigma}}}}.
\end{aligned}
\end{equation}
By the substitution $x(t)=\phi(t)u(t)$ and \eqref{omegad1}, we have
\begin{equation} \label{omegad01}
\begin{aligned}
\omega^{\Delta}
&=- p-r\frac{(\phi u)^{\Delta}[(\phi u)^{\alpha}]^{\Delta}}{{(\phi u)^{\alpha}}
 {(\phi u)^{\alpha^{\sigma}}}} \\
&=- p-r\frac{[\phi u^{\Delta}+\phi^{\Delta} u^{\sigma}][\phi^{\alpha}
 u^{{\alpha}^{\Delta}}+\phi^{{\alpha}^{\Delta}}
 u^{\alpha^{\sigma}}]}{\phi^{\alpha}u^{\alpha}\phi^{\alpha^{\sigma}}
 u^{\alpha^{\sigma}}} \\
&=- p-r\frac{\phi\phi^{\alpha}u^{\Delta}u^{{\alpha}^{\Delta}}
 + \phi^{\alpha}\phi^{\Delta}u^{\sigma}u^{{\alpha}^{\Delta}}
 +\phi\phi^{{\alpha}^{\Delta}}u^{\alpha^{\sigma}}u^{\Delta}
 + \phi^{\Delta}\phi^{{\alpha}^{\Delta}}u^{\sigma}u^{\alpha^{\sigma}}}
 {\phi^{\alpha}\phi^{\alpha^{\sigma}}u^{\alpha}u^{\alpha^{\sigma}}}.
\end{aligned}
\end{equation}
Multiplying both sides of \eqref{omegad01} by $\phi^{\alpha^{\sigma}}$,
we obtain
\begin{equation} \label{omegad2}
\phi^{\alpha^{\sigma}}\omega^{\Delta}
=- \phi^{\alpha^{\sigma}}p-r\frac{\phi\phi^{\alpha}u^{\Delta}u^{{\alpha}^{\Delta}}+
 \phi^{\alpha}\phi^{\Delta}u^{\sigma}u^{{\alpha}^{\Delta}}
+\phi\phi^{{\alpha}^{\Delta}}u^{\alpha^{\sigma}}u^{\Delta}
+ \phi^{\Delta}\phi^{{\alpha}^{\Delta}}u^{\sigma}u^{\alpha^{\sigma}}}
{\phi^{\alpha}u^{\alpha}u^{\alpha^{\sigma}}}.
\end{equation}
Integrating \eqref{omegad2} from $t_1$ to $t$, and using an integration
by parts formula we obtain
\begin{equation} \label{omegad3}
\begin{aligned}
\phi^{\alpha}\omega
&=\phi^{\alpha}(t_1)\omega(t_1)+\int^t_{t_1}\phi^{{\alpha}^{\Delta}}
 \omega\Delta s-\int^t_{t_1} \phi^{\alpha^{\sigma}}p\Delta s \\
&\quad-\int^t_{t_1}r\frac{\phi\phi^{\alpha}u^{\Delta}u^{{\alpha}^{\Delta}}+
 \phi^{\alpha}\phi^{\Delta}u^{\sigma}u^{{\alpha}^{\Delta}}
+\phi\phi^{{\alpha}^{\Delta}}u^{\alpha^{\sigma}}u^{\Delta}
 + \phi^{\Delta}\phi^{{\alpha}^{\Delta}}u^{\sigma}u^{\alpha^{\sigma}}}
{\phi^{\alpha}u^{\alpha}u^{\alpha^{\sigma}}}\Delta s.
\end{aligned}
\end{equation}
From Lemma \ref{Wu}, it is easy to see that
\begin{equation}\label{Lemme3-2}
 \alpha u^{(\alpha-1)^{\sigma}}u^{\Delta}
\leq u^{{\alpha}^{\Delta}}\leq \alpha u^{\alpha-1}u^{\Delta}.
\end{equation}
Then from \eqref{Lemme3-2}, we have
\begin{equation}\label{Lemme3-3}
 u^{\Delta}u^{{\alpha}^{\Delta}}\geq0.
\end{equation}
From \eqref{1omega}, \eqref{omegad3} and \eqref{Lemme3-3}, we obtain
\begin{equation} \label{omegad4}
\begin{aligned}
\frac{r\phi u^{\Delta}}{u^{\alpha}}
&\leq\phi^{\alpha}(t_1)\omega(t_1)
 -\int^t_{t_1} \phi^{\alpha^{\sigma}}p\Delta s
 +\int^t_{t_1}\phi^{{\alpha}^{\Delta}}[\frac{r\phi u^{\Delta}}{\phi^{\alpha}
 u^{\alpha}}+\frac{r\phi^{\Delta}u^{\sigma}}{\phi^{\alpha}u^{\alpha}}]\Delta s \\
&\quad-\int^t_{t_1}r\phi^{\Delta}\frac{u^{\sigma}u^{{\alpha}^{\Delta}}}
 {u^{\alpha}u^{\alpha^{\sigma}}}\Delta s-\int^t_{t_1}
 \frac{r\phi\phi^{{\alpha}^{\Delta}}}
 {\phi^{\alpha}}\frac{u^{\Delta}}
 {u^{\alpha}}\Delta s-\int^t_{t_1}\frac{r\phi^{\Delta}\phi^{{\alpha}^{\Delta}}}
 {\phi^{\alpha}}\frac{u^{\sigma}} {u^{\alpha}}\Delta s \\
&=\phi^{\alpha}(t_1)\omega(t_1)-\int^t_{t_1} \phi^{\alpha^{\sigma}}p\Delta s
 -\int^t_{t_1}r\phi^{\Delta}\frac{u^{\sigma}u^{{\alpha}^{\Delta}}}
{u^{\alpha}u^{\alpha^{\sigma}}}\Delta s.
\end{aligned}
\end{equation}
From \eqref{Lemme3-2}, \eqref{omegad4} and Lemma \ref{Jia}, for $t\in[t_1,\infty)$,
we obtain
\begin{equation} \label{omegada}
\begin{aligned}
\frac{r\phi u^{\Delta}}{u^{\alpha}}
&\leq\phi^{\alpha}(t_1)\omega(t_1)-\int^t_{t_1} \phi^{\alpha^{\sigma}}p\Delta s
-\int^t_{t_1}\alpha r\phi^{\Delta}\frac{u^{\Delta}} {u^{\alpha}}\Delta s \\
&=\phi^{\alpha}(t_1)\omega(t_1)-\int^t_{t_1} \phi^{\alpha^{\sigma}}p\Delta s
 -r(t_1)\phi^\Delta(t_1)\Lambda(t),
\end{aligned}
\end{equation}
 where $m_x\leq \Lambda(t) \leq M_x$, and $m_x$ and $M_x$ denote the infimum
and supremum, respectively, of the function
 $\int^s_{t_1}\frac{u^{\Delta}} {u^{\alpha}}\Delta \xi$ for $s\in[t_1,t]$.
 Letting $F(u)= \int_{\varepsilon}^{u}\frac{1}{v^{\alpha}}dv$ and
$G(\xi)=u(\xi)$, by Lemma \ref{Wu}, for all $\varepsilon>0$, we have
\begin{equation} \label{etheoremad}
\begin{aligned}
 [F(G(\xi))]^{\Delta}
=\Big[\int_{\varepsilon}^{u(\xi)}\frac{1}{v^{\alpha}}dv\Big]^{\Delta}
\leq\frac{u^{\Delta}}{u^{\alpha}}.
\end{aligned}
\end{equation}
Integrating the above equation from $t_1$ to $s$, we obtain
\begin{equation}\label{theorem3-3}
\begin{aligned}
 \int_{t_1}^{s}\frac{u^{\Delta}}
{u^{\alpha}}\Delta \xi&\geq\int_{\varepsilon}^{u(s)}
 \frac{1}{v^{\alpha}}dv-\int_{\varepsilon}^{u(t_1)}\frac{1}{v^{\alpha}}dv \\
&=(1-\alpha)u^{(1-\alpha)}(s)-(1-\alpha)u^{(1-\alpha)}(t_1)\\
&>-(1-\alpha)u^{(1-\alpha)}(t_1).
\end{aligned}
\end{equation}
 So, from \eqref{theorem3-3}, we have
\begin{equation}\label{2.13}
 \Lambda(t)\geq m_x=-(1-\alpha)u^{(1-\alpha)}(t_1)
 \end{equation}
for $t\in[t_1,\infty)$.
 From \eqref{omegada} and \eqref{2.13}, we have
\begin{equation} \label{omegada1}
\frac{r\phi u^{\Delta}}{u^{\alpha}}
\leq\phi^{\alpha}(t_1)\omega(t_1)-\int^t_{t_1}
\phi^{\alpha^{\sigma}}p\Delta s+(1-\alpha)r(t_1)
\phi^\Delta(t_1)u^{(1-\alpha)}(t_1).
\end{equation}
Since $\int_{t_0}^{\infty} \phi^\alpha(\sigma(s)) p(s)\Delta s=\infty$,
 from \eqref{omegada1}, there exists a sufficiently large $t_2\geq t_1$
such that
\begin{equation}\label{omegada2}
\frac{r\phi u^{\Delta}}{u^{\alpha}}<-1,\quad\text{for } t\geq t_2.
\end{equation}
Multiplying both sides of \eqref{omegada2} by $\frac{1}{r\phi}$, we obtain
\[
\frac{u^{\Delta}}{u^{\alpha}}<-\frac{1}{r\phi}.
\]
Integrating the above equation from $t_2$ to $t$, by
 Lemma \ref{Wu} and \eqref{etheoremad}, we have
\[
 -(1-\alpha)u^{(1-\alpha)}(t_2)\leq\int_{t_2}^{t}\frac{u^{\Delta}}
{u^{\alpha}}\Delta \xi<-\int_{t_2}^{t}\frac{1}{ r(s)\phi(s)}\Delta
s\to-\infty,\quad\text{as} \quad t\to\infty,
\]
which is a contradiction. This completes the proof.
\end{proof}

Let $\phi(s)=s^\beta$. As a consequence of Theorem \ref{MainTheorem2}, 
we obtain the following theorem which is the main result of Jia et al \cite{Jiab}
on a regular time scale when $r(t)=1$.

\begin{theorem}\label{t2.1b}
If there exists a real number $\beta$ satisfying $0<\beta\leq 1$, such that
$ \int^\infty_{t_0} \sigma^{\alpha\beta}(s) p(s)\Delta t =\infty$.
Then \eqref{Sublinear} with $r(t)=1$ is oscillatory.
\end{theorem}

\section{Some examples}

Let us consider the following examples to better understand our results.

\begin{example} \label{examp1} \rm
 Consider the difference equation
\begin{equation}\label{last5.1}
\Delta^2x(n)+[\frac{a}{\ln^{b+1}(n)}+\frac{c(-1)^n}{\ln^{b}(n)}]| x(n+1)|^{\alpha}
\operatorname{sgn}x(n+1)=0,
\end{equation}
for $\alpha>0$ and $n>1$,
where $a>0$, $0<b\leq 1$ and $c$ is any real number.
 Letting $\phi(n)=\ln^{b}(n-1)$, from \eqref{condition1}, 
equation \eqref{last5.1} is oscillatory when $\alpha>1$, since
\[
\sum^{\infty}_{n=1}\ln^{b}(n)[\frac{a}{\ln^{b+1}(n)}+\frac{c(-1)^n}{\ln^{b}(n)}]
=\sum^{\infty}_{n=1}[\ln(n)+c(-1)^n]=\infty.
\]
\end{example}

Specifically, all bounded solutions of \eqref{last5.1} are oscillatory
 when $\alpha>0$.

\begin{example} \label{examp5.2} \rm
 Consider the second-order sublinear difference equation
\begin{equation}\label{last2}
\Delta^2x(n)+[\frac{a}{\ln^{b+1}(n)}+\frac{c(-1)^n}{\ln^{b}(n)}]
| x(n+1)|^{\alpha}\operatorname{sgn}x(n+1)=0,
\end{equation}
for $0<\alpha<1$ and $n>1$,
where $a>0$, $0<b\leq \alpha$ and $c$ is any real number. Letting 
$\phi(n)=\ln(n-1)$, from \eqref{condition2}, the equation \eqref{last2}
is oscillatory, since
\[
\sum^{\infty}_{n=1}\ln^{\alpha}(n)[\frac{a}{\ln^{b+1}(n)}+\frac{c(-1)^n}{\ln^{b}(n)}]
\geq\sum^{\infty}_{n=1}[\ln(n)+c(-1)^n]=\infty.
\]
\end{example}


\begin{example} \label{examp5.3} \rm
 Consider the second-order dynamic equation
\begin{equation}\label{last3}
x^{\Delta\Delta}(t)+p(t)| x(\sigma(t))|^{\alpha-1}x(\sigma(t))=0,\quad
 \alpha>1,\; t\geq\frac{3\pi}{2}.
\end{equation}
Let
\[
 p(t)=\begin{cases}
\frac{1}{t^{1+\beta}}+\frac{\sin t}{t^{\beta}},
 &t\in[2k\pi-\frac{\pi}{2},\,2k\pi+\frac{\pi}{2}], \\
\frac{1}{k^{1+\beta}}+\frac{(-1)^{k}}{k^{\beta}},
 &t=2k\pi+\pi,
\end{cases}
\]
where $0<\beta\leq1$, $k\geq1$. Here we take $\phi(t)=t^{\beta}$. 
It is easy to see that
\[
 \sigma^{\beta}(t)p(t)=\begin{cases}
\frac{1}{t}+\sin t,
 &t\in[2k\pi-\frac{\pi}{2},\,2k\pi+\frac{\pi}{2}), \\
[2k\pi+\pi]^{\beta}\big[[2k\pi+\frac{\pi}{2}]^{-1-\beta}+[2k\pi
+\frac{\pi}{2}]^{-\beta}\big],
 &t=2k\pi+\frac{\pi}{2}, \\
[2k\pi+\frac{3\pi}{2}]^{\beta}[k^{-1-\beta}+(-1)^{k}k^{-\beta}],
 &t=2k\pi+\pi.
\end{cases}
\]
From Theorem \ref{MainTheorem}, we obtain
\[
\int_{t_0}^{\infty}\frac{1}{\phi(s)r(s)}\Delta
s=\int_{t_0}^{\infty}\frac{1}{s^{\beta}}\Delta
s=\infty,\]
and
\begin{align*} %\label{last4}
&\int^\infty_{t_0} \phi^\sigma(s) p(s)\Delta s\\
&=\int^\infty_{\frac{3\pi}{2}} \sigma^{\beta}(s) p(s)\Delta s \\
&=\sum^{\infty}_{k=1}\int^{2k\pi+\frac{\pi}{2}}_{2k\pi
 -\frac{\pi}{2}}[\frac{1}{s}+\sin s]\Delta s+
 \sum^{\infty}_{k=1}[2k\pi+\pi]^{\beta}\big[[2k\pi+\frac{\pi}{2}]^{-1-\beta} 
 +[2k\pi+\frac{\pi}{2}]^{-\beta}\big]\\
&\quad +\sum^{\infty}_{k=1}
 [2k\pi+\frac{3\pi}{2}]^{\beta}[k^{-1-\beta}+(-1)^{k}k^{-\beta}] \\
&\geq\sum^{\infty}_{k=1}\int^{2k\pi+\frac{\pi}{2}}_{2k\pi-\frac{\pi}{2}}[\frac{1}{s}+\sin s]\Delta s+\sum^{\infty}_{k=1}
[2k\pi+\frac{3\pi}{2}]^{\beta}[k^{-1-\beta}+(-1)^{k}k^{-\beta}] \\
&=\sum^{\infty}_{k=1}\ln\frac{2k\pi+\frac{\pi}{2}}{2k\pi-\frac{\pi}{2}}
 +\sum^{\infty}_{k=1} \big[\frac{1}{k}[2\pi+\frac{3\pi}{2k}]^{\beta}
 +(-1)^{k}[2\pi+\frac{3\pi}{2k}]^{\beta}\big] \\
&\geq\sum^{\infty}_{k=1}\ln[1+\frac{\pi}{2k\pi-\frac{\pi}{2}}]+\sum^{\infty}_{k=1}
 (-1)^{k}[2\pi+\frac{3\pi}{2k}]^{\beta} \\
&=\sum^{\infty}_{k=1}\ln[1+\frac{\pi}{2k\pi
 -\frac{\pi}{2}}]+[2\pi]^{\beta}\sum^{\infty}_{k=1}
(-1)^{k}[1+\frac{3\beta}{4k}+O\big(\frac{1}{k^2}\big)]^{\beta}.
\end{align*}
Since 
\[
\sum^{\infty}_{k=1}\frac{\pi}{2k\pi-\frac{\pi}{2}}=\infty, \quad
\big|\sum^{m}_{k=1}(-1)^{k}\big|\leq1,\quad 
\sum^{\infty}_{k=1}(-1)^{k}\frac{3\beta}{4k}<\infty,
\]
 from, it is easy to see that
\[
\int^\infty_{t_0} \phi^\sigma(s) p(s)\Delta
s=\int^\infty_{\frac{3\pi}{2}} \sigma^{\beta}(s) p(s)\Delta
s=\infty.
\]
From \eqref{condition1}, the equation
\eqref{last3} is oscillatory. We note that the results of Jia et al
\cite{Jiak,Jiab} do not handled since the time scale is irregular;
however, our results are established for arbitrary time scales.
\end{example}

\subsection*{Acknowledgments}
This project was supported by the NNSF of China (Nos. 11271139 and 11271380)
and by the China Scholarship Council (Nos. 201306155015 and
201406385006)


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\end{document}
