\documentclass[reqno]{amsart}
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\AtBeginDocument{{\noindent\small
Seventh Mississippi State - UAB Conference on Differential Equations and
Computational Simulations,
{\em Electronic Journal of Differential Equations},
Conf. 17 (2009),  pp. 207--212.\newline
ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu
\newline ftp ejde.math.txstate.edu}
\thanks{\copyright 2009 Texas State University - San Marcos.}
\vspace{9mm}}

\begin{document} \setcounter{page}{207}
\title[\hfilneg EJDE-2009/Conf/17\hfil
 Quasilinear semipositone Dirichlet problems]
{Existence and nonexistence results for quasilinear semipositone Dirichlet
problems}

\author[M. Rudd\hfil EJDE/Conf/17 \hfilneg]
{Matthew Rudd}

\address{Matthew Rudd \newline
Department of Mathematics \\
University of Idaho \\
Moscow, ID 83844, USA}
\email{mrudd@uidaho.edu}

\thanks{Published April 15, 2009.}
\subjclass[2000]{34B10, 35J20}
\keywords{semipositone problems; p-Laplacian; positive solutions}

\begin{abstract}
 We use the sub/supersolution method to analyze a semipositone Dirichlet
 problem for the $p$-Laplacian. To find a positive solution, we therefore
 focus on a related problem that produces positive subsolutions.
 We establish a new nonexistence result for this subsolution problem on
 general domains, discuss the existence of positive radial subsolutions
 on balls, and then apply our results to problems involving particular
 semipositone nonlinearities.
\end{abstract}

\maketitle
\numberwithin{equation}{section}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{proposition}[theorem]{Proposition}

\section{Introduction}

A model problem in nonlinear analysis is the Dirichlet problem
\begin{equation} \label{main}
\begin{gathered}
-\Delta_{p}u = f(u) \quad \text{in }  \Omega, \\
 u = 0 \quad \text{on }  \partial \Omega \,,
\end{gathered}
\end{equation}
where   $\Omega \subset \mathbb{R}^{N}$   is a bounded domain with smooth
boundary $\partial \Omega$,  $p > 1$, $ \Delta_{p}u :=
\operatorname{div}{ \big( | \nabla u |^{p-2} \nabla u \big)}$ is
the $p$-Laplacian, and $f : \mathbb{R} \to \mathbb{R}$   is a continuous function.
We make no attempt to review the many solvability and multiplicity
results for \eqref{main} when the nonlinearity $f$ is nonnegative;
we are concerned, instead, with the fact that far less is known
when $f$ satisfies the \textit{semipositone} condition
\begin{equation} \label{semipos}
f(0) < 0 \, ,
\end{equation}
which we henceforth assume.  This condition arises naturally in
resource  management models, for example \cite{castro:nep00},
leading to a problem of the form \eqref{main} for which only
positive solutions are meaningful.  In a similar vein, this note
focuses on determining when the semipositone problem \eqref{main}
has at least one positive solution, i.e., a positive function $u
\in W^{1,p}_{0}(\Omega)$ such that
\[
\int_{\Omega}{ | \nabla u |^{p-2} \nabla u \cdot \nabla \varphi \,
dx} = \int_{\Omega}{ f(u)  \varphi \, dx }
\]
for all test functions $\varphi \in C_{0}^{\infty}(\Omega)$.

To answer this question, we rely on the well-known
sub/supersolution  method (see, for instance, the seminal paper
\cite{hess:sne76} or the more recent \cite{drabek:eup01}).  We
therefore seek positive functions   $\underline{u} \in
W^{1,p}_{0}(\Omega)$   and   $\overline{u} \in
W^{1,p}_{0}(\Omega)$ such that

\begin{itemize}

\item
$\underline{u}$   is a subsolution : $ \Delta_{p}\left(
\underline{u} \right) +  f( \underline{u} ) \geq 0 $,

\item
$\overline{u}$   is a supersolution :   $ \Delta_{p}\left(
\overline{u} \right)   +   f( \overline{u} )   \leq   0 $, and

\item
$\underline{u}   \leq   \overline{u} $.

\end{itemize}
With such an ordered pair of sub- and supersolutions in hand, it follows
 that problem \eqref{main} has a positive solution.

Finding a positive subsolution   $\underline{u}$   is the real difficulty in
semipositone problems (\cite{chhetri:eps05},\cite{oruganti:erc05}), since the semipositone condition (\ref{semipos}) precludes the constant function $0$ from
being a subsolution.  As shown below, a positive solution of
\begin{equation} \label{sub}
\begin{gathered}
- \Delta_{p} u = \sigma(u) \quad \text{in } \Omega, \\
 u = 0 \quad \text{on }\partial \Omega
\end{gathered}
\end{equation}
will be a positive subsolution of \eqref{main} for
certain nonlinearities $f$, where
$\sigma : \mathbb{R} \to \mathbb{R}$ is the step function
\[
\sigma(t) :=  \begin{cases}
K, & \text{for }  t > 1 \,, \\
L, & \text{for }  t \leq 1 \,,
\end{cases}
\]
defined by constants $K > 0$ and $L \leq 0$; in
\cite{drabek:mps06}, Dr\'{a}bek and Robinson used an auxiliary
problem of this form to analyze \textit{positone} problems.  These
constants cannot be given indiscriminately, so we must first
determine those values of $K$ and $L$ such that \eqref{sub} has a
positive solution.

\section{A nonexistence result: Auxiliary problem}

We begin with a new nonexistence result for problem \eqref{sub}.
Since $\Omega$ is a smooth domain, it is well-known that
$-\Delta_{p}$  has a simple principal eigenvalue $\lambda_{1} > 0
$ on $\Omega$.  A direct calculation shows that $\lambda_{1}$
provides a lower bound on admissible values of $K$ in problem
\eqref{sub}.

\begin{proposition} Equation \eqref{sub} cannot have a positive solution
if $K < \lambda_{1}$.
\end{proposition}

\begin{proof}
If   $u$   is a positive solution of    \eqref{sub},   then
multiplying both sides of the equation by $u$ and integrating
yields
\begin{align*}
\int_{\Omega}{ | \nabla u |^{p} \, dx }
& =  \int_{ \{ u > 1 \} }{ K u \, dx } + \int_{ \{ 0 \leq u \leq 1 \} }{ L u \, dx } \\
& \leq  K  \int_{ \Omega }{ |u|^{p} \, dx } \\
& \leq  \frac{K}{\lambda_{1}} \int_{ \Omega }{ |\nabla u|^{p} \,dx} \, ,
\end{align*}
where we have used the definition of $\sigma(u)$, the fact that $L \leq 0$, and the
Poincar\'{e} inequality with its optimal constant.  It follows, as claimed,
that $K$ cannot be less than $\lambda_{1}$.
\end{proof}

A natural problem, then, is to determine the smallest value of $K
\geq \lambda_{1}$ corresponding to a given $L \leq 0$ such that
\eqref{sub} does have a positive solution.  Having found such a
value of $K$, a subsequent question is to determine or estimate
the number of positive solutions of \eqref{sub}.

\section{Existence results: Auxiliary problem}

There seem to be no existence results for problem \eqref{sub} on
\textit{general} domains $\Omega$; one inherent difficulty is the
free boundary   $ \{ u = 1 \} $. When $\Omega$ is a
ball, however, conditions on $L$ and $K$ can be found that
guarantee the existence of a positive radial solution $ u = u(r)
$, where $r = |x|$.

\subsection{Positive radial subsolutions}

Looking for radial solutions of \eqref{sub} on the unit ball,
$\Omega = B_{1}(0) \subset \mathbb{R}^{N}$, leads to consideration of  the
boundary value problem
\begin{equation} \label{bvp}
\begin{gathered}
r^{-\gamma} \left( r^{\alpha} | u' |^{\beta} u'  \right)' +   \sigma(u)  = 0,
\quad  0 < r < 1 \, , \\
u'(0) = u(1) = 0 ,
\end{gathered}
\end{equation}
for parameters  $\alpha \geq 0$, $\gamma + 1 > \alpha$,  and
 $\beta > -1$. This framework includes the radial versions of operators
other than the $p$-Laplacian, as indicated
in the following table \cite{jacobsen:rsq04}:
 \renewcommand{\arraystretch}{1.3}
\begin{center}
\begin{tabular}{|c|c|c|c|}
\hline
  $\alpha$   &   $\beta$   &   $\gamma$   &   Operator   \\
\hline
  $N-1$   &   $0$     &   $N-1$   &   Laplacian   \\
  $N-1$   &   $p-2$   &   $N-1$   &   $p$-Laplacian   \\
  $N-k$   &   $k-1$   &   $N-1$   &   $k$-Hessian   \\
\hline
\end{tabular}
\end{center}
 \renewcommand{\arraystretch}{1}
\smallskip

 It is not difficult to show that $u$ solves \eqref{bvp} if and only if
it is a fixed point of the operator   $T : C[0,1] \to C[0,1]$
defined by
\begin{equation} \label{T}
( T( v ))(r) :=
\int_{r}^{1}{ \Big( t^{-\alpha} \int_{0}^{t}{  s^{\gamma}
\sigma( v(s) ) \, ds } \Big)^{\frac{1}{\beta + 1}} \, dt } \, .
\end{equation}
By analyzing this explicit operator carefully, \cite{rudd:rsq07}
established the following existence result.

\begin{theorem} \label{quasi-model}
Given any   $\mu \in (0,1)$,   suppose that   $L < 0$   and   $K > 0$
satisfy
\bigskip
\begin{equation} \label{mu2}
\Big( \frac{ \mu K - L }{ K - L } \Big)^{\frac{1}{\gamma+1}} +
\Big( \frac{ \gamma + 1 }{ \mu K } \Big)^{\frac{1}{\beta + 1}} \leq 1 \,.
\end{equation}
Then \eqref{bvp} has at least one positive solution.
\end{theorem}

In short, the proof of Theorem \ref{quasi-model} in \cite{rudd:rsq07}
proceeds by finding   $\rho \in (0,1)$   such that   $C_{\rho}$
is invariant under   $T$,   where   $C_{\rho} \subset C[0,1]$   is the set
\[
C_{\rho} :=\{   v   : v \geq 1   \text{on}   [0,\rho],   0
\leq v < 1   \text{on}   (\rho,1] \} \, .
\]
Working with the set $C_{\rho}$ therefore simplifies the problem
by specifying the free boundary from the outset (at the point
$\rho$).  It is important here to note that, for a fixed value of
$\rho$, $T$ maps all of $C_{\rho}$ onto a single function.

We next outline an alternative approach to proving an existence
result  along the lines of Theorem \ref{quasi-model}. This
technique can be applied in other situations, as shown in detail
in \cite{rudd:pss} where it yields existence results for singular
problems of the form
\begin{equation} \label{L-sing}
 \begin{gathered}
r^{-\gamma} \left( r^{\alpha} | u' |^{\beta} u' \, \right)' +
  \sigma(u) u^{-\delta}   = 0   , \quad  0 < r < 1 \, , \\
u'(0) = 0, \quad  u(1) = 0
\end{gathered}
\end{equation}
for exponents   $\delta \in (0,1)$.  As in the present paper, positive
solutions of (\ref{L-sing})
serve as positive subsolutions of related boundary value problems.

Returning to problem \eqref{bvp}, suppose that   $L < 0$ has been given.
We first determine   $\rho \in (0,1)$   such that
\begin{equation} \label{L-rho}
 \begin{gathered}
r^{-\gamma} \left( r^{\alpha} | u_{1}' |^{\beta} u_{1}' \right)'+ L  = 0 ,
\quad \rho < r < 1 \, , \\
u_{1}(\rho) = 1, \quad  u_{1}(1) = 0
\end{gathered}
\end{equation}
has a positive solution   $u_{1}$; solutions are of the form
\[
u_{1}(r) = \int_{r}^{1}{ \Big( \frac{L}{\gamma + 1} s^{\gamma + 1
- \alpha} + c s^{-\alpha} \Big)^{\frac{1}{\beta +1}} \, ds } \,
, \quad \text{for }  c \geq \frac{ -L }{\gamma + 1}   ,
\]
and the value of $\rho$ follows from choosing the constant $c$.
In particular, the smallest possible value of $\rho$ corresponds to
$c = (-L)/(\gamma + 1)$, and increasing $c$ increases $\rho$.

Having found   $\rho$, we identify   $K = K(L) > 0 $ such that the
solution $u_{2}$ of
\begin{gather*}
r^{-\gamma} \left( r^{\alpha} | u_{2}' |^{\beta} u_{2}' \right)' +   K   = 0,
\quad  0 < r < \rho \, , \\
u_{2}'(0) = 0, \quad u_{2}(\rho) = 1
\end{gather*}
matches the solution of (\ref{L-rho}) at   $\rho$; i.e.,
satisfies $u_{2}'(\rho) = u_{1}'(\rho)$ ;  the solution is
\[
u_{2}(r) = 1 + \int_{r}^{\rho}{ \Big( \frac{K}{\gamma + 1} s^{\gamma
+ 1 - \alpha} \Big)^{\frac{1}{\beta + 1}} \, ds } \, .
\]
As noted above, increasing the choice of $c$ increases $\rho$ and thereby
increases $K$ as well. Combining these solutions produces a solution
of \eqref{bvp}, namely
\[
u(r) :=  \begin{cases}
u_{2}(r), \quad \text{for }  0 \leq r \leq \rho \, , \\
u_{1}(r), \quad \text{for }  \rho \leq r \leq 1 \, .
\end{cases}
\]
Letting $K^{*} > 0$ denote the value of $K$ corresponding to the
choice $c = (-L)/(\gamma + 1)$, we have thus sketched the proof.

\begin{theorem} \label{thm3.2}
Let $L < 0$ be given.  There is a corresponding $K^{*} > 0$ such
that problem \eqref{bvp} has  a positive, strictly decreasing
solution for any $K \geq K^{*}$, and this value of $K^{*}$
increases as $|L|$ increases.
\end{theorem}

This approach of piecing together solutions of subproblems to
solve \eqref{bvp} determines an admissible region of pairs $(L,K)$
such that \eqref{bvp}   has a positive solution; the resulting
region has the same qualitative shape as that described by the
inequality (\ref{mu2}).  (This region can be described explicitly
in the semilinear case; see \cite{robinson:mrs06}.)  A benefit of
this new approach is that it clarifies the relationship between
$L$, $K$, and the free boundary $\rho$.  It would be very
interesting to implement this technique on more general domains
$\Omega$, for which problem \eqref{sub} does not reduce to the
simple form \eqref{bvp}.

\section{Applications}

The pair $(L,K)$ is an \textit{admissible point} if the
corresponding problem \eqref{sub} has a positive solution.  Having
determined a region of admissible points in the previous section,
the following theorems illustrate how to use a positive solution
of \eqref{sub} to solve the original problem \eqref{main} when
$\Omega$ is the unit ball.  Although these theorems only concern
radial solutions, their proofs are intentionally written in a form
that would apply on a more general domain if a positive
subsolution were available.  This highlights the fact stated
earlier that finding such a subsolution is the central difficulty.
Finally, we emphasize that, modulo the bounds stated below, the
nonlinearity $f$ can behave arbitrarily.

\begin{theorem} \label{pos-soln}
Let   $(L,K)$   be an admissible point, let   $\psi$   be a
positive solution of the corresponding problem   \eqref{sub},
and let   $M$   be its maximum value.
  If   $ 0 < a < b^{p-1} < c/K $,   $\Omega = B_{1}(0)$, and
 $f : \mathbb{R} \to \mathbb{R} $   is a continuous function such that
\begin{itemize}

\item $f(t) > b^{p-1}   K$   for   $ b \leq t \leq M b$   and

\item $ aL < f(t) < c$  for all  $t$,

\end{itemize}
 then  \eqref{main}  has a positive radial solution.
\end{theorem}

\begin{proof}
 Define   $\underline{u} := b   \psi $; this function is clearly positive.
Since
\[
\Delta_{p} \underline{u} + f( \underline{u} ) = b^{p-1} \Delta_{p} \psi
+ f( b \psi ) =
- b^{p-1} \sigma( \psi) + f( b \psi ) \, ,
\]
it follows from the definition of $\sigma$ and the given bounds on
$f$ that
\[
\Delta_{p} \underline{u} + f( \underline{u} ) \geq 0 \, .
\]
Thus, $\underline{u}$ is a positive subsolution of \eqref{main}.

Now let   $\overline{u}$   be the (radial) solution of
\begin{gather*}
-\Delta_{p}  \overline{u} = \overline{C} \quad \text{in }\Omega,\\
 u = 0 \quad \text{on } \partial \Omega \, .
\end{gather*}
If   $\overline{C} > c$,   it is easy to see that   $\overline{u}$
is a supersolution of   \eqref{main}.
  Moreover,   $\underline{u}   \leq   \overline{u}$   when
$\overline{C}$   is large enough that
  $\overline{u}(0) \geq b \psi(0)$,   so
applying the sub/supersolution theorem completes the proof.
\end{proof}

Imposing further conditions on  $f$ yields a multiplicity result.

\begin{theorem} \label{3solns}
Let   $(L,K)$   be an admissible point,   let   $\psi$   be a
positive solution of the corresponding problem   \eqref{sub},
and let   $M$   be its maximum value.   If
  $ 0 < a < b^{p-1} < c/K $,   $\Omega = B_{1}(0)$,   and
$f : \mathbb{R} \to \mathbb{R} $   is a continuous function such that
\begin{itemize}

\item $ f(t) < 0$  for   $t \leq 0$,

\item $f(t) > b^{p-1}   K$   for  $ b \leq t \leq M b$,   and

\item $ aL < f(t) < c$  for all  $t$,

\end{itemize}
then  \eqref{main}  has at least three distinct radial solutions,
one of which is positive and one of which is negative.
\end{theorem}

\begin{proof}
 Let $\underline{u}_{1}$ and  $\overline{u}_{2}$   solve
\[
-\Delta_{p}  \underline{u}_{1} = \underline{C} , \quad
-\Delta_{p}  \overline{u}_{2} = \overline{C} \quad \text{in }\Omega,
\]
respectively, with  $\underline{u}_{1} = \overline{u}_{2} = 0$  on
 $\partial \Omega$,
\[
\underline{C}   <   aL , \quad \text{and}\quad  \overline{C}  > c \, .
\]
Finally, define $\overline{u}_{1} \equiv 0$ and
 $ \underline{u}_{2} := b \psi $.
Calculating directly shows that $ \underline{u}_{1}$ and
$\underline{u}_{2}$ are subsolutions and that
$ \overline{u}_{1}$   and   $\overline{u}_{2}$   are supersolutions, with
$ \underline{u}_{1} < \overline{u}_{1} < \underline{u}_{2}
 < \overline{u}_{2}$.
The sub/supersolution theorem immediately yields two distinct solutions,
and a standard argument (cf. \cite{shivaji:ret87}) guarantees the existence
of a distinct third solution.
\end{proof}

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\end{thebibliography}

\end{document}
